Help me and if the answer is correct and neat I will give you brainliest. Its about line plots.
Answer:
Step-by-step explanation:
The inspection division of the Lee County Weights μ. and Measures Department is interested in estimatin actual amount of soft drink that is placed in 2- to at the local bottling plant of a large nationally tles known soft-drink company. The bottling plant has ision that the standard deviation for 2-liter bottles is 0.05 liter. A random sanm ple of 100 2-liter bottles obtained from this botting plant indicates a sample average of 1.99 liters Section 8 (a) Set up a 95% confidence interval estimate of the (b) Does the population of soft-drink fill have to be (c) Explain why an observed value of 2.02 liters is not true average amount of soft drink in each bottle. normally distributed here? Explain. 8. unusual, even though it is outside the confidence interval you calculated. uppose that the sample average had been 1.97 liters. What would be your answer to (a)?
Answer:
hello your question is poorly written attached below is the complete question
answer
a) ( 1.9802 , 1.9998 )
b) The population of soft drink does not have to be normally distributed in order to calculate the confidence interval for a sample mean.
c) A single value of 2.02 is not unusual
d) (1.9602, 1.9798)
Step-by-step explanation:
A) set up 95% confidence interval estimate
std = 0.05 liter
average ( mean ) X = 1.99 liters
n = 100
95% confidence interval = X ± [tex]Z_{95%}[/tex] ( std / √n )
= 1.99 ± 1.96 ( 0.05 / √100 )
= ( 1.9802 , 1.9998 )
B) The population of soft drink does not have to be normally distributed in order to calculate the confidence interval for a sample mean. as seen in this scenerio the value of n > 30 and sampling distribution of X is required instead
C) A single value of 2.02 is not unusual because the confidence interval we calculated above is for 100 samples of the soft drink ( using true population mean ) but when we calculate for a one sample we will observe that the value ( 2.02 ) will not be unusual e.g. ( 2 ± 2*0.05 ) = ( 1.9, 2.1 )
D) when the sample average ( X ) = 1.97
confidence interval = X ± [tex]Z_{95%}[/tex] ( std / √n )
= 1.97 ± 1.96 ( 0.05 / √100 )
= (1.9602, 1.9798)
There are four sub-parts in the question, whose answers are mentioned below:
Given information:
Mean of sample = [tex]\overline{x}[/tex] =1.99
Standard deviation of population= [tex]\sigma[/tex] = 0.05
Size of sample = n = 100
Part a: Setting 95% confidence interval
[tex]CI = \overline{x} \: \pm Z_{0.95}\dfrac{\sigma}{\sqrt{n}}\\CI = 1.99 \pm 1.96 \times \dfrac{0.05}{10}\\CI = (1.9802, 1.9998)\\[/tex]
Part b: Yes, the population has to be normally distributed here, since the CI here cannot be calculated without it being normally distributed.
Part c: It is because we took n = 100 and not for single value of observation. The single value of observation has 2 liter or value is 2, and 2.02 is near 2 thus not an unusual value.
Part d: If sample average be 1.97, then CI will be as follows:
[tex]CI = \overline{x} \: \pm Z_{0.95}\dfrac{\sigma}{\sqrt{n}}\\CI = 1.97 \pm 1.96 \times \dfrac{0.05}{10}\\CI = (1.9602, 1.9798)\\[/tex]
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There were 20 boys and 26 girls in a chess club last year. This year the number of boys increased by 30% but the number of girls decreased by 15%. Was there an increase or
decrease in overall membership?
Step-by-step explanation:
Boys
[tex]20 + (20 \div 100)30 = \\ = 20 + 0.2 \times 30 = \\ = 20 + 6 = \\26[/tex]
Girls
[tex]26 - (26 \div 100)15 = \\ = 26 - 0.26 \times 15 = \\ = 26 - 3.9 = \\ = 22[/tex]
Total last year 46
Total this year 48
Increase
Hallar un par ordenado (x,y) que sea una solución de la ecuación.
6x+y=9
In a pre-election poll, 58% of a large random sample of voters responded as planning to vote for the school enhancement millage. A 95% confidence interval was computed for the proportion of all such voters who plan to vote for the school enhancement millage. Review each of the following statements regarding the meaning of the 95% confidence level. Determine if it is a correct (true) meaning or incorrect (false).
Answer: Hello the statement related to your question is missing attached below is the statement
answer : The statement is false
Step-by-step explanation:
The statement is false
This is because a confidence interval gives a range of values for an unknown parameter.
A 95% confidence interval is calculated and it gives a lower and upper limit in which the 58% of the voters can fall into i.e. The 58% of voters can fall within the upper and lower limit of the 95% confidence interval and not exactly 95% . Hence the statement is false.
Choose all of the expressions that can be used to find the volume of the rectangular prism.
Answer:
C. (6 × 5) × 2 = 60 m³
D. 5 × (6 × 2)
E. (2 × 5) × 6
Step-by-step explanation:
Volume of a rectangular prism can be given as, V = L*W*H
L = 6
W = 5
H = 2
However, whichever way we choose to use as either L, W, or H, we would still get the same value as the volume.
Thus:
✔️V = (6 × 5) × 2 = 60 m³
✔️V = 5 × (6 × 2) = 60 m³
✔️V = (2 × 5) × 6 = 60 m³
These are the three expressions that can be used to find the volume.
In deenas class, 3/12 of the students voted for cats as their favorite pet, and 5/12 voted for dogs. What fraction of the class voted for cats or dogs as their favorite pet?
Answer:
8/12 or 2/3
Step-by-step explanation:
5/12+3/12=8/12
8/12 simplifies to 2/3
Solve Similar triangles
Solve for x.
x=?
Answer:
x = 2
Step-by-step explanation:
AB/BC = AD/DE
[tex]\frac{2}{1}[/tex] = [tex]\frac{2+x}{2}[/tex]
cross-multiply:
2+x = 4
x = 2
I need help! Please show all the steps and work! :)
Inspired by zoom, you want to determine whether there are significant differences in the satisfaction of couples that had their first date in person vs. couples who had their first date virtually. Based on the following satisfaction data (larger values indicate greater satisfaction), conduct an independent samples t-test using (alpha=.01) and an pooled variance. Is there a significant difference?
Virtual Date In person date
X= 23.76 X= 34.54
s2 = 123.43 s2 = 105.65
n = 5 n = 20
A) Write the null and alternative hypotheses in symbols
B) What is your critical value?
C) What's your pooled variance?
D) What's your standard error?
E) What's your obtained t?
Answer:
A) The null hypothesis is H₀; [tex]\overline x_1[/tex] = [tex]\overline x_2[/tex]
The alternative hypothesis is Hₐ; [tex]\overline x_1[/tex] ≠ [tex]\overline x_2[/tex]
B) The critical value is 4.604
C) The pooled variance is 11,870.2777
D) The standard error is-0.2321
E) The obtained is -0.2040
Step-by-step explanation:
The given values are;
[tex]\overline x_1[/tex] = 23.76, [tex]\overline x_2[/tex] = 34.54
s₁ = 123.43, s₂ = 105.65
n₁ = 5, n₂ = 20
A) The null hypothesis, H₀; [tex]\overline x_1[/tex] = [tex]\overline x_2[/tex]
The alternative hypothesis, Hₐ; [tex]\overline x_1[/tex] ≠ [tex]\overline x_2[/tex]
B) The degrees of freedom, df = 4 - 1 = 3
The critical t-value is given at α = 0.01 is given on the t-table for two tailed test as t = 4.604
C) The pooled variance is given by the following formula;
[tex]S_P^2 = \dfrac{(n_1 - 1) \cdot s_1^2 + (n_2-1) \cdot s_2^2}{n_1 + n_2 - 2 }[/tex]
Plugging in the values gives;
[tex]S_P^2 = \dfrac{(5 - 1) \cdot 123.43^2 + (20-1) \cdot 105.65^2}{5+ 20 - 2 } = 11,870.2777[/tex]
The pooled variance, [tex]s_p^2[/tex] = 11,870.2777
D) The standard error, SE, is given as follows;
[tex]t=\dfrac{(\bar x_{1}-\bar x_{2})}{\sqrt{\dfrac{s_{1}^{2} }{n_{1}}-\dfrac{s _{2}^{2}}{n_{2}}}}[/tex]
Therefore, we get;
[tex]t=\dfrac{(23.76-35.34)}{\sqrt{\dfrac{123.43^{2} }{5}-\dfrac{105.65^{2}}{20}}} = -0.2321[/tex]
The standard error, SE ≈ -0.2321
E) The obtained 't' is given as follows;
[tex]\sigma _{\overline x_1 - \overline x_2} = \sqrt{\dfrac{s_1^2}{n_1-1} +\dfrac{s_2^2}{n_2-1} }[/tex]
Therefore, we have;
[tex]\sigma _{\overline x_1 - \overline x_2} = \sqrt{\dfrac{123.43^2}{5-1} +\dfrac{105.65^2}{20-1} } \approx 56.7564[/tex]
The obtained t is given as follows;
[tex]t(Obtained)=\dfrac{(\bar x_{1}-\bar x_{2})}{\sigma _{\overline x_1 - \overline x_2} }[/tex]
Therefore, we get;
[tex]t(Obtained)=\dfrac{(23.76-34.54)}{56.7564} \approx -0.2040[/tex]
The obtained t = -0.2040
A bag has 4 red marbles, 5 blue marbles, and 6 green marbles. What is the probability if choosing a red marble from the bag, not putting it back, and then choosing a green marble?
4/15
6/14
12/105
24/225
Step-by-step explanation:
hope u get it...
mark brainlist!!!
Can someone please answer this question? It is from RSM. The first to answer will be marked brainliest
Answer:
16/20=0.8
Step-by-step explanation:
hope this helps
Answer:
I think it's the second one
How was Franklin D. Roosevelt a lasting impact even on today's society
Answer:
Franklin Delano Roosevelt, often referred to by his initials FDR, was an American politician who served as the 32nd president of the United States from 1933 until his death in 1945. A member of the Democratic Party, he won a record four presidential elections and became a central figure in world events during the first half of the 20th century. Roosevelt directed the federal government during most of the Great Depression, implementing his New Deal domestic agenda in response to the worst economic crisis in U.S. history. As a dominant leader of his party, he built the New Deal Coalition, which defined modern liberalism in the United States throughout the middle third of the 20th century. His third and fourth terms were dominated by World War II, which ended shortly after he died in office.
Step-by-step explanation:
to this ‘Great Man Theory’ it can be said that Franklin Delano Roosevelt upheld his victorious and highly regarded government through means of social, economic and political reforms, as well as ambitious personal and strategic decisions that have successfully remained influential to American society today and maintained his image as a prominent historic leader.
1. Dicey Odds [2 Points]You roll two six-sided dice. Die 1 is fair. Die 2 is unfair such that the probability of rolling anodd number is23and the probability of rolling an even number is13, though the probabilityrolling of each odd number is the same, and the probability of rolling each even number isthe same. What is the probability of:a) rolling a number less than 4 on Die 1 and rolling a 5 on Die 2.b) the sum of both dice adding up to 4.
Answer:
a) P(rolling a number less than 4 on Die 1 and rolling a 5 on Die 2) = [tex]\frac{1}{9}[/tex]
b) P( the sum of both dice adding up to 4) = [tex]\frac{5}{54}[/tex]
Step-by-step explanation:
Given - You roll two six-sided dice. Die 1 is fair. Die 2 is unfair such that the probability of rolling an odd number is [tex]\frac{2}{3}[/tex] and the probability of rolling an even number is [tex]\frac{1}{3}[/tex] , though the probability rolling of each odd number is the same, and the probability of rolling each even number is the same.
To find - What is the probability of:
a) rolling a number less than 4 on Die 1 and rolling a 5 on Die 2.
b) the sum of both dice adding up to 4.
Proof -
The sample space , S = { (1,1), (1,2), (1,3), (1,4), (1,5), (1,6)
(2,1), (2,2), (2,3), (2,4), (2,5), (2,6)
(3,1), (3,2), (3,3), (3,4), (3,5), (3,6)
(4,1), (4,2), (4,3), (4,4), (4,5), (4,6)
(5,1), (5,2), (5,3), (5,4), (5,5), (5,6)
(6,1), (6,2), (6,3), (6,4), (6,5), (6,6) }
Now,
Given that , Dice 1 is fair
⇒P₁(1) = P₁(2) = P₁(3) = P₁(4) = P₁(5) = P₁(6) = [tex]\frac{1}{6}[/tex]
Also, Given Dice 2 is unfair
⇒P₂(1) = P₂(3) = P₂(5) = [tex]\frac{2}{3}.\frac{1}{3} = \frac{2}{9}[/tex]
P₂(2) = P₂(4) = P₂(6) = [tex]\frac{1}{3}.\frac{1}{3} = \frac{1}{9}[/tex]
Now,
a)
P(rolling a number less than 4 on Die 1 and rolling a 5 on Die 2) = P₁(1)P₂(5) + P₁(2)P₂(5) + P₁(3)P₂(5)
= P₂(5) [ P₁(1) + P₁(2) + P₁(3) ]
= [tex]\frac{2}{9}[/tex] [ [tex]\frac{1}{6}[/tex] + [tex]\frac{1}{6}[/tex] + [tex]\frac{1}{6}[/tex] ] = [tex]\frac{2}{9}[ \frac{3}{6}]\\[/tex] = [tex]\frac{1}{9}[/tex]
⇒P(rolling a number less than 4 on Die 1 and rolling a 5 on Die 2) = [tex]\frac{1}{9}[/tex]
b)
P( the sum of both dice adding up to 4) = P₁(1)P₂(3) + P₁(2)P₂(2) + P₁(3)P₂(1)
= [tex]\frac{1}{6}[/tex] × [tex]\frac{2}{9}[/tex] + [tex]\frac{1}{6}[/tex] × [tex]\frac{1}{9}[/tex] + [tex]\frac{1}{6}[/tex] ×[tex]\frac{2}{9}[/tex] = [tex]\frac{5}{54}[/tex]
⇒P( the sum of both dice adding up to 4) = [tex]\frac{5}{54}[/tex]
Factor the expression 5m2−20m
Answer: 5m (m - 4)
Step-by-step explanation:
Just divide by the highest common factor which for the constants it’s 5 and for the variables it’s m
"K Co.'s" bonds currently sell for $1,150. They have a 6.75% semi-annual coupon rate and a 15-year maturity and are callable in 6 years at $1,067.50. Assume that no costs other than the call premium would be incurred to call and refund the bonds, and also assume that the yield curve is horizontal, with rates expected to remain at current levels on into the future. Under these conditions, what rate of return should an investor expect to earn if he or she purchases these bonds, the YTC or the YTM? Why?
Ans.......
YTC ...................................
Step-by-step explanation:
what is the answer to (8+10) x1/2 =
Answer:
9
Step-by-step explanation:
18 x 1/2
18/2
9
Answer: 9
Step-by-step explanation:
Parenthesis first, so 8+10 =18 .
18 multiplied by 1/2 = 9
CALCULUS: Which of the following functions grows the fastest as x goes to infinity?
A. 2^x
B. ln(x)
C. sin(x)
D. x^20 (I put this my first try & got it wrong)
I believe D is the right answer, but I got it wrong. Can someone please tell me why?
Answer:
It is A. 2^x
Step-by-step explanation:
For relative rates of growth, we know: Log < Poly < Exponential.
This rules out B, C, and D quickly. Although, if you do L'Hôpital's rule, it might seem like A & D are very comparable. However, if you continually took the derivative of 2^x and x^20, eventually x^20 would equal zero, while 2^x would still be a variable. So, you would have:
[tex]\lim_{x \to \infty} \frac{2^{x}}{0} =[/tex] ∞
When the limit of x as it approaches infinity is infinity, then f(x) grows at a faster rate than g(x).
Also, by looking at the graph (which is attached), you can see that 2^x grows faster than x^20.
The Cobb-Douglas production model is a function that relates production outputs with a combination of different inputs. Agricultural data from 44 countries around the world, concerning agricultural production Q, labor L, capital K, fertilizer F, and hectares of arable land H, can be used to create an agricultural production model for countries using a Cobb-Douglas function given by
Q= 3.41 L^0.266 .K^2.06 F^0.299.H^1.41
The exponents in the Cobb-Douglas model are called elasticities. Find the percentage increment in production if a country has a 1% increase in Labor.
Answer:
0.266 percent
Step-by-step explanation:
With labor increasing by 1 percent, we are to find how much level of production would also increase given the coubglas function in the question.
Level of production = ∆Q/Q
We differentiate the function Q with respect to Labour, L.
∆Q/∆L = 0.266Q/L
∆Q/Q = 0.266∆L/L
∆L/L = 1
∆Q/Q x 100 = 1 *0.266
= 0.266%
Please refer to the attachment
I NEED HELP ASAP!!!!!!!!!
Answer:
a=81.0
there ya go
What is the mean for this list of numbers? 19, 22, 24, 45
Answer:
27.5
Step-by-step explanation:
To find the mean you basically just add all of the numbers then divide by how many there are.
So, for this problem, 19+22+24+45=110
110/4=27.5
Hope this helped!!
The Total cost to rent 5 chairs and 3 tables is $31 dollars. What is the cost to rent each chair and each table? No links please
Answer:
b
Step-by-step explanation:
Select all of the terms that apply to the shape.
A) pentagon
B) hexagon
C) heptagon
D) octagon
E) nonagon
F) decagon
G) regular polygon
H) irregular polygon
I) m concave
J) m convex
Which is more 7/10 or $0.75?
Answer:
I think $0.75
Step-by-step explanation:
$0.75 because 7/10 is 0.7
Round 53,738 to the nearest thousand.
Answer:
54000
Step-by-step explanation:
53,738
3 is in the thousands place so we look at the hundreds place
7 is 5 or above so we round the 3 up to 4
54000
Another game you’ve set up at casino night involves rolling a fair six-sided die followed by tossing a fair coin. In this game, players earn points depending on the number they get on the die and which side of the coin turns up. For example, the player earns 5 points for getting (2, tails) Question 3 Find the probability that tails and an even number do not occur together.
Answer:
The probability that tails and an even number do not occur together is 3/4.
Step-by-step explanation:
There are three outcomes in which tails occurs with an even number (2, tails), (4, tails), (6, tails). The probability of this event is 3/12 = 1/4 . The probability that tails and an even number do not occur together is 1 - 1/4 = 3/4.
Answer:
Sample answer for Edmentum
Step-by-step explanation:
Write the polynomial in standard form: I need help with this
Write the polynomial in standard form:
18
Calculator
13 in
94
7.5 in.
What is the area of this triangle?
Enter your answer as a decimal in the box. Round only your final
answer to the nearest tenth.
Answer:
9165.0
Step-by-step explanation:
13*94*7.5 = 9165.0
Help pls! show step by step
Answer:
He started with 37 CDs
Step-by-step explanation:
Variable: Let x be the number of CDs he got at the start
Equation: (x + 7) /2 = 22
x + 7 = 44
x = 37
Check: (37+7) /2 = 22
giving brainliest *easy*