Which equation represents a line which is perpendicular to the line x – 2y = 2?

Answer:

x = -11

Step-by-step explanation:

−3x + 6 = 39

-3x = 33

x = -11

Step-by-step explanation:

-3x+6=39

-3x=39-6

-3x=33

x=33/-3

x=11

Answer:

8/21

Step-by-step explanation:

Add the number of marbles : 4+9+8= 21

Then how many are blue: 8

Answer 8/21. Can't be simplified

0.38

Answer:

Step-by-step explanation:

Another similar triangle.  then the sides that are the same are:

r /d =  p / b

r =30

d = 72

b  = 60

p = QR

30 / 72 = QR / 60

( 30 / 72 ) 60 = QR

1800 / 72 = QR

25 = QR

:)  glad they makes these work out to easy numbers.. I mean not some long decimal  

Answer:

30.99

Step-by-step explanation:

31 - 0.01 = 30.99

The bill cost is directly proportional to the calling time.

In this exercise we need to check if the cost of the phone bill (y), in US dollars, is directly proportional to calling time (x), in minutes. Then, the following model has to be fulfilled:

k = y / x

Where k is the constant of proportionality, in US dollars per minute.

The bill model is directly proportional if and only if the constant of proportionality is the same for every pair of values:

k₁ = 12 / 80

k₁ = 3 / 20

k₂ = 9 / 60

k₂ = 3 / 20

There, the bill cost is directly proportional to the calling time.

To learn more on direct proportion models: https://brainly.com/question/20400984

#SPJ1

Answer:

52

Step-by-step explanation:

52x0.25=13

Answer:

52 quarters

Step-by-step explanation:

13 dollars x 100 cents

= 1,300 cents

1,300 cents / 25 cents

= 52 quarters

Answer:

a) P(rolling a number less than 4 on Die 1 and rolling a 5 on Die 2) = [tex]\frac{1}{9}[/tex]

b) P( the sum of both dice adding up to 4) = [tex]\frac{5}{54}[/tex]

Step-by-step explanation:

Given - You roll two six-sided dice. Die 1 is fair. Die 2 is unfair such that the probability of rolling an odd number is  and the probability of rolling an even number is  , though the probability rolling of each odd number is the same, and the probability of rolling each even number is the same.

To find - What is the probability of:

                a) rolling a number less than 4 on Die 1 and rolling a 5 on Die 2.

                b) the sum of both dice adding up to 4.

Proof -

The sample space , S = { (1,1), (1,2), (1,3), (1,4), (1,5), (1,6)

                                          (2,1), (2,2), (2,3), (2,4), (2,5), (2,6)

                                          (3,1), (3,2), (3,3), (3,4), (3,5), (3,6)

                                           (4,1), (4,2), (4,3), (4,4), (4,5), (4,6)

                                           (5,1), (5,2), (5,3), (5,4), (5,5), (5,6)

                                            (6,1), (6,2), (6,3), (6,4), (6,5), (6,6) }

Now,

Given that , Dice 1 is fair

⇒P₁(1) = P₁(2) = P₁(3) = P₁(4) = P₁(5) = P₁(6) = [tex]\frac{1}{6}[/tex]

Also,

Given Dice 2 is unfair

⇒P₂(1) = P₂(3) = P₂(5) = [tex]\frac{2}{3}.\frac{1}{3} = \frac{2}{9}[/tex]

    P₂(2) = P₂(4) = P₂(6) = [tex]\frac{1}{3}.\frac{1}{3} = \frac{1}{9}[/tex]

Now,

a)

P(rolling a number less than 4 on Die 1 and rolling a 5 on Die 2) = P₁(1)P₂(5) + P₁(2)P₂(5) + P₁(3)P₂(5)

= P₂(5) [ P₁(1) + P₁(2) + P₁(3) ]

= [tex]\frac{2}{9}[/tex] [ [tex]\frac{1}{6}[/tex] + [tex]\frac{1}{6}[/tex] + [tex]\frac{1}{6}[/tex] ] =  [tex]\frac{2}{9}[/tex][tex][\frac{3}{6} ][/tex] = [tex]\frac{1}{9}[/tex]

⇒P(rolling a number less than 4 on Die 1 and rolling a 5 on Die 2) = [tex]\frac{1}{9}[/tex]

b)

P( the sum of both dice adding up to 4) = P₁(1)P₂(3) + P₁(2)P₂(2) + P₁(3)P₂(1)

                                                                   = [tex]\frac{1}{6}[/tex] × [tex]\frac{2}{9}[/tex]  + [tex]\frac{1}{6}[/tex] × [tex]\frac{1}{9}[/tex] + [tex]\frac{1}{6}[/tex] × [tex]\frac{2}{9}[/tex]   =  [tex]\frac{5}{54}[/tex]

⇒P( the sum of both dice adding up to 4) = [tex]\frac{5}{54}[/tex]

Answer:

D. -7/3, 7/3

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Equality Properties

Algebra I

Step-by-step explanation:

Step 1: Define

9x² - 49 = 0

Step 2: Solve for x

Answer:

True

Terms are separated by the signs

Complete Question:

Leslie placed this ad in Collector Car Monthly.

1957 Chevrolet Nomad station wagon. Tropical

Turquoise, 6 cyl. auto, PS, PW, AM/FM, repainted,

rebuilt transmission, restored two-tone interior.

Mint! Moving, sacrifice, $52,900. 555-4231

(a) If the publication charges $48 for the first three lines and $5 for each extra  line, how much will this ad cost Leslie?  

(b) b. Ruth buys the car for 8% less than the advertised price. How much does she pay?

(c) Ruth must pay her state 6% sales tax on the sale. How much must she pay in sales tax?

Answer:

[tex]Total = \$53[/tex]

[tex]Ruth = \$48668[/tex]

[tex]Sales\ Tax = \$2920.08[/tex]

Step-by-step explanation:

Given

[tex]Ad = 4\ lines[/tex]

[tex]Charges: \$48[/tex] --- First 3 lines

[tex]Additional: \$5[/tex] -- Extra lines

Solving (a) : Determine the total charge

The ad has 4 lines. This means that 3 of the 4 lines will be charged at $48 (in total) while the extra line will be charged at $5 per line

So, the total charge is calculated as:

[tex]Total = 3\ lines + 1\ line[/tex]

[tex]Total = \$48 + 1 * \$5[/tex]

[tex]Total = \$48 + \$5[/tex]

[tex]Total = \$53[/tex]

Solving (b): How much does Ruth pay?

From the ads, the price of the car is:

[tex]Price = \$52,900[/tex]

And Ruth pays 8% less.

This means that she pays 92% (i.e. 100% - 8% = 92%)

So, the calculation is:

[tex]Ruth = 92\% * Price[/tex]

[tex]Ruth = 92\% * \$52900[/tex]

[tex]Ruth = \$48668[/tex]

Solving (c): The sales tax

[tex]Sales\ Tax = Sales\ Tax\% * Amount\ Paid[/tex]

[tex]Sales\ Tax = 6\% * \$48668[/tex]

[tex]Sales\ Tax = \$2920.08[/tex]

Answer:

70 units²

Step-by-step explanation:

Area of the figure = area of rectangle + area of triangle

= L*W + ½*bh

L = 10

W = 5

b = 5

h = 18 - 10 = 8

Substitute:

Area of the figure = 10*5 + ½*5*8

= 50 + 20

= 70 units²

Explanation is in the file

tinyurl.com/wpazsebu

There is 13 diamonds and 4 numbers greater than 2 but less than 7. This means your probability of selecting one of these specific cards is a 17/52 chance

Answer:

1/3

Step-by-step explanation:

Answer:

y=5x-9

Step-by-step explanation:

You want to find the equation for a line that passes through the point (1,-4) and has a slope of 5.

First of all, remember what the equation of a line is:

y = mx+b

Where:

m is the slope, and

b is the y-intercept

To start, you know what m is; it's just the slope, which you said was 5. So you can right away fill in the equation for a line somewhat to read:

y=5x+b.

Now, what about b, the y-intercept?

To find b, think about what your (x,y) point means:

(1,-4). When x of the line is 1, y of the line must be -4.

Because you said the line passes through this point, right?

Now, look at our line's equation so far: . b is what we want, the 5 is already set and x and y are just two "free variables" sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the the point (1,-4).

So, why not plug in for x the number 1 and for y the number -4? This will allow us to solve for b for the particular line that passes through the point you gave!.

(1,-4). y=mx+b or -4=5 × 1+b, or solving for b: b=-4-(5)(1). b=-9.

The equation of the line that passes through the point (1,-4) with a slope of 5

is

y=5x-9

Answer:

(11/15)'s

Step-by-step explanation:

(2/5) is equal to (6/15)

(1/3) is equal to (5/15)

(5/15)+(6/15)=(11/15)

Answer:

63360

Step-by-step explanation:

==> 5280 ft = x inch. ==> x = 12*5280 = 63360 inch. Then, there are 63,360 inches in one mile.

Answer:

There are 63,360 inches in one mile.

Step-by-step explanation:

We multiply by the conversion factor:

1 mile (5280 feet/1 mile)(12 inches/1 foot)= 63,360 inches per mile.

Answer:

The answer is "Option b".

Step-by-step explanation:

Calculating the common Box-Cox Transformation:

[tex]\lambda \ value \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ Transformed \ data \ (Y')\\\\[/tex]

  [tex]-3 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ Y^{-3} =\frac{1}{Y^3} \\\\ -2 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ Y^{-2} =\frac{1}{Y^2} \\\\ -1 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ Y^{-1} =\frac{1}{Y^1} \\\\ -0.5 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ Y^{-0.5} =\frac{1}{\sqrt{Y}} \\\\ 0 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \log(Y)^{**} \\\\[/tex]

    [tex]0.5 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ Y^{-0.5} =\sqrt{(Y)} \\\\ 1 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ Y^{1} =Y \\\\ 2 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ Y^{2} \\\\ 3 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ Y^{3} \\\\[/tex]

9514 1404 393

Answer:

  (a)  4 in²

Step-by-step explanation:

The volume of a rectangular prism is given by the formula ...

  V = Bh

where B is the area of the base, and h is the height of the prism.

We can find the area of the base by solving for B.

  B = V/h

  B = (12 in³)/(3 in)

  B = 4 in² . . . . . . . . . . matches the first choice

Answer:

(x-1)(x+4)

Step-by-step explanation:

[tex]x^2+3x-4\\x^2-x+4x-4\\x(x-1) 4(x-1)\\(x-1)(x+4)[/tex]

Answer:

0.5 = 50%, 3/4 = 75%

Step-by-step explanation:

Answer:

x=17/13

Step-by-step explanation:

pretty sure you just shift x alone by itself

Answer: [tex]17/13=1.30769231[/tex]

Step-by-step explanation:

Answer:

-12.6

Step-by-step explanation:

Answer:

4 adaults

Step-by-step explanation:

Answer:

73*-2 =-146 you have to multiply the 73 to the -2

Step-by-step explanation:

Answer:

Step-by-step explanation:

Remark

This is a cosine law problem.

a = 12

b = 15

C = 83

Notice that the angle is enclosed by 2 given sides. That's what a cosine problem looks like (one of the two choices.

Formula

c^2 = a^2 + b^2 - 2ab*cos(C)

Solution

c^2 = 12^2 + 15^2 - 2*12*15 * cos(83)

c^2 = 144 + 225 - 360 * cos(83)

cos(83) = 0.1219

c^2 = 144 + 225 - 360 * 0.1219

c^2 = 369 - 43.884

c^2 = 325.116

sqrt(c^2) = sqrt(325.116)

c = 18.031

To the nearest tenth, the answer is 18.0 and you must include the 0.