why is it necessary to specify temperature when giving Ka value
Answer:
Because the equilibrium constant is only at constant at temperature. Changing the temperature changes the Ka.
A compound with molecular formula C6H9No that has an amide functional group and does not have an alkene group
Answer:
Following are the responses to the given question:
Explanation:
[tex]\to C_6H_9NO[/tex]
calculating the HOI:
[tex]= \frac{2C+2+N-H-X}{2} \\\\ =\frac{2\times 6+2+1-9-0}{2}\\\\ =\frac{12-6}{2}\\\\=\frac{6}{2}\\\\=3[/tex]
So, in the above compund there are three bounds or we can say that one is double and two bound is single.
Please find the attachment file of the Function group:
In the above given conditon compound doesn't include the alkene functional group that is absense of[tex]-C=C-[/tex] , and compound include [tex]-C\equiv C-[/tex] So, please find the attached file of the structure of the compound:
Calculate the mass of 5.22 mol of He.
Answer:
The mass is 20, 89 grams of He.
Explanation:
We calculate the weight of 1 mol of He, from the atomic weight of each element obtained from the periodic table: Weight 1 mol He= 4, 0020602 g. 1 mol He-----4, 0020602 g. 5,22 mol He---x= (5,22 mol He x4, 0020602 g)/ 1 mol He= 20, 89 g
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The mass of 5.22 mol of He will be 20.84 grams.
We have 5.22 mol of He.
We have to calculate its Mass.
Which element is represented by symbol He ?Helium is a chemical element with the symbol He and atomic number 2. It is a gas which is colorless, odorless, tasteless, non-toxic, inert and monatomic.
According to the question -
Number of moles of Helium = 5.22 mol
Now, I mole of Helium will have its mass equal to its Atomic weight. Therefore -
Mass of 1 mole of He = 4.002602 g
So, the mass of 5.2 mol of He will be = 5.2 x 4.002602 = 20.84 grams
Hence, the mass of 5.22 mol of He will be 20.84 grams.
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How many moles of gas are in a 30 liter compressed air tank if the
temperature of the tank is 300K and the pressure is 200 atmospheres? *
Answer:
B
Explanation: