When the palmaris longus muscle in the forearm is flexed, the wrist moves back and forth. If the muscle generates a force of 53.5 N and it is acting with an effective lever arm of 2.25 cm , what is the torque that the muscle produces on the wrist

Answer:

Explanation:

Elongation in the spring when a mass of 2 kg hangs from it

k d = mg where d is the elongation

32 d = 2 x 9.8

d = .6125 m .

When it rises by .40 m , the elongation reduces to .6125 - .40 = .2125 m

upward restoring force at this point = 32 x .2125 = 6.8 N .

Its weight = 2 x 9.8 = 19.6 N acting downwards

Net force on mass of 2 kg = 19.6 - 6.8 N = 12.8 N .

acceleration in downward direction = net force / mass = 12.8 / 2 = 6.4 m/s²

At the bottommost  point , total extension = .6125 + .40 = 1.0125 m

restoring force in upward direction = 32 x 1.0125 = 32.4 N .

Net force in upward direction = 32.4 - 19.6 N = 12.8 N

acceleration = 12.8 / 2 = 6.4 m /s² in upward direction .

Answer:

13.1 m/s

Explanation: Given that a pendulum that was originally erected by Foucault at the Pantheon in Paris for the Paris Exhibition in 1851 was restored in 1995. It has a 28.0 kg sphere suspended from a 67.0-m light cable. If the amplitude of the swing is 5.00 m, what is the maximum speed of the sphere

The formula to use is :

W = sqrt ( L/g )

Where

L = 67m

g = 9.8m/s^2

A = 5m

Substitute all the parameters into the formula

W = sqrt ( 67 / 9.8 )

W = 2.6

To get the maximum velocity, we use the below formula.

V = wA

V = 2.6 × 5

V = 13.07 m/s

Therefore the maximum speed of the sphere is 13.1 m/s approximately.

Answer:

Option C: Third Class

Explanation:

This is third class because the effort or the input force is in the middle between the fulcrum and the load.

To solve this, we must be knowing each and every concept related to lever.  Therefore,  due to the effort or input force being in the center between the edge as well as the load, the supplied lever is of 3rd class. The correct option is option C.

A lever is a basic device that consists of a beam or stiff rod located at a set tight, or edge. It is used to apply force to a load and often offers a mechanical advantage.

A stiff object that can rotate about a spot on itself is called a lever. The three types of levers are categorized according to where the edge, weight, and effort are located. Due to the effort or input force being in the center between the edge as well as the load, the supplied lever is of  3rd class.

Therefore,  the correct option is option C.

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Answer:

The kinetic energy will be "399.65 J".

Explanation:

Given:

Mass,

m = 1.2 kg

Velocity,

v = 31.3 m/s

The total energy of mass will be:

⇒ [tex]E=K+U[/tex]

or,

⇒ [tex]E=.5mv^2+mgh[/tex]

By putting the values, we get

        [tex]=.5(1.2)(31.3)^2+0[/tex]

        [tex]=0.6\times 979.69+0[/tex]

        [tex]=587.81 \ J[/tex]

Since,

The system's total energy is unchanged, then

⇒ [tex]E=K+U[/tex]

or,

⇒ [tex]E=K+mgh[/tex]

   [tex]587.81=K+1.2(9.8)(16)[/tex]

   [tex]587.81=K+188.16[/tex]

          [tex]K=587.81-188.16[/tex]                

               [tex]=399.65 \ J[/tex]

Explanation:

Extrusive rocks may have a few grains that are large enough to see, but most of them will be too small to see individual minerals. ... The individual mineral grains are almost too small to see. Some extrusive rocks cool so quickly that they do not form any grains. Instead, they form a natural glass.

Answer:

Negative electric charges

Answer:

(a) I = 625 A

(b) I = 101 A    

Explanation:

The relationship between current, voltage and resistance can be given by Ohm's Law:

V = IR

where,

V = Voltage

I = Current

R = Resistance

(a)

Here,

V = 12.5 V

R = 0.02 Ω

Therefore,

[tex]12.5\ V = I(0.02\ \Omega)\\\\I = \frac{12.5\ V}{0.02\ \Omega}[/tex]

I = 625 A  

(b)

Here,

V = 10.1 V

R = 0.1 Ω

Therefore,

[tex]10.1\ V = I(0.1\ \Omega)\\\\I = \frac{10.1\ V}{0.1\ \Omega}[/tex]

I = 101 A    

a) The speed of the bead at B is 11.79m/s.

b) The change in mechanical energy due to friction as it  moves from B to C is 36.064 J.  

If we drop the object from the shelf or release the spring, that potential energy is converted back into kinetic energy. Kinetic energy can also be transferred from one body to another in a collision, which can be elastic or inelastic.

a)

Potential energy is converted  to kinetic energy

[tex]\frac{1}{2} mv^2=mgh\\\\v=\sqrt{2gh} \\\\v_B=\sqrt{2(9.8)(7.1-0)} \\\\v_B=11.79m/s[/tex]

The speed of the bead at B is 11.79m/s.

b)

[tex]W = mg(h_A) - mg(h_B) = 0.8(9.8)(7.1 - 2.5) = 36.064 J\\\\W=36.064J[/tex]

The change in mechanical energy due to friction as it  moves from B to C is 36.064 J.

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Answer: hi your question is incomplete attached below is the complete question

answer :

Explanation:

Using the information provided in the question attached I will match each term with its corresponding meaning

Answer:

A&B

Explanation:

Answer:

Chemical to mechanical(b) and Chemical to Thermal(a)

Explanation:

It will be B.Its particles have no kinetic energy.

Answer:

stretching prior to an exercise is a great way to improve a range of motion, along with yoga and Pilates!

Answer:

D

Explanation:

D ok ok ok ok bye

The correct statement is that the alcohol has lower boiling point than water. The correct option is B.

At the boiling point, the pressure exerted by the surroundings on a liquid equals the pressure exerted by the liquid's vapor, under this condition, adding heat outcomes in the transformation of the liquid into its vapor without raising the temperature.

The boiling point of alcohol is low. Because there is less hydrogen bonding between ethanol molecules than between water molecules.

The ethanol requires less energy to vaporize than water, and water has a higher boiling point than ethanol.

The boiling point of a liquid can be known by utilizing the capillary method, that encompasses placing an inverted capillary in the liquid of interest as well as heating it.

Thus, the correct option is B.

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Answer:

In fission, energy is gained by splitting apart heavy atoms, for example uranium, into smaller atoms such as iodine, caesium, strontium, xenon and barium, to name just a few. However, fusion is combining light atoms, for example two hydrogen isotopes, deuterium and tritium, to form the heavier helium.

Explanation:

I hope this helped you

(Sorry If it didn't)

Answer:

732.96 N

Explanation:

In fresh water the diver carries ; 10 Ib of lead alloy = 44.5 N

Ballast density : 1.1 * 10^4 kg/m^3

Diver must carry 59% more ballast in seawater

first step : For fresh water

mass of lead alloy in freshwater

mf = wf /g  = 44.5 N / 9.81 = 4.536 kg

Volume of lead alloy ballast in fresh water

Vf = mf / plead  

    = ( 4.536 ) / ( 1.1 * 10^4 ) = 4.1 * 10^ -4 m^3

Second step : For sea water

mass of alloy in seawater

Ms = Ws / g

Ws = 10 Ib + 5 Ib = 15 Ib = 66.75 N

hence ; Ms = 66.75 / 9.81 = 6.804 kg

Volume of alloy in seawater

Vs = Ms / plead  = 6.804 / ( 1.1 * 10^4 ) = 6.2 * 10^-4 m^3

Next : considering the diver in freshwater with Ballast weight

= weight of diver + ballast weight (Wf) = ( pfresh * ( V + Vf ) ) * g   ----  ( 1 )

where : pfresh = 1000 kg/m^3 , Vf = 4.1 * 10^-4 m^3,  g = 9.81 , Wf = 44.5 N

hence equation 1 becomes

W + 44.5  = 9810 * V + 4.1

W + 40.4 = 9810 V --------------- ( 3 )

Considering Diver in seawater with Ballast weight

weight of diver + ballast weight (Ws) = ( psea * ( V + Vs ) ) * g   ---- ( 2 )

where : psea = 1026 kg/m^3 , Vs = 6.2 * 10^-4 m^3 , g = 9.81 , Ws = 66.75 N

equation 1 becomes

W + 66.75 = 10065.06 * V + 6.2

W + 60.55 = 10065.06 V

∴ V = ( W + 60.55 )/ 10065.06 (  Input value into equation 3 to determine the weight of the diver )

W + 40.4  = 9810 (  ( W + 60.55 )/ 10065.06  )

10065.6 ( W + 40.4 ) = 9810 ( W + 60.55 )  

10065.6 W - 9810 W = 593995.5 - 406650.24

∴ W ( weight of diver ) = 187345.26 / 255.6  = 732.96 N

Answer:

force on the electron is upwards

Explanation:

The magnetic force is given by the relation

        F = q v x B

the bold indicates vectors, we can write the module of this expression

        F = q v  B sin θ

the direction of the force is given by the right hand rule.

If we have a positive charge, the flea points in the direction of velocity, in this case towards the inside of the page.

fingers extended in the direction of the magnetite field, in our case to the right and

the palm gives the direction of the force for a positive charge, for a negative charge it is in the opposite direction. The palm points downwards, so the force on the electron is upwards

Answer:

[tex]\boxed {\boxed {\sf D.\ 6.4\ m/s^2}}[/tex]

Explanation:

We need to find the acceleration of the 2 kilogram object. Let's complete this in 2 steps.

First, we can find the force of the first, 8 kilogram object.

According to Newton's Second Law of Motion, force is the product of mass and acceleration.

[tex]F=m \times a[/tex]

The mass of the object is 8 kilograms and the acceleration is 1.6 meters per square second.

Substitute these values into the formula.

[tex]F= 8 \ kg * 1.6 \ m/s^2[/tex]

Multiply.

[tex]F= 12.8 \ kg*m/s^2[/tex]

Now,  use the force we just calculated to complete the second part of the problem. We use the same formula:

[tex]F= m \times a[/tex]

This time, we know the force is 12.8 kilograms meters per square second and the mass is 2 kilograms.

Substitute the values into the formula.

[tex]12.8 \ kg*m/s^2= 2 \ kg *a[/tex]

Since we are solving for the acceleration, we must isolate the variable (a). It is being multiplied by 2 kg. The inverse of multiplication is division. Divide both sides of the equation by 2 kg.

[tex]\frac {12.8 \ kg*m/s^2}{2 \ kg}= \frac{2\ kg* a}{2 \ kg}[/tex]

[tex]\frac {12.8 \ kg*m/s^2}{2 \ kg}=a[/tex]

The units of kilograms cancel.

[tex]\frac {12.8}{2}\ m/s^2=a[/tex]

[tex]6.4 \ m/s^2=a[/tex]

The acceleration is 6.4 meters per square second.

Answer:

It can travel in various wavelengths. brainliest?

Explanation:

The evidence that reveals about the light is that  It can travel in various wavelengths.

It is the wave property that should be blending of the wave related to the corners.

At the time when the wave is bending so it passed via the openings.

Also, the light diffracted via the small slits and it should be shown to arise in the water waves and the sound waves.

hence, the first option is correct.

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Answer:

c

Explanation:

the gas pedal gives the engine the fuel it needs to give the car the power to go

Explanation:

Potential energy=MGH

100=3×10×H.

H=100/30

H=3.40m

Answer:

Explanation:

Slit distance d = .25 x 10⁻³ m .

Distance of screen D = 60 x 10⁻² m

Distance between first and fifth minimum = 5.5 x 10⁻³ m .

There will be four bright fringes between first and 5 th minimum so

distance between them = 4 x λ D / d  where λ is the wavelength of light .

Substituting the values

4 x λ x 60 x 10⁻² m  /  .25 x 10⁻³ m = 5.5 x 10⁻³ m

4 x λ x 60 x 10⁻² m =  .25 x 10⁻³ m x  5.5 x 10⁻³ m = 1.375 x 10⁻⁶ m

λ = .005729 x 10⁻⁴

= 572.9 x 10⁻⁹ m

= 572.9 nm .

Answer:

The same current flows through each resistor in series. Individual resistors in series do not get the total source voltage, but divide it. The total resistance in a series circuit is equal to the sum of the individual resistances: RN(series)=R1+R2+R3+…

Answer: creo que es A o D

Explanation:

Answer: When a ray of light approaches a smooth polished surface and the light ray bounces back, it is called the reflection of light. The incident light ray which lands upon the surface is said to be reflected off the surface. The ray that bounces back is called the reflected ray.

Have a great day and stay safe !

Answer:

the required distance is 89.125 m

Explanation:

Given the data in the question;

we know that, sound intensity B in decibels of sound is;

β(dB) = 10log₁₀( [tex]I[/tex] / [tex]I_0[/tex] )

where intensity [tex]I[/tex] = power / area carried by wave

[tex]I_0[/tex] = 10⁻¹² W/m² { minimum threshold intensity }

Now,

intensity [tex]I[/tex] = power / area carried by wave = P/A = P/4πr² { spherical  }

given that; β = 80.0 dB and P = 10 W

so

β(dB) = 10log₁₀( [tex]I[/tex] / [tex]I_0[/tex] )

we substitute

80 = 10log₁₀( P / 4πr²× [tex]I_0[/tex])

80 = 10log₁₀( 10 / 4πr²× 10⁻¹² )

8 = log₁₀(10) - log₁₀( 4πr²× 10⁻¹² )  

8 = 1 - log₁₀( 4πr²× 10⁻¹² )

8 - 1 = -log₁₀( 4πr²× 10⁻¹² )

7 = -log₁₀( 1.2566 × 10⁻¹¹ × r² )

7 = -[ log₁₀( 1.25 × 10⁻¹¹) + log₁₀( r² ) ]

7 = -[ -10.9 + log₁₀( r² ) ]

7 = 10.9 - log₁₀( r² )

-log₁₀( r² ) = 7 - 10.9

-log₁₀( r² )  = - 3.9

log₁₀( r² ) = 3.9

2log₁₀r = 3.9

log₁₀r  = 3.9 /2

log₁₀r = 1.95

r = 89.125 m

Therefore, the required distance is 89.125 m

place's absolute location is its exact place on Earth, often given in terms of latitude and longitude. For example, the Empire State Building is located at 40.7 degrees north (latitude), 74 degrees west (longitude).

Place's absolute location is its exact place on Earth, often given in terms of latitude and longitude.

A point's longitude, which might refer to the east-west position of a point on the surface of the Earth or another celestial body, is a geographic coordinate. The Greek symbol lambda is used to represent the angular measurement, which is often given in degrees.

Latitude is a coordinate used in geography that describes a point's north-south location on the surface of the Earth or another celestial body. Latitude is measured as an angle, with 0° at the Equator and values ranging from -90° at the south pole to 90° at the north pole.

Place's absolute location is its exact place on Earth, often given in terms of latitude and longitude.

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