Answer:
Bye
bye
bye
bye
Explanation:
Answer:
HELLO Hello thank you for your points...
Write an algorithm (pseudo-code) that takes an unsorted list of n integers and outputs a sorted list of all duplicate integers. There must be no duplicates in the output list, also the output list should be a sorted list. The algorithm must run in O(n) time. Show your analysis of the running time. Note: Assume that inputs are integer values from 0 to 255. (Hint: use the concept that being used in the separate chaining)
Answer:
brainliest if it did help you
Explanation:
Given array : A[0...n-1]Now, create a count array Cnt[0...n-1]then, initialize Cnt to zero
for(i=0...n-1)
Cnt[i]=0 ---------O(n) time
Linearly traverse the list and increment the count of respected number in count array.
for(i=0...n-1)
Cnt[A[i]]++; ---------O(n) time
Check in the count array if duplicates exist.
for(i=0...n-1){
if(C[i]>1)
output (i); -----------O(n) time
}
analysis of the above algorithm:
Algorithm takes = O(1 + n + n + n)
= O(n)
//java code
public class SortIntegers {
public static void sort(int[] arr) {
int min = arr[0];
int max = arr[0];
for (int i = 0; i < arr.length; ++i) {
if (arr[i] > max) {
max = arr[i];
}
if (arr[i] < min) {
min = arr[i];
}
}
int counts[] = new int[max - min + 1];
for (int i = 0; i < arr.length; ++i) {
counts[arr[i] - min]++;
}
for (int i = 0; i < counts.length; ++i) {
if (counts[i] > 1) {
System.out.print((i + min) + " ");
}
}
System.out.println();
}
public static void main(String[] args) {
sort(new int[] { 5, 4, 10, 2, 4, 10, 5, 3, 1 });
}
}
A company is choosing a database. Several options are available, but the business owner needs help deciding which one is best. The company is a big city law firm with many clients. Which tool would you recommend?
a server database
a desktop database
a spreadsheet
Answer:
a. Server database
Explanation:
Answer:
The next one is C. Spreadsheet.
Explanation:
Edge
Prepare a document to list down at least 10 features/operations (on process and thread) you can do using Process Explorer.
Answer:
The operations that can be carried out using process explorer include but are not limited to:
Explanation:
Killing a Process TreeEnding or terminating a processSuspending a processExamining which process has locked a fileManually detecting a virusUnhiding a process. This can help to callup the window for a process that is not visible under normal explorer activitiesMonitor CPU usage setting the priority of a processchanging a service process's access securityMonitoring Graphics Processing Unit
Cheers
Taran is concerned with the security of his macros in a database. Which security option could he use to provide protection?
digital signatures
hide database objects
start-up options
secure VBA code
Answer:security VBA code
Explanation:
Select all that apply.
What two values do comparison operators return?
TRUE
EQUAL
LESS THAN
FALSE
Answer:
Equal
Less than
Explanation:
state two reason why there is a carry out a feasibility srudy in SDLC
Answer:Feasibility studies are important to business development.
1.) They can allow a business to address where and how it will operate.
2.) They can also identify potential obstacles that may impede its operations and recognize the amount of funding it will need to get the business up and running.
The variable strFirst's scope is _____.
Answer:
- the usernameMaker function
Explanation:
When you look at the code, you can see it's located alongside the usernameMaker. It it only utilized then, therefore being it's scope. For reassurance, it's also correct on Edge.
I hope this helped!
Good luck <3
Sergio needs to tell his team about some negative feedback from a client. The team has been
working hard on this project, so the feedback may upset them. Which of the following explains
the best way for Sergio to communicate this information?
A) Hold an in person meeting so that he can gauge the team's body language to assess their
reaction
B) Send a memorandum so everyone will have the feedback in writing
C) Hold a video conference so everyone can see and hear about the client's concern without the group witnessing each other's reactions
D) Send an email so everyone will have time to think about the feedback before the next team meeting
Answer:
A
Explanation:
I feel that if everyone is with eachother, there may be a better hope to improve the next time
The following table describes the required fields for two classes and typical values stored in those fields.
You are required to create a base class Printer and its child class PrinterCumScanner. Each of these classes should have user defined constructor and overridden Display() method so that the following test driver can work properly.
Answer:
hope this helps,if it did pls mark my ans as brainliest
Explanation:
using System;
class Printer{ string companyName; int pagesOutput;
double price;
public Printer(string companyName,int pagesOutput,double price){
this.companyName=companyName; this.pagesOutput=pagesOutput; this.price=price;
}
public virtual void Display(){ Console.WriteLine("companyName: "+companyName+" pagesOutput: "+pagesOutput+" price: "+price);
}
}
class PrinterCumScanner:Printer{ int imageDpi;
public PrinterCumScanner(string companyName,int pagesOutput,double price,int imageDpi):base(companyName,pagesOutput,price){ this.imageDpi=imageDpi; }
public override void Display(){ base.Display(); Console.WriteLine("imageDpi: "+imageDpi);
}
}
public class Program { static void Main(string[] args) { const int NUM_PRINTERS=3;
Printer []stock=new Printer[NUM_PRINTERS];
stock[0]=new Printer("HP",40,89.50);
stock[1]=new PrinterCumScanner("HP",40,215.0,320); stock[2]=new PrinterCumScanner("Cannon",30,175.0,240);
foreach(Printer aPrinter in stock){ aPrinter.Display();
}
}
}
CHALLENGE ACTIVITY
1.6.1: Type casting: Computing average owls per zoo.
Assign avg_owls with the average owls per zoo. Print avg_owls as an integer.
Sample output for inputs: 1 2 4
Average owls per zoo: 2
-------------------------------------------------------------------
Someone please explain what I am doing wrong?
Answer:
avg_owls=0.0
num_owls_zooA = int(input())
num_owls_zooB = int(input())
num_owls_zooC = int(input())
num_zoos = 3
avg_owls = (num_owls_zooA + num_owls_zooB + num_owls_zooC) / num_zoos
print('Average owls per zoo:', int(avg_owls))
Explanation:
There is a problem while you are trying the calculate the average owls per zoo.
As you may know, in order to calculate the average, you need to get the total number of owls in all the zoos, then divide it to the number of zoos. That is why you need to sum num_owls_zooA + num_owls_zooB + num_owls_zooC and divide the result by num_zoos
Be aware that the average is printed as integer value. That is why you need to cast the avg_owls to an int as int(avg_owls)
Internet __________, or IP, describes how data pachets move through a network.
Answer:
Packets
Explanation:
Answer:
protocol
Explanation:
IP stands for internet protocol
Let's implement a classic algorithm: binary search on an array. Implement a class named BinarySearcher that provides one static method named search. search takes a SearchList as its first parameter and a Comparable as its second. If either parameter is null, or if the SearchList is empty, you should throw an IllegalArgumentException. SearchList is a provided class. It provides a get(int) method that returns the Comparable at that index, and a size method that returns the size of the SearchList. Those are the only two methods you should need! search returns a boolean indicating whether the passed value is located in the sorted SearchList. To search the sorted SearchList efficiently, implement the following algorithm: Examine the value in the middle of the current array (index (start + end) / 2) If the midpoint value is the value that we are looking for, return true If the value that we are looking for is greater than the midpoint value, adjust the current array to start at the midpoint if the value that we are looking for is less than the midpoint value, adjust the current array to end at the midpoint Continue until you find the value, or until the start reaches the end, at which point you can give up and return false This is a fun problem! Good luck! Keep in mind that every time you call SearchList.get that counts as one access, so you'll need to reduce unnecessary accesses to pass the test suite.
Answer:
Hope this helped you, and if it did , do consider giving brainliest.
Explanation:
import java.util.ArrayList;
import java.util.List;
//classs named BinarySearcher
public class BinarySearcher {
// main method
public static void main(String[] args) {
// create a list of Comparable type
List<Comparable> list = new ArrayList<>();
// add elements
list.add(1);
list.add(2);
list.add(3);
list.add(4);
list.add(5);
list.add(6);
list.add(7);
// print list
System.out.println("\nList : "+list);
// test search method
Comparable a = 7;
System.out.println("\nSearch for 7 : "+search(list,a));
Comparable b = 3;
System.out.println("\nSearch for 3 : "+search(list,b));
Comparable c = 9;
System.out.println("\nSearch for 9 : "+search(list,c));
Comparable d = 1;
System.out.println("\nSearch for 1 : "+search(list,d));
Comparable e = 12;
System.out.println("\nSearch for 12 : "+search(list,e));
Comparable f = 0;
System.out.println("\nSearch for 0 : "+search(list,f));
}
// static method named search takes arguments Comparable list and Comparable parameter
public static boolean search(List<Comparable> list, Comparable par) {
// if list is empty or parameter is null the throw IllegalArgumentException
if(list.isEmpty() || par == null ) {
throw new IllegalArgumentException();
}
// binary search
// declare variables
int start=0;
int end =list.size()-1;
// using while loop
while(start<=end) {
// mid element
int mid =(start+end)/2;
// if par equal to mid element then return
if(list.get(mid).equals(par) )
{
return true ;
}
// if mid is less than parameter
else if (list.get(mid).compareTo(par) < 0 ) {
start=mid+1;
}
// if mid is greater than parameter
else {
end=mid-1;
}
}
// if not found then retuen false
return false;
}
}import java.util.ArrayList;
import java.util.List;
//classs named BinarySearcher
public class BinarySearcher {
// main method
public static void main(String[] args) {
// create a list of Comparable type
List<Comparable> list = new ArrayList<>();
// add elements
list.add(1);
list.add(2);
list.add(3);
list.add(4);
list.add(5);
list.add(6);
list.add(7);
// print list
System.out.println("\nList : "+list);
// test search method
Comparable a = 7;
System.out.println("\nSearch for 7 : "+search(list,a));
Comparable b = 3;
System.out.println("\nSearch for 3 : "+search(list,b));
Comparable c = 9;
System.out.println("\nSearch for 9 : "+search(list,c));
Comparable d = 1;
System.out.println("\nSearch for 1 : "+search(list,d));
Comparable e = 12;
System.out.println("\nSearch for 12 : "+search(list,e));
Comparable f = 0;
System.out.println("\nSearch for 0 : "+search(list,f));
}
// static method named search takes arguments Comparable list and Comparable parameter
public static boolean search(List<Comparable> list, Comparable par) {
// if list is empty or parameter is null the throw IllegalArgumentException
if(list.isEmpty() || par == null ) {
throw new IllegalArgumentException();
}
// binary search
// declare variables
int start=0;
int end =list.size()-1;
// using while loop
while(start<=end) {
// mid element
int mid =(start+end)/2;
// if par equal to mid element then return
if(list.get(mid).equals(par) )
{
return true ;
}
// if mid is less than parameter
else if (list.get(mid).compareTo(par) < 0 ) {
start=mid+1;
}
// if mid is greater than parameter
else {
end=mid-1;
}
}
// if not found then retuen false
return false;
}
}
14. Video game legend Shigeru Miyamoto designed all EXCEPT which of the following games?
a) Donkey Kong
b) Mario Bros
c) The Legend of Zelda
d) Pac-Man
Assume that class BankAccount exists, and that it has a constructor that sets the private field balance, and that setBalance and getBalance are defined by class BankAccount and set and get double values. Then what is the output of the following code:________.
a. 600.0
b. 0.0
c. 300.0
d. null
e. an error will result
Assume that class BankAccount exists, and that it has a constructor that sets the private field balance, and that setBalance and getBalance are defined by class BankAccount and set and get double values.
Then what is the output of the following code?
BankAccount b1 = new BankAccount(600.0);
BankAccount b2 = b1;
b1.setBalance(300.0);
System.out.println(b2.getBalance() );
Answer:300.0
Explanation:The given snippet of code is as follows:
=======================================
BankAccount b1 = new BankAccount(600.0);
BankAccount b2 = b1;
b1.setBalance(300.0);
System.out.println(b2.getBalance() );
=======================================
Line 1: An object b1 of the BankAccount class is created which sets the value of its balance to 600.0
Line 2: A second object, b2, is created referencing or pointing to the first object, b1 in memory. It could also be interpreted to mean that a second object b2 is created from the exact copy of the first object, b1. This is called object cloning. This by implication means that all the fields (including the contents of the fields) of the first object b1, are copied to b2 which also means that when there's a change in b1, an update is made to b2 also. If a change is made to b2, b1 also gets updated.
Line 3: Object b1 is updated by setting the value of its balance field to 300.0 using the setBalance() method. This will also update the same field for the second object b2.
Line 4: The value of the balance field of object b2 is being printed to the console. Since the value has been updated in line 3 when that of b1 was updated, 300.0 will be printed to the console.
Two character strings may have many common substrings. Substrings are required to be contiguous in the original string. For example, photograph and tomography have several common substrings of length one (i.e., single letters), and common substrings ph, to, and ograph as well as all the substrings of ograph. The maximum common substring length is 6. Let X = X122 . Im and Y = yıy2 - - • Yn be two character strings. Using dynamic programming, design an algorithm to find the maximum common substring length for X and Y using dynamic programming. Please follow the general steps for designing a dynamic programming solution as in Q1 (other than the actual programming part).
Answer:
Explanation:
The following function is written in Java. It takes two strings as parameters and calculates the longest substring between both of them and returns that substring length.
import java.util.*;
class Test
{
public static void main(String[] args)
{
String X = "photograph";
String Y = "tomography";
System.out.println(X + '\n' + Y);
System.out.println("Longest common substring length: " + longestSub(X, Y));
}
static int longestSub(String X, String Y)
{
char[] word1 = X.toCharArray();
char[] word2 = Y.toCharArray();
int length1 = X.length();
int length2 = Y.length();
int substringArray[][] = new int[length1 + 1][length2 + 1];
int longestSubstringLength = 0;
for (int i = 0; i <= length1; i++)
{
for (int j = 0; j <= length2; j++)
{
if (i == 0 || j == 0)
substringArray[i][j] = 0;
else if (word1[i - 1] == word2[j - 1])
{
substringArray[i][j]
= substringArray[i - 1][j - 1] + 1;
longestSubstringLength = Integer.max(longestSubstringLength,
substringArray[i][j]);
}
else
substringArray[i][j] = 0;
}
}
return longestSubstringLength;
}
}
A major advantage of direct mapped cache is its simplicity and ease of implementation. The main disadvantage of direct mapped cache is: a. it is more expensive than fully associative and set associative mapping. b. it has a greater access time than any other method. c. its performance is degraded if two or more blocks that map to the same location are used alternately. d. it does not allow the cache to store the tag that corresponds to the block currently residing in that cache location.
brainlest pl jk mmmmmmmmmmmmm
What is the full form of LAPTOP?
Answer:
The full form of Laptop is Lightweight Analytical Platform Total Optimized Power.
11. Its collection of toys which could be used in the game via an implanted RFID chip made Activision’s game _______ one of the most important in gaming history.
a) 102 Dalmations
b) Skylanders
c) Lego Star Wars
d) Super Monkey Ball
Answer:
I think it's B correct me if I'm wrong
Explanation:
Answer:
B
Explanation:
I say it is the right one although in this 2021 there is no other game but it is its 10th anniversary
I need help
I am thinking about coming out to my mom because we are going to the store today and I will be in the car, I dont know if I should or not
Answer:
do it! you will have to one day so why not now? hopefully she will understand and say nice things as well and be like mom ive
been thinking a lot and i really want to tell you something. Explanation:
Answer:most likely she is your parent that you live with so she might already know but has not said anything it also depends her personality but if your ready and know or think she would not hate you forever go for it
Explanation:
Create a class named TestCircle whose main() method declares Several Circle objects. Using the setRadius() method, assign one Circle a small radius value, and assign another a larger value. Do not assign a value to the radius of the third circle; instead, retain the value assigned at construction. Display all the values for all the Circle objects. Save the application as TestCircle.java
Answer:ublic class Circle {
public int radius = 1;
public double diameter;
public double area;
//Constructor for circle class
public double Circle(int First){
return radius;
}
//Start set and get for radius
private double setRadius(int r){
return radius = 5;
}
private double getRadius(){
return radius;
}
//Start set and get for diameter
public double setDiamter(double d){
return diameter = 7;
}
public double getDiamter(){
return radius * diameter;
}
a friend emails a presentation to isabella to view. what kind of change can she make?
Answer:
She can enable editing. She can change the view.
Explanation:
why do we need to make a plan before actions?
Answer:
Creating an action plan gives you a clear guide to success.
Explanation:
It helps prioritize goals, maximize resources, and make better decisions
(main.c File)
Counting the character occurrences in a file
For this task you are asked to write a program that will open a file called “story.txt”
and count the number of occurrences of each letter from the alphabet in this file.
At the end your program will output the following report:
Number of occurrences for the alphabets:
a was used – times.
b was used – times.
c was used – times…. …and so, on
Assume the file contains only lower-case letters and for simplicity just a single
paragraph. Your program should keep a counter associated with each letter of the
alphabet (26 counters) [Hint: Use array]
Your program should also print a histogram of characters count by adding
a new function print Histogram (int counters []). This function receives the
counters from the previous task and instead of printing the number of times each
character was used, prints a histogram of the counters. An example histogram for
three letters is shown below) [Hint: Use the extended asci character 254]
Answer:
C code
Explanation:
#include <stdio.h>
void histrogram(int counters[])
{
int i,j;
int count;
for(i=0;i<26;i++)
{
count=counters[i];
printf("%c ",i+97);
for(j=0;j<count;j++)
{
printf("="); //= is used
}
printf("\n");
}
}
int main()
{
FILE* fp;
int i;
int arr[26];
char c;
int val;
// Open the file
fp = fopen("story.txt", "r");
if (fp == NULL) {
printf("Could not open file ");
return 0;
}
else
{
for(i=0;i<26;i++)
arr[i]=0;
for (c = getc(fp); c != EOF; c = getc(fp))
{
if(c>='a' && c<='z')
{
val = c-97;
//printf("%d ",val);
arr[val]++;
}
}
histrogram(arr);
}
}
how many nibbles make one kilobyte
Answer:
2000 nibbles
Explanation:
2000 nibbles is needed for 1 kilobyte
Selection Sort List the resulting array after each iteration of the outer loop of the selection sort algorithm. Indicate the number of character-to-character comparisons made for each iteration (line 07 of the Selection Sort algorithm at the end of the assignment). Sort the following array of characters (sort into alphabetical order): CQS A XBT Selection Sort 01 public static void selectionSort (int[] a) { 02 03 int n = a.length; for (int i = 0 ; i 0; j--) { if ( a[j-1] > a[j] ) { exchange(a, j-1, j); } else break; 10 } 12 private static void exchange (int[] a, int i, int j) { 13 // exchange the value at index i with the value at index j int temp = a[i]; a[i] = a[j]; a[j] = temp; 17 }
Solution :
Initial array = [tex]$\text{C,Q,S,A,X,B,T}$[/tex]
[tex]$n= 7$[/tex](length of the array)
[tex]$\text{1st}$[/tex] Iteration:
i = 1
j = 1
[tex]$\text{a[j-1]}$[/tex] = C
a[j] = Q
since [tex]$\text{a[j-1]}$[/tex] < a[j] , break from inner loop
Number of comparisons in 1st Iteration = 1
After 1st Iteration:
Array : C,Q,S,A,X,B,T
2nd Iteration:
i = 2
j = 2
a[j-1] = Q
a[j] = S
since a[j-1] < a[j], break from inner loop
Number of comparisons in 2nd Iteration = 1
After 2nd Iteration:
Array : C,Q,S,A,X,B,T
3rd Iteration:
i = 3
j = 3
a[j-1] = S
a[j] = A
since a[j-1] > a[j], exchange a[2] with a[3]
Array : C,Q,A,S,X,B,T
j = 2
a[j-1] = Q
a[j] = A
since a[j-1] > a[j], exchange a[1] with a[2]
Array : C,A,Q,S,X,B,T
j = 1
a[j-1] = C
a[j] = A
since a[j-1] > a[j], exchange a[0] with a[1]
Array : A,C,Q,S,X,B,T
j = 0, break from inner loop
Number of comparisons in 3rd Iteration = 3
After 3rd Iteration:
Array : A,C,Q,S,X,B,T
4th Iteration:
i = 4
j = 4
a[j-1] = S
a[j] = X
since a[j-1] < a[j], break from inner loop
Number of comparisons in 4th Iteration = 1
After 4th Iteration:
Array : A,C,Q,S,X,B,T
5th Iteration:
i = 5
j = 5
a[j-1] = X
a[j] = B
since a[j-1] > a[j], exchange a[4] with a[5]
Array : A,C,Q,S,B,X,T
j = 4
a[j-1] = S
a[j] = B
since a[j-1] > a[j], exchange a[3] with a[4]
Array : A,C,Q,B,S,X,T
j = 3
a[j-1] = Q
a[j] = B
since a[j-1] > a[j], exchange a[2] with a[3]
Array : A,C,B,Q,S,X,T
j = 2
a[j-1] = C
a[j] = B
since a[j-1] > a[j], exchange a[1] with a[2]
Array : A,B,C,Q,S,X,T
j = 1
a[j-1] = A
a[j] = B
since a[j-1] < a[j], break from inner loop
Number of comparisons in 5th Iteration = 5
After 5th Iteration:
Array : A,B,C,Q,S,X,T
6th Iteration:
i = 6
j = 6
a[j-1] = X
a[j] = T
since a[j-1] > a[j], exchange a[5] with a[6]
Array : A,B,C,Q,S,T,X
j = 5
a[j-1] = S
a[j] = T
since a[j-1] < a[j], break from inner loop
Number of comparisons in 6th Iteration = 2
After 6th Iteration:
Array : A,B,C,Q,S,T,X
Sorted Array : A B C Q S T X
What type of system enables computer data to be stored in multiple locations and shared with multiple users simultaneously?
A. content delivery network
B. consumer delivery network
C. cloud storage
D. World Wide Web
Answer:
A
Explanation:
is it possible to unlock a password without a password if you forgot
Answer:
no
Explanation:
because u will need an code
Answer:
it should have a reset with email option
Explanation:
Karen is designing a website for her uncle's landscaping business. She wants to ensure that it's engaging and provides a lot of information about the services that he provides. She already has a lot of images that make the website visually attractive, but she hasn't found a way to provide information about the services and still engage the visitors. What is something that Karen can add to the website to meet these needs.
Explanation:
Talk About The Benefits. of your service over other compines
According to the above scenario, Karen can add an upbeat video that describes about the services offered by them to the website to meet these needs.
What is Website?A website is a collection of internet pages and related material recognized by a common domain name and hosted on at least one web server.
Websites are usually focused on a single topic or goal, such as news, education, business, entertainment, or social networking. The navigation of the site, which typically begins with a home page, is guided by hyperlinking between online pages.
Websites may be accessed using a variety of devices, including desktops, laptops, tablets, and smartphones. The app that is utilized on these smartphones is known as Web Browser.
According to the aforesaid situation, Karen can post an uplifting video to the website that outlines the services they offer to suit these demands.
Learn more about Website here:
https://brainly.com/question/19459381
#SPJ2
list area where ICT tools can be integrated
Answer:
In surgical labs
In Aviation control centres
In secretarial sects of organizations
the levels of classification of organisms in order are: domain, kingdom, phylum, class, order, family, genus, and species. The broadest, least specific level is____________________
Answer:
Domain.
Explanation:
In Science, this biological classification of living organisms based on similarities or characteristics such as eyes, number of legs, etc., is generally referred to as taxonomy.
Taxonomy can be defined as the process of naming, classification and description of living organisms such as plants and animals.
Basically, the eight (8) biological classification (taxonomy) used for grouping and organizing organisms are; kingdom, domain, phylum, family, order, class, species and genus.
Hence, taxonomy helps scientist to have a good understanding and knowledge when studying various organisms.
Furthermore, the broadest, least specific level of the biological classification of living organisms is domain. The three (3) domain in which living organisms can be classified are: Bacteria, Eukaryote, and Archaea.
Answer:
doman
Explanation: