Which equation is represented by the intersection of the graphs below?
A. Csc x=0
B. sec x = 0
C. secx = 1
D. CSC X=1

The solution set for the quadratic equation (2x - 7)² = 25 is 6 and 1.

A quadratic equation is an algebraic expression in the form of variables and constants.

A quadratic equation has two roots as its degree is two.

The solution set for a quadratic equation is the roots of the quadratic equation.

Given, (2x - 7)² = 25.

2x - 7 = ± 5.

2x = ± 5 + 7.

x = (± 5 + 7)/2.

x = 12/2 Or 2/2.

x = 6 or 1.

learn more about quadratic equations here :

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Answer:

a=-12

b=15

c=12

d=-12

Step-by-step explanation:

3(-4)=a

b(-3)=12

c=12

d(24)=12

3(-4)=a

-12=a

a=-12

b(-3)=12

-3b=12

b=12+3

b=15

c= 12

d(24)=12

24d=12

d=12-24

d=-12

100+2y = 180

2y=180-100

2y=80

y=40

Answer:

2n + 20

Step-by-step explanation:

Step-by-step explanation:

1/2×28×(21+16)

calculate then u get the answer

Answer: 213

Step-by-step explanation: U are beautiful in the picture u showed

Answer:

It's 3 and 177.

Step-by-step explanation:

Let the angle be x°. Then its supplementary is 59x°.

We know,

x+ 59x=180

or, x = 3°

and another angle, 59x°= 177°

Answer:

2.[tex]-2m^4-6m^2+4m+9[/tex]

3.[tex]-2m^4-6m^2-4m+9[/tex]

Step-by-step explanation:

In general we can write a polynomial in standard form as

[tex]ax^n+bx^n^-^1+cx^n^-^2+...+px+q[/tex]

Given [tex]4m-2m^4-6m^2-4m+9[/tex]

Combine the like terms: 4m and -4m

4m-4m=0

We have 4m-4m=0

So, write the remaining terms

[tex]-2m^4-6m^2+9+0[/tex]

= [tex]-2m^4-6m^2+9[/tex]

This is in decreasing order of powers.

Hence the answer is the standard form is

[tex]-2m^3-6m^2+9[/tex]

But in the given options, you can choose option 2 and option 3 are in standard form.

Because they are in decreasing order of powers.

In other two options, the constants term is first and the highest power term is at the last. So, they are not in standard form.

-2m^4-6m^2+4m+9

-2m^4-6m^2-4m+9

I hope this helps you.

And please comment if I need to do corrections.

Please let me know if you have any questions.

Answer:

so,

the room (2×3) × (3×3) feet, or 6x9 feet.

6x9= 54square feet

54 x 1.75= $94.50

The interquartile range of the data-set is of 5.5, which means that the middle 50% kindergarten classes has a number of students that differ by at most 5.5.

For this problem, the ordered data-set is given by:

18, 18, 18, 20, 21, 22, 23, 23, 24, 24.

There are 10 elements, hence:

Then the IQR is:

Q3 - Q1 = 23.5 - 18 = 5.5.

The IQR is of 5.5, which means that the middle 50% kindergarten classes has a number of students that differ by at most 5.5.

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Answer:

B

Step-by-step explanation:

the blue parabola shows (1/4x)^2, the red shoes x^2, you can see the horizontal stretch, hope this helps :)

Answer:

43.96

Step-by-step explanation:

To find Circumference the formula is

2*3.14*R=C

replace R with your radious which is 7

2*3.14*7=43.96

Answer:

B

Step-by-step explanation:

Answer:

[tex]Q = \frac{k}{14}[/tex]

Step-by-step explanation:

Given

k and 14

Required

Determine the quotient

Quotient implies that we divide k by 14.

So, the quotient (Q) of k and 14 is:

[tex]Q = \frac{k}{14}[/tex]

Answer:

25%, 40 trees, 50%, 36 trees

Answer:

-16

Step-by-step explanation:

If you look at the sequence, you'll notice that each number is two less than the number preceding it

-8 is 2 less than -6

-10 is 2 less than -8

And so on.

-16 is two less than -14, so it is the next number in the sequence.

Answer: im in 100% sure but i think its yes

Step-by-step explanation:

Answer:

No

Step-by-step explanation:

I used photomath

Answer:

[tex]x5 {36}^{?65} \\ [/tex]

Answer:

wait what

Step-by-step explanation:

Answer: C

Step-by-step explanation:

992/4=165

846/6=141

165+141=306

(992/4) + (846/6) = 306 total calories consumed

Answer:

B.

Step-by-step explanation:

edge2020

Answer:

B. 10.6

Step-by-step explanation:

(x + 15)*15 = (20 + 12)*12 => interacting secants theorem

15x + 225 = (32)*12

15x + 225 = 384

Subtract both sides by 225

15x = 384 - 225

15x = 159

Divide both sides by 15

x = 159/15

x = 10.6

Answer:

Step-by-step explanation: so

First you should have paired attention and I don’t understand either sorry!

Answer:

so this is clearly a division problem

the equation will be

5 ÷1/3     Keep switch flip

according to KSF the equation will change to this

5*3  = 15

So she will be able to cut 15 peices.

Thank you, Hope it helps

Answer:

see below

Step-by-step explanation:

Consider the year 2000 to be year 0. This would make year 2028 year 8.

Population growth or decay function: [tex]A = Pe^{rt}[/tex]

where A is the final amount, P is the principal amount, r is the rate, and t is time.

[tex]A = 18,500e^{(0.048)(8)}[/tex]

This can be simplified to

[tex]A = 18,500e^{0.384}[/tex]

Hopefully this is what the question is asking!

Answer:

1) [tex]sin \left(\dfrac{- \pi}{12} \right) = \dfrac{(\sqrt{2} - \sqrt{6} }{4}[/tex]

2) [tex]tan\left(\dfrac{ \pi}{12} \right) = 2 - \sqrt{3}[/tex]

3) [tex]tan\left(\dfrac{ 5\cdot \pi}{12} \right) = 2 + \sqrt{3}[/tex]

Step-by-step explanation:

1) [tex]sin \left(\dfrac{- \pi}{12} \right) = sin(-15^{\circ})[/tex]

sin(-15°)  = sin(30° + (- 45°)) = sin(30°)cos(-45°) + cos(30°)sin(-45°)

sin(30°)cos(-45°) + cos(30°)sin(-45°) = 1/2 × (√2)/2 + (√3)/2 × (-√2)/2

1/2 × √2/2 + √3/2 × -√2/2 = (√2)/4 - (√6)/4 = ((√2) - (√6))/4

sin(-15°)  = ((√2) - (√6))/4

[tex]sin \left(\dfrac{- \pi}{12} \right) = sin(-15^{\circ}) = \dfrac{(\sqrt{2} - \sqrt{6} }{4}[/tex]

2) [tex]tan\left(\dfrac{ \pi}{12} \right) = tan(15^{\circ})[/tex]

tan(15°)  = tan(45° + (-30°)) = (tan(-30°) + tan(45°))/(1 - tan(-30°)×tan(45°))

(tan(-30°) + tan(45°))/(1 - tan(-30°)×tan(45°)) = ((-1/√3) + 1)/(1 - (-1/√3))

((-1/√3) + 1)/(1 - (-1/√3)) = (3 - √3)/(3 + √3) = (3 - √3)·(3 -√3)/((3 - √3)·(3 + √3))

(3 - √3)·(3 -√3/((3 - √3)·(3 + √3)) = (9 - 6·√3 + 3)/(9 - 3) = (12 - 6·√3)/6

(2 - √3)

[tex]tan\left(\dfrac{ \pi}{12} \right) = tan(15^{\circ}) = 2 - \sqrt{3}[/tex]

3) [tex]tan\left(\dfrac{ 5\cdot \pi}{12} \right) = tan(75^{\circ})[/tex]

tan(75°)  = tan(30° + 45°) = (tan(30°) + tan(45°))/(1 - tan(30°)×tan(45°))

(tan(30°) + tan(45°))/(1 - tan(30°)×tan(45°)) = ((1/√3) + 1)/(1 - 1/√3)

((1/√3) + 1)/(1 - 1/√3) = (3 + √3)/(3 - √3) = (3 + √3)·(3 +√3/((3 - √3)·(3 + √3))

(3 + √3)·(3 +√3/((3 - √3)·(3 + √3)) = (9 + 6·√3 + 3)/(9 - 3) = (12 + 6·√3)/6

(12 + 6·√3)/6 = 2 + √3

[tex]tan\left(\dfrac{ 5\cdot \pi}{12} \right) = tan(75^{\circ}) = 2 + \sqrt{3}[/tex]