Answer:
mass divided by volume
Step-by-step explanation:
The density can be calculated as the mass divided by volume. So, the correct option is A.
How to find the density?Density is like rate. It tells you how much of a thing is available for each unit other thing which contains the first thing.
Density = (Total amount available)/(total space which contains that amount)
Suppose that a finite amount of substance is there having its properties as:
The mass of substance = m kg
The density of substance = d kg/m³
The volume of that substance = v m³
Then, they are related as:
[tex]d = \dfrac{m}{v}[/tex]
Therefore, the density can be calculated as the mass divided by volume. So, the correct option is A.
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The mean annual tuition and fees for a sample of 15 private colleges was with a standard deviation of . A dotplot shows that it is reasonable to assume that the population is approximately normal. You wish to test whether the mean tuition and fees for private colleges is different from 32,500 a) state the null and alternate hypotheses b) calculate the standard error c) calculate the test statistic d) find the p - value .
Answer:
Step-by-step explanation:
The question is incomplete. The complete question is:
The mean annual tuition and fees for a sample of 15 private colleges was $35,500 with a standard deviation of $6500. A dotplot shows that it is reasonable to assume that the population is approximately normal. You wish to test whether the mean tuition and fees for private colleges is different from $32,500. State the null and alternate hypotheses. A) H0: 4 = 32,500, H:4=35,500 C) H: 4 = 35,500, H7:35,500 B) H: 4 = 32,500, H : 4 # 32,500 D) H0:41 # 32,500, H : 4 = 32,500
Solution
We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean
For the null hypothesis,
H0: µ = 32500
For the alternative hypothesis,
Ha: µ ≠ 32500
This is a two tailed test.
Since the number of samples is small and the population standard deviation is not given, the distribution is a student's t.
Since n = 15,
Degrees of freedom, df = n - 1 = 15 - 1 = 14
t = (x - µ)/(s/√n)
Where
x = sample mean = 35500
µ = population mean = 32500
s = samples standard deviation = 6500
t = (35500 - 32500)/(6500/√15) = 1.79
We would determine the p value using the t test calculator. It becomes
p = 0.095
Assuming alpha = 0.05
Since alpha, 0.05 < than the p value, 0.095, then we would fail to reject the null hypothesis.
Kyra is using rectangular tiles of two types for a floor design. They Tyler each type is shown below:
Answer: b) the tiles are not similar because both SP:SR is 5:4 and MJ:ML is 5:2
Step-by-step explanation:
We are given that the tiles are rectangular which implies that they both have a 90° angle.
In order to prove similarity, We need to show that the lengths and widths are proportional.
P Q R S
J K L M
a) PQ : QR JK : LM
w=4 L=5 w=2 w=2
↓
We need Length (not width)
b) SP : SR MJ : ML
L=5 w=4 L=5 w=2
5 : 4 5 : 2
When comparing length to width they do not have the same ratio so the rectangles are not similar.
c) PQ : QR JK : KL
w=4 L=5 w=2 L=5
4 : 5 2 : 5
When comparing width to length they do not have the same ratio so the rectangles are not similar.
d) SR : ML PQ : JK
w=4 w=2 w=4 w=2
↓ ↓
We need Length (not width)
5/a - 4/b as a single fraction
Answer:
I'm not completely sure what you mean by a, "single fraction," but I'm pretty sure the answer you are looking for is [tex]\frac{5-4}{a-b}[/tex]
Step-by-step explanation:
Please answer this correctly
Answer:
0
Step-by-step explanation:
The sorted data set is ...
1 2 3 3 5 7 8 9
The median is the average of the middle two numbers: (3+5)/2 = 4.
Replacing one of the 3s with a 1 makes the data set be ...
1 1 2 3 5 7 8 9
The average of the middle two numbers is (3+5)/2 = 4.
The median increases by 4 - 4 = 0.
Bronson is ordering pizza at a restaurant, and the server tells him that he can have up to three toppings: spinach, bacon, and pepperoni. Since he cannot decide how many of the toppings he wants, he tells the server to surprise him. If the server randomly chooses which toppings to add, what is the probability that Bronson gets just spinach? Express your answer as a fraction or a decimal number rounded to four decimal places.
Answer:
The probability that Bronson gets just spinach is;
P = 1/7
or
P = 0.1429
Step-by-step explanation:
There are three possibilities;
- just one topping
- two topping
- three topping
For just one topping, the number of possible outcomes is;
N1 = 3C1 = 3!/(1!2!) = 3 possible outcomes
For two topping, the number of possible outcomes is;
N2 = 3C2 = 3!/(2!1!) = 3 possible outcomes
For three topping, the number of possible outcomes is;
N3 = 3C3 = 3!/3! = 1 possible outcomes
Total number of possible outcomes;
N = N1+N2+N3
N = 3+3+1 = 7
The probability that Bronson gets just spinach is;
Getting spinach is one out of seven possible outcomes, so;
P = 1/N = 1/7
P = 1/7 or 0.1429
Find the equation of the line.
Use exact numbers.
Answer:
y = 2/3x + 4
Step-by-step explanation:
Step 1: Find slope
m = (4-0)/(0+6)
m = 2/3
Step 2: Write in y-int (0, 4)
y = 2/3x + 4
one teaspoon equals 0.5 centiliters. how many liters equal 50 teaspoon ? round to the nearest hundredth.
Answer:
50 teaspoons = 0.246446 liters
0.246446 rounded to the nearest hundredth is 0.25
so your answer is 0.25
Step-by-step explanation:
Answer:
Step-by-step explanation:
It's A 0.25 I litteraly random guessed it
An experiment was conducted to record the jumping distances of paper frogs made from construction paper. Based on the sample, the corresponding 95% confidence interval for the mean jumping distance is (8.8104, 11.1248)cm. What is the corresponding 98% confidence interval for the mean jumping distance?
Answer:
[tex] 9.9676 - 2.326*0.5904 =8.594[/tex]
[tex] 9.9676 + 2.326*0.5904 =11.341[/tex]
Step-by-step explanation:
Notation
[tex]\bar X[/tex] represent the sample mean
[tex]\mu[/tex] population mean (variable of interest)
s represent the sample standard deviation
n represent the sample size
Solution to the problem
The confidence interval for the mean is given by the following formula:
[tex]\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}[/tex] (1)
For this case the 9% confidence interval is given by:
[tex] 8.8104 \leq \mu \leq 11.1248[/tex]
We can calculate the mean with the following:
[tex]\bar X = \frac{8.8104 +11.1248}{2}= 9.9676[/tex]
And we can find the margin of error with:
[tex] ME= \frac{11.1248- 8.8104}{2}= 1.1572[/tex]
The margin of error for this case is given by:
[tex] ME = t_{\alpha/2}\frac{s}{\sqrt{n}} = t_{\alpha/2} SE[/tex]
And we can solve for the standard error:
[tex] SE = \frac{ME}{t_{\alpha/2}}[/tex]
The critical value for 95% confidence using the normal standard distribution is approximately 1.96 and replacing we got:
[tex] SE = \frac{1.1572}{1.96}= 0.5904[/tex]
Now for the 98% confidence interval the significance is [tex]\alpha=1-0.98= 0.02[/tex] and [tex]\alpha/2 = 0.01[/tex] the critical value would be 2.326 and then the confidence interval would be:
[tex] 9.9676 - 2.326*0.5904 =8.594[/tex]
[tex] 9.9676 + 2.326*0.5904 =11.341[/tex]
Refer to the following frequency distribution of days absent during a calendar year by employees of a manufacturing company:_______.
Days Absent Number of employees
0 up to 3 60
3 up to 6 31
6 up to 9 14
9 up to 12 6
12 up to 15 2
How many employees were absent fewer than six days?
Answer:
91 employees
Step-by-step explanation:
To find the number of employees absent fewer than six days...add the frequency of those absent for 0 to 3 days and that of 3 to 6 days
The frequency of 0 to 3 days = 60
The frequency of 3 to 6 days = 31
Thus, the numbers of employees absent fewer than 6 days is 60+31 = 91
Which transformations could have occurred to map AABC
to AA"B"C"?
O a rotation and a dilation
O a rotation and a reflection
O a reflection and a dilation
O a translation and a dilation
Answer:
A reflection and a dialation
Step-by-step explanation:
Reflection is when you flip a figure over a line. Rotation is when you rotate a figure a certain degree around a point. Dilation is when you enlarge or reduce a figure.In this case a rotation is not nessasary, so I would suggest a reflection in the y-axis and a dialation to shrink the triangle to A'B'C'
So for the transformations that could have occurred to map ABC to A'B'C' you should choose the answer
a reflection and a dialation
The transformations that occurred to map ABC to A'B'C are: C. a reflection and a dilation
Key Facts on TransformationsReflection is simply flipping a shape over an axis.Dilation means enlarging a figure or reducing the size of a figure.Rotation simply involves rotating a figure around a given point while maintaining same size.Translation is shifting the points of a figure to move it to another position.Thus, in the transformation shown, figure ABC was reflected over the y-axis and then dilated to give A'B'C'.
Therefore, the transformations that occurred to map ABC to A'B'C are: C. a reflection and a dilation
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Any help would be great
Answer:
-8 * 5 = -40
a⁵ * a = a⁶
b⁶ * b³ = b⁹
Answer is -40a⁶b⁹
Henrique began to solve a system of linear equations using the linear combination method. His work is shown below: 3(4x – 7y = 28) → 12x – 21y = 84 –2(6x – 5y = 31) → –12x + 10y = –62 12x – 21y = 84 + –12x + 10y = –62 –11y = 22 y = –2 Complete the steps used to solve a system of linear equations by substituting the value of y into one of the original equations to find the value of x. What is the solution to the system? ( , )
Answer:
( 3.5 , -2 )
Step-by-step explanation:
Answer:
( 3.5 , -2)
Explanation:
On edge
If a square with a width of 30 feet a length of 72 feet, and the diagonal is 78 feet, would the square have right angles. Yes or No answer please explain
As director of the employee wellness and productivity program in your company, you are interested in comparing the effects of strength training, aerobic training, and yoga on decreasing rates of injury and absenteeism. The company has 9 divisions with roughly the same number of employees, and you randomly assign 3 divisions to participate in strength training, 3 to aerobic training, and 3 to yoga. Your alternative hypothesis is
Answer:
[tex]\mu_1 \neq \mu_2 \neq \mu_3[/tex]
Where [tex]\mu_1[/tex] is the average effect of strength training
[tex]\mu_2[/tex] is the average effect of aerobic training
[tex]\mu_3[/tex] is the average effect of yoga
Step-by-step explanation:
The aim of this study is to confirm whether the strength training, aerobic training, and yoga have equal effect on the decreasing rates of injury and absenteeism or not. The null hypothesis suggests that these three training have equal effect on the decreasing rates of injury and absenteeism because according to the null hypothesis, there is no statistical difference between observed variables.
The alternative hypothesis on the other hand suggests a statistical difference between the observed variables. In this case, the alternative hypothesis suggests that the observed variables have different effects on the decreasing rates of injury and absenteeism.
My alternative hypothesis as the director of the employee wellness and productivity program is [tex]\mu_1 \neq \mu_2 \neq \mu_3[/tex]
Where [tex]\mu_1[/tex] is the average effect of strength training
[tex]\mu_2[/tex] is the average effect of aerobic training
[tex]\mu_3[/tex] is the average effect of yoga
The alternative hypothesis is, [tex]\mu_1 \neq \mu_2 \neq \mu_ 3[/tex].
Where, [tex]\mu_1[/tex] is the average effect of strength training,
[tex]\mu_2[/tex] is the average effect of aerobic training.
[tex]\mu_3[/tex] is the average effect of yoga.
Given that,
As director of the employee wellness and productivity program in your company,
you are interested in comparing the effects of strength training, aerobic training, and yoga on decreasing rates of injury and absenteeism.
The company has 9 divisions with roughly the same number of employees, and you randomly assign 3 divisions to participate in strength training, 3 to aerobic training, and 3 to yoga.
We have to determine,
Your alternative hypothesis is.
According to the question,
The effects of strength training, aerobic training, and yoga on decreasing rates of injury and absenteeism.
The aim of this study is to confirm whether strength training, aerobic training, and yoga have equal effects on decreasing rates of injury and absenteeism or not.
The null hypothesis suggests that these three pieces of training have an equal effect on the decreasing rates of injury and absenteeism because according to the null hypothesis,
There is no statistical difference between observed variables.
The alternative hypothesis on the other hand suggests a statistical difference between the observed variables.
In this case, the alternative hypothesis suggests that the observed variables have different effects on the decreasing rates of injury and absenteeism.
The company has 9 divisions with roughly the same number of employees, and you randomly assign 3 divisions to participate in strength training, 3 to aerobic training, and 3 to yoga.
Therefore, The alternative hypothesis as the director of the employee wellness and productivity program is,
Where [tex]\mu_1[/tex] is the average effect of strength training,
[tex]\mu_2[/tex] is the average effect of aerobic training.
[tex]\mu_3[/tex] is the average effect of yoga.
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The mayor of a town has proposed a plan for the construction of an adjoining bridge. A political study took a sample of 900 voters in the town and found that 60% of the residents favored construction. Using the data, a political strategist wants to test the claim that the percentage of residents who favor construction is above 56%. Determine the P-value of the test statistic. Round your answer to four decimal places.
Answer:
Test statistic z = 2.3839.
P-value = 0.0086.
At a signficance level of 0.05, there is enough evidence to support the claim that the percentage of residents who favor construction is above 56%.
Step-by-step explanation:
This is a hypothesis test for a proportion.
The claim is that the percentage of residents who favor construction is above 56%.
Then, the null and alternative hypothesis are:
[tex]H_0: \pi=0.56\\\\H_a:\pi>0.56[/tex]
The significance level is 0.05.
The sample has a size n=900.
The sample proportion is p=0.6.
The standard error of the proportion is:
[tex]\sigma_p=\sqrt{\dfrac{\pi(1-\pi)}{n}}=\sqrt{\dfrac{0.56*0.44}{900}}\\\\\\ \sigma_p=\sqrt{0.000274}=0.017[/tex]
Then, we can calculate the z-statistic as:
[tex]z=\dfrac{p-\pi-0.5/n}{\sigma_p}=\dfrac{0.6-0.56-0.5/900}{0.017}=\dfrac{0.039}{0.017}=2.3839[/tex]
This test is a right-tailed test, so the P-value for this test is calculated as:
[tex]\text{P-value}=P(z>2.3839)=0.0086[/tex]
As the P-value (0.0086) is smaller than the significance level (0.05), the effect is significant.
The null hypothesis is rejected.
There is enough evidence to support the claim that the percentage of residents who favor construction is above 56%.
From past, a company knows that in cartons of bulbs, 90% contain no defective bulbs, 5%
contain one defective bulb, 3% contain two defective bulbs, and 2% contain three defective
bulbs. Find the mean and standard deviation for the number of defective bulbs.
Answer:
The mean is M=0.17 defective bulbs.
The standard deviation is s=0.165 defective bulbs.
Step-by-step explanation:
We can calculate the mean as the sum of the product between the number of defective bulbs and its proportion:
[tex]M=\sum_i p_i\cdot X_i=0.9\cdot0+0.05\cdot 1+0.03\cdot2+0.02\cdot3\\\\M=0+0.05+0.06+0.06\\\\M=0.17[/tex]
The standard deviation can be calculated as the sum of the product between the deviation from the mean for each number of defective bulbs and its proportion:
[tex]s=\sqrt{\sum_i p_i\cdot (X_i-M)^2}\\\\s=\sqrt{0.9\cdot(0-0.17)^2+0.05\cdot (1-0.17)^2+0.03\cdot(2-0.17)^2+0.02\cdot(3-0.17)2}\\\\s=\sqrt{0.02601+0.00072+0.000363+0.000242}\\\\s=\sqrt{0.027335}\\\\s\approx0.165[/tex]
Find the explicit formula for the arithmetic sequence cn given below. Note that c1=8. 8,17,26,35,44,…
Answer:
[tex]c_n=9\,n-1[/tex]
Step-by-step explanation:
Recall that the general formula for the nth term of an arithmetic sequence is given by:
[tex]c_n=c_1+(n-1)\,d[/tex]
where [tex]c_1[/tex] is the first term of the sequence (in our case 8), and [tex]d[/tex] is the common difference for the sequence (the number that is added to a term in order to get the term that follows. In our case, "9" is the common difference (you can check this by subtraction between any two consecutive terms.
Then, the formula for the nth term of this sequence is
[tex]c_n=8+(n-1)\,9=8+9\,n-9=9\,n-1[/tex]
How do i work out the probability of rolling two sixes
Answer: p = 1/25
Step-by-step explanation:
Ok, you know that the probability of rolling a six is p = 1/5
now, if you want to have two sixes, then you have two events with a probability of 1/5.
And as you know the joint probability for two events is equal to the product of the probabilities, then the probability of rolling two sixes is:
p = (1/5)*(1/5) = 1/25.
What is the present value of a $1,600 payment made in five years when the discount rate is 10 percent?
Answer:
Present value is $993.47
Step-by-step explanation:
PV = present value
Fv = future value = $1,600
Discount (i) = 10%
N = Years = 5
The formula for this is given by:
PV = FV/(1 + i)^N
PV = $1600/(1 + 0.10)^5
PV = $1600/1.1^5
PV = $1600/1.61051
PV = $993.47
A student carried out an experiment to determine the amount of vitamin C in a tablet sample. He performed 5 trials to produce the following results: 490 mg, 502 mg, 505 mg, 495mg, and 492 mg. The manufacturer claims that the tablet contains 500 mg of vitamin C. Do an appropriate statistical analysis to find out whether the results obtained by the student is consistent with bottle claim.
Answer:
There is not enough evidence to support the claim that the amount of vitamin C in a tablet sample is different from 500 mg.
P-value = 0.166.
Step-by-step explanation:
We start by calculating the mean and standard deviation of the sample:
[tex]M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M=\dfrac{1}{5}(490+502+505+495+492)\\\\\\M=\dfrac{2484}{5}\\\\\\M=496.8\\\\\\s=\sqrt{\dfrac{1}{n-1}\sum_{i=1}^n\,(x_i-M)^2}\\\\\\s=\sqrt{\dfrac{1}{4}((490-496.8)^2+(502-496.8)^2+(505-496.8)^2+(495-496.8)^2+(492-496.8)^2)}\\\\\\s=\sqrt{\dfrac{166.8}{4}}\\\\\\s=\sqrt{41.7}=6.5\\\\\\[/tex]
Then, we can perform the hypothesis t-test for the mean.
The claim is that the amount of vitamin C in a tablet sample is different from 500 mg.
Then, the null and alternative hypothesis are:
[tex]H_0: \mu=500\\\\H_a:\mu< 500[/tex]
The significance level is 0.05.
The sample has a size n=5.
The sample mean is M=496.8.
As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=6.5.
The estimated standard error of the mean is computed using the formula:
[tex]s_M=\dfrac{s}{\sqrt{n}}=\dfrac{6.5}{\sqrt{5}}=2.907[/tex]
Then, we can calculate the t-statistic as:
[tex]t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{496.8-500}{2.907}=\dfrac{-3.2}{2.907}=-1.1[/tex]
The degrees of freedom for this sample size are:
[tex]df=n-1=5-1=4[/tex]
This test is a left-tailed test, with 4 degrees of freedom and t=-1.1, so the P-value for this test is calculated as (using a t-table):
[tex]\text{P-value}=P(t<-1.1)=0.166[/tex]
As the P-value (0.166) is bigger than the significance level (0.05), the effect is not significant.
The null hypothesis failed to be rejected.
There is not enough evidence to support the claim that the amount of vitamin C in a tablet sample is different from 500 mg.
A quick quiz consists of a multiple-choice question with 6 possible answers followed by a multiple-choice question with 5 possible answers. If both questions are answered with random guesses, find the probability that both responses are correct. Report the answer as a percent rounded to two decimal place accuracy. You need not enter the "%" symbol
Answer:
3.33
Step-by-step explanation:
Independent events:
If two events, A and B, are independent, we have that:
[tex]P(A \cap B) = P(A)*P(B)[/tex]
In this question, we have that:
The question are independent of each other.
Event A: Correct guess on the first question.
Event B: Correct guess on the second question.
A quick quiz consists of a multiple-choice question with 6 possible answers followed by a multiple-choice question with 5 possible answers.
This means that [tex]P(A) = \frac{1}{6}, P(B) = \frac{1}{5}[/tex]
Probability that both responses are correct.
[tex]P(A \cap B) = \frac{1}{6}*\frac{1}{5} = \frac{1}{30} = 0.333[/tex]
The answer is 3.33%. Since it asks without the "%" symbol, 3.33
Each of the following is a confidence interval for μ = true average (i.e., population mean) resonance frequency (Hz) for all tennis rackets of a certain type:(111.6, 112.4) (111.4, 112.6)(a) What is the value of the sample mean resonance frequency?
Answer:
The value of the sample mean resonance frequency is 112Hz
Step-by-step explanation:
A confidence interval has two bounds, a lower bound and an upper bound.
A confidence interval is symmetric, which means that the point estimate used is the mid point between these two bounds, that is, the mean of the two bounds.
In this problem, we have that:
Lower bound: 111.6
Upper bound: 112.4
Sample mean: (111.6 + 112.4)/2 = 112Hz
The value of the sample mean resonance frequency is 112Hz
The value of the sample mean resonance frequency is 112 Hz.
What is the value of the sample mean resonance frequency?The value of the sample mean resonance frequency is equivalent to the average of the upper limit and the lower limit.
The sample mean resonance frequency = (lower limit + upper limit) / 2
(111.6 +112.4) / 2
= 224 / 2
= 112 Hz
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Before a researcher specified the relationship among variables he must have a (an): A: Inventory of variables B: Inventory of propositions C: Arrangement of propositions D: Schematic diagram
Answer:
Option B
Step-by-step explanation:
Before a researcher specifies the relationship among variables he must have an inventory of propositions/constructs which are mostly stated in a declarative form. These are then tested by examining the relationships between measurable variables of this constructs/propositions.
Verify the identity algebraically. 7 sec(y) cos(y) = 7
Answer:
7 sec(y) cos(y) = 7
Use identity sec(y) = 1/cos(y).
7 * 1/cos(y) * cos(y) = 7
7 * 1 = 7
7 = 7
GIVING BRAIN AND 30pointsWhat is the solution to the system of equations below?
y=-3x+2 and 3y =-
3
4
X-6
no solution
infinitely many solutions
(-16, 6)
O (-16, -2)
Answer:
No solution
Step-by-step explanation:
Using substitution, we get to the answer 12=0, which is untrue meaning no solution.
Hope this helps! Please give Brainliest!!
Answer:
no solution
Step-by-step explanation:
y= -1/4x+2
3y = - 3/4x-6 ⇒ y= - 1/4x - 2
These are parallel lines as have same slope of -1/4, so there is no solution
Triangle L M N is cut by line segment O P. Line segment O P goes from side M L to side M N. The length of O L is 14, the length of O M is 28, the length of M P is y, and the length of P N is 18.
Which value of y would make O P is parallel to L N?
16
24
32
36
Answer:
The value of y that would make O P parallel to L N = 36
Step-by-step explanation:
This is a question on similar triangles. Find attached the diagram obtained from the given information.
Given:
The length of O L = 14
the length of O M = 28
the length of M P = y
the length of P N = 18
Length MN = MP + PN = y + 18
Length ML = MO + OL = 28+14 = 42
For OP to be parallel to LN,
MO/ML = MP/PN
MO/ML = 28/42
MP/PN= y/(y+18)
28/42 = y/(y+18)
42y = 28(y+18)
42y = 28y + 18(28)
42y-28y = 504
14y = 504
y = 504/14 = 36
The value of y that would make O P parallel to L N = 36
Answer:
D-36
Step-by-step explanation:
This table represents a quadratic function with a vertex at (1, 2). What is the
average rate of change for the interval from x = 5 to x = 6?
Answer:
D: 9
Step-by-Step Explanation:
The average rate is synonymous with the slope. Since we want to find the average rate of change from x = 5 to x = 6, we will use the two points (5, 18) and (6, ?). We will need to find ? first.
Since the table represents a quadratic function and we are given the vertex, we can use the vertex form of a quadratic:
[tex]\displaystyle f(x)=a(x-h)^2+k[/tex]
Where (h, k) is the vertex.
The vertex is (1, 2). Hence:
[tex]f(x)=a(x-1)^2+2[/tex]
To determine a, pick a sample point from the table and solve for a. We can use (2, 3). Hence:
[tex](3)=a((2)-1)^2+2[/tex]
Solve for a:
[tex]1=a(1)^2\Rightarrow a=1[/tex]
Hence, our function is:
[tex]f(x)=(x-1)^2+2[/tex]
Evaluate the function when x = 6:
[tex]\displaystyle f(6)=(6-1)^2+2=27[/tex]
So, our two points are (5, 18) and (6, 27).
Again, to find the average rate of change between x= 5 and x = 6, find the slope between their two points. Hence:
[tex]\displaystyle m=\frac{27-18}{6-5}=9[/tex]
Our answer is D.
Two fair dice are tossed and the number on each die is recorded, e.g. (3,2) indicates the first die had 3 and the second die had a 2. In total, there are 36 (equally likely) outcomes in the sample space. What is the probability the sum of the two dice is 7 or 11? Group of answer choices
Answer:
P(7 or 11) = 0.2222
Step-by-step explanation:
First let's find the cases where we get a sum of 7 and a sum of 11:
The cases where we get a sum of 7 are:
(1,6), (2,5), (3,4), (4,3), (5,2), (6,1)
And the cases where we get a sum of 11 are:
(5,6), (6,5)
So we have a total of 8 cases among the 36 total possible outcomes.
So the probability of the sum of the two dice being 7 or 11 is:
P(7 or 11) = 8 / 36 = 0.2222
Show that every triangle formed by the coordinate axes and a tangent line to y = 1/x ( for x > 0)
always has an area of 2 square units.
Hint: Find the equation of the tangent line at x = a. (It will contain a’s as well as x and y.) Then find the
x-and y-intercepts for that line to find the lengths of sides of the right triangle.
Answer:
Step-by-step explanation:
given a point [tex](x_0,y_0)[/tex] the equation of a line with slope m that passes through the given point is
[tex]y-y_0 = m(x-x_0)[/tex] or equivalently
[tex] y = mx+(y_0-mx_0)[/tex].
Recall that a line of the form [tex]y=mx+b [/tex], the y intercept is b and the x intercept is [tex]\frac{-b}{m}[/tex].
So, in our case, the y intercept is [tex](y_0-mx_0)[/tex] and the x intercept is [tex]\frac{mx_0-y_0}{m}[/tex].
In our case, we know that the line is tangent to the graph of 1/x. So consider a point over the graph [tex](x_0,\frac{1}{x_0})[/tex]. Which means that [tex]y_0=\frac{1}{x_0}[/tex]
The slope of the tangent line is given by the derivative of the function evaluated at [tex]x_0[/tex]. Using the properties of derivatives, we get
[tex]y' = \frac{-1}{x^2}[/tex]. So evaluated at [tex]x_0[/tex] we get [tex] m = \frac{-1}{x_0^2}[/tex]
Replacing the values in our previous findings we get that the y intercept is
[tex](y_0-mx_0) = (\frac{1}{x_0}-(\frac{-1}{x_0^2}x_0)) = \frac{2}{x_0}[/tex]
The x intercept is
[tex] \frac{mx_0-y_0}{m} = \frac{\frac{-1}{x_0^2}x_0-\frac{1}{x_0}}{\frac{-1}{x_0^2}} = 2x_0[/tex]
The triangle in consideration has height [tex]\frac{2}{x_0}[/tex] and base [tex]2x_0[/tex]. So the area is
[tex] \frac{1}{2}\frac{2}{x_0}\cdot 2x_0=2[/tex]
So regardless of the point we take on the graph, the area of the triangle is always 2.
A sector of angle 125° is revomed from a thin circular sheet of radius 18cm. it is then folded with straight edges coinciding to form a right circular cone. what are the steps you would use to calculate the base radius, the semi- vertical, and the volume of the cone?
Answer:
Volume of the cone is 1883.7 cm³
Step-by-step explanation:
The circumference of the full circle with radius 18 cm :
360 := 2*π*18 = 36π cm
125 := 125/360 * 36π
The new circumference is maller:
36π - 125/360 * 36π
36π * 0.652(7)
Calculate the new r based on the new circomference:
2*π * r = 36π * 0.652(7)
r = 36π/2π * 0.652(7)
r = 18 * 0.652(7)
r = 11.75 cm
Based on this radius you can calculate the area of the base of the cone.
area base = π*(11.75)²
The Volume V of this cone = 1/3 π r² * h
You can calculate the height h by using Pythagoras theorum.
The sector is the hypothenusa= 18 cm
The h is the height, which is the "unknown"
The r is the new radius = 11.75 cm
s² = r² + h²
h² = s² - r²
h = √(s² - r²)
h = √(18² - 11.75²)
h = 13.6358901432946 cm
h = 13.636 cm
V cone
V = 1/3 π 11.75² * h
V = 1/3 π 11.75² * √(18² - 11.75²)
V = 1/3 π 11.75² * 13.636
V = 1883.7 cm³