The climatic change in Earth's history that has resulted in glaciers is the cold climate.
During the last 2.6 million years, the Earth has experienced a series of ice ages, or periods of colder global climate, which have led to the growth of glaciers in regions with sufficient snowfall.
These colder periods are associated with changes in the Earth's orbit, tilt, and precession, which affect the amount and distribution of solar radiation received by the Earth. These climatic changes have had significant impacts on the Earth's surface and have influenced the evolution of life on our planet.
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2 NaN3 → 2 Na + 3 N
Given 9.98 grams of N2, how many moles of NaN3 are produced?
0.238 moles of NaN₃ are produced from 9.98 grams of N₂.
What is the moles of NaN₃ produced?The moles of he mass of NaN₃ produced
The balanced equation for the reaction is:
2 NaN₃ → 2 Na + 3 N₂
The molar ratio between NaN₃ and N₂ is 2:3, which means that for every 2 moles of NaN₃, 3 moles of N₂ are produced.
The mole ratio is used to determine how many moles of NaN₃ are produced from 9.98 grams of N₂.
First, we need to convert the mass of N₂ to moles:
moles of N₂ = mass of N2 / molar mass of N₂
moles of N₂ = 9.98 g / 28.02 g/mol
moles of N₂ = 0.356 mol
moles of NaN₃ = (2/3) * moles of N₂
moles of NaN₃ = (2/3) * 0.356 mol
moles of NaN₃ = 0.238 mol
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Choose the equation below that is balanced correctly.
S8 +24 028 SO3
S8+ 12 0₂8 SO3
6 S8+8 026 SO3
2 S8 +3 022 SO3
The balanced equation for the reaction between sulfur (S₈) and oxygen (O₂) to form sulfur trioxide (SO₃) is 2S₈ + 16O₂ → 16SO₃.
What is the balanced chemical equation?Balancing chemical equations involves the addition of stoichiometric coefficients to the reactants and products.
The balanced equation for the reaction between sulfur (S₈) and oxygen (O₂) to form sulfur trioxide (SO₃) is determined as;
2S₈ + 16O₂ → 16SO₃
From the reactants side we can see that sulfur is 16 and also 16 in the product side. The number of oxygen in the reactant side is 32 and also 32 in the product side.
Thus, the balanced equation for the reaction between sulfur (S₈) and oxygen (O₂) to form sulfur trioxide (SO₃) is 2S₈ + 16O₂ → 16SO₃.
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Which number is the same as 2.5
10-3?
The number that is the same as the exponentiation given as follows: 2.5 × 10-³ is 0.0025.
What is exponentiation?Exponentiation is the process of calculating a power by multiplying together a number of equal factors, where the exponent specifies the number of factors to multiply.
For example, if 10 is multiplied three times, then it can be written as "10 raised to 3" which means 10³. In this case, 10 is the base, and 3 is the exponent.
Therefore, a number 0.0025 can be written in exponentiation as 2.5 × 10-³ by counting the number of zeros forward.
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what is the complex equation for copper sulfate and sodium hydroxide reaction?
Cuso4 + NaoH -》cu(oH)2 +Na2So4
Cuso4 + 2NaoH -》cu(oH)2 +Na2So4
Explanation:
this is balanced equation
Does anyone know the answer to this question
Answer:
A
Explanation:
If Hydrogen is H₂ There will be two silver
and is Carbon is C There will only be one gray
and if Oxygen is O₃ There will be three red
An ideal gas (which is is a hypothetical gas that conforms to the laws governing gas behavior) confined to a container with a massless piston at the top. (Figure 2) A massless wire is attached to the piston. When an external pressure of 2.00 atm
is applied to the wire, the gas compresses from 4.40 to 2.20 L. When the external pressure is increased to 2.50 atm , the gas further compresses from 2.20 to 1.76 L .
In a separate experiment with the same initial conditions, a pressure of 2.50 atm
was applied to the ideal gas, decreasing its volume from 4.40 to 1.76 L
in one step.
If the final temperature was the same for both processes, what is the difference between q for the two-step process and q for the one-step process in joules?
The difference between q for the two-step process and q for the one-step process is 220.38 joules.
To solve this problem, we use the first law of thermodynamics, which states that change in internal energy (ΔU) of system will be equal to the heat (q) added or removed from the system, minus the work (w) done by or on the system;
[tex]Δ_{U}[/tex] = q - w
For an ideal gas, the internal energy depends only on the temperature, so [tex]Δ_{U}[/tex] is zero if the final temperature is the same for both processes. Therefore, we can set [tex]Δ_{U}[/tex] to zero and solve for the difference in heat (q) between the two processes;
q(two-step) - q(one-step) = w(two-step) - w(one-step)
The work done by or on the gas can be calculated using the equation;
w = -P[tex]Δ_{V}[/tex]
where P is the external pressure, and [tex]Δ_{U}[/tex] is the change in volume. The negative sign indicates that work is done on the gas when it is compressed ([tex]Δ_{U}[/tex] < 0), and work is done by the gas when it expands ([tex]Δ_{U}[/tex] > 0).
For the two-step process, we can calculate the work done in two stages;
w(two-step) = -2.00 atm × (4.40 L - 2.20 L) - 2.50 atm × (2.20 L - 1.76 L)
= -3.32 atm L - 0.605 atm L
= -3.925 atm L
For the one-step process, we can calculate the work done in one step;
w(one-step) = -2.50 atm × (4.40 L - 1.76 L)
= -6.10 atm L
Substituting these values into the equation for the difference in heat, we get;
q(two-step) - q(one-step) = -3.925 atm L - (-6.10 atm L)
= 2.175 atm L
To convert this to joules, we need to multiply by the conversion factor for atm L to joules;
1 atm L = 101.3 J
Therefore; q(two-step) - q(one-step) = 2.175 atm L × 101.3 J/atm L
= 220.38 J
Therefore, the difference in heat between the two processes is 220.38 joules.
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What is the final temperature when 625 grams of water at 75.0 deg C loses 7.96 x 10^4 J? (hint: remember ΔT = Tfinal - Tinitial )
The final temperature of the water is 71.99°C.
The final temperature when 625 grams of water at 75.0°C loses 7.96 x 10⁴ J can be found using the specific heat capacity equation:
q = mcΔT
where q is the amount of heat transferred, m is the mass of the substance, c is the specific heat capacity, and ΔT is the change in temperature.
First, we need to determine the specific heat capacity of water, which is 4.18 J/g°C. Then we can rearrange the equation to solve for ΔT:
ΔT = q / (mc)
Substituting the given values, we get:
ΔT = (7.96 x 10⁴ J) / (625 g x 4.18 J/g°C)
ΔT = 3.01°C
Therefore, the final temperature is:
Tfinal = Tinitial - ΔT
Tfinal = 75.0°C - 3.01°C
Tfinal = 71.99°C
As a result, the water's ultimate temperature is 71.99°C.
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What sample at STP has the same number of molecules as 5 L of NO2
Answer:
5l NO
2
at STP
No. of molecules=
22.4
5
mol=
22.4
5
×N
A
molecules
A) 5ℊ of H
2
(g)
No. of moles=
2
5
mol=
2
5
×N
A
molecules
B) 5l of CH
4
(g)
No. of moles of CH
4
=
22.4
5
mol=
22.4
5
N
A
molecules
C) 5 mol of O
2
=5N
A
O
2
molecules
D) 5×10
23
molecules of CO
2
(g)
Molecules of 5l NO
2
(g) at STP=5l of CH
4
(g) molecules at STP
Therefore, option B is correct.
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2
Select the correct answer.
Which phrase best describes heat?
OA.
B.
OC.
D.
the energy that an object has as a result of its temperature
the average translational kinetic energy of the particles in an object
the energy transferred between objects at different temperatures
the total amount of energy possessed by the particles in an object
Heat is most accurately described as "the energy transferred between objects at different temperatures" (C). Until they reach thermal equilibrium, or the same temperature, heat is a type of energy that flows freely from a hotter to a colder item.
Heat can be transferred through conduction, convection, or radiation. The temperature differential between the items and the thermal conductivity of the materials involved determine how much heat is transported.
Temperature, a measurement of the average kinetic energy of the particles in an item, is not the same as heat. Internal energy is the entire amount of energy held by an object's particles, which includes both their kinetic and potential energies.
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