The distance indicator can be used to measure the most distant objects among all indicators stated above is Type Ia supernovae
In the field of Astronomy, there are different kind of distance indicators that can be used to measure the distance objects.
Few among them are :
Cepheids Type Ia supernovae Parallax Main-sequence fittingCepheid variables can be measured up to 18 million light years.
The expansion rate of the universe can also be measured by trying to measure the apparent brightness of the Type Ia supernovae
Parallax means illusory state of an object when viewed from different points
Main sequence fitting makes use of a H-R diagram of the cluster to determine the distance to a stellar cluster.
The distance indicator can be used to measure the most distant objects among all indicators stated above is Type Ia supernovae
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Twins Bo and Joe have a combined mass of 200 kg and are zooming along at 10 m/s in a 100 kg amusement park bumper car. They bump into Melinda’s car, which is sitting still. Melinda has a mass of 25 kg and is also in a 100 kg car. After the collision, the twins continue moving with a speed of 4.12 m/s.
a. What is the initial momentum of the system?
b. What must be the final momentum of the system?
c. How fast is Melinda’s car bumped across the floor?
The speed with which Melinda’s car is bumped across the floor is 14 ms-1.
Total mass of the twins and the car = 300 Kg
Initial velocity of the twins car = 10 m/s
Total mass of Melinda and her car = 125 Kg
Initial velocity of Melinda's car = 0 m/s (at rest)
Final velocity of the twins car = 4.12 m/s
Final velocity of Melinda's car = ?
Initial momentum of the system = (300 × 10) + (125 × 0) = 3000 Kgms-1
Final momentum of the system = (300 × 4.12) + (125 × x) = (1236 + 125x) Kgms-1
Using the principle of conservation of linear momentum;
Total momentum before collision = Total momentum after collision
m1u1 + m2u2 = m2v1 + m2v2
(300 × 10) + (125 × 0) = (300 × 4.12) + (125 × x)
3000 = 1236 + 125x
x = 3000 - 1236 /125
x = 14 ms-1
The speed with which Melinda’s car is bumped across the floor is 14 ms-1.
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If your friend was on a skateboard and you pushed them with forward (away from your) with a force of 15N, would you feel a force? If so, how much and what direction? *
Yes. you would feel a force 20 N towards backward direction due to this.
What is force?The definition of force in physics is: The push or pull on a massed object changes its velocity.
An external force is an agent that has the power to alter the resting or moving condition of a body. A spring balance can be used to calculate the Force. The Newton is the SI unit of force.
"When one body exerts a force on the other body, the first body experiences a force that is equal in size in the opposite direction of the force which is exerted," according to Newton's third law of motion.
Hence, according to Newton's third law of motion, when you pushed them with forward (away from your) with a force of 15N, you would feel a force of equal magnitude (20 N) in opposite direction (backward direction).
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Which is an action that can cause an object to move or change its state of motion? energy force equilibrium inertia
Answer:
correct
Explanation:
In physics, a force is any interaction that, when unopposed, will change the motion of an object. A force can cause an object with mass to change its velocity (which includes to begin moving from a state of rest), i.e., to accelerate. Secondly, what force is necessary to change an object's motion?
Answer:
force
Explanation:
got it right on the test
1. A student adds water and sugar to a jar and seals the jar so that nothing can get in or out. The
student then finds the mass of the jar containing the water and sugar. After some sugar dissolves, the
student finds the mass of the jar and its contents again.
Water
Sugar
and
Water
Sugar
Sugar
Before
After
Vhat will happen to the mass of the jar containing the water and sugar after some of the sugar
issolves?
a. The mass will stay the same
b. The mass will increase
c. The mass will decrease
The moon will donend on how much sunar dissolves
Answer:
The mass will stay the same throughout time
Two Magnets are placed near each other on the space station orbiting earth. The south poles are facing each other which statement explains what what happen to the magnets.
A. They will be repelled because they are in each others magnetic field
B. They will be attracted because they’re magnetic fields will add together
C. They will not move because they are not in earths gravitational field.
D. They will not move because they do not have electric fields.
Explanation: A) They will be repelled because they are in each others magnetic field
An object with a mass of 5 kg is accelerated from rest by a 60 N*s impulse. What is the change in the object's velocity?
Hi there!
Using the Impulse-Momentum theorem:
I = Δp = mΔv
Where:
I = Impulse (Ns)
m = mass of object (kg)
Δv = change in velocity (vf - vi, m/s)
Plug in the given values and solve:
60 = 5Δv
Δv = 12 m/s
Dan is working as a family resources coordinator. Which of these statements are true about him?
Dan is responsible for overseeing the administrative functions and daily operations of a childcare center. He also helps families with children
who have special needs to uphold the rights of the children. He assists daycare teachers in carrying out their everyday duties. He also helps
families make use of early intervention services.
Reset
Next
rights reserved
The true statement about Dan is that "he also helps families make use of early intervention services."
Family resource coordinators are experts whose job it is to help families to ensure that children get along in early intervention services. They always work with families and school age children.
If Dan is working as a family resources coordinator, then a true statement about him is that "he also helps families make use of early intervention services."
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Answer:
-He also helps families make use of early intervention services.
-He also helps families with children who have special needs to uphold the rights of the children
Explanation:
Got it right on plato.
What’s 5.1 cm in Newton’s?
Describe the way that distance is changing in relation to tiMe
Answer:
DistaNcE chanGes iN relAtiOn tO TiMe Bc ThE fuRthEr yOu Go ThE mOrE TiMe goeS bY
which term is equal to velocity change per second?
Answer:
Acceleration is measured in meters per second squared (m/s²) change in velocity is measured in meters per second (m/s) time taken
A wave has a wavelength of 1.5 m and a frequency of 6.0 Hz. What is the
speed of the wave?
Answer:
9 m/sExplanation:
The speed of the wave given only it's frequency and wavelength can be found by using the formula
[tex]c = f \times \lambda[/tex]
where
c is the velocity of the wave in m/s
[tex] \lambda[/tex] is the wavelength in m
f is the frequency in Hz
From the question we have
c = 6 × 1.5 = 9
We have the final answer as
9 m/sHope this helps you
Match the definition with the appropriate word.
temperature
part of internal energy that can be
transferred
heat
measure of the average kinetic energy of a
substance
thermal energy
total potential and kinetic energies of the
particles in a substance
internal energy
thermal energy that flows from one
substance to another
Answer:
Temperature: measure of the average kinetic energy of a substance
Internal energy: total potential and kinetic energies of the particles in a substance
Heat: thermal energy that flows from one substance to another
Thermal energy: part of internal energy that can be transferred
Explanation:
Proof for correct answers on edge :)
A rectangular room twice as long as it is wide would contain 145 square feet more if each side were one foA rectangular room twice as long as it is wide would contain 145 square feet more if each side were one foot longer. What is the length of the room
The length of the room is 96 ft.
Let L be the length of the room and W be the width of the room.
Since the length is twice its width, L = 2W.
Its area A = LW
= 2W × W
= 2W²
If each side were increased by 1 foot, then its new area is A' = (L + 1)(W + 1)
= (2W + 1)(W + 1)
= 2W² + 3W + 1
Since the room would contain 145 ft more if each side were increased by 1 foot, then its new area is A' = A + 145 = 2W² + 3W + 1
2W² + 145 = 2W² + 3W + 1
145 = 3W + 1
3W = 145 - 1
3W = 144
W = 144/3
W = 48 ft.
Since its length L = 2W, substituting W = 48 into the equation, we have
L = 2(48)
L = 96 ft
So, the length of the room is 96 ft.
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What is the density of a substance that has a volume of 30ml and a mass of 20g?
Answer:
0.67 g/mLExplanation:
The density of a substance can be found by using the formula
[tex]d = \frac{m}{v} \\ [/tex]
m is the mass
v is the volume
From the question
m = 20 g
v = 30 mL
We have
[tex]d = \frac{20}{30} = \frac{2}{3} \\ = 0.66666...[/tex]
We have the final answer as
0.67 g/mLHope this helps you
A sled is launched off a cliff 39 m high and lands 74 m away from the base of the cliff. How fast was the sled launched?
The sled was launched with a velocity of 26.24 m/s
We'll begin by calculating the the time taken for the sled to land
Height (h) = 39 m
Acceleration due to gravity (g) = 9.8 m/s²
Time (t) =?[tex]t = \sqrt{ \frac{2h}{g}} \\ \\t = \sqrt{ \frac{2 \times 39}{9.8}} \\ \\ t = 2.82 \: s \\ \\ [/tex]
Finally, we shall determine the velocity.Time (t) = 2.82 s
Horizontal distance (s) = 74 m
Horizontal velocity (u) =?[tex]u = \frac{s}{t} \\ \\ u= \frac{74}{2.82} \\ \\ u = 26.24 \: m/s \\ \\ [/tex]
Therefore, the sled was launched with a velocity of 26.24 m/s
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Please help with this ski question to find Delta y
Why does calcium chloride have a greater affect on colligative properties verses sodium
chloride?
Answer:
Calcium chloride is very effective, working at temperatures below most products, and is significantly more effective than sodium chloride because of its ability to extract moisture from its surroundings and to cause exothermic or heat generating reactions.
Explanation:
Hope this helps
plz help
Suppose one of the three students in Guided Example 7.6 stops pushing the car after 6.00 s. In this case the force exerted on the car is 305 N for the first 6.00 s and 215 N for the second 6.00 s.
(a) What is the final momentum of the car?
(b) What is the final speed of the car?
Answer:
520 n is the final momentum of the car and is also the final speed of the car
Explanation:
The final momentum is 250 newton.
What is momentum?Momentum is the result of a particle's mass and velocity. Being a vector quantity, momentum possesses both magnitude and direction. According to Isaac Newton's second equation of motion, the force applied on a particle is equal to the time rate of change of momentum.
According to Newton's second law, if a particle is subjected to a constant force for a specific amount of time, the result of the force and time (referred to as the impulse) is equal to the change in momentum.
On the other hand, a particle's momentum represents the length of time needed for a consistent force to bring it to rest.
Therefore, The final momentum is 250 newton.
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HELP!!!
Which of the following statements is true about magnets?
A. The molecules of the atom are unaligned
B. The orientation of atoms does not affect a magnet
C. The north pole is stronger than the south pole
D. The molecules of the atom are all aligned
Giving brainliest to the correct answer! (If both are correct I'll give whoever answered correctly 1st brainliest!)
Answer:
Explanation:
A is not correct. That means that D is since they offer exactly the opposite meanings.
C is rubbish. One pole could not be stronger than the other. Heaven help us if touched the stronger pole.
B the very point of a magnet is that it does matter how the atoms are orientated.
Write a summary paragraph discussing this experiment and the results. Use the following questions and topics to help
guide the content of your paragraph.
1. According to your data, was your hypothesis for each experiment correct? (Be sure to refer to your data and graphs
when answering this question.)
2. Summarize the conclusions that you can draw from this experiment. Use the questions above to gulde your ideas.
3. Summarize any difficulties or problems you had in performing the experiment that might have affected the results.
Describe how you might change the procedure to avoid these problems.
4. Give at least one more example from real life where the principles demonstrated in this lab are evident.
Answer:
Sample answer: part 1:
What was your hypothesis?
This is what you wanted to prove or study with the experiment. Reading the question I can see that the experiment seems to study the relation between the viscosity of honey and the temperature, so the hypothesis may be something like:
"The viscosity of honey decreases as temperature increases".
According to your data, do you think your hypothesis was correct?
Here you need to see your experimental data, probably, you found that yes, as you increase the temperature the viscosity decreases.
The last thing we need to do here is to summarize difficulties and problems that you had in the experiment, and propose how you could solve them in order to have a better experiment.
Obviously, this depends on how you performed the experiment, but for example, if you saw that the temperature of the honey increased too fast, you could say:
"one problem was that the temperature of the honey increased too fast"
And one way to solve that would be submerging the honey in a water bath so the temperature increases a bit slower.
part 2:
Viscosity depends strongly on temperature, but this relation depends also on the given material.
Generally, we would see that the viscosity decays exponentially as the temperature increases.
So for the first question:
What effect did the temperature have on the viscosity of the honey?
You should have seen that, as the temperature increased, the viscosity decreased.
Now, we need to give some practical examples where knowledge of viscosity is important.
The first one is for cleaning: We know that if we increase the temperature, the viscosity decreases. Thus if we have some object with some viscous thing on it, increasing the temperature will cause it to be easier to clean.
Another example is to store/transport viscous things, for example, honey, it is actually a lot easier to pour honey in bottles if you first heat it a little, so it becomes less viscous.
So there you have two examples where knowing about viscosity (and how it relates to temperature) may be important.
Explanation:
A 0.40 kg bead slides on a straight frictionless wire with a velocity of 3.50 cm/s to the right. The
bead collides elastically with a larger 0.60 kg bead initially at rest. After the collision the smaller
bead moves to the left with a velocity of 0.70 cm/s. Find the distance the larger bead moves along
the wire in the first 5.0 s following the collision?||
Answer:
Total momentum before collision
P1 =.4 * 3.5 = 1.4 ignoring units here
Total momentum after collision
P2 = .6 * V - .4 * .7 = .6 V - .28
.6 V = 1.4 + .28 momentum before = momentum after
V = 2.8 cm/sec
In 5 sec V moves 2.8 cm/sec * 5 sec = 14 cm
A strong weightless rope has a mass, m, hanging from the middle of it. The tension force on each rope is 25 N, and the rope droops at an angle of 20.0 degrees. How much mass is hanging from the rope?
By using Lami's theorem, Mass m = 1.75 kg approximately
Given that a strong weightless rope has a mass, m, hanging from the middle of it. If the tension force on each rope is 25 N, and the rope droops at an angle of 20.0 degrees to the horizontal.
By using Lami's theorem, we can get how much mass is hanging from the rope.
Let the angle between the rope = α = 180 - 40
α = 140 degrees
The angle between one of the rope and mass = β = 20 + 90
β = 110 degrees
The angle between the mass and the other rope = γ = 360 - (140 + 110)
γ = 360 - 250
γ = 110 degrees
W/ sinα = T/ sinβ = T/sinγ
W/ sinα = T/ sinβ
Substitute all the necessary parameters
W/sin140 = 25/sin 110
W / 0.643 = 25 / 0.939
W = 17.1 N
Weight W = mg
17.1 = 9.8m
mass m = 17.1/9.8
Mass m = 1.7455 kg
Mass m = 1.75 kg approximately
Therefore, 1.75 kg mass is hanging from the rope.
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Simplicity of conducting the study is to ________ as ability to test large numbers of participants is to ________.
Simplicity of conducting the study is to archival research as ability to test large numbers of participants is to surveys.
What is Archival research?Archival research is a type of research which involves seeking out and extracting the evidence from archival records. These archival records may be held together either in the collection of institutions, such as libraries and museums, or in the custody of the organization that originally generated or accumulated them, or in that of a successor object.
Archival research can be contrasted with the secondary research, which involves identification and consulting the secondary sources related to the topic of enquiry; and with the other types of primary research and empirical investigation such as fieldwork and experiment.
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Bill pushed 327 kg. bucket of concrete with a force of 10N. What was the
acceleration?
Answer:
F(10)=mass(327)x acceleration(m/s)
Explanation:
A block of mass M is attached to a spring of negligible mass and can slide on a horizontal surface along the x-direction, as shown above. There is friction present between the block and the surface. The spring exerts no force on the block when the center of the block is located at x=0. At the instant shown above, the block is located at x=0 and moving toward the right with speed v=v0. (a) For the instant shown above, with the block located at x=0 and moving to the right, predict the direction of the net force on the block. If the net force is zero, select “The net force is zero.”
_ To the left _ The net force is zero _ To the right
Briefly justify your prediction.
Answer:
Because of the frictional force, the net force will oppose direction of the block and be directed towards the left even tho the spring exerts no force at this point
A dart is thrown at a target that is supported by a wooden backstop. It strikes the backstop with an initial velocity of 350 m/s [E] The dart comes to rest in 0.0050 s.
a. What is the acceleration of the dart?
b. How far does the dart penetrate into the backstop?
Answer:u=350m/sec
v=0m/sec
t=0.005sec
a=v-u/t
=0-350/0.005
= -350/0.005
= -350×1000/5
= -70×1000
= -70000 m/sec^2
Explanation: i think this will help you thankyou
Assertion: In domestic electric circuits, the metallic body is connected to the earth wire, which
provides a low-resistance conducting path for the current.
Reason: It ensures that any leakage of current to the metallic body of the appliance keeps its
potential to that of the earth, and the user may not get a severe electric shock. pls fast
Answer:
The answare is it ensures that any leakage of current to the metallic body of the appliance keeps its potential to that of the earth, and the user may not get a severe electric shock.
Why is saving important to the economy.......and to you?
Answer: Saving is important to the economic progress of a country because of its relation to investment. If there is to be an increase in productive wealth, some individuals must be willing to abstain from consuming their entire income.
Explanation:
Savings is important to the economy because it enables growth and development of a nation.
Importance of savings
The importance of savings to the economy in general can not be over emphasized.
The following are some importance of savings to the economy;
Growth in the economy: when people save money the economy grows.Development: The increase in the economy due to savings can help in the development of a nation.Thus, savings is important to the economy because it enables growth and development of a nation.
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A small charge q is placed near a large spherical charge Q. The force experienced by both charges is F. The electric eld created by Q at the position of q is:
The electric field created by Q at the position of q is [tex]\frac{F}{Q}[/tex].
The given parameters:
Magnitude of charge, = qSpherical charge, = QForce experienced by both charges, = FThe electric field created by Q at the position of q is calculated as follows;
[tex]E = \frac{F}{Q} \\\\[/tex]
where;
E is the magnitude of electric field strength F is the force experienced by both chargesQ is the chargeThus, the electric field created by Q at the position of q is [tex]\frac{F}{Q}[/tex].
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A circle has a radius of 10 inches. Find the approximate length of the arc intersected by a central angle of mc001-1. Jpg 6. 67 inches 10. 47 inches 20. 94 inches 62. 8 inches.
The approximate length of the arc intersected by the central angle is 20.94 inches.
The given parameters:
Radius of the circle, r = 10 inchesCentral angle, [tex]\theta = \frac{2\pi }{3} \ rad[/tex]The approximate length of the arc intersected by the central angle is calculated as follows;
S = rθ
where;
S is the length of the arcSubstitute the given parameters and solve for the length of the arc
[tex]S = 10 \ in \times \frac{2\pi }{3} \\\\S = 20.94 \ inches[/tex]
Thus, the approximate length of the arc intersected by the central angle is 20.94 inches.
Your question is not complete, find the complete question below:
A circle has a radius of 10 inches. Find the approximate length of the arc intersected by a central angle of [tex]\frac{2\pi}{3}[/tex].
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