Which graph is an exponential growth model?
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В
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Answer:

a)    distance = (rate) x (time)   or do they want    rate = distance / time

Step-by-step explanation:

the rate is 420 km / 3 hr       =  140 km/hr

I think that it is a dont listen to me tho I'm just guessing

Answer:

Step-by-step explanation:

224 sq in.

Answer:

Step-by-step explanation:

If diameter is 6 then the radius is half of that or 3.

A = pi * r^2

A = pi * 3^2

A = 9pi ft^2

Answer:

La probabilidad de que tanto el caballo como la vaca vivan 20 años es [tex]\frac{2a}{3b}[/tex], en que [tex]\frac{a}{b}[/tex] es la probabilidad de que una vaca viva 20 años.

Step-by-step explanation:

Probabilidades Independientes:

Quanto las probabilidades de dos eventos son independientes, la probabilidad de los dos ocurrir simultáneamente es la multiplicacion de las dos probabilidades.

La probabilidad de que un caballo viva 20 años es dos tercios

Entonces [tex]P(C) = \frac{2}{3}[/tex]

La de una vaca viva 20 años es

Incomplete, entonces dire que es [tex]P(V) = \frac{a}{b}[/tex]

Cuál es la probabilidad de que tanto el caballo como la vaca vivan 20 años​

[tex]P(C \cap V) = P(C) \times P(V) = \frac{2}{3}*\frac{a}{b} = \frac{2a}{3b}[/tex]

La probabilidad de que tanto el caballo como la vaca vivan 20 años es [tex]\frac{2a}{3b}[/tex], en que [tex]\frac{a}{b}[/tex] es la probabilidad de que una vaca viva 20 años.

La probabilidad de que tanto el caballo como la vaca vivan 20 años es [tex]\frac{2}{5}[/tex].

Sean [tex]A[/tex] y [tex]B[/tex] dos eventos independientes aunque no mutuamente excluyentes, es decir, que la esperanza de vida del caballo ([tex]A[/tex]) no dependa de la esperanza de vida de la vaca ([tex]B[/tex]) y viceversa y que pueden ocurrir al mismo tiempo.

En este caso, la probabilidad de que tanto el caballo como la vaca vivan 20 años equivale a una operación de intersección que se manifiesta en la siguiente ecuación:

[tex]P(A \cap B) = P(A)\cdot P(B)[/tex] (1)

Si sabemos que [tex]P(A) = \frac{2}{3}[/tex] y [tex]P(B) = \frac{3}{5}[/tex], entonces la probabilidad de que tanto caballo como la vaca vivan 20 años es:

[tex]P(A\cap B) = \frac{2}{3}\times \frac{3}{5}[/tex]

[tex]P(A\cap B) = \frac{2}{5}[/tex]

La probabilidad de que tanto el caballo como la vaca vivan 20 años es [tex]\frac{2}{5}[/tex].

Invitamos cordialmente a ver esta pregunta sobre probablidades: https://brainly.com/question/24290732

Nota - El enunciado original presenta omisiones y errores tipográficos, la forma completa se presenta a continuación:

La probabilidad de que un caballo viva 20 años es de dos tercios y la de que una vaca viva 20 años es de tres quintos. ¿Cuál es la probabilidad de que tanto el caballo como la vaca vivan 20 años?

Answer:

El conjunto finito de pares ordenados son;

(1, 1), (1, 1/9), (1, 1/49), (1, 1/121), (1, 1/169)

Step-by-step explanation:

si f (X) = 1 / X2, determine el conjunto finito de pares ordenados para X = {1,3,7,11,13}

Dado que f (X) = 1 / X²

Para X = {1, 3, 7, 11, 13}

Tenemos;

f (X) = 1 / X²

f (1) = 1 / 1² = 1, Por lo tanto, tenemos el primer par ordenado, (1, 1)

f (3) = 1 / 3² = 1/9, por lo tanto, tenemos el segundo par ordenado (1, 1/9) ≈ (1. 0.11)

f (7) = 1 / 7² = 1/49, por lo tanto, tenemos el tercer par ordenado (1, 1/49) ≈ (1. 0.02)

f (11) = 1 / 11² = 1/121, por lo tanto, tenemos el cuarto par ordenado (1, 1/121) ≈ (1. 0083)

f (13) = 1 / 13² = 1/169, por lo tanto, tenemos el quinto par ordenado (1, 1/169) ≈ (1. 0.006)

Answer:

In mathematics, a rational number is a number such as −3/7 that can be expressed as the quotient or fraction p/q of two integers, a numerator p and a non-zero denominator q. Every integer is a rational number: for example, 5 = 5/1.

In mathematics, the irrational numbers are all the real numbers which are not rational numbers. That is, irrational numbers cannot be expressed as the ratio of two integers.

Step-by-step explanation:

hope it helps :)))

Answer:

2 whole and 1/8

Step-by-step explanation:

Find out the total pounds of strawberries for the 4 containers.

4/8 + 2/8 + 5/8 + 6/8 = 17/8

17/8 = 2 whole and 1/8

Answer:

2 1/8

Step-by-step explanation:

4/8+2/8+5/8+6/8=17/8

17/8 as a mixed number is 2 1/8

if the figure is a rectangle the answer is 473

Answer:

473

Step-by-step explanation:

First you need to make the fractions mixed numbers

27 1/2= 55/2

17 1/5= 86/5

Then you multiply across

55/2*86/5= 4730/10

then you divide 4730 by 10 to make it an improper fraction.

(because the denominator is 10 just take the 0 out of the end of 4630, this trick only works if the last number in the numerator is 0.)

And your anwser should be 473

I hope this helps!!!!!

Answer:

0.00043 is the answer

Step-by-step explanation:

10^-4=1/10000

43*1/10000= 0.00043

Answer:

a=3; (3,5) and (4,0) for the graph  

Step-by-step explanation:

ax-y=4

x=3, y=5 so...

a(3)-5=4

3a-5=4

+5 +5

3a=9

/3 .  /3

a=3

For the graph, use (3,5) and substitute x and y for anything:

ax-y=4

if x=0...

a(0)-y=4

-y=4

y=4

a=3; (3,5) and (4,0) for the graph!

Answer:

81989970383

Step-by-step explanation:

Answer and Step-by-step explanation:

When it says (f + g)(x), it means that it wants you to add the functions together.

So, let's add them.

[tex](2x^2 + 6x - 4) + (5x^3 -6x^2-3)\\\\\\5x^3 - 4x^2 + 6x - 7\\\\\\\\\\\\\\5x^3 - 4x^2 + 6x - 7[/tex]is the answer. (Answer choice B.)

#teamtrees #PAW (Plant And Water)

Answer:

When two like-poles point together.

Step-by-step explanation:

When two like-poles point together, the arrows from the two magnets point in OPPOSITE directions and the field lines cannot join up. So the magnets will push apart (repel). ... It's only when you hold unlike-poles together (a north pointing to a south) that magnets stick together (they are attracted).

Answer:

When two like-poles point together, the arrows from the two magnets point in opposite directions and the field lines cannot join up. So the magnets will push apart. It's only when you hold unlike-poles together that magnets stick together.

Step-by-step explanation:

Answer:

y = 4n^2

Step-by-step explanation:

Because m = 2n, and y = m^2, then substitute m = 2n into y equation, can get y = (2n)^2 = 4n^2.

Answer:

y = 6x + 8?

Step-by-step explanation:

The starting equation was unclear but if its perpindecular, flip the given slope. For example, if the slope was 3/4, its perpindecular slope would be 4/3.

Answer:

true

Step-by-step explanation:

Answer:

3/32

Step-by-step explanation:

9/16 × 3/4=27/144=3/16×1/2=3/32

Answer:

[tex]F\ or\ G= \{5,6,7,8,9,10,11,12\}[/tex]

[tex]P(F\ or\ G) = \frac{2}{3}[/tex]

Step-by-step explanation:

Given

[tex]S= \{7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18\}[/tex]

[tex]E=\{9, 10, 11, 12, 13, 14, 15, 16\}[/tex]

[tex]F=\{5, 6, 7, 8, 9\}[/tex]

[tex]G=\{9, 10, 11, 12\}[/tex]

[tex]H=\{2, 3, 4\}.[/tex]

Solving (a): Outcomes of F or G

F or G is the list of items in F, G or F and G.

So:

[tex]F=\{5, 6, 7, 8, 9\}[/tex]

[tex]G=\{9, 10, 11, 12\}[/tex]

[tex]F\ or\ G= \{5,6,7,8,9,10,11,12\}[/tex]

Solving (b): P(F or G)

The general addition rule is:

[tex]P(F\ or\ G) = P(F) + P(G) - P(F\ and\ G)[/tex]

Where:

[tex]P(F) = \frac{n(F)}{n(S)} = \frac{5}{12}[/tex]

[tex]P(G) = \frac{n(G)}{n(S)} = \frac{4}{12}[/tex]

[tex]P(F\ and\ G) = \frac{n(F\ and\ G)}{n(S)}[/tex]

[tex]F\ and\ G = \{9\}[/tex]

So:

[tex]P(F\ and\ G) = \frac{1}{12}[/tex]

[tex]P(F\ or\ G) = P(F) + P(G) - P(F\ and\ G)[/tex]

[tex]P(F\ or\ G) = \frac{5}{12} + \frac{4}{12} - \frac{1}{12}[/tex]

[tex]P(F\ or\ G) = \frac{5+4-1}{12}[/tex]

[tex]P(F\ or\ G) = \frac{8}{12}[/tex]

[tex]P(F\ or\ G) = \frac{2}{3}[/tex]

Answer:

26904

Step-by-step explanation:

Answer:

11 maybe

Step-by-step explanation:

cant recheck the test

Complete question is;

A farmer is building a fence to enclose a rectangular area against an existing wall. Three of the sides will require fencing and the fourth wall already exists. If the farmer has 144 feet of fencing, what is the largest area the farmer can enclose?

Answer:

A_largest = 2592 ft²

Step-by-step explanation:

Let the width which is going to be perpendicular to the already existing fourth wall be denoted by y. Since there will be 2, it means total width = 2y.

Since the farmer has 144 ft of fencing and the total width is 2y,it means that the length of the fence will be expressed as;

Length = 144 - 2y

Area of rectangular fencing is;

A = y(144 - 2y)

A = 144y - 2y²

To find the largest area, we will find the first derivative and the equate to 0 after which we plug the value of y back into the area equation to get it.

dA/dy = 144 - 4y

At dA/dy = 0;

144 - 4y = 0

y = 144/4

y = 36 ft

Thus, largest area is;

A_largest = 144(36) - 2(36)²

A_largest = 2592 ft²

    The largest area the farmer can enclose with the fence with him will be 2592 square feet.

      Let the length of the field = [tex]x[/tex] feet

      And the width of the field = [tex]y[/tex] feet

Therefore, area of the rectangular field = Length × Width

                                                              A = [tex]x\times y[/tex] square feet

Since, length of the fence = 144 feet

And the farmer has to enclose three sides of the rectangle as shown in the figure attached.

Therefore, length of the fence = length + 2(width)

                                                   = [tex](x+2y)[/tex] feet

Hence, [tex](x+2y)=144[/tex]

[tex]x=144-2y[/tex]

By substituting the value of 'x' in the expression for the area of the rectangular field.

[tex]A=(144-2y)y[/tex]

[tex]A=-2y^2+144y[/tex]

Find the derivative of the expression with respect to [tex]y[/tex],

[tex]A'=-4y+144[/tex]

Now equate it to zero to get the value of y,

[tex]A'=-4y+144=0[/tex]

[tex]y=36[/tex]

Now substitute the value of 'y' in the expression of area to get the maximum area enclosed.

[tex]A=-2(36)^2+144(36)[/tex]

   [tex]=-2592+5184[/tex]

   [tex]=2592[/tex] square feet

   Therefore, maximum area the farmer can enclose with the 144 feet of fencing will be 2592 square feet.

Learn more,

https://brainly.com/question/16880549

Answer:

a) The 95% CI for the true average porosity of a certain seam if the average porosity for 15 specimens from the seam was 4.85 is (4.46, 5.24).

b) The 98% CI for true average porosity of another seam based on 11 specimens with a sample average porosity of 4.56 is (4.01, 5.11).

c) A sample size of 12 is needed.

d) A sample size of 125 is needed.

Step-by-step explanation:

(a) Compute a 95% CI for the true average porosity of a certain seam if the average porosity for 15 specimens from the seam was 4.85.

We have that to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:

[tex]\alpha = \frac{1 - 0.95}{2} = 0.025[/tex]

Now, we have to find z in the Ztable as such z has a pvalue of [tex]1 - \alpha[/tex].

That is z with a pvalue of [tex]1 - 0.025 = 0.975[/tex], so Z = 1.96.

Now, find the margin of error M as such

[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]

In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.

[tex]M = 1.96\frac{0.78}{\sqrt{15}} = 0.39[/tex]

The lower end of the interval is the sample mean subtracted by M. So it is 4.85 - 0.39 = 4.46

The upper end of the interval is the sample mean added to M. So it is 4.85 + 0.39 = 5.24

The 95% CI for the true average porosity of a certain seam if the average porosity for 15 specimens from the seam was 4.85 is (4.46, 5.24).

(b) Compute a 98% CI for true average porosity of another seam based on 11 specimens with a sample average porosity of 4.56. (Round your answers to two decimal places.)

We have that to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:

[tex]\alpha = \frac{1 - 0.98}{2} = 0.01[/tex]

Now, we have to find z in the Ztable as such z has a pvalue of [tex]1 - \alpha[/tex].

That is z with a pvalue of [tex]1 - 0.01 = 0.99[/tex], so Z = 2.327.

Now, find the margin of error M as such

[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]

In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.

[tex]M = 2.327\frac{0.78}{\sqrt{11}} = 0.55[/tex]

The lower end of the interval is the sample mean subtracted by M. So it is 4.56 - 0.55 = 4.01

The upper end of the interval is the sample mean added to M. So it is 4.56 + 0.55 = 5.11

The 98% CI for true average porosity of another seam based on 11 specimens with a sample average porosity of 4.56 is (4.01, 5.11).

(c) How large a sample size is necessary if the width of the 95% interval is to be 0.46?

95% CI means that [tex]z = 1.96[/tex]

A sample of n is needed, and n is found when M = 0.46. So

[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]

[tex]0.46 = 1.96\frac{0.78}{\sqrt{n}}[/tex]

[tex]0.46\sqrt{n} = 1.96*0.78[/tex]

[tex](\sqrt{n})^2 = (\frac{1.96*0.78}{0.46})^2[/tex]

[tex]n = 11.05[/tex]

Rounding up

A sample size of 12 is needed.

(d) What sample size is necessary to estimate true average porosity to within 0.18 with 99% confidence?

99% CI means that [tex]z = 2.575[/tex]

A sample of n is needed, and n is found when M = 0.18. So

[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]

[tex]0.18 = 2.575\frac{0.78}{\sqrt{n}}[/tex]

[tex]0.18\sqrt{n} = 2.575*0.78[/tex]

[tex](\sqrt{n})^2 = (\frac{2.575*0.78}{0.18})^2[/tex]

[tex]n = 124.5[/tex]

Rounding up

A sample size of 125 is needed.

Answer:

Area = 132 Square units

Step-by-step explanation:

Looking at the diagram, the top horizontal chord distance that's missing is calculated as;

21 - (9 + 3) = 9 units

Total distance of top horizontal chord = 9 + 3 = 12 units

Now, formula for area of trapezium is;

Area = ½(a + b)h

Where h is height = 8 units

The parallel sides are a & B.

In this case; a = 12 units

b = 21 units

Thus;

Area = ½(12 + 21)8

Area = 4 × 33

Area = 132 Square units

well if she payed 40% and an average baseball glove costs $120 – $300

and a bat costs $75-$185. that would mean she spent around $197 or $485

which would mean

40% out of 197 is 78.8

and 291

i believe is the correct answer

Answer:

5x^2 - 2x + 4

Step-by-step explanation:

Answer:

24

Step-by-step explanation:

It will take 50 minutes!

-378/7=-54

2700/-54=-50

Answer:

b.

Step-by-step explanation: