where do you see symbols that are smarter, symbols that are way more sophisticated, more complex?

A code of ethics is important because it clearly lays out the rules for behavior and provides the groundwork for a preemptive warning. While a code of ethics is often not required, many firms and organizations choose to have one.

Under the Spoils System, appointments were completely based on party loyalty and activity.

What is the spoil system?

The spoil system is a political party's habit of offering its supporters government jobs after winning an election as payback for their support and as a clever way to keep doing so.

Appointees under the Spoils System were required to actively participate in political activities in favor of their patron, and appointments were solely based on party allegiance and participation. In actuality, appointees were elected politicians' cronies.

Therefore, Appointments were solely determined by party loyalty and action under the Spoils System.

To learn more about the spoil system, refer to the link:

https://brainly.com/question/28780678

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Option 1! “Wait to speak until others are finished with their thoughts”

Answer:A

Explanation:

i took the test

This problem is asking for the probability that less than 220 out of 250 cars sold have air-conditioning, given that the dealer states that 90% of all automobiles sold have air-conditioning. To solve this, we can use the binomial probability formula and a binomial distribution table. The formula is P(x) = (n choose x) * p^x * (1-p)^(n-x), where n is the total number of cars sold, x is the number of cars with air-conditioning, p is the probability of a car having air-conditioning (0.9 in this case), and (n choose x) is the binomial coefficient. We can use a binomial distribution table to find the probability that less than 220 cars have air-conditioning, which is the sum of the probabilities for x = 0, 1, 2, ..., 219.
For this problem, we know that the electric bills are normally distributed with a mean of $72 and a standard deviation of $6. We are asked to find the probability that the mean of the bills for 15 randomly selected residents will be more than $75. This problem is asking for the probability of a sample mean, which is a type of statistical inference. To solve this, we can use the z-score formula, z = (x - mu) / (sigma / sqrt(n)), where x is the sample mean, mu is the population mean, sigma is the population standard deviation, and n is the sample size. We can use this formula to find the z-score corresponding to a sample mean of $75, and then use a standard normal distribution table to find the probability that a z-score is greater than this value.
For this problem, we know that the purchases at the Train Station hobby shop are normally distributed with a mean of $12.50 and a standard deviation of $2.50. We are asked to find the probability that the mean of a random sample of 40 purchases is between $12.50 and $13.00. This problem is asking for the probability of a sample mean, which is a type of statistical inference. To solve this, we can use the Central Limit Theorem which states that the mean of a sample of size n, taken from a population with mean mu and standard deviation sigma, will be approximately normally distributed with mean mu and standard deviation sigma/sqrt(n). Using this theorem, we can find the standard deviation of the sample mean, which is sigma/sqrt(n) = $2.5/sqrt(40) = $0.3125. We can use this standard deviation and the sample mean to find the z-score that corresponds to the sample mean of $13.00, and then use a standard normal distribution table to find the probability that a z-score is between this value and the z-score that corresponds to the sample mean of $12.50.
For this problem, we know that 30% of the employees choose to enroll in a financial investment program offered by the company. We are asked to find the probability that of 800 randomly selected employees at least 28% have enrolled in the program. This problem is asking for the probability of a sample proportion, which is a type of statistical inference. To solve this, we can use the normal approximation to the binomial distribution, which states that if np and n(1-p) are both greater than or equal to 5, then the sample proportion will be approximately normally distributed with mean p and standard deviation sqrt(p*(1-p)/n). Using this approximation, we can find the standard deviation of the sample proportion, which is sqrt(0.3 * (1 - 0.3) / 800) = 0.0158. We can use this standard deviation and the sample proportion to find the z-score that corresponds to 28%, and then use a standard normal distribution table to find the probability that a z-score is greater than this value.

For this problem, we know that the lifetime of a particular brand of toasters are normally distributed with an average lifetime of 14 months, with a standard deviation of 4 months. If 20 toasters are selected at random, find the probability that the mean lifetime of the sample will be less than 1 year (12 months). This problem is asking for the probability of a sample mean, which is a type of statistical inference. To solve this, we can use the Central Limit Theorem as we did in the third question. Using this theorem, we can find the standard deviation of the sample mean, which is sigma/sqrt(n) = 4/sqrt(20) = 0.8. We can use this standard deviation and the sample mean to find the z-score that corresponds to the sample mean of 12 and then use a standard normal distribution table to find the probability that a z-score is less than this value.