Answer:
As the ball falls from C to E, potential energy is converted to kinetic energy. The velocity of the ball increases as it falls, which means that the ball attains its greatest velocity, and thus its greatest kinetic energy
Explanation:
Answer:As the ball falls from C to E, potential energy is converted to kinetic energy. The velocity of the ball increases as it falls, which means that the ball attains its greatest velocity, and thus its greatest kinetic energy
Explanation:
Explain gravitational implicit energy in terms of work done against graveness.Show how knowledge of the implicit energy as a function of position can be used to simplify computations and explain physical marvels. Show that the gravitational potential energy of an object of mass m at height h on Earth is given by PEg=mgh.When a radio is playing in the room next door, which sound waves can be heard best?
(Please it’s due by 11 p.m)
Answer:
low sound waves like bass pass through walls better
Explanation:
A body weighing 250 grams was dropped from a helicopter flying at an altitude of 100 meters. Determine the potential energy of this body. (g = 10 m/s² ). PLEASE HURRY ITS A TEST
[tex]\huge{ \mathfrak{ \underline{question : }}}[/tex]
A body weighing 250 grams was dropped from a helicopter flying at an altitude of 100 meters. Determine the potential energy of this body.
[tex] \huge{ \mathfrak{given : }}[/tex]
mass = [tex] 0.250 kg[/tex]acceleration = [tex] 10 m/s^2 [/tex]height = [tex] 100 m [/tex][tex]\huge{ \mathfrak{ \underline{ Answer \: \: ✓ }}}[/tex]
[tex] \boxed{ \mathbf{potential \: \: energy = mgh}}[/tex]
[tex] 0.250 \times 10 \times 100[/tex][tex] {250}{} [/tex]potential energy = 250 joules
[tex] \#TeeNForeveR[/tex]
Could anyone help me on this question?
You really don't need any help on the question. It's all right there in the picture. What you need help with is the answer.
The number of times the same thing happens each second is called its "frequency". The frequency of the dragonfly's flaps is 477 Hz. (If you're close enough to the dragonfly, you can hear the wings flapping. It sounds like a raspy tone with a frequency of 477 Hz.)
The "period" is just the length of time it takes to happen once. That length of time is just (1 / frequency) .
The dragonfly flaps its wings once every (1 / 477 Hz) = 0.0021 second (C)
In an old Sesame Street skit, Kermit the Frog interviewed a local resident on the planet Koozebane, who measures time in gleeps and distance in glorps. One glorp is defined as the distance a rock will fall from rest in one gleep. How far will a rock fall from rest during the second gleep
Answer:
four glorps
Explanation:
We know :
[tex]$y=v_{0y}t + \frac{1}{2}a_yt^2$[/tex]
[tex]$\Rightarrow -1 \text{glorp} = 0 - \frac{g}{2} \times (1 g\text{ gleep})^2$[/tex]
[tex]$\Rightarrow 1 \text{ glorp}= \frac{g}{2} (1 \text{ gleep})^2$[/tex] .............(i)
Now, t' = 2 gleep
[tex]$y=v_{0y}t + \frac{1}{2}a_yt^2$[/tex]
[tex]$=0+ \frac{-g}{2} (2 \text{ gleep})^2$[/tex]
[tex]$=-\frac{4g}{2}(2 \text{ gleep})^2$[/tex]
[tex]$=4\left[\frac{-g}{2} (\text{gleep})^2\right]$[/tex]
= 4 (-1 gleep) (From (i))
So, |y| = 4 glorp
What is Hooke's law? what is meant by elastic limit?
please answer me
Answer:
Hooke's law describes the elastic properties of materials only in the range in which the force and displacement are proportional. Hooke's law states that the applied force F equals a constant k times the displacement or change in length x, or F = kx. the maximum extent to which a solid may be stretched without permanent alteration of size or shape, is called elastic limit
mark me brainliestt :))
You purchased 1.9 kg of apples from Wollaston. You noticed that they used a spring scale with the smallest division of 2.1 g to weigh them. What is the relative error in this weight measurement as a percentage
The relative error in this weight measurement as percentage is
[tex]0.1105\%[/tex]What is relative error?is the ratio of the absolute error of a measurement to the measurement being taken. In other words, this type of error is relative to the size of the item being measured.
Therefore,
[tex]\% relative error = \frac{smallest division}{mass of apples}*100\\\\\% relative error = \frac{2.1g}{1900}*100\\\\\% relative error = 0.1105\%[/tex]
For more information on relative error, visit
https://brainly.com/question/64815
Answer:
The relative error in this weight measurement is approximately 0.1105 %.
Explanation:
We know that,
Relative Error is the ratio of the absolute error of a measurement to the actual measurement . It can be mathematically represented as,
Relative Error = (Measured Value - Actual Value) / Actual Value * 100
In this case, the actual weight is 1.9 kg, and the smallest division of the spring scale is 2.1 g.
Actual Weight = 1.9 * 1000 = 1900 (As 1 kg = 1000g)
We know that the absolute error will be equal to the smallest division hence,
Measured Value - Actual Value = 2.1 g
By replacing this in the general formula we get,
Relative Error = (Measured Value - Actual Value) / Actual Value * 100
= [tex]\frac{2.1}{1900} *100[/tex] %
= [tex]\frac{2.1}{19}[/tex] %
≈ 0.1105 %
Therefore, the relative error in this weight measurement is approximately 0.1105 %.
For more information on relative error, visit
brainly.com/question/64815
A bell is ringing inside of a sealed glass jar that is connected to a vacuum pump. Initially, the jar is filled with air. What does one hear as the air is slowly removed from the jar by the pump
Answer:
See Explanation
Explanation:
Sound is a mechanical wave. A mechanical wave requires a material medium for propagation. This means that sound waves must be carried in air. If there are no air molecules, sound waves can not travel.
When air is gradually removed from the jar by the pump, the sound intensity from the bell gradually decreases owing to the fact that air which is the medium through which sound waves are propagated is gradually being removed from the jar.
Two parallel slits are illuminated by light composed of two wavelengths, one of which is 657 nm. On a viewing screen, the light whose wavelength is known produces its third dark fringe at the same place where the light whose wavelength is unknown produces its fourth-order bright fringe. The fringes are counted relative to the central or zeroth-order bright fringe. What is the unknown wavelength
Answer:
λ = 5.75 10⁻⁷ mm
Explanation:
This is a slit interference exercise, we analyze each wavelength separately
λ = 657 nm indicate that the third dark pattern
a sin θ = (m + ½) lam
a sin θ = (3 + ½) 657 10⁻⁹
a sin θ = 2299.5 10⁻⁹ nm
for the other wavelength in the same place we have m = 4 bright
a sin θ = m lam
we substitute
2299.5 10⁻⁹ = 4 λ
λ = [tex]\frac{2299.5 \ 10^9 }{ 4}[/tex]
λ = 5.75 10⁻⁷ mm
Two boats - Boat A and Boat B - are anchored a distance of 24 meters apart. The incoming water waves force the boats to oscillate up and down, making one complete cycle every 10 seconds. When Boat A is at its peak, Boat B is at its low point and there is a crest in between the two boats. The vertical distance between Boat A and Boat B at their extreme is 8 meters. The wavelength is ___ m, the period is ___ s, the frequency is ___ Hz, and the amplitude is ___ m.
Answer:
wavelength = 24 m
Period = 10 s
f = 0.1 Hz
Amplitude = 4 m
Explanation:
Wavelength:
Since the boats are at crest and trough, respectively at the same time. Hence, the horizontal distance between them is the wavelength of the wave:
wavelength = 24 m
Period:
The period is given as:
[tex]Period = \frac{time}{no.\ of\ cycles} \\\\Period = \frac{10\ s}{1}\\\\[/tex]
Period = 10 s
Frequency:
The frequency is given as:
[tex]f = \frac{1}{time\ period}\\\\f = \frac{1}{10\ s}\\\\[/tex]
f = 0.1 Hz
Amplitude:
Amplitude will be half the distance between extreme points, that is, crest and trough:
Amplitude = 8 m/2
Amplitude = 4 m
1. Pam has a mass of 48.3 kg and she is at rest on
smooth, level, frictionless ice. Pam straps on
a rocket pack. The rocket supplies a constant
force for 27.3 m and Pam acquires a speed of
62 m/s.
What is the magnitude of the force?
Answer in units of N.
2. What is Pam’s final kinetic energy?
Answer in units of J.
3. A child and sled with a combined mass of 55.7
kg slide down a frictionless hill that is 11.3 m
high at an angle of 29 ◦
from horizontal.
The acceleration of gravity is 9.81 m/s
3. If the sled starts from rest, what is its speed
at the bottom of the hill?
Answer in units of m/s
Answer:
1. F = 3400 N = 3.4 KN
2. [tex]K.E_f=92832.6\ J = 92.83\ KJ[/tex]
3. v = 14.9 m/s
Explanation:
1.
First, we will calculate the acceleration of Pam by using the third equation of motion:
[tex]2as = v_f^2-v_i^2[/tex]
where,
a = acceleration = ?
s = distance = 27.3 m
vf = final speed = 62 m/s
vi = initial speed = 0 m/s
Therefore,
[tex]2a(27.3\ m) = (62\ m/s)^2-(0\ m/s)^2\\\\a = 70.4\ m/s^2[/tex]
Now, we will calculate the force by using Newton's Second Law of Motion:
F = ma
F = (48.3 kg)(70.4 m/s²)
F = 3400 N = 3.4 KN
2.
Final kinetic energy is given as:
[tex]K.E_f = \frac{1}{2}mv_f^2\\\\K.E_f = \frac{1}{2} (48.3\ kg)(62\ m/s)^2[/tex]
[tex]K.E_f=92832.6\ J = 92.83\ KJ[/tex]
3.
According to the law of conservation of energy:
[tex]Potential\ Energy\ at\ top = Kinetic\ Energy\ at\ bottom\\mgh = \frac{1}{2}mv_2 \\\\v = \sqrt{2gh}[/tex]
where,
v = speed at bottom = ?
g = acceleration due to gravity = 9.81 m/s²
h = height at top = 11.3 m
Therefore,
[tex]v = \sqrt{(2)(9.81\ m/s^2)(11.3\ m)}[/tex]
v = 14.9 m/s
An individual's belief that they can master a situation and produce positive outcomes is
Answer:
optimism
Explanation:
just an idea
....
David is driving a steady 30.0 m/s when he passes Tina, who is sitting in her car at rest. Tina begins to accelerate at a steady 2.10 m/s2 at the instant when David passes. Part A How far does Tina drive before passing David
Answer:
Explanation:
Let after time t , Tina catches up David .
Distance travelled by them are equal ,
Distance travelled by Tina
s = ut + 1/2 a t²
= .5 x 2.10 t²
= 1.05 t²
Distance travelled by David
= 30 t ( because of uniform velocity )
1.05 t² = 30t
t = 28.57 s
Distance travelled by Tina
= 1/2 a t²
= .5 x 2.10 x 28.57²
= 857 m approx.
Answer: [tex]857\ m[/tex]
Explanation:
Given
Speed of David car [tex]v=30\ m/s[/tex]
Tina begins to accelerate [tex]2.1\ m/s^2[/tex] after David pass the tina
Suppose it took t time for tina to catch David
Distance traveled by David in t time
[tex]\Rightarrow s_d=30\times t[/tex]
Using the equation of motion to get the distance of Tina is
[tex]s_t=ut+\dfrac{1}{2}at^2\\\\s_t=0+\dfrac{1}{2}\times 2.1t^2[/tex]
now, [tex]s_d=s_t[/tex]
[tex]30t=\dfrac{2.1}{2}t^2\\\\\Rightarrow 2.1t^2-60t=0\\\Rightarrow t(2.1t-60)=0\\\Rightarrow t=0,28.57\ s[/tex]
Neglecting [tex]t=0[/tex]
Distance traveled by tina in [tex]28.57\ s[/tex] is
[tex]s_t=\dfrac{1}{2}\times 2.1\times (28.57)^2\\\\s_t=857.057\approx 857\ m[/tex]
I'm a little bit unsure about this question.
Answer:
Option C. 4 Hz
Explanation:
To know the correct answer to the question given above, it is important we know the definition of frequency.
Frequency can simply be defined as the number of complete oscillations or circles made in one second.
Considering the diagram given above, the wave passes through the medium over a period of one second.
Thus, we can obtain the frequency by simply counting the numbers of complete circles made during the period.
From the diagram given above,
The number of circles = 4
Thus,
The frequency is 4 Hz
cellus
Find the x-component of this
vector:
92.5 m
32.0
Explanation:
x-component:
Vx = Vcos(theta)
= (92.5 m)cos(32.0)
= 78.4 m
Answer:
-78.4
Explanation:
For acellus students
If a 4 Ohm resistor and a 12 Ohm resistor are connected in parallel, what is the total
resistance?
Rt = 3 ohms
Explanation:
Let R1 = 4-ohm resistor
R2 = 12-ohm resistor
For 2 resistors connected in parallel, the total resistance Rt is given by
1/Rt = 1/R1 + 1/R2
or
Rt = R1R2/(R1 + R2)
= (4 ohms)(12 ohms)/(4 ohms + 12 ohms)
= 48 ohms^2/16 ohms
= 3 ohms
9. Cellular respiration occurs in what types of cells?
Answer:
Cellular respiration takes place in the cells of all organisms. It occurs in autotrophs such as plants as well as heterotrophs such as animals. Cellular respiration begins in the cytoplasm of cells. It is completed in mitochondria
Explanation:
Cellular respiration takes place in the cells of all organisms. It happening in autotrophs such as plantas as well as heterotrophs such as animals. Cellular respiration starts in the cytoplasm of cells.
It is finished in mitochondria.
Help me with this please
Answer:
yong may check po ayon yong sagot
Two waves that have
(10 Points)
will add together to produce beats *
the same frequency
slightly different frequencies
different speeds
the same wavelength
Answer:
slightly different frequencies
Explanation:
The alternate increase or decrease of sound produced by the interference of two sound waves of slightly different frequencies is called ‘Beat’. The maximum beat frequency that a human ear can detect is 7 beats/sec.
This definition of the beats is clearly pointing out that the two waves whose frequencies are slightly different will add together to produce the beats.
Therefore, the correct answer will be:
slightly different frequencies
Help me with this please
Answer:
check out of phase
Explanation:
this is my answer
Moving current has electrical energy.
Blue whales apparently communicate with each other using sound of frequency 17.0 Hz, which can be heard nearly 1000 away in the ocean. What is the wavelength of such a sound in seawater, where the speed of sound is 1531 m/s
Answer:
the wavelength of the sound in seawater is 90.1 m.
Explanation:
Given;
frequency of the sound, f = 17 Hz
speed of the sound in seawater, v = 1531 m/s
The wavelength of the wave is calculated as follows;
v = fλ
λ = v / f
where;
λ is the wavelength of the sound
λ = 1531 / 17
λ = 90.1 m
Therefore, the wavelength of the sound in seawater is 90.1 m.
A 0.14-km wide river flows with a uniform speed of 4.0 m/s toward the east. It takes 20 s for a boat to cross the river to a point directly north of its departure point on the south bank. What is the speed of the boat relative to the water
Answer:
The right approach is "8.1 m/s". A further explanation is provided below.
Explanation:
According to the table,
Speed of Boat
= [tex]\frac{s}{t}[/tex]
[tex]V_b=\frac{140}{20}[/tex]
[tex]V_a = 4 \ m/s[/tex]
[tex]V_B = 7 \ m/s[/tex]
Now,
⇒ [tex](V_{relative})^2 = (7)^2+(4)^2[/tex]
or,
⇒ [tex](V_r)^2=49+16[/tex]
[tex]=65[/tex]
[tex]V_r=\sqrt{65}[/tex]
[tex]=8.1 \ m/s[/tex]
PLEASE HELP ME WITH THIS ONE QUESTION
The frequency of violet light is 7.5 x 10^14 Hz. How much energy does a photon of violet light carry? (h = 6.626 x 10^-34 J·s; 1 eV = 1.60 x 10^-19 J)
Answer:
3.11ev
Explanation:
[tex]E = hf[/tex]
[tex]E = 6.626 * 10^-^3^4 * 7.5 * 10^1^4\\E = 49.695 * 10^-^2^0[/tex]
[tex]1ev = 1.60 * 10^-^1^9\\xev = 49.695 * 10^-^2^0 / 1.60 * 10^-^1^9\\xev = 3.1059\\xev = 3.11eV[/tex]
Two identical circular, wire loops 35.0 cm in diameter each carry a current of 2.80 A in the same direction. These loops are parallel to each other and are 24.0 cm apart. Line ab is normal to the plane of the loops and passes through their centers. A proton is fired at 2600 m/s perpendicular to line ab from a point midway between the centers of the loops.
Find the magnitude of the magnetic force these loops exert on the proton just after it is fired.
Answer:
The answer is "[tex]4659.2 \times 10^{-24} \ N[/tex]"
Explanation:
The magnetic field at ehe mid point of the coils is,
[tex]\to B=\frac{\mu_0 i R^2}{(R^2+x^2)^{\frac{3}{2}}}\\\\[/tex]
Here, i is the current through the loop, R is the radius of the loop and x is the distance of the midpoint from the loop.
[tex]\to B=\frac{(4\pi\times 10^{-7})(2.80\ A) (\frac{0.35}{2})^2}{( (\frac{0.35}{2})^2+ (\frac{0.24}{2})^2)^{\frac{3}{2}}}\\\\[/tex]
[tex]=\frac{(12.56 \times 10^{-7})(2.80\ A) \times 0.030625}{( 0.030625+ 0.0144)^{\frac{3}{2}}}\\\\=\frac{ 1.07702 \times 10^{-7} }{0.0095538976}\\\\=112.730955 \times 10^{-7}\\\\=1.12\times 10^{-5}\ \ T\\[/tex]
Calculating the force experienced through the protons:
[tex]F=qvB=(1.6 \times 10^{-19}) (2600)(1.12 \times 10^{-5})= 4659.2 \times 10^{-24}\ N[/tex]
Light travels at 300,000,000 m/s. This is an example
Answer:
ook soooooo
Explanation:
A chemist measures the flow of charged ions through a circuit. Which of these would increase the current? Select all that apply.
You purchase a motor in Germany designed to run at 415 Volts, 50 Hz. It has 75 kW output power, runs at 2978 RPM and has 240 N-m of rated torque. You ship it Canada and run it at 480 Volts, 60 Hz. What will be the new torque in N-m
Answer:
230N-m
Explanation:
Given data
Power P= 75kW
Frequency f= 60Hz
w= 2πf
w=2*π*60
w=120π rad/s
Power= T*w
Power= IV= 415*I
75*10^3= 415*I
I=180.72 A
V= 480V
Power= 180.72*480
Power= 86.746kW
Power= 86.746= T*120π
T= 120π/86.746
T= 230N-m
g a mass of 1.3 kg is pushed horizontally against a massless spring with a spring constant of 58 n/m until the spring compresses 19.5 cm if the mass is then released what is the kinetic energy of the mass when it is no longer in contact with the spring ignore friction
Answer: [tex]1.102\ J[/tex]
Explanation:
Given
Mass [tex]m=1.3\ kg[/tex]
Spring constant [tex]k=58\ N/m[/tex]
Compression in the spring [tex]x=19.5\ cm\ or\ 0.195\ m[/tex]
When the mass leaves the spring, the elastic potential energy of spring is being converted into kinetic energy of mass i.e.
[tex]\Rightarrow \dfrac{1}{2}kx^2=\dfrac{1}{2}mv^2\\\\\Rightarrow \dfrac{1}{2}\cdot 58\cdot (0.195)^2=\dfrac{1}{2}mv^2\\\\\Rightarrow \dfrac{1}{2}mv^2=1.102\ J[/tex]
The kinetic energy of the mass is 1.102 J.
A wind turbine is rotating 5.98 rad/s when the wind abruptly stops blowing. It takes the turbine 27.5s to stop rotating. how many revolutions does his turbine make before it comes to a stop
Answer:
S = Vo t * 1/2 a t^2 equation for distance traveled
w = w0 t + 1/2 a t^2 equivalent circular equation where w equals omega
w = 5.98 * 27.5 + a (27.5)^2/ 2
a = (w2 - w1) / t = -5.98 / 27.5 = -.217
w = 5.98 * 27.5 - 1/2 * .217 * 27.5^2 = 82.4
Since 1 Rev = 2 pi radians
Rev = 82.4 / 2 * pi = 13.1 Rev
PHYSICS HELP !! 30 points please answer correctly !! questions attached below