Which is a correct statement about the description “two less than the quotient of a number cubed and sixteen, increased by eight” when n = 4?
The correct expression is StartFraction n cubed Over 16 EndFraction minus 2 + 8.
The correct expression is 2 minus StartFraction n cubed Over 16 EndFraction + 8.
One of the steps to determining the value when n = 4 is 1 minus 2 + 8.
One of the steps to determining the value when n = 4 is 2 minus 1 + 8.
The value when n = 4 is 6.
The value when n = 4 is 7.
The value when n = 4 is 9.
The value when n = 4 is 10.

Answer:

a= (Z + 2b)/24

Step-by-step explanation:

given:

Z = 24a - 2b

to solve for a, we will try to move "a" to one side of the equation and all other terms to the other side:

Z = 24a - 2b    (add 2b to both sides)

Z + 2b = 24a -2b +2b

Z + 2b = 24a  (switch sides)

24a = Z + 2b (divide both sides by 24)

a/24 = (Z + 2b)/24

a= (Z + 2b)/24

Answer:

Step-by-step explanation:

Rule for the dilation of a point by a scale factor 'k',

(x, y) → (kx, ky)

If we impose this rule in this problem,

k = [tex]\frac{\text{Distance of A' from P}}{\text{Distance of A from P}}[/tex]

1). If k = 3

   Therefore, Distance of A' from P = 3(Distance of A from P)

   And point A' will be on the third circle.

2). If k = 2

   Distance of B' from P = 2(Distance of B from P)

   Since, B is on circle 2, B' will be on circle 4.

Now we can plot these points A' and B' on the graph.

After the dilation point A becomes A' and it is at a distance of 3 units from point P and after the dilation point B becomes B' and it is at a distance of 2 units from point P.

1)

Given :

Dilate A using P as the center of dilation and a scale factor of 3.

Let the coordinates of point A be (x,y) then after dilation point A becomes A'(3x , 3y). So, the distance of the point A' from the point P is 3 units

2)

Given :

Dilate Busing P as the center of dilation and a scale factor of 2.

Let the coordinates of point B be (x',y') then after dilation point B becomes B'(2x' , 2y'). So, the distance of the point B' from the point P is 2 units

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Answer:

Ich weiß nicht =13

die Antwort -2 -4 (6p-5)

Step-by-step explanation:

Step-by-step explanation:

the regular form of r=8

Answer:

202 miles per day

Step-by-step explanation:

Answer:

165

Step-by-step explanation:

A 2-column table with 3 rows. Column 1 is labeled Days, x with entries 3, 4, 5. Column 2 is labeled Miles, y with entries 771, 973, 1,175.

The Bodens drove for awhile before they made a plan to drive a set number of miles each day. Days 3, 4, and 5 are displayed in the table. Assume the relationship is linear.

Determine the initial number of miles that the Boden family drove before they made their plan.

771 miles

367 miles

165 miles

135 miles

This is your correct answer 165, oops this is the wrong question sorry

Answer:

Let's define the symbols:

x <  y

means that x is strictly less than y.

x ≤ y

means that x is less than or equal to y.

(both of these signs can be in the other direction, take that in mind).

A) " a is always less than another number b"

Here we should have:

a < b.

a is always less than the other number b.

This is not in the options, so i suppose that there is a mistake in the question.

B) The expression "above" is not shown here, so i will just writhe the correspondent expression for each option, and you can see which one matches with the expression above.

a) "The product between 3 and a number is no less than 9"

3*n ≥ 9.

b) "The product between 3 and a number is greater than 9."

3*n > 9

c) "The product between 3 and a number is no more than 9"

3*n ≤ 9

d) "The product between 3 and a number is less than 9"

3*n < 9

Answer:

-8 and 3

Step-by-step explanation:

The asked numbers are -8 and 3.

An equation is a mathematical statement that shows that two mathematical expressions are equal.

For instance, 3x + 5 = 14 is an equation, in which 3x + 5 and 14 are two expressions separated by an 'equal' sign.

Given that, two numbers multiply to -24 and add up to -5

Let the two numbers be x and y

x+y = -5...(i)

xy = -24

x = -24/y...(ii)

Put eq (ii) in eq (i)

-24/y + y = -5

-24 + y² = -5y

y²+5y-24 = 0

Factorizing,

y = 8 and 3

Taking y = 3, put it in eq(ii)

x = -24/3

x = -8

Hence, the asked numbers are -8 and 3.

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Answer:

the mean of which the team won is 8.75

The mean of which the team lost is 11.5

Step-by-step explanation:

add all the numbers of which the team won by then divide the sum by the number of numbers there are

example:

7+8+11+9=35/4=8.75

Answer:

The y intercept is (0, 8). The equation of the function is f(x) = 10x + 8

Step-by-step explanation:

Given that after 1 hour of work, Jack will make 18 dollars and the slope is 10, subtract 10 dollars from 18 dollars to find his set amount, or y-intercept.

18 - 10 = 8 dollars.

Now that we have the m and b values, we can create our equation.

The equation in standard form is f(x) = mx +b, where m = the slope and b = the y-intercept. Plug our values in and the equation will be f(x) = 10x + 8. You can test if this is correct by plugging in x values from the table and seeing if your calculated value correctly corresponds to the given y value in the table.

Answer:

C. [tex] d = \frac{at^2}{2} [/tex]

Step-by-step explanation:

Given:

[tex] t = \sqrt{\frac{2d}{a}} [/tex]

Required:

Make d the subject of the formula.

SOLUTION:

[tex] t = \sqrt{\frac{2d}{a}} [/tex]

Square both sides

[tex] t^2 = (\sqrt{\frac{2d}{a}})^2 [/tex]

[tex] t^2 = \frac{2d}{a} [/tex]

Multiply both sides by a

[tex] a*t^2 = \frac{2d}{a}*a [/tex]

[tex] at^2 = 2d [/tex]

Divide both sides by 2

[tex] \frac{at^2}{2} = \frac{2d}{2} [/tex]

[tex] \frac{at^2}{2} = d [/tex]

[tex] d = \frac{at^2}{2} [/tex]

Answer:

Step-by-step explanation:

1. use the slope formula --> (y2-y1)/(x2-x1)

2. (8 - 4)/(13 -(-3))

3. 4/16

4. m = 1/4

Answer:

-1.48148148

Step-by-step explanation:

-7 x -8 = 56

-7 x -4a = 28a

25-56=-31

27a/-31

a=-1.48148148

Answer:

The solution is too long. So, I included them in the explanation

Step-by-step explanation:

This question has missing details. However, I've corrected each question before solving them

Required: Determine the inverse

1:

[tex]f(x) = 25x - 18[/tex]

Replace f(x) with y

[tex]y = 25x - 18[/tex]

Swap y & x

[tex]x = 25y - 18[/tex]

[tex]x + 18 = 25y - 18 + 18[/tex]

[tex]x + 18 = 25y[/tex]

Divide through by 25

[tex]\frac{x + 18}{25} = y[/tex]

[tex]y = \frac{x + 18}{25}[/tex]

Replace y with f'(x)

[tex]f'(x) = \frac{x + 18}{25}[/tex]

2. [tex]g(x) = \frac{12x - 1}{7}[/tex]

Replace g(x) with y

[tex]y = \frac{12x - 1}{7}[/tex]

Swap y & x

[tex]x = \frac{12y - 1}{7}[/tex]

[tex]7x = 12y - 1[/tex]

Add 1 to both sides

[tex]7x +1 = 12y - 1 + 1[/tex]

[tex]7x +1 = 12y[/tex]

Make y the subject

[tex]y = \frac{7x + 1}{12}[/tex]

[tex]g'(x) = \frac{7x + 1}{12}[/tex]

3: [tex]h(x) = -\frac{9x}{4} - \frac{1}{3}[/tex]

Replace h(x) with y

[tex]y = -\frac{9x}{4} - \frac{1}{3}[/tex]

Swap y & x

[tex]x = -\frac{9y}{4} - \frac{1}{3}[/tex]

Add [tex]\frac{1}{3}[/tex] to both sides

[tex]x + \frac{1}{3}= -\frac{9y}{4} - \frac{1}{3} + \frac{1}{3}[/tex]

[tex]x + \frac{1}{3}= -\frac{9y}{4}[/tex]

Multiply through by -4

[tex]-4(x + \frac{1}{3})= -4(-\frac{9y}{4})[/tex]

[tex]-4x - \frac{4}{3}= 9y[/tex]

Divide through by 9

[tex](-4x - \frac{4}{3})/9= y[/tex]

[tex]-4x * \frac{1}{9} - \frac{4}{3} * \frac{1}{9} = y[/tex]

[tex]\frac{-4x}{9} - \frac{4}{27}= y[/tex]

[tex]y = \frac{-4x}{9} - \frac{4}{27}[/tex]

[tex]h'(x) = \frac{-4x}{9} - \frac{4}{27}[/tex]

4:

[tex]f(x) = x^9[/tex]

Replace f(x) with y

[tex]y = x^9[/tex]

Swap y with x

[tex]x = y^9[/tex]

Take 9th root

[tex]x^{\frac{1}{9}} = y[/tex]

[tex]y = x^{\frac{1}{9}}[/tex]

Replace y with f'(x)

[tex]f'(x) = x^{\frac{1}{9}}[/tex]

5:

[tex]f(a) = a^3 + 8[/tex]

Replace f(a) with y

[tex]y = a^3 + 8[/tex]

Swap a with y

[tex]a = y^3 + 8[/tex]

Subtract 8

[tex]a - 8 = y^3 + 8 - 8[/tex]

[tex]a - 8 = y^3[/tex]

Take cube root

[tex]\sqrt[3]{a-8} = y[/tex]

[tex]y = \sqrt[3]{a-8}[/tex]

Replace y with f'(a)

[tex]f'(a) = \sqrt[3]{a-8}[/tex]

6:

[tex]g(a) = a^2 + 8a- 7[/tex]

Replace g(a) with y

[tex]y = a^2 + 8a - 7[/tex]

Swap positions of y and a

[tex]a = y^2 + 8y - 7[/tex]

[tex]y^2 + 8y - 7 - a = 0[/tex]

Solve using quadratic formula:

[tex]y = \frac{-b\±\sqrt{b^2 - 4ac}}{2a}[/tex]

[tex]a = 1[/tex] ; [tex]b = 8[/tex]; [tex]c = -7 - a[/tex]

[tex]y = \frac{-b\±\sqrt{b^2 - 4ac}}{2a}[/tex] becomes

[tex]y = \frac{-8 \±\sqrt{8^2 - 4 * 1 * (-7-a)}}{2 * 1}[/tex]

[tex]y = \frac{-8 \±\sqrt{64 + 28 + 4a}}{2 * 1}[/tex]

[tex]y = \frac{-8 \±\sqrt{92 + 4a}}{2 * 1}[/tex]

[tex]y = \frac{-8 \±\sqrt{92 + 4a}}{2 }[/tex]

Factorize

[tex]y = \frac{-8 \±\sqrt{4(23 + a)}}{2 }[/tex]

[tex]y = \frac{-8 \±2\sqrt{(23 + a)}}{2 }[/tex]

[tex]y = -4 \±\sqrt{(23 + a)}[/tex]

[tex]g'(a) = -4 \±\sqrt{(23 + a)}[/tex]

7:

[tex]f(b) = (b + 6)(b - 2)[/tex]

Replace f(b) with y

[tex]y = (b + 6)(b - 2)[/tex]

Swap y and b

[tex]b = (y + 6)(y - 2)[/tex]

Open Brackets

[tex]b = y^2 + 6y - 2y - 12[/tex]

[tex]b = y^2 + 4y - 12[/tex]

[tex]y^2 + 4y - 12 - b = 0[/tex]

Solve using quadratic formula:

[tex]y = \frac{-b\±\sqrt{b^2 - 4ac}}{2a}[/tex]

[tex]a = 1[/tex] ; [tex]b = 4[/tex]; [tex]c = -12 - b[/tex]

[tex]y = \frac{-b\±\sqrt{b^2 - 4ac}}{2a}[/tex] becomes

[tex]y = \frac{-4\±\sqrt{4^2 - 4 * 1 * (-12-b)}}{2*1}[/tex]

[tex]y = \frac{-4\±\sqrt{4^2 - 4 *(-12-b)}}{2}[/tex]

Factorize:

[tex]y = \frac{-4\±\sqrt{4(4 - (-12-b))}}{2}[/tex]

[tex]y = \frac{-4\±2\sqrt{(4 - (-12-b))}}{2}[/tex]

[tex]y = \frac{-4\±2\sqrt{(4 +12+b)}}{2}[/tex]

[tex]y = \frac{-4\±2\sqrt{16+b}}{2}[/tex]

[tex]y = -2\±\sqrt{16+b}[/tex]

Replace y with f'(b)

[tex]f'(b) = -2\±\sqrt{16+b}[/tex]

8:

[tex]h(x) = \frac{2x+17}{3x+1}[/tex]

Replace h(x) with y

[tex]y = \frac{2x+17}{3x+1}[/tex]

Swap x and y

[tex]x = \frac{2y+17}{3y+1}[/tex]

Cross Multiply

[tex](3y + 1)x = 2y + 17[/tex]

[tex]3yx + x = 2y + 17[/tex]

Subtract x from both sides:

[tex]3yx + x -x= 2y + 17-x[/tex]

[tex]3yx = 2y + 17-x[/tex]

Subtract 2y from both sides

[tex]3yx-2y =17-x[/tex]

Factorize:

[tex]y(3x-2) =17-x[/tex]

Make y the subject

[tex]y = \frac{17 - x}{3x - 2}[/tex]

Replace y with h'(x)

[tex]h'(x) = \frac{17 - x}{3x - 2}[/tex]

9:

[tex]h(c) = \sqrt{2c + 2}[/tex]

Replace h(c) with y

[tex]y = \sqrt{2c + 2}[/tex]

Swap positions of y and c

[tex]c = \sqrt{2y + 2}[/tex]

Square both sides

[tex]c^2 = 2y + 2[/tex]

Subtract 2 from both sides

[tex]c^2 - 2= 2y[/tex]

Make y the subject

[tex]y = \frac{c^2 - 2}{2}[/tex]

[tex]h'(c) = \frac{c^2 - 2}{2}[/tex]

10:

[tex]f(x) = \frac{x + 10}{9x - 1}[/tex]

Replace f(x) with y

[tex]y = \frac{x + 10}{9x - 1}[/tex]

Swap positions of x and y

[tex]x = \frac{y + 10}{9y - 1}[/tex]

Cross Multiply

[tex]x(9y - 1) = y + 10[/tex]

[tex]9xy - x = y + 10[/tex]

Subtract y from both sides

[tex]9xy - y - x = y - y+ 10[/tex]

[tex]9xy - y - x = 10[/tex]

Add x to both sides

[tex]9xy - y - x + x= 10 + x[/tex]

[tex]9xy - y = 10 + x[/tex]

Factorize

[tex]y(9x - 1) = 10 + x[/tex]

Make y the subject

[tex]y = \frac{10 + x}{9x - 1}[/tex]

Replace y with f'(x)

[tex]f'(x) = \frac{10 + x}{9x -1}[/tex]

Answer:

It's 576 if you mean 64 times 9!

Step-by-step explanation:

Answer:

A. -x² + 2x + 8

General Formulas and Concepts:

Algebra I

Step-by-step explanation:

Step 1: Define

f(x) = 2x + 1

g(x) = x² - 7

(f - g)(x) is f(x) - g(x)

Step 2: Solve

Answer:

R= - 95/7

Step-by-step explanation:

Answer:

niwebfasfbjsdfb

Step-by-step explanation:

jsdfhsdbfjhadsjbdsfhb

Answer:

0.0425

Step-by-step explanation:

Answer:

0.0425

Step-by-step explanation:

hope this helped ^^

Answer:

the first questions answer is yes the seconds is no

HAVE A NICE DAY!!!

Answer:           0.875

Step-by-step explanation:

Answer:X=3

y= -4

Step-by-step explanation:

If we're solving for x or y, then the intercept we're not solving for is equal to zero. Solving for y means x=0, solving for x means y=0.

so solving for x, 4x=12--> x=3, since y=0 in this scenario.

Solving for y, x=0, so -3y=12--> y=(-4)

9514 1404 393

Answer:

  see below for a table

Step-by-step explanation:

You can easily identify intercept points by solving for one variable when the other is zero.

x-intercept (y=0)

  4x = 12

  x = 12/4 = 3

y-intercept (x=0)

  -3y = 12

  y = 12/-3 = -4

So, the coordinate pairs of these points are ...

  (3, 0) and (0, -4)

__

If you solve for y, you get ...

  -3y = 12 -4x

  y = (4/3)x -4 . . . . . divide by -3

This suggests that x being a multiple of 3 will be useful for finding integer values of y.

We already have points for x=0 and x=3. We can add points for x=6 and x=-3.

  y = 4/3(6) -4 = 4

  y = 4/3(-3) -4 = -8

So, the additional points are ...

  (6, 4) and (-3, -8)

Answer:

5/2

Step-by-step explanation:

25 and 10 so 25/10 or 5/2 or 2 1/2

Answer for #5:

7 friends

Step-by-step explanation:

convert fraction into 4ths:

1/4, 2/4, 3/4, 1/4

add together:

7/4ths

if each friend ate 1/4 of the pizzas, then there are 7 friends

Answer:

6A7C8B

Step-by-step explanation:

Add them in and try to solve for 7 and 6, for 8. I usually put all number on one side and all x on other side.

Answer:

(1,1)

Step-by-step explanation:

Answer:

rise : atmospheric pressure increases

fall : atmospheric pressure decreases

Step-by-step explanation:

In the context, it is given that a weather forecaster takes the help of the barometer to check the air pressure and predicts the weather. The column of mercury level in the barometer shows a rise or fall in the glass tube as the weight of the atmosphere falling on the mercury surface changes.

Here it is given that the mercury rises for 0.02 in, then it falls 0.09 in,  it then rises by 0.07 in and then again falls by 0.18 in. The word "rise" here shows that the weight of the atmosphere is more. In other words, increase in atmospheric pressure increases the level of mercury in the glass tube and the decrease in or "fall" in the mercury level shows the drop in atmospheric pressure.