Biology High School

When reproducing, Robins (a species of bird) typically lay four eggs. Laying more eggs might result in malnourished chicks and laying fewer eggs might result in no viable offspring. This is an example of

Answers

Answer 1

Answer:

stabilizing selection

Explanation:

The illustration is an example of stabilizing selection.

Stabilizing selection is an evolutionary mechanism in which the extremes of traits are selected against, leading to an increase in the frequency of such traits in the population.

Laying too many eggs would lead to reduced fitness of the population of the bird as a result of malnutrition while laying too few eggs would lead to a reduction in the population. Reproduction needs to be optimized for maximum fitness.

Answer 2

There are different types of natural selection. One of them is stabilizing selection that favors the intermediate phenotype. The exposed scenario is an example of stabilizing selection.

Balancing selection, also called Stabilizing selection, decreases the frequency of individuals with extreme traits, and favors individual that exhibit medium-range characteristics, that gets to survive.

Selective pressure is against h0m0zyg0tes, promoting genetic diversity.

Genes expressing extreme characteristics in a h0m0zyg0sis are kept in a heter0zyg0us state, as a favorable adaptation to environmental conditions.  

In a graph, you will see that

→  The curve gets higher and thinner in the middle of the horizontal axe, indicating an increase in the heter0zyg0us genotype frequency.

→  The tails of the curve that coincides with h0m0zyg0us dominant and recessive genotypes frequencies will be near zero.

In the exposed example,

laying more than four eggs and less than four eggs are extreme phenotypes. laying four eggs is an intermediate favored phenotype.

The intermediate phenotype results in the species' fitness increase, so it is favored by natural selection.

Laying four eggs leads to well-nourished chicks, and all of them get to survive. Parents ensure their reproductive success.

You will learn more about stabilizing selection at

https://brainly.com/question/9479133

https://brainly.com/question/8563440

Related Questions

Cross a person who does not have freckles and is heterozygous for dimples with a person who has
freckles (but her mom does not) but no dimples.
1. What is the probability that these parents will have a child with dimples?
2. What is the probability that these parents will have a child with freckles?
3. What is the probability that these parents will have a child with dimples and freckles?

Answers

Answer:

1. 1/2

2. 1/2

3. 1/4

Explanation:

Let the allele for freckles be A or a while that of dimples be B or b.

A person without freckles but heterozygous for dimples = aaBb

A person who has freckles (whose mother has no freckles) but no dimples = Aabb

      aaBb    x    Aabb

Offspring

4 AaBb - freckled and dimpled

4 Aabb - freckled and non dimpled

4 aaBb - non freckled and dimpled

4 aabb - non freckled and non dimpled

1. Probability that the parents will have a dimpled child = 8/16 or 1/2

2. Probability that they will have a child with freckles = 8/16 or 1/2

3. Probability that they will have a child with freckles and dimples = 4/16 or 1/4

See the attached image for the Punnet's square analysis of the cross

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