Answer:
H 4so8 is the answer of balance the reaction
Based on a specific example of titration method. How do titration methods play a role in agriculture industry?
Answer:
Titration is an analytical technique that is widely used in the food industry. It allows food manufacturers to determine the quantity of a reactant in a sample. For example, it can be used to discover the amount of salt or sugar in a product or the concentration of vitamin C or E, which has an effect on product colour.
Answer:
How is titration used in the industry?
Titration is an analytical technique that is widely used in the food industry. It allows food manufacturers to determine the quantity of a reactant in a sample. For example, it can be used to discover the amount of salt or sugar in a product or the concentration of vitamin C or E, which has an effect on product colour.
Which of these statements are true? Select all that apply.
The AH+ for Br2() is 0 kJ/mol.
The AH; for Hel) is 0 kJ/mol.
The AH+ for Hg() is 0 kJ/mol.
The AHp for Cl2(g) is 0 kJ/mol.
The AH; for N261) is 0 kJ/mol.
Answer:
The AH+ for Br2() is 0 kJ/mol.
The AH+ for Hg() is 0 kJ/mol.
The AH; for N261) is 0 kJ/mol.
Explanation:
The statements 1,3,4 and 5 are true.
What is meant by enthalpy ?Enthalpy is defined as a thermodynamic quantity, which can be considered equal to the total heat of the system.
Here,
1) The enthalpy of formation of Br₂ (cr, l) is 0 kJ/mol.
So, the statement is true.
2) The enthalpy of formation of He(l) is not zero.
So, the statement is false.
3) The enthalpy of formation of Hg(l) is 0 kJ/mol.
So, the statement is true.
4) The enthalpy of formation of Cl₂(g) is 0 kJ/mol.
So, the statement is true.
5) The enthalpy of formation of N₂ is 0 kJ/mol.
So, the statement is true.
Hence,
The statements 1,3,4 and 5 are true.
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A metal, M, forms an oxide having the formula MO2 containing 59.93% metal by mass. Determine the atomic weight in g/mole of the metal (M). Please provide your answer in 2 decimal places.
a. How many moles of oxygen atoms are found in 4.00 g of O2?
b. How many atoms of hydrogen are found in 0.400 mol of H2S?
c. How many hydrogen atomsare present in 0.235 g of NH3?
Answer:
See solution.
Explanation:
Hello there!
In this case, according to the given information, it turns out possible for us to set up the formula for the calculation of the by-mass percentage of the metal:
[tex]\% M=\frac{m_M}{m_M+2*m_O}*100 \%\\\\59.93\% =\frac{m_M}{m_M+32.00}*100 \%[/tex]
Thus, we solve for the molar mass of the metal to obtain:
[tex]59.93\% (m_M+32.00) =m_M*100 \%\\\\m_M*59.93\% +1917.76\% =m_M*100 \%\\\\m_M=47.86g/mol[/tex]
For the subsequent problems, we proceed as follows:
a.
[tex]4.00gO_2*\frac{1molO_2}{32.00gO_2}=0.125molO_2[/tex]
b.
[tex]0.400molH_2S*\frac{2molH}{1molH_2S}*\frac{6.022x10^{23}atomsH}{1molH}=4.82x10^{23}atomsH[/tex]
c.
[tex]0.235gNH_3*\frac{1molNH_3}{17.03gNH_3} *\frac{3molH}{1molNH_3}*\frac{6.022x10^{23}atomsH}{1molH}=2.49x10^{22}atomsH[/tex]
Regards!
Calculate the lattice energy of CuBr(s) using a Born–Haber cycle.
Data:
Enthalpy of sublimation of Cu(s) = 337.7 kJ/mol
1st ionization energy of Cu(g) = 745 kJ/mol
Enthalpy of vaporization of Br2(l) = 29.96 kJ/mol
Two 10 L glass flasks are evacuated and sealed. 35.0 of Liquid A are injected through the seal into one flask, and 35.0 mL of Liquid B are injected into the other flask. After 30 minutes, the pressures PA and inside the flasks are measured.
a. PA will be greater than
b. PA will be less than PB
c. PA will be equal to PB
d. It's impossible to predict whether PA or will be greater without more information.
The question is incomplete, the complete question is:
Liquid A is known to have a lower viscosity and lower vapor pressure than Liquid B. Two 10 L glass flasks are evacuated and sealed. 35.0 of Liquid A are injected through the seal into one flask, and 35.0 mL of Liquid B are injected into the other flask. After 30 minutes, the pressures [tex]p_A[/tex] and [tex]p_B[/tex] inside the flasks are measured.
a. [tex]p_A[/tex] will be greater than
b. [tex]p_A[/tex] will be less than [tex]p_B[/tex]
c. [tex]p_A[/tex] will be equal to [tex]p_B[/tex]
d. It's impossible to predict whether [tex]p_A[/tex] or will be greater without more information.
Answer: The correct option is b) [tex]p_A[/tex] will be less than [tex]p_B[/tex]
Explanation:
Vapor pressure is defined as the equilibrium pressure which is exerted by the vapor phase to be in thermodynamic equilibrium with its condensed state (liquid phase) in a closed system at a given temperature.
We are given:
Vapor pressure of A < Vapor pressure of B
This means that a lesser number of gaseous molecules will form over its surface and thus, will experience lower pressure.
Thus, [tex]p_A<p_B[/tex]
Hence, the correct option is b) [tex]p_A[/tex] will be less than [tex]p_B[/tex]
11. Which of these conditions would decrease the rate of photosynthesis in a plant?
A. above average precipitation
B. Changing the daylight hours from 14 hrs to 10 hrs
C. Changing the CO2 concentration from 380 ppm to 410 ppm
D. All of these choices
Answer:
B. Changing the daylight hours from 14 hrs to 10 hrs
Explanation:
The ideal gas law is PV = nRT.
Use 8.31 for R. (8.31 Lx kPa / Kx mol)
What is the temperature of 3.0 moles of a gas that is in a closed container of
volume 9L, and has a pressure of 85kPa?
1. 3.4 kelvin
2. 0.03 kelvin
3. 30.7 kelvin
4. 28.6 kelvin
Answer: 30.66945 kelvin
Explanation:
PLEASE HELP ME SOLVE THIS.Thank you so much!
Answer: The coefficients for the given reaction species are 1, 6, 2, 3.
Explanation:
The given reaction equation is as follows.
[tex]Cr_{2}O^{2-}_{7} + Cl^{-} \rightarrow Cr^{3+} + Cl_{2}[/tex]
Now, the two half-reactions can be written as follows.
Reduction half-reaction: [tex]Cr_{2}O^{2-}_{7} + 3e^{-} \rightarrow Cr^{3+}[/tex]
This will be balanced as follows.
[tex]Cr_{2}O^{2-}_{7} + 14H^{+} + 6e^{-} \rightarrow 2Cr^{3+} + 7H_{2}O[/tex] ... (1)
Oxidation half-reaction: [tex]Cl^{-} \rightarrow Cl_{2} + 1e^{-}[/tex]
This will be balanced as follows.
[tex]6Cl^{-} \rightarrow 3Cl_{2} + 6e^{-}[/tex] ... (2)
Adding both equation (1) and (2) we will get the resulting equation as follows.
[tex]Cr_{2}O^{2-}_{7} + 14H^{+} + 6Cl^{-} \rightarrow 2Cr^{3+} + 3Cl_{2} + 7H_{2}O[/tex]
Thus, we can conclude that coefficients for the given reaction species are 1, 6, 2, 3.
Explain the science of water pressure
"At sea level, the air that surrounds us presses down on our bodies at 14.7 pounds per square inch . (gooxgle) "
Basically the deeper you go under the water, whether that be a pool or the sea the pressure will increase because of the weight of the water above you. Which causes greater force.
How many grams of oxygen are present in 93.98 g of CO2?
Answer:
There are about 68.33 grams of oxygen present in 93.98 g of CO2.
PLS HELP ME PLZ AND THANKS
Answer:
q6= third option
q7= third option
Explanation:
kinetic molecular theory deals with temperature
pressure inversely proportional to volume so when volume doubled, pressure halved given that mass and temperature constant
Two hundred forty-eight milliliters of an acid with an unknown concentration are titrated with a base that has a
concentration of 1.4 M. The indicator changed color when 82 milliliters of base were added. What is the concentration of
the unknown acid?
O 0.46 M
4.2 M
Answer:0.46
Explanation:
Which sequence contains elements listed from most reactive
to least reactive?
Answer:
Transition metals, alkali metals, alkaline earth metals Transition metals - Middle of the periodic chart, only average reactivity. alkali metals - As mentioned above, very reactive. Bad choice, going from lower reactivity to higher reactivity.
Hope this answer is right!
If a light beam strikes a shiny object at a 90-degree angle, to what are the angle of incidence and the angle of reflection equal?
Answer:
Angle of incidence = angle of reflection = 0
Explanation:
Given that,
A light beam strikes a shiny object at a 90-degree angle.
The angle made by incident ray and normal to the mirror is called the angle of incidence and the angle made by the reflected ray and the normal is called the angle of reflection.
Here, the beam strikes normally. So, the angle of incidence is 0.
A/c to the law of reflection,
Angle of incidence = angle of reflection
So, the angle of reflection is also equal to 0.
g Calculate the moles of methanol in a first distillate that has a total volume of 0.5 mL and contains 23.4% methanol. The density of methanol is 0.791 g/mL, and the molar weight of methanol is 32.04 g/mol. 2.9 x10-3 mol Methanol 9.3 x10-3 mol Methanol 1.17 x 10-2 mol Methanol None of the above
Answer:
2.9 × 10⁻³ mol
Explanation:
Step 1: Calculate the volume of methanol
0.5 mL of distillate contains 23.4% methanol.
0.5 mL × 23.4% = 0.117 mL
Step 2: Calculate the mass corresponding to 0.117 mL of methanol
The density of methanol is 0.791 g/mL.
0.117 mL × 0.791 g/mL = 0.0925 g
Step 3: Calculate the moles corresponding to 0.0925 g of methanol
The molar weight of methanol is 32.04 g/mol.
0.0925 g × 1 mol/32.04 g ≈ 2.9 × 10⁻³ mol
Which compounds, on heating with an excess of concentrated sulfuric acid, produce only one product with molecular formula C7H10? [choices on the picture]
Answer:
1 and 2
Explanation:
When Concentrated H2SO4 reacted with the alcohols, they produce cycloalkenes. This is a mechanism known as dehydration of alcohols with an acid catalyst. This is because concentrated H2SO4 acts as a great oxidizing agent. In the process, the alcohols are heated to a high temperature with an excess of pure sulfuric acid. By passing the gases through a sodium hydroxide solution, the carbon dioxide and sulfur dioxide produced by reactive species are eliminated. The reaction mechanism shown in the image below indicates that only compounds 1 and 2 produce only one product.
What volume of water must be added to 10.5 mL of a pH 2.0 solution of HNO3 in order to change the pH to 4.0 g
Answer:
[tex]V'=1040ml[/tex]
Explanation:
From the question we are told that:
Initial Volume [tex]V_1=10.5mL[/tex]
Initial Aciditity of [tex]HN0_3 pH_1=2.0g[/tex]
Finial Aciditity of [tex]HN0_3 pH_2=4.0g[/tex]
Generally the equation for Acidity &Volume Relationship is mathematically given by
[tex]N_1V_1=N_2V_2[/tex]
Therefore
[tex]V_2=\frac{N_1V_2}{N_2}[/tex]
[tex]V_2=\frac{10^{-2}*10.5}{10^{-4}}V_2=1050ml[/tex]
Therefore
Change in Water volume is
[tex]V'=V_2-V_1[/tex]
[tex]V'=1050ml-10ml[/tex]
[tex]V'=1040ml[/tex]
3 enzimas presentes en nuestro organismo e indique en que procesos actúan
Answer:
ATP asa, Helicasa, Proteasa, ARN polimerasa
Explanation:
Las enzimas son un tipo de biomoleculas que se corresponden con las proteinas.
Al momento de referirse a ellas, se utiliza la terminación asa.
ATPasa → Sintetizando ATP para el funcionamiento celular
Helicasa → Abre las hebras de ADN permitiendo el paso de la horquilla para el proceso de replicación de ADN.
Proteasas → Enzimas que degradan proteinas mal plegadas, rompen los enlaces peptídicos.
ARN polimerasa → Sintesis de ARN mensajero a partir de ADN en el proceso de la Transcripción. Se la puede conocer a veces, como primasa.
Suppose 0.879 g of ammonia reacts with 28.5 mL of a hypobromite solution. Calculate the concentration of the hypobromite solution.
Answer:
0.877 M
Explanation:
Number of moles of ammonia = 0.879 g /17 g/mol = 0.05 moles
The reaction equation is ;
2NH3 + OBr-→ N2H4 + Br- + H2O
2 moles of NH3 reacts with 1 mole of hypobromite
0.05 moles of NH3 reacts with 0.05 moles ×1 mole/2 moles
= 0.025 moles
Number of moles = concentration × volume
Concentration = Number of moles / volume
Concentration = 0.025 moles × 1000/28.5
Concentration = 0.877 M
Given that vat contains 9600 kg of milk, what is the mass of mg of the milk that vat contains?
Answer:
9.6x10⁹ mg
Explanation:
In order to solve this problem we need to convert 9600 kg into mg.
First we convert 9600 kg into g, keeping in mind that 1 kg = 1000 g:
9600 kg * [tex]\frac{1000g}{1kg}[/tex] = 9.6x10⁶ g
Then we convert 9.6x10⁶ g into mg, keeping in mind that 1 g = 1000 mg:
9.6x10⁶ g * [tex]\frac{1000mg}{1g}[/tex] = 9.6x10⁹ mg
The mass of milk miligrams is 9.6x10⁹.
what is the formula for trioxocarbonate (IV)
Answer:
[tex]CO_3^{2-}[/tex]
Explanation:
Trioxocarbonate (iv) salts result from the reaction of trioxocarbonate(iv) acid with metals and metal oxides.
All sodium, potassium, and ammonium of trioxocarbonate(iv) salts appearas to be soluble, while all others are insoluble.
Apart from Na and K, all trioxocarbonate (iv) salts breakdown to release CO2 when heated.
The formula for Trioxocarbonate (iv) is: [tex]CO_3^{2-}[/tex]
So, we can have Sodium trioxocarbonate as [tex]Na_2CO_3[/tex] and sodium hydrogen trioxocarbonate (iv) [tex]NaHCO_3[/tex]
Suppose that you add 21.0 g of an unknown molecular compound to 0.250 kg of benzene, which has a K f of 5.12 oC/m. With the added solute, you find that there is a freezing point depression of 2.58 oC compared to pure benzene. What is the molar mass (in g/mol) of the unknown compound
Enter the molecular formula for butane, C4H10
Answer:
C4H10
Explanation:
you already written it :)
The atomic particle with a charge of -1.6 x 10-19 C is
no sefdrcdftrgfkjj jhhhgfd
If a swimming pool contains 2850 kg liters of water how many gallons of water does it contain
Which bodies of water in the list are found to the west of the Philippines?
Answer:
South China sea
Explanation:
To the west is the South China Sea, to the east the Philippine Sea and the Pacific Ocean, and to the south the Celebes Sea (or Sulawesi Sea).
Select the correct answer.
Which value of Keq represents a scenario where the reactants of an equilibrium reaction are favored?
A.
Keq=1
B.
Keq = 6.0 x 10-2
O C.
Keq = 3.8 x 104
OD
Keq = 490.5
O E. Keq = 2.5
Answer:
B. Keq = 6.0 x 10-2.
Explanation:
Hello there!
In this case, according to the given information, it turns out possible for us to remember that any equilibrium constant is computed by dividing the concentration of products by that of reactants:
[tex]Keq=\frac{[Prod]}{[Reac]}[/tex]
Thus, a reaction that is reactant-favored will have a Keq>1 because the concentration of reactants prevail over that of products at equilibrium, and thus, the correct answer is B. Keq = 6.0 x 10-2.
Regards!
first law of the thermodynamic indicates.?
Answer:
The first law of thermodynamics states that energy can neither be created nor destroyed, only altered in form. For any system, energy transfer is associated with mass crossing the control boundary, external work, or heat transfer across the boundary. These produce a change of stored energy within the control volume.
Explanation:
Calculate the pKa of hypochlorous acid (HClO, a weak acid). A 0.015 M solution of hypochlorous acid has a pH of 4.64.
Answer:
"7.46" is the correct answer.
Explanation:
Given that:
[tex]pH=4.64[/tex]
[tex]C=0.015 \ M[/tex]
The equation:
⇒ [tex]HA \rightleftharpoons H^++A^-[/tex]
HA = C - Cα
H⁺ = Cα
A⁻ = Cα
now,
⇒ [tex]pH=-log(H^+)[/tex]
[tex]=-log(C \alpha)[/tex]
[tex]=4.64[/tex]
[tex]C \alpha = 2.3\times 10^-5 \ M[/tex]
As we know,
⇒ [tex]K_a=C \alpha^2[/tex]
[tex]=(\frac{C \alpha}{C} )^2\times C[/tex]
[tex]=\frac{(2.3\times 10^{-5})^2}{0.015}[/tex]
[tex]=3.5\times 10^{-8}[/tex]
hence,
⇒ [tex]pK_a=-log(K_a)[/tex]
[tex]=7.46[/tex]
Arrange the following aqueous solutions in order from smallest to greatest freezing point depression: 0.400 m CaCl2, 0.400 m glucose or 0.400 m NaCl, Then determine the freezing point depression for each. For water, Kf = 1.86°C/m.
Answer:
glucose<NaCl<CaCl2
Explanation:
Hello there!
In this case, since the general equation for the calculation of the freezing point depression is:
[tex]\Delta T=-i*m*Kf[/tex]
Whereas m and Kf are the same for the given salts, then we conclude that the greatest freezing point is exhibited by the salt with the greatest Van't Hoff's factor and the smallest freezing point with the smallest Van't Hoff's factor. In such a way, since this factor is equal to the number of ionized species, we infer that CaCl2 has i=3, glucose i=1 (nonionizing) and NaCl i=2; therefore, the order from smallest to greatest is:
glucose<NaCl<CaCl2
Regards!