Answer:
Burning, cooking, rusting and rotting are examples of chemical changes.What is the molarity of a solution
made by dissolving 18.9 g of
ammonium nitrate (NH4NO3) in
enough water to make 855 mL of
solution?
Molar Mass N: 14.01 g/mol
Molar Mass H: 1.008 g/mol
Molar Mass O: 16.00 g/mol
Answer:
Molarity = 0.28 M
Explanation:
Given data:
Mass of NH₄NO₃ = 18.9 g
Volume of solution = 855 mL (855mL × 1 L/1000 mL = 0.855 L)
Molarity of solution = ?
Solution:
Number of moles of NH₄NO₃:
Number of moles = mass/molar mass
Number of moles = 18.9 g/ 80.043 g/mol
Number of moles = 0.24 mol
Molarity:
Molarity = number of moles of solute / volume in L
Molarity = 0.24 mol /0.855 L
Molarity = 0.28 M
Answer:
0.28
Explanation:
:D
When can I use ideal gas law?
A group 2 metal carbonate has a mass of 84 g/mol. Identify the group 2 metal X using its chemical formula.
Please show your working out. number of moles in 0.3g of calcium carbonate.
Answer:
Magnesium
0.003mole
Explanation:
The problem here entails we find the metal in the carbonate.
For group 2 member, let the metal = X;
The carbonate is XCO₃;
If we sum the atomic mass of the elements in the metal carbonate, we should arrive at 84g/mol
Atomic mass of C = 12g/mol
O = 16g/mol
Atomic mass of X + 12 + 3(16) = 84
Atomic mass of X = 84 - 60 = 24g/mol
The element with atomic mass of 24g is Magnesium
B.
Number of moles in 0.3g of CaCO₃:
Molar mass of CaCO₃ = 40 + 12 + 3(16) = 100g/mol
Number of moles = [tex]\frac{mass}{molar mass}[/tex]
Number of moles = [tex]\frac{0.3}{100}[/tex] = 0.003mole
which term refers to the condition that exists when no over all change in concentration results from diffusion?
a. concentration
b. osmosis
c. equilibrium
d. randomness
Answer:
a.cocentration es la respuesta
If a concentrated solution of acetic acid is 99.5 % HC 2 H 3 O 2 and has a density of 1.05 g/mL, what is the concentration of this acid in moles per litre?
The concentration of this acid in moles per litre : 17.41
Further explanationGiven
99.5% acetic acid
density=ρ=1.05 g/ml
Required
the concentration (mol/L)
Solution
99.5% dan density 1.05 g/ml (MW acetic acid = 60 g/mol)
[tex]\tt 99.5\%\times 1.05\dfrac{g}{ml}\times \dfrac{1000~ml}{L}=1044.75~g/L\\\\\dfrac{1044.75~g/L}{60~g/mol}=17.41~mol/L[/tex]
Explain Joule's law in your own words. pls help
Answer:
Joules first law is a law that expresses the relatioship between heat that is generated and the current flowing heat thats through a conductor. The second law says that internal energy is independent of volume and pressure, depending only on temperature!
Explanation:
Calculate the maximum mass of aluminium which can be extracted from 10 kg of
aluminium oxide
2AlO3+ 3C ----->4Al + 3CO2
Answer:
Hrishikesh. bshjsjbd. jwjjja
Wass, volume and density are all properties of
matter
3
weight.
formula
Answer:
:)
Explanation:
They are all properties of Matter. weight and formula wouldn't make sense.
Dry ice changes from a solid to a gas in a process known as A. Melting B. Freezing C.sublimation
Answer:
c
Explanation:
solid to gas directly
PLEASE ANSWER QUICK! 50 POINTS!!!!
How does the structure of amino acids allow them to form a polypeptide?
Options:
A. Each amino acid has an amino group and a carboxyl group.
B. Each amino acid has a hydrogen atom and a carboxyl group.
C. Each amino acid has a carboxyl group and an R group.
D. Each amino acid has an R group and a hydrogen atom.
Answer:
A. Each amino acid has an amino group and a carboxyl group.
Answer:a
Explanation:
A gas with a volume of 2 L at 25°C is placed into a container that is 4 L. What is the new temperature of the gas?
Given :
A gas with a volume of 2 L at 25°C is placed into a container that is 4 L.
To Find :
The new temperature of the gas.
Solution :
Since, their is no information regarding pressure. We will assume that pressure is constant.
Now, we know when at constant pressure, volume is directly proportional to volume.
[tex]\dfrac{V_1}{V_2}=\dfrac{T_1}{T_2}\\\\\dfrac{2}{4} = \dfrac{25 + 273 }{x}\\\\x = 2 \times ( 25 + 273 )\\\\x = 596\ K[/tex]
Therefore, the new temperature of the gas is 596 - 273 K = 323 K.
BRAINLIEST!! PLZ HELP
Answer:
1.0 is Answer
Explanation:
May be this is helpful!
____ NaBr + ____ Ca(OH)2 ___ CaBr2 + ____ NaOH
Answer:
2 NaBr + 1 Ca(OH)2 ---> 1 CaBr2 + 2 NaOH
a student finishes an experiment and is left with three empty beakers that held liquids during the experiment .the best lab practice is to
Answer:
Rinse With distilled water
Once we use up all the nonrenewable Energy sources they cannot be replenished.
O True
O False
Answer:
true
Explanation:
it says none renewable so you can't reuse it
Answer:
false
Explanation:
becuase nonrenewable means it can not be replenished
Aluminum metal reacts with hydrochloric acid to produce solid aluminum chloride and hydrogen gas. how many moles of aluminum are needed to produce 1.2 moles of hydrogen gas?
Moles of Aluminum needed : 0.8
Further explanationGiven
1.2 moles H₂
Required
moles of aluminum
Solution
The reaction coefficient in a chemical equation shows the mole ratio of the components of the compounds involved in the reaction (reactants and products)
Reaction(balanced equation)
2Al + 6 HCl = 2AlCl₃ + 3H₂
From the equation, mol ratio of Al : H₂ = 2 : 3, so mol Al :
= 2/3 x mol H₂
= 2/3 x 1.2
= 0.8 moles
1. List the types of fronts found on this map
Answer:
Cold Front. A side view of a cold front (A, top) and how it is represented on a weather map (B, bottom). ...
Warm Front. ...
Stationary Front. ...
Occluded Front.
Please help: A 0.200 M NaOH solution was used to titrate a 18.25 mL HF
solution. The endpoint was reached after 31.20 mL of titrant
were added. Find the molar concentration of the original HF
solution.
The molar concentration of the original HF solution : 0.342 M
Further explanation
Given
31.2 ml of 0.200 M NaOH
18.2 ml of HF
Required
The molar concentration of HF
Solution
Titration formula
M₁V₁n₁=M₂V₂n₂
n=acid/base valence (amount of H⁺/OH⁻, for NaOH and HF n =1)
Titrant = NaOH(1)
Titrate = HF(2)
Input the value :
[tex]\tt 0.2\times 31.2\times 1=M_2\times 18.25\times 1\\\\M_2=0.342[/tex]
How does Cyanoacrylate compare to the elements that make it up?
Answer: The elements of the cyanoacrylate are different as compared to the main cyanoacrylate.
Explanation:
The cyanoacrylate is a adhesive water based substance. It is used for developing fingerprints by fuming method. It is the acrylic monomer which has property to develop into a plastic form after application another of its composition is the acrylic resin which imparts adhesiveness to the cyanoacrylate.
17. Calculate the percent composition of B2Br6
Answer:
%composition of B₂ = 4.3%
%composition of Br₆ = 95.7%
Explanation:
Given data:
Percent composition of B₂Br₆ = ?
Solution:
Total mass of B₂Br₆ = 10.8×2 + 79.9×6 = 501 g/mol
%composition of B₂ = ( 21.6 g/ 501 g ) × 100
%composition of B₂ = 0.043 × 100
%composition of B₂ = 4.3%
%composition of Br₆ = ( 479.4 g/ 501 g ) × 100
%composition of Br₆ = 0.957 × 100
%composition of Br₆ = 95.7%
A 0.200 M NaOH solution was used to titrate a 18.25 mL HE
solution. The endpoint was reached after 31.20 mL of titrant
were added. Find the molar concentration of the original HF
solution.
Answer:
M₂ = 0.34 M
Explanation:
Given data:
Molarity of NaOH =M₁ = 0.200 M
Volume of HF =V₂= 18.25 mL
Volume of NaOH added = V₁ = 31.20 mL
Molarity of HF solution = M₂ = ?
Solution:
M₁V₁ = M₂V₂
by putting values,
0.200 M × 31.20 mL = M₂ × 18.25 mL
M₂ = 0.200 M × 31.20 mL / 18.25 mL
M₂ = 6.24 M.mL / 18.25 mL
M₂ = 0.34 M
Which of the following statements best describes how metamorphic rock was formed?
A. Low temperature and low pressure may transform an igneous rock into a metamorphic rock with banded layers.
B. High temperature and intense pressure may transform an igneous rock into a metamorphic rock with banded layers.
C. Low temperature intense pressure may transform a sedimentary rock into a metamorphic rock with banded layers.
Answer:
High temperature and intense pressure may transform an igneous rock into a metamorphic rock with banded layers.
Explanation:
A metamorphic rock is formed under high temperature and intense pressure may transform an igneous rock into a metamorphic rock with banded layers.
An igneous rock is often formed when molten magma erupts from the earth's crust. The molten magma is usually very hot but cools off with time to form a solid mass.
This rock that was first formed eventually gets transformed in the course of time as it is acted upon by high temperature and intense pressure which gradually transforms the igneous rock into a metamorphic rock with banded layers.
Learn more: https://brainly.com/question/19930528
How many moles of nitrogen are in 9.82x10^23 formula units of nitrogen? Please show work!
Answer:
1.63 mols
Explanation:
to convert mols to formula unit, or formula unit to mols, u need the avagadros number which is 6.022*10^23 and the number of mols/formula units
so since the given is formula units, u just have to divide the number by 6.022*10^23 to get the amount of mols
9.82*10^23 / (6.022*10^23) = 1.63 mols
*be careful for sig figs
Uranium contains two isotopes, U-235 with an atomic mas of 235 g/mol, and u-238 with an atomic mass of 238g/mol. U-235 is needed
as a fuel in nuclear reactors. Until recently, the method used to separate U-235 from U-238 was by gas diffusion. Use U-235 as R1, and
U-238 as R2 and determine the rate of diffusion and which gas will diffuse faster.
⚪︎U-235 diffused 10.01 times faster than U-238
⚪︎U-235 diffused 1.01 times slower than U-238
⚪︎U-235 effused 2.01 times slower than U-238
⚪︎U-235 effused 1.01 times faster than U-238
⚪︎U-235 diffused 1.01 times faster than U-238
Answer:
the answer is in the image
Explanation:
Some metal chips with a total volume of 3.29 cm3 are placed on a piece of paper and weighed. The combined mass is found to be 18.43 g, and the paper itself weighs 1.2140 g. Calculate the density of the metal to the proper number of significant figures.
Answer:
d = 5.23 g/cm³
Explanation:
Given data:
Volume of metal chips = 3.29 cm³
Mass of metal chips and paper = 18.43 g
Mass of paper = 1.2140 g
Density of metal = ?
Solution:
Mass of metal = combined mass - mass of paper
Mass of metal = 18.43 g - 1.2140 g
mass of metal = 17.22 g
Density:
d = mass/ volume
d = 17.22 g/ 3.29 cm³
d = 5.23 g/cm³
does something that is hot have more thermal energy than something that’s cold?
Answer:
Yes it does because the atoms/molecules are moving faster than they are in a cold substance.
Explanation:
3. A 240 mL sample of argon gas at 270 K is cooled until the volume is 180 mL. What is the new temperature?
Answer:
202.5 K
Explanation:
The total number of the elements above with 2 valence electron is ____.
Answer:
four elements
Explanation:
He = 1s²
Be = 1s² 2s²
C = 1s² 2s² 2p²
Mg = 1s² 2s² 2p⁶ 3s²
Si = 1s² 2s² 2p⁶ 3s² 3p²
Ca = 1s² 2s² 2p⁶ 3s² 3p⁶ 4s²
Valence electrons are those electrons which are present in outer most electronic shell.
He, Be, Mg, Ca these four elements have 2 valence electrons.
While Si and C have four valance electrons.
The total number of the elements above with 2 valence electron is four.
The electronic configurations of the elements are given:
He = 1s²
Be = 1s² 2s²
C = 1s² 2s² 2p²
Mg = 1s² 2s² 2p⁶ 3s²
Si = 1s² 2s² 2p⁶ 3s² 3p²
Ca = 1s² 2s² 2p⁶ 3s² 3p⁶ 4s²
Valence electrons are those electrons which are present in outer most electronic shell.
He, Be, Mg, Ca these four elements have 2 valence electrons.Learn more:
brainly.com/question/16089134
Balance the following equations
Al + Cl2 AlCl3
Ag2O + Be Ag + BeO
K + O2 K2O
CoP + NaBr CoBr3 + Na3P
Si + Hg2S SiS2 + Hg
Li + Ni3N2 Li3N + Ni
Ca + K3N --> Ca3N2 + K
SnS2 + F2 --> SnF4 + S
Answer:
Explanation:
2Al + 3Cl2 --> 2AlCl3
Ag2O + Be -----> 2Ag + BeO
4K + O2 ---> 2K2O
CoP + 3NaBr ---> CoBr3 + Na3P
Si + Hg2S ---> SiS2 + Hg
6Li + Ni3N2 --- > 2Li3N + 3Ni
3Ca + 2K3N --> Ca3N2 + 6K
SnS2 + 2F2 --> SnF4 + 2S
which of the two metal ions mg2+ and zn2+ is the most reactive why?
Answer:
Mg2+
Explanation:
The most reactive ions from the given choices is the magnesium ion. This is because it is higher in the activity series of metals.
Zinc ion is below this specie in the activity series.
As a rule, ions above another on the activity series are generally more reactive than those below.
From any solution, magnesium ion will displace the zinc ion in such process.
The position of metallic ions determines their reactivity.