Biology College

Which activity involves a chemical change?
A. Ice melting into liquid water
B. A metal rod being bent into a ring
C. Colorless egg becoming a white solid
D. Salt dissolving in water
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Answers

Answer 1

option C is correct........

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Related Questions

Specialized cells such as white blood cells interact with foreign particles in the body. A particular cell belonging to this category recognizes bacteria and forms a covering around it, pinching off the vacuole. The cell then performs . The foreign particles recognized by the particular type of cells differ from the ones recognized by another type of white blood cell. This situation indicates that the receptors are .

Answers

Answer:

specific

Explanation:

The immune system contains different types of cells that act in both innate and acquired (adaptive) immune responses to destroy pathogenic microorganisms that invade our body. The immune cells include B and T cells, dendritic cells, macrophages, neutrophils, eosinophils, monocytes, etc. These cells contain specific receptors that play different roles in the immune response. For example, macrophages and dendritic cells contain receptors required for antigen presentation, while white blood cells (B and T cells) have receptors required for antigen recognition.

Answer: I just took the test

Explanation:

Here's the answer

150 ml of 54% CaCI2 solution contains how many grams of CaCI2?

Answers

Answer:

mass of CaCl₂ = 67.4 g of CaCl₂

Explanation:

A 45% CaCl₂ Solution contains 45 g of solute per 100 mL of solution.

mass concentration = mass of solute (g)/ volume of solution (L)

100 mL of solution = 100 * 1L /1000 = 0.1 L

Mass concentration of solution = 45 g/0.1 L = 450 g/L

Molar concentration of solution = mass concentration / molar mass

molar mass of CaCl₂  = 111 g/mol

molar concentration = 450 g/L / 111 g/mol = 4. 05 mol/L

Number of moles of CaCl₂ present in 150 ml of 4.05 mol/L  solution = molar concentration *  volume (L)

number of moles of CaCl₂  = 4.05 * 150 * 1 L/1000 = 0.6075 moles

mass of CaCl₂  present in 0.6075 moles  = number of moles * molar mass

mass of CaCl₂ = 0.6075 * 111 = 67.4 g of CaCl₂

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