Which group of elements will form molecular compounds? (Choose all that apply)

Answer:

acid rain is a problem associated with the use of fossil fuels

Answer:

Explanation:

The compound shown is Carbon Dioxide and is as a result of a covalent bond between Carbon and Oxygen where carbon is sharing two electrons each with the oxygen atoms.

The O is the atomic symbol for Oxygen and the C is the symbol for Carbon. Carbon Dioxide then has the atomic symbol of CO₂ to show the relative number of atoms of each element in it.

Answer:

78.8%

Explanation:

The equation of the reaction is;

2 Al(s) + Fe2O3(aq) ------> Al2O3(aq) + 2Fe(s)

Number of moles in 20g of Al= 20g/27 g/mol = 0.74 moles

From the reaction equation;

2 moles of Al yields 2 moles of Fe

0.74 moles of Al yields 0.74 moles of Fe

Hence;

Mass of Fe produced = 0.74 moles of Fe * 56 g/mol

Mass of Fe produced = 41.44 g of Fe (This is the theoretical yield of Fe)

percent yield = actual yield/ theoretical yield  * 100

actual yield = 32.67 grams of iron

percent yield = 32.67 g/41.44 g * 100

percent yield = 78.8%

Answer:

grams CaF₂ = grams Al₂(CO₃)₃ = 167.7 grams (4 sig. figs.)

Explanation:

                     3CaCO₃          +           2AlF₃            =>     3CaF₂   +   Al₂(CO₃)₃

Given:    214.5g/(100g/mol)      321.9g/(84g/mol) =>2.15 moles & 0.71 mole

                   = 2.15 mole               = 3.83 mole    =>       ?g CaF₂    ?g Al₂(CO₃)₃

ID of Limiting Reactant => divide mole values by respective coefficient & smaller value is the Limiting Reactant.

           CaCO₃ => (2.15/3) = 0.72  and    AlF₃ => (3.83/2) = 1.92

The value for CaCO₃ (=0.72)          <        the value for AlF₃ (=1.92)  => CaCO₃ is the Limiting Reactant

Note: When working problem using mole ratios, use mole value for Limiting Reactant and not the value used to determine Limiting Reactant, in this case 2.15 moles CaCO₃.

grams CaF₂ Produced:

moles CaF₂ produced = 3/3(2.15) moles CaF₂ = 2.15 moles CaF₂

grams CaF₂ produced = 2.15 moles CaF₂ x 78 g CaF₂ / mole CaF₂

= 167.7 grams CaF₂

grams Al₂(CO₃)₃ produced:

moles Al₂(CO₃)₃ produced = 1/3(2.15) moles Al₂(CO₃)₃ = 0.72 mole Al₂(CO₃)₃

grams Al₂(CO₃)₃ = 0.72  mole Al₂(CO₃)₃  x  234 g Al₂(CO₃)₃ / mole Al₂(CO₃)₃ = 167.7 grams  Al₂(CO₃)₃  

Answer:

b. The splitting of the d-orbitals is smaller in the [Ni(Cl)6]4- complex than in the [Ni(en)3]2+ complex.

Explanation:

The spectrochemical series is an arrangement of ligands in increasing order of their magnitude of crystal field splitting.

Ligands that occurs towards the right in the series are called strong field ligands and they tend to cause a greater magnitude of crystal field splitting. Ligands that occur towards the left hand side in the series are called weak field ligands and they tend to cause a lesser magnitude of crystal field splitting.

Since Cl^- is a weak field ligand, it causes a lesser magnitude of d orbital splitting compared to ethylenediammine (en) which causes a greater magnitude of d orbital splitting.

Hence; the splitting of the d-orbitals is smaller in the [Ni(Cl)6]4- complex than in the [Ni(en)3]2+ complex.

Answer: The concentration of hydrogen ions for this solution is [tex]1.99 \times 10^{-3}[/tex].

Explanation:

Given: pOH = 11.30

The relation between pH and pOH is as follows.

pH + pOH = 14

pH + 11.30 = 14

pH = 14 - 11.30

= 2.7

Also, pH is the negative logarithm of concentration of hydrogen ions.

[tex]pH = - log [H^{+}][/tex]

Substitute the values into above formula as follows.

[tex]pH = -log [H^{+}]\\2.7 = -log [H^{+}]\\conc. of H^{+} = 1.99 \times 10^{-3}[/tex]

Thus, we can conclude that the concentration of hydrogen ions for this solution is [tex]1.99 \times 10^{-3}[/tex].

Answer:

Are a form of fat in which all or most of the fatty acid chains are single bonds. Glycerol and fatty acids are the two types of smaller molecules that make up fat.

hope it helps...

Answer:

[tex]n_{N_2}=6.41mol[/tex]

Explanation:

¡Hola!

En este caso, teniendo en cuenta la información dada por el problema, inferimos que primero se debe usar la ecuación del gas ideal con el fin de calcular las moles de gas que se encuentran al inicio del experimento:

[tex]PV=nRT\\\\n=\frac{RT}{PV} \\\\n=\frac{0.08206\frac{atm*L}{mol*K}*(50.0+273.15)K}{740/760atm*4.25L}\\\\n=6.41mol[/tex]

Seguidamente, usamos la ley de Avogadro para calcular las moles finales, teniendo el cuenta que el volumen final es el doble del inicial (8.50 L):

[tex]n_2=\frac{6.41mol*8.50L}{4.25L}\\\\n_2=12.82mol[/tex]

Quiere decir que las moles de N2(g) que se agregaron son:

[tex]n_{N_2}=12.81mol-6.41mol\\\\n_{N_2}=6.41mol[/tex]

¡Saludos!

Answer:

3mL of 5M NaOH must be added to adjust the pH to 7.20

Explanation:

When NaOH is added to phosphoric acid, H₃PO₄, the reaction that occurs are:

NaOH + H₃PO₄ ⇄ NaH₂PO₄ + H₂O pKa1 = 2.15

NaOH + NaH₂PO₄ ⇄ Na₂HPO₄ + H₂O pKa2 = 7.20

NaOH + Na₂HPO₄ ⇄ Na₃PO₄ + H₂O pKa3 = 12.38

We can adjust the pH at 7.20 = pKa2 if NaH₂PO₄ = Na₂HPO₄. To make that, we must convert, as first, all H₃PO₄ to NaH₂PO₄ and the half of NaH₂PO₄ to Na₂HPO₄. To solve this question we need to find the moles of phophoric acid in the initial solution. 1.5 times these moles are the moles of NaOH that must be added to fix the pH to 7.20:

Moles H₃PO₄:

100mL = 0.100L * (0.100mol / L) = 0.0100 moles H₃PO₄

Moles NaOH:

0.0100 moles H₃PO₄ * 1.5 = 0.0150 moles NaOH

Volume NaOH:

0.0150 moles NaOH * (1L / 5moles) = 3x10⁻³L 5M NaOH are required =

3 mL of 5 Molar NaOH is required to adjust the pH of phosphoric acid.

It is the negative log of the concentration of Hydrogen ions in the solution.

To calculate the volume of NaOH first, calculate the moles of NaOH and H₃PO₄.

Moles of H₃PO₄.

[tex]\rm moles \ of \ H_3PO_4 = 100\rm \ mL = 0.100\rm \ L \times (0.100 \ mol / L)\\\\\rm moles \ of \ H_3PO_4 = 0.01[/tex]

The moles of NaOH:

[tex]\rm Moles \ of \ NaOH =0.01 \ moles \ H_3PO_4\times 1.5 \\\\\rm Moles \ of \ NaOH= 0.0150[/tex]

The volume of NaOH:

[tex]\rm Volume\ of \ NaOH = \rm 0.0150\ moles\ NaOH \times (1 \ L / 5 \ moles) \\\\\rm Volume\ of \ NaOH = 3\times 10^{-3} L[/tex]

Therefore, 3 mL of 5 Molar NaOH is required to adjust the pH of phosphoric acid.

Learn more about pH:

https://brainly.com/question/3262317

Answer:

Reaction type: Single displacement

Reactant: Magnesium

Product: Dihydrogen - H2

Answer:

hot spring

Explanation:

The mineral water in hot springs can also help reduce stress by relaxing tense muscles. Meanwhile as your body temperature rises in the bath, and then cools once you exit can also help you relax and fall into a deeper sleep.

Answer:

Explanation:

harmless

...............

Answer:

Warmer

Cooler

Explanation:

Answer:

1.765x10²⁵ molecules

Explanation:

First we convert 7.328 moles of propane (C₃H₈) into moles of H₂O, using the stoichiometric coefficients of the balanced reaction:

Then we convert 29.312 moles of H₂O into molecules, using Avogadro's number:

Answer:

0.040M RbOH

Explanation:

The reaction of Rb with water is:

2Rb + 2H₂O → 2RbOH + H₂

As 2 moles of rubidium produce 2 moles of rubidium hydroxide, we need to find the moles of rubidium added. With these moles and the volume we can find molar concentration of RbOH as follows:

Moles Rb = Moles RbOH -Molar mass Rb = 85.4678g)

8.5g * (1mol / 85.4678g) = 0.099 moles RbOH

As 1dm³ = 1L, the volume in liters is 2.5L

That means molarity is:

0.099 moles RbOH / 2.5L =

Explanation:

Charge flow occurs in solution by ions carrying positive or negative charges. Oxidation always occurs at the Anode and Reduction always at the Cathode. Electron flow through the metal is from the anode to the cathode.

Explanation:

For a Galvanic - Voltaic Cell, electron flow is from the anode to the cathode. The following diagram gives reactions at electrodes and direction

Answer:

kc = [G]² / [E] [F], kc = [1.30M]² / [0.60M] [0.80M]

Explanation:

The reaction is:

E + F ⇄ 2G

The equilibrium constant, kc, must be written as the ratio of the molar concentrations of products over reactants. Each concentration powered to its coefficient.

For the reaction of the problem, kc is:

Replacing the given concentrations:

Answer: 6.04 g

Explanation: In STP conditions, amoint of substance

n = V / Vm = 4.23 l / 22.41 l/mol = 0.188755 mol

Molar mass M(O2) = 32 g/mol  and

mass m = nM

Answer: 2.23 is the difference.

Explanation: Sodium has an electronegativity of 0.93 and Chlorine has an electronegativity of 3.16, so when Sodium and Chlorine form an ionic bond, in which the chlorine takes an electron away from sodium, forming the sodium cation, Na+, and the chloride anion, Cl-.

Answer:

This really depends on what you belive in honestly, as a christian i belive a supreme being created all but school says something happend with bacteria and evolution or something lol. If this was a serious question and you need an answer for school just search up the evolution theory

Explanation:

Answer: The energy of an electron in the n = 2 level of a hydrogen atom is 3.40 eV.

Explanation:

Given: n = 2

The relation between energy and [tex]n^{th}[/tex] orbit of an atom is as follows.

[tex]E = - \frac{13.6}{n^{2}} eV[/tex]

Substitute the values into above formula as follows.

[tex]E = - \frac{13.6}{n^{2}} eV\\= - \frac{13.6}{(2)^{2}}\\= - 3.40 eV[/tex]

The negative sign indicates that energy is being released.

Thus, we can conclude that the energy of an electron in the n = 2 level of a hydrogen atom is 3.40 eV.

Answer:

The reaction will proceed to the right to attain the equilibrium.

Explanation:

Step 1: Write the balanced equation

2 N₂(g) + 3 H₂(g) = 2 NH₃(g)

Step 2: Calculate the reaction quotient

The reaction quotient (Qc) is calculated in the same way as the equilibrium constant (Kc) but it uses the concentrations at any time.

Qc = [NH₃]² / [N₂]² × [H₂]³

Qc = 8.00² / 1.50² × 1.00³ = 28.4

Since Qc ≠ Kc, the reaction is not at equilibrium.

Since Qc < Kc, the reaction will proceed to the right to attain the equilibrium.

Answer:

See Explanation

Explanation:

The colour of many transition metal complexes stem from transitions of electrons between energy levels. These transitions are governed by the spin selection rules and the colour is determined by the magnitude of crystal field splitting.

According to the spin selection rules, transitions in which ΔS = 0 are forbidden. Hence, a Mn^2+high spin compound is expected to be colourless. However, contrary to the spin selection rules Mn^2+high spin compounds do exhibit transitions in which the intensity is only about one-hundredth of the intensity of the spin allowed transitions. Thus many Mn^2+  high spin compounds such as Mn(NO3)2 are very pale pink or off white.

Note also that the crystal field stabilization energy of Mn^2+ which is a d^5 low spin ion is zero hence the very pale colour observed.

K4[Mn(CN)6] is deep blue as a result of charge transfer. Also, the compound exhibits an observed crystal field stabilization energy because it is a d^5 low spin compound hence the observed colour. Its low spin nature is because the cyanide ion is a strong field ligand hence it causes a greater magnitude of crystal filed splitting.

The following compounds are colourless;

Zn(NO3)2

CdSO4

AgClO3

One thing that is common to all the compounds listed above is that they are all d^10 compounds. This means that they all possess completely filled d-orbitals hence they are colourless.

Answer:

a) (I) and (iii) only

Explanation:

Because different plastics have different size.

Answer:

most rocks are a mixture of minerals

Answer:

Salinization is the increase of salt concentration in soil and is, in most cases, caused by dissolved salts in the water supply. This supply of water can be caused by flooding of the land by seawater, seepage of seawater or brackish groundwater through the soil from below.

Explanation: