When testing the voltage drop on the positive side of the starter circuit (high current side), connect the red voltmeter lead to:
Select one:
tot
a. the input of the starter motor.
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b. the battery negative post.
c. the "S" terminal of the solenoid.
0
d. the battery positive post.

Answers

Answer 1
D. The battery positive post.

For example, if your starter is engaging slowly when you crank it, to measure voltage drop in the positive battery cable hold the red probe lead on the positive battery post, hold the black probe lead on the post on the starter solenoid that the positive battery cable connects to, then have someone try to start the car while you watch the meter.

Related Questions

What’s the answer to this problem?

Answers

Answer:

answer is B I hope it helps

Shane's 100-watt radio draws 7 amps of current on a 120-volt circuit. What is the resistance in the radio?

Answers

Answer:

Resistance, R = 2.04 Ohms.

Explanation:

Given the following data;

Current = 7 amps

Circuit voltage = 120 Volts

Power = 100 Watts

To find the resistance;

First of all, we would calculate the potential difference (voltage level) used by the radio.

Power = current * voltage

100 = 7 * voltage

Voltage = 100/7

Voltage = 14.29 Volts

Next, we solve for the resistance of the radio;

Ohm's law states that at constant temperature, the current flowing in an electrical circuit is directly proportional to the voltage applied across the two points and inversely proportional to the resistance in the electrical circuit.

Mathematically, Ohm's law is given by the formula;

[tex] V = IR[/tex]

Where;

V represents voltage measured in voltage.

I represents current measured in amperes.

R represents resistance measured in ohms.

Substituting into the formula, we have;

[tex] 14.29 = 7*R[/tex]

[tex] R = \frac {14.29}{7} [/tex]

Resistance, R = 2.04 Ohms.

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