which decimal is equal to this fraction​

Answer: 21

Step-by-step explanation:

3x+2+5x+10= 180 (the Angles are supplementary)

8x+12=180

8x=168

x=21

Answer:

388

Step-by-step explanation:

i looked it up

Answer:

i think 18 since 11+7=18

i think this it is not corect 100%100

Answer:

£510

Step-by-step explanation:

Simple interest = (principal × rate × time) / 100

Principal = £1700

Rate = 10%

Time = 3 years

Simple interest = (principal × rate × time) / 100

= (1700 × 10 × 3) / 100

= 51,000/100

= 510

Simple interest = £510

Answer: it will be subtract try all things possible

Step-by-step explanation:

Answer:

Height: 300

Width: 1000

Step-by-step explanation:

All you have to do is look at where the lines start and end on the graph for instance the top is at 0 and the very bottom line is at 300 so that means its 300 feet tall.

Answer:

[tex] \sf8 \: \frac{newspapers}{plie}\: or\: \text{8 newspapers per pile} [/tex]

Step-by-step explanation:

according to the question

Answer:

Solution given:

48 newspaper in 6 pile=48news paper per 6 piles

=48/6=8 news paper per pile

the unit rate of 48 newspapers in 6 piles is 8 news paper per pile

Answer:

The answer is 91.

Step-by-step explanation:

If p = -3, then your equation is 64 + (-9 × -3).

-9 times -3 is 27.

27 + 64 = 91

Answer:

Your number is 3

Step-by-step explanation:

3*3 is 9 and there are no other numbers multiplied by itself to get 9

Answer:

its easy

use this formula

the right one is the solution of question number 1

Step-by-step explanation:

Answer: 2.11 s

Step-by-step explanation:

Given

Equation of rockets height is given by

[tex]\Rightarrow h(t)=-8t^2+16+2[/tex]

Height will be zero once the rocket lands on the ground

So, we can write

[tex]\Rightarrow h(t)=0\ \text{or}\ -8t^2+16t+2=0\\\Rightarrow 8t^2-16t-2=0\\\\\Rightarrow t=\dfrac{16\pm \sqrt{(-16)^2-4(8)(-2)}}{2\times 8}\\\\\Rightarrow t=\dfrac{16\pm \sqrt{320}}{16}\\\\\text{Neglecting negative value of t}\\\\\Rightarrow t=\dfrac{16+17.888}{16}=2.11\ s[/tex]

The rocket of height h(t) and modeled equation [tex]\rm h(t)=-8t^2+16t+2\\[/tex]

was in the air for 2.1 seconds.

The given equation is  [tex]\rm h(t)=-8t^2+16t+2\\[/tex], where h(t) is the rocket's height in meters t seconds after launch.

In algebra, a quadratic equation is an equation that can be written in standard form as

[tex]\rm ax^{2}+bx+c=0}[/tex]

where x represents variable, and a, b, and c represent coefficient.

The given equation is

h(t) = 0

[tex]\rm h(t)=-8t^2+16t+2\\h(t)=-8t^2+16t+2 = 0\\[/tex][tex]\rm h(t)=-8t^2+16t+2\\[/tex]

The roots will be

[tex]\rm {\displaystyle t={\frac {-b\pm {\sqrt {b^{2}-4ac}}}{2a}}.}[/tex]

[tex]\rm {\displaystyle t={\frac {16\pm {\sqrt {(-16)^{2}-4\times 8\times 2}}}{16}}.}\\\rm {\displaystyle t={\frac {16\pm {\sqrt{320} }}{16}}}\\\rm {\displaystyle t={\frac{16+17.88}{16}\\[/tex]

Here, we have neglected the negative value of t

t = 2.1 seconds

So, the rocket of height h(t) and modeled equation [tex]\rm h(t)=-8t^2+16t+2\\[/tex]

was in the air for 2.1 seconds.

Here learn more about quadratic equations here:

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Answer:

I am pretty sure there equivalent

Answer:

B. x ≤ 2.5

Step-by-step explanation:

a and d say 3 which is wrong

either b or c

the filled in dot at the line indicates this is inequality

so its b

Answer:

Your answer would be -2/5

Step-by-step explanation:

The value of the given expression is -2/5.

The given expression is [tex]\sqrt[3]{-\frac{8}{125} }[/tex].

In mathematics, the definition of cube root is written as Cube root is the number that needs to be multiplied three times to get the original number. Now, let us look at the cube root formula, where y is the cube root of x. ∛x = y.

Now, [tex]\sqrt[3]{-\frac{8}{125} }[/tex] can be written as [tex]\sqrt[3]{(-\frac{2}{5})^{3} }[/tex].

Here, cube and cube root will get cancelled.

We get -2/5

Therefore, the value of the given expression is -2/5.

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Answer:

8

Step-by-step explanation:

That's the value for 6- (-2)=8

Answer:

Step 1 and step 2

Step-by-step explanation:

she has to subtract 30 not add 30.

2(3x+6)=3(x-10)

6x + 12 = 3x-30

6x +12 - 12 = 3x - 30 - 12

6x = 3x - 42

6x - 3x = 3x - 42 - 3x

3x = -42

3x/3 = -42/3

x = -14

Answer:

B

Step-by-step explanation:

Hey There!

So the first thing we're going to do is solve it and then compare it to Maya's steps to see where she made the mistake

2(3x+6)=3(x-10)

step 1 distribute the 2 to whats inside of the parenthesis (3x+6)

2*3x=6x

2*6=12

now we have

6x+12=3(x-10)

step 2 distribute 3 to what's inside of the parenthesis

3*x=3x

3*-10=-30

we're left with

6x+12=3x-30

step 3 add 30 to each side

12+30=42

now we have

6x+42=3x

step 4 subtract 6x from each side

3x-6x=-3x

now we have

-3x=42

step 5 divide each side by -3

42/-3=-14

so x = -14

now lets compare our steps to maya's

as we look at the steps we notice that she messes up on step 2

when distributing 3 to -10

she gets positive 30 but its supposed to be -30

so we can conclude that she mad a mistake from step 1 to step 2

therefore the second one is your answer

Answer:

rg+2d= 12

Step-by-step explanation:

(3+5)+2(2)

8+4=12

Answer:

5/6

4/5

6/7

Step-by-step explanation:

Answer:

6 and 7; 1 and 4; 4 and 5

Step-by-step explanation:

a supplementary angle is when two angles added together equal 180 degrees. In other words, if two angles make a straight line when put together, they are supplementary.

8/9 = 0.88...

11/15 = 0.733...

8/9 is bigger

Answer:

8/9 is bigger

Step-by-step explanation:

11/15 equals 0.733333.....

8/9 equals 0.88888.....

Answer:

[tex] \purple {\bold {m\angle PTR=136\degree}} [/tex]

[tex] \orange {\bold {m\angle PQR=68\degree}}[/tex]

Step-by-step explanation:

PS and RS are tangents to the circle with center T at points P and R. (given)

TP and TR are radii of the given circle.

[tex] \therefore PS\perp TP\: \&\: RS\perp TR[/tex]

(radius is perpendicular to the tangent)

[tex] \therefore m\angle TPQ= m\angle TRS =90\degree [/tex]

In quadrilateral SPTR

[tex] m\angle TPQ+ m\angle TRS+m\angle PSR +m\angle PTR=360\degree [/tex]

[tex] 90\degree+ 90\degree+44\degree +m\angle PTR=360\degree [/tex]

[tex] 224\degree +m\angle PTR=360\degree [/tex]

[tex] m\angle PTR=360\degree - 224\degree[/tex]

[tex] \purple {\bold {m\angle PTR=136\degree}} [/tex]

By inscribed angle theorem:

[tex] m\angle PQR=\frac{1}{2} \times m\angle PTR[/tex]

[tex] m\angle PQR=\frac{1}{2} \times 136\degree[/tex]

[tex] \orange {\bold {m\angle PQR=68\degree}}[/tex]

Answer:

I believe it is Option 1

Step-by-step explanation:

Since the fourth root of 81 will be 3 and of 16 will be 2.

Answer:

18?

Step-by-step explanation:

Well uh since it's 2 cakes wouldn't you multiply 9 by 2?

I mean I tried given the little information in the question so

Answer: you need to add the choices

Step-by-step explanation:

Answer:

code lazar

Step-by-step explanation:

Answer:

the answer is: 8(x)= 4 -5

Step-by-step explanation:

The graph of parent function and translated function are given below. Therefore, the transformation is shifted down 5 units.

The given function is g(x)=x-5.

A translation in math moves a shape left or right and/or up or down. The translated shapes look exactly the same size as the original shape, and hence the shapes are congruent to each other. They just have been shifted in one or more directions.

Here, parent function is g(x) = x

To find the transformation, compare the function to the parent function and check to see if there is a horizontal or vertical shift, reflection about the x-axis or y-axis, and if there is a vertical stretch.

Shifted down: 5 units

The graph of parent function and translated function are given below. Therefore, the transformation is shifted down 5 units.

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Answer:

Odel has sold 84 Pizzas and Sam has sold 42

Step-by-step explanation:

:p

Answer:

b. 18

Step-by-step explanation:

b is 18 units because it is reflected across that line, and since MC, equals 18 units, then it would be the same for b

c is yes

Answer:

90 clockwise (or counterclockwise) rotation and then a reflection over the axis between the two shape (those two steps go in any order)

Step-by-step explanation:

for this lets mark the innermost point of each shape a (blue or A) and a' (red or B)* and the second point b and b'

here we see that the two shapes are in a position to where they seem reflected over a non-existent third diagonal axis, though this is not the case, we need to bring the shape into a position where it can be transformed to the quadrant of shape B and overlap the shape

so when you have a reflection over a diagonal axis, we can rotate or reflect the shape to a new quadrant, and perform the step thats not the first, so say we made a reflection over the X-axis, the shape is now in the lower half of the graph with shape B, from here we perform our last step wich is to rotate the shape into the quadrant of shape B in a clockwise motion, now a and a' overlap and b and b' overlap, same for c, c',d and d'

(*the ' in this case is called a prime symbol, when used, distinguishes two points or lines on a graph, A' = A prime)