When Ethyl Acetoacetate is treated with 1,3-Dibromopropane and 2 moles of Sodium Ethoxide in Ethanol, a compound is produced that has the formula C9H14O3. This compound has an infrared spectrum that shows only one carbonyl adsorption and no OH bond stretch. Suggest a structure for this compound, and provide a mechanism for its formation.
Answers
Answer:
The reaction of ethyl acetoacetate with 1,3-Dibromopropane and 2 moles of Sodium Ethoxide in Ethanol.
Explanation:
The structure of ethyl acetoacetate is shown below:
The structure of 1,3-dibromopropane is shown below:
Ethyl acetoacetate on reaction with sodium ethoxide in ethanol forms a carbanion intermediate and the formation of carbanion takes place twice and form a cyclic ring.
The entire reaction is shown below:
The structure of C9H14O3 is shown in the chemical reaction that is shown below:
Related Questions
A mixture of BaCl2 and NaCl is analyzed by precipitating all the barium as BaSO4. After addition of an excess of Na2SO4 to a 3.656-g sample of the mixture, the mass of precipitate collected is 1.658 g. What is the mass percentage of barium chloride in the mixture
Answers
Answer:
[tex]\% m=40.46\%[/tex]
Explanation:
Hello there!
in this case, according to the given information, it turns out firstly necessary for us to write up the chemical equation as shown below:
[tex]BaCl_2+Na_2SO_4\rightarrow BaSO_4+2NaCl[/tex]
Thus, we calculate the mass of BaCl2 stoichiometrically related to the produced 1.658 g of precipitate in order to discard it from the sample:
[tex]m_{BaCl_2}=1.658gBaSO_4*\frac{1molBaSO_4}{233.38 gBaSO_4} *\frac{1molBaCl_2}{1molBaSO_4}*\frac{208.23 gBaCl_2}{1molBaCl_2}\\\\m_{BaCl_2}=1.479gBaCl_2[/tex]
Thus, the mass percentage is calculated as shown below:
[tex]\% m=\frac{1.479g}{3.656g}*100 \% \\\\\% m=40.46\%[/tex]
Regards!
The acid-base reaction between HCl and NaOH produces a solution with a pH of 7 at the equivalence point (NaCl H2O). Why does an acid-base indicator that changes color at pH 5 or 9 work just as well for this reaction as one that changes color at pH 7
Answers
Answer:
Answer is in the explanation.
Explanation:
Before the equivalence point, the pH of the solution of HCl that is titrated with NaOH has a pH <<< 7. When you are adding more NaOH nearing, thus, to the equivalence point the change in pH occurs quickly, and, with 1 drop of excess of NaOH after equivalence, the pH of the solution change to a pH >>> 7
That means the volume added at pH 5 or pH 9 is, almost, the same doing the indicator work just as well as an indicator with change color at pH 7
Glycerol. C3HgO3, is a substance used extensively in the manufacture of cosmetics, foodstuffs, antifreeze, and plastics. Glycerol is a water-soluble liquid
with a density of 1.2656 g/mL at 15 °C. Calculate the molarity of a solution of glycerol made by dissolving 50.000 mL glycerol at 15 °C in enough water to
make 250.00 mL of solution. The molecular weight of C3HgO3 is 92.094 amu.
O A 0.6871
O B. 3.600
O C. 63.28
O 0.92.10
O E. 2.749
Answers
Answer: The correct option is E.) 2.749 M.
Explanation:
Density is defined as the ratio of mass and volume of a substance.
[tex]\text{Density}=\frac{\text{Mass}}{\text{Volume}} [/tex] ......(1)
Given values:
Volume of glycerol = 50.0 mL
Density of glycerol = 1.2656 g/mL
Putting values in equation 1, we get:
[tex]\text{Mass of glycerol }=(1.2656g/mL\times 50.0mL)=63.28g[/tex]
Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L. The formula used to calculate molarity:
[tex]\text{Molarity of solution}=\frac{\text{Given mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (mL)}}[/tex] .....(2)
Given values:
Given mass of glycerol = 63.28 g
Molar mass of glycerol = 92.094 g/mol
Volume of the solution = 250.00 mL
Putting values in equation 2, we get:
[tex]\text{Molarity of solution}=\frac{63.28\times 1000}{92.094\times 250.00}\\\\\text{Molarity of solution}=2.749M[/tex]
Hence, the correct option is E.) 2.749 M.
Which best defines the term drug
Answers
Answer:
a medicine or other substance which has a physiological effect when ingested or otherwise introduced into the body.
Explanation:
The diagram shows a food chain.
Which term best describes the green plant in the food chain?
antiter
A. Competitor
B. Producer
C. Consumer
D. Predator
Answers
A suspension is
•A heterogenous mixture where the solid particles are large enough to be filtered out.
•A homogenous mixture where the solid particles are large enough to be filtered out.
•A heterogenous mixture where the solid particles are too small to be filtered out.
•A homogenous mixture where the solid particles are too small to be filtered out
Answers
Answer:
A heterogeneous mixture where the solids particles are large enough to be filtered out.
Explanation:
Indica, con base en la siguiente ecuación:
HNO3 + H2S
NO + S + H30
a) Los números de oxidación de todos los átomos que forman cada compuesto
o elemento.
b) los átomos cuyo número de oxidación varía.
c) El elemento que se reduce y el que se oxida.
d) El agente oxidante y el agente reductor.
e) El átomo que gana electrones y el átomo que los pierde.
f) Los coeficientes apropiados para balancear la ecuación química.
Answers
m
Un cocodrilo se arrastró 25 m hacia la derecha con una velocidad promedio de –1.2 -.
¿Cuántos segundos se arrastró el cocodrilo?
Answers
Answer:
El cocodrilo se arrastró durante 20.833 segundos.
Explanation:
El enunciado presenta omisiones y errores conceptuales. La forma correcta es la siguiente: "Un cocodrilo se arrastró 25 metros hacia la derecha con una rapidez promedio de 1.2 metros por segundo. ¿Cuántos segundos se arrastró el cocodrilo?"
Consideremos que el cocodrilo tiene un movimiento rectilíneo uniforme, el tiempo requerido para el recorrido se calcula con la siguiente ecuación cinemática:
[tex]t = \frac{x}{v}[/tex] (1)
Donde:
[tex]x[/tex] - Distancia recorrida, en metros.
[tex]v[/tex] - Rapidez del cocodrilo, en metros por segundo.
[tex]t[/tex] - Tiempo, en segundos.
Si [tex]x = 25\,m[/tex] y [tex]v = 1.2\,\frac{m}{s}[/tex], entonces el tiempo empleado por el cocodrilo es:
[tex]t = \frac{25\,m}{1.2\,\frac{m}{s} }[/tex]
[tex]t = 20.833\,s[/tex]
El cocodrilo se arrastró durante 20.833 segundos.
An imaginary line dividing the earth's surface into two hemisphere the northern and southern hemisphere, it is locatedat 0⁰, which of the following imaginary lines is being described? a.equator b.latitude c.longitude d.prime meridian
Answers
Answer:
A. Equator
Explanation:
The equator is located in the centre of the Earth, dividing the northern and southern hemispheres.
Answer:
Equator because equator divides the earth into Northern and Southern hemisphere.
Which element has a higher first ionization energy than chlorine (Cl)?
A. Argon (Ar)
B. Phosphorus (P)
C. Lithium (Li)
D. Iodine (I)
Answers
Answer:
Argon
Explanation:
It has more electron than chlorine
Extension: Cedric has been in the hospital for 15 weeks, how many minutes is that? Use
conversion factors with units to solve the problem and show your work
Answers
Answer:
151200 minutes.
Explanation:
From the question given above, the following data were obtained:
Time (in week) = 15 weeks
Time (in min) =?
Next, we shall convert 15 weeks to days. This can be obtained as follow:
1 week = 7 days
Therefore,
15 weeks = 15 weeks × 7 days / 1 week
15 weeks = 105 days
Next, we shall convert 105 days to hours. This can be obtained as follow:
1 day = 24 h
Therefore,
105 days = 105 days × 24 h / 1 day
105 days = 2520 h
Finally, we shall convert 2520 h to mins. This can be obtained as follow:
1 h = 60 mins
Therefore,
2520 h = 2520 h × 60 mins / 1 h
2520 h = 151200 mins
Thus, 15 weeks is equivalent to 151200 minutes.
Identify the calculations possible using only 28.02 g/mol as a conversion factor. Select one or more:
Answers
The question is incomplete, the complete question is:
Identify the calculations possible using only 28.02 g/mol as a conversion factor. Select one or more:
(a): Calculate the grams of [tex]N_2[/tex] in 10.58 L of nitrogen gas
(b): Calculate the grams of [tex]N_2[/tex] in [tex]5.03\times 10^{20}[/tex] moles of nitrogen gas
(c): Calculate the moles of [tex]N_2[/tex] molecules in 3.94 grams of nitrogen gas
(d): Calculate the moles of [tex]N_2[/tex] molecules in 4.73 L of nitrogen gas
Answer: The correct options are (b) and (c).
Explanation:
We are given:
Molar mass of [tex]N_2[/tex] = 28.02 g/mol
The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]
At STP conditions:
1 mole of gas occupies 22.4 L of volume
For the given options:
(a): Volume is given and to calculate the mass of [tex]N_2[/tex], we need to use both the conversion factors above.
The equation formed will be:
Mass of [tex]N_2[/tex] = [tex]\frac{1mol}{22.4L}\times 10.58L\times 28.02 g/mol[/tex]
(b): Moles are given and to calculate the mass of [tex]N_2[/tex], we need only the first conversion factor.
The equation formed will be:
Mass of [tex]N_2[/tex] = [tex](5.03\times 10^{20}mol)\times 28.02g/mol[/tex]
(c): Mass is given and to calculate the moles of [tex]N_2[/tex] molecules, we need only the first conversion factor.
The equation formed will be:
Moles of [tex]N_2[/tex] molecules = [tex]\frac{3.94 g}{28.02g/mol}[/tex]
(d): Volume is given and to calculate the moles of [tex]N_2[/tex] molecules, we need only the second conversion factor.
The equation formed will be:
Moles of [tex]N_2[/tex] molecules = [tex]\frac{1mol}{22.4L}\times 4.73L[/tex]
Hence, the correct option is (b) and (c)
Using only 28.02 g/mol as a conversion factor, we can:
(b): Calculate the grams of N₂ in 5.03 × 10²⁰ moles of nitrogen gas. (c): Calculate the moles of N₂ molecules in 3.94 grams of nitrogen gas.We want to identify the conversion factors required in a series of calculations.
What is a conversion factor?A conversion factor is an arithmetical multiplier for converting a quantity expressed in one set of units into an equivalent expressed in another.
28.02 g/mol, which is the molar mass of nitrogen, is a conversion factor to convert moles to mass and vice versa.
(a): Calculate the grams of N₂ in 10.58 L of nitrogen gas.We want to convert 10.58 L (volume) to grams (mass). We need to conversion factors:
22.4 L/mol is the conversion factor to convert volume to moles.28.02 g/mol is the conversion factor to convert moles to mass.(b): Calculate the grams of N₂ in 5.03 × 10²⁰ moles of nitrogen gas.We want to convert 5.03 × 10²⁰ moles (moles) to grams (mass). We can do so by just using 28.02 g/mol as the conversion factor.
(c): Calculate the moles of N₂ molecules in 3.94 grams of nitrogen gas.We want to convert 3.94 grams (mass) to moles. We can do so by just using 28.02 g/mol as the conversion factor.
(d): Calculate the moles of N₂ molecules in 4.73 L of nitrogen gas.We want to convert 4.73 L (volume) to moles. The required conversion factor is 22.4 L/mol.
Using only 28.02 g/mol as a conversion factor, we can:
(b): Calculate the grams of N₂ in 5.03 × 10²⁰ moles of nitrogen gas. (c): Calculate the moles of N₂ molecules in 3.94 grams of nitrogen gas.The question is incomplete, the complete question is:
Identify the calculations possible using only 28.02 g/mol as a conversion factor. Select one or more:
(a): Calculate the grams of N₂ in 10.58 L of nitrogen gas.
(b): Calculate the grams of N₂ in 5.03 × 10²⁰ moles of nitrogen gas.
(c): Calculate the moles of N₂ molecules in 3.94 grams of nitrogen gas.
(d): Calculate the moles of N₂ molecules in 4.73 L of nitrogen gas.
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Which of the following is considered a nucleon?
proton
neutron
All of the above
None of the above
Answers
12. The reaction 2NO, (g) = N20,(g) reaches equilibrium.
How does increasing the pressure on this system affect the amount o
The amount of N20 remains the same.
The amount of N20 increases.
The amount of N20 decreases.
Answers
Answer:
The amount of N2O4 increases.
Explanation:
Based on LeCh's principle, a change in the state of an equilibrium produce an effect in the system that try to restore the initial equilibrium.
For example, in the problem, the change is the increasing in the pressure. The system will try to decrease the pressure of the system. To decrease the pressure the system needs to decrease the moles of gas. As 2 moles of NO2 produce 1 mole of N2O4, the system will:
Shift to the right increasing the amount of N2O4 and decreasing the amount of NO2. Right option is:
The amount of N2O4 increases.
The physical properties of a substance containing the bonded atoms y and z ?
Answers
For each of the scenarios, determine if the ionic strength of the solution would increase, decrease, or not change. Ignore any effects caused by the change in volume.
1) If a solution of HNO3 were added to a solution of KOH , the ionic strength of the KOH solution would:_____.
A. Increase.
B. Decrease.
C. Not change.
2) If a dilute solution of KOH were added to a solution of CaCl2 (Ca(OH)2 (s) is formed), the ionic strength would:____.
A. Increase.
B. Decrease.
C. Not change.
3) If a dilute solution of benzoic acid were titrated with a solution of KOH the ionic strength would:____.
4) If a solution of NaOH were added to a solution of iron(II) chloride, the ionic strength would:____. A. Increase.
B. Decrease.
C. Not change.
Answers
Answer:
1) increases
2) decrease
3) increase
4) decrease
Explanation:
When ionic compounds dissolve in water, the concentration of ions in solution increases since ionic substances dissociate into ions in solution. The greater the concentration of ions in a solution, the greater the ionic strength of that solution.
Hence, if HNO3 is added to KOH solution, the ionic strength of the solution is increased due to an increase in the number of ions in the solution.
Also, when benzoic acid is titrated against KOH, potassium benzoate (an ionic substance) is formed thereby increasing the ionic strength of the solution.
However, when KOH is added to CaCl2, a precipitate (Ca(OH)2) is formed. Also, when NaOH is added to FeCl2, a precipitate (Fe(OH)2) is formed. In both cases, the formation of the precipitate decreases the concentration of ions in the solution thereby decreasing the ionic strength of the solution.
61. Using the symbol of the previous noble gas to indicate the core
electrons, write the electron configuration for each of the fol-
lowing elements.
a. scandium, Z= 21 c. lanthanum, Z= 57
b. yttrium, Z = 39
d. actinium, Z= 89
Answers
Answer:
Scandium, with atomic number of 21 = [Ar]3d¹4s²
Yttrium, with atomic number of 39 = [Kr]4d¹5s²
Lanthanum, with atomic number of 57 = [Xe]5d¹6s²
Actinium, with atomic number of 89 = [Rn]6d¹7s²
Explanation:
The electronic configuration of atoms of elements describes how electrons are arranged in the atomic orbitals of the atom. The electron configurations of atoms in standard notation is usually written sequentially with all electron-containing atomic subshells (s, p, d and f) and the number of electrons they contain in superscript. For example, the electron configuration of Neon is 1s²2s²2p⁶. However, an abbreviated notation can be used especially for elements having large atomic numbers. The symbol of the previous noble gas in square brackets indicating the core electrons is written before the outermost shell electrons of the atom. For example, the abbreviated electron configuration of sodium is [Ne]3s¹.
The electronic configuration of the given elements are shown below:
Scandium, with atomic number of 21 = [Ar]3d¹4s²
Yttrium, with atomic number of 39 = [Kr]4d¹5s²
Lanthanum, with atomic number of 57 = [Xe]5d¹6s²
Actinium, with atomic number of 89 = [Rn]6d¹7s²
Is Dioxin chemical ionic or covalent and acidic or basic? Explain
Answers
Answer:
Learning Objective Identify element pairs which are likely to form ionic or covalent bonds Key Points Ionic compounds are formed from strong electrostatic interactions between ions, which result in higher melting points and electrical conductivity compared to covalent compounds.Dioxins are a group of highly toxic chemical compounds that are harmful to health. They can cause problems with reproduction, development, and the immune system. They can also disrupt hormones and lead to cancer. Known as persistent environmental pollutants (POPs), dioxins can remain in the environment for many years. Covalent compounds have bonds where electrons are shared between atoms. Due to the sharing of electrons, they exhibit characteristic physical properties that include lower melting points and electrical conductivity compared to ionic compounds. Terms electronegativity: The tendency of an atom or molecule to attract electrons and form bonds. octet rule: Atoms lose, gain, or share electrons in order to have a full valence level of eight electrons. Hydrogen and helium are exceptions because they can hold a maximum of two valence electrons. valence electrons: Electrons in the outermost principal energy (valence) level of an atom that can participate in the formation of chemical bonds with other atoms. Two Classes of Compounds Compounds are defined as substances containing two or more different chemical elements. They have distinct chemical structures characterized by a fixed ratio of atoms held together by chemical bonds. Here, we discuss two classes of compounds based on the bond type that holds the atoms together: ionic and covalent. Covalent Compounds Covalent bonds are characterized by the sharing of electrons between two or more atoms. These bonds mostly occur between nonmetals or between two of the same (or similar) elements.Two atoms with similar electronegativity will not exchange an electron from their outermost shell; the atoms instead share electrons so that their valence electron shell is filled. Examples of compounds that contain only covalent bonds are methane (CH4), carbon monoxide (CO), and iodine monobromide (IBr). Ionic Compounds Ionic bonding occurs when there is a large difference in electronegativity between two atoms. This large difference leads to the loss of an electron from the less electronegative atom and the gain of that electron by the more electronegative atom, resulting in two ions. These oppositely charged ions feel an attraction to each other, and this electrostatic attraction constitutes an ionic bond. Ionic bonding occurs between a nonmetal, which acts as an electron acceptor, and a metal, which acts as an electron donor. Metals have few valence electrons, whereas nonmetals have closer to eight valence electrons; to easily satisfy the octet rule, the nonmetal will accept an electron donated by the metal. More than one electron can be donated and received in an ionic bond. Some examples of compounds with ionic bonding include NaCl, KI, MgCl2.Explanation:
#hopeithelpsstaysafe and keep wellcan you mark me as your brainliest pls?The neutralization of a 0.455 g sample of recrystallized aspirin required 38.6 mL of 0.100 M NaOH solution. An additional 25.0 mL of 0.100 M NaOH was added to the sample to hydrolyze the neutralized aspirin in the solution. The solution was heated. Phenolphthalein was added to the cooled solution and was back-titrated with 11.2 mL of 0.100 M HCl. Which of the following statements is true
A) Before the solution is titrated with HCl it is pink and when the color changes from pink to colorless, the moles of H*(aq) equals the moles of OH"(aq) used in the hydrolysis of the neutralized aspirin.
B) Before the solution is titrated with HCl it is colorless and when the color changes from colorless to pink, the moles of H*(aq) equals the excess moles of OH(aq) added.
C) 25.0 mL of 0.100 M NaOH was added to the sample to hydrolyze the neutralized aspirin in the solution. The titration with HCl allows us to determine the moles of excess OH(aq) added. Once we determine the moles of excess OH(aq), we can determine moles of OH"(aq) used in the hydrolysis of the neutralized aspirin, which is equal to the moles of aspirin in the recrystallized aspirin.
D) We can determine the moles of aspirin in the recrystallized aspirin by titrating with the 0.100 M NaOH to the neutralization point. The purpose of the hydrolysis of the neutralized aspirin and the back-titration with the 0.100 M HCl is to confirm the moles of aspirin in the recrystallized aspirin.
E) Two of the above statements are true.
Answers
Answer:
E) Two of the above statements are true.
Explanation:
The options are:
A) Before the solution is titrated with HCl it is pink and when the color changes from pink to colorless, the moles of H*(aq) equals the moles of OH"(aq) used in the hydrolysis of the neutralized aspirin. TRUE. Before the solution is titrated, there is an excess of NaOH (Basic solution, phenolphtalein is pink). Then, at equivalence point, after the addition of HCl, the pH is acidic and phenolphtalein is colorless.
B) Before the solution is titrated with HCl it is colorless and when the color changes from colorless to pink, the moles of H*(aq) equals the excess moles of OH(aq) added. FALSE. As was explained, before the titration, the solution is pink.
C) 25.0 mL of 0.100 M NaOH was added to the sample to hydrolyze the neutralized aspirin in the solution. The titration with HCl allows us to determine the moles of excess OH(aq) added. Once we determine the moles of excess OH(aq), we can determine moles of OH"(aq) used in the hydrolysis of the neutralized aspirin, which is equal to the moles of aspirin in the recrystallized aspirin. TRUE. Aspirin requires an excess of base (NaOH) for a complete dissolution (Hydrolysis). Then, we add H+ as HCl to know the excess moles of OH-. As we know the added moles of OH-, we can find the moles of OH that reacted = Moles of aspirin.
D) We can determine the moles of aspirin in the recrystallized aspirin by titrating with the 0.100 M NaOH to the neutralization point. The purpose of the hydrolysis of the neutralized aspirin and the back-titration with the 0.100 M HCl is to confirm the moles of aspirin in the recrystallized aspirin. FALSE. NaOH can be added directly unyil neutralization point because, initially, aspirin can't be dissolved completely
E) Two of the above statements are true. TRUE
Right option is:
E) Two of the above statements are true.In this exercise it is necessary to identify the true alternatives and the false alternatives. Thus, classifying these alternatives we have:
A) True
B) False
C) True
D) False
E) True
So we can say that: Two of the above statements are true.
The options are:
A) Before the solution is titrated with [tex]HCl[/tex] it is pink and when the color changes from pink to colorless, the moles of [tex]H*(aq)[/tex] equals the moles of [tex]OH"(aq)[/tex] used in the hydrolysis of the neutralized aspirin. TRUE. Before the solution is titrated, there is an excess of [tex]NaOH[/tex] (Basic solution, phenolphtalein is pink). Then, at equivalence point, after the addition of [tex]HCl[/tex], the pH is acidic and phenolphtalein is colorless.
B) Before the solution is titrated with [tex]HCl[/tex] it is colorless and when the color changes from colorless to pink, the moles of [tex]H*(aq)[/tex] equals the excess moles of [tex]OH(aq)[/tex] added. FALSE. As was explained, before the titration, the solution is pink.
C) 25.0 mL of 0.100 M NaOH was added to the sample to hydrolyze the neutralized aspirin in the solution. The titration with [tex]HCl[/tex] allows us to determine the moles of excess [tex]OH(aq)[/tex] added. Once we determine the moles of excess [tex]OH(aq)[/tex], we can determine moles of [tex]OH"(aq)[/tex] used in the hydrolysis of the neutralized aspirin, which is equal to the moles of aspirin in the recrystallized aspirin. TRUE. Aspirin requires an excess of base [tex](NaOH)[/tex] for a complete dissolution (Hydrolysis). Then, we add [tex]H+[/tex] as [tex]HCl[/tex] to know the excess moles of [tex]OH-[/tex]. As we know the added moles of [tex]OH-[/tex], we can find the moles of [tex]OH[/tex] that reacted (Moles of aspirin).
D) We can determine the moles of aspirin in the recrystallized aspirin by titrating with the [tex]0.100 M NaOH[/tex] to the neutralization point. The purpose of the hydrolysis of the neutralized aspirin and the back-titration with the [tex]0.100 M HCl[/tex] is to confirm the moles of aspirin in the recrystallized aspirin. FALSE. [tex]NaOH[/tex] can be added directly unyil neutralization point because, initially, aspirin can't be dissolved completely
E) Two of the above statements are true. TRUE
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Describe each of the following types of reactions and give one example of each: combustion, synthesis, decomposition, single replacement, double replacement.
Answers
Explanation:
Combustion Reaction:-A kind of chemical reaction in which a reaction between any combustible substance and an oxidizer takes place in order to form an oxidized product.
Eg: Fuel + O2 → CO2 + H2O.
The burning of charcoal is a combustion reaction.
Synthesis Reaction:-A synthesis reaction occurs when two or more reactants combine to form a single product.
Eg: Na + Cl → NaCl
An example of a synthesis reaction is the combination of sodium (Na) and chlorine (Cl) to produce sodium chloride (NaCl).
Decomposition Reaction:-A decomposition reaction occurs when one reactant breaks down into two or more products.
Eg: NaCl → Na + Cl
An example of a decomposition reaction is the breakdown of Sodium chloride to give sodium and chloride.
Single Replacement Reaction:-A single replacement reaction, sometimes called a single displacement reaction, is a reaction in which one element is substituted for another element in a compound.
Eg: Zn + 2 HCl → 2 ZnCl + H2
The reaction between zinc metal and hydrochloric acid to produce zinc chloride and hydrogen gas is an example of a single-displacement reaction.
Double Replacement Reaction:-A double replacement reaction is a type of chemical reaction that occurs when two reactants exchange cations or anions to yield two new products.
Eg: AgNO 3 + NaCl → AgCl + NaNO
The reaction between silver nitrate and sodium chloride to produce silver chloride and sodium nitrate is an example of a double-displacement reaction.
A student performs an experiment three times. The results are 4.52 g/mL, 4.54 g/mL, and 4.39 g/mL. Which of the following best describes these results with only the information given in this question?
a. high accuracy
b. high accuracy and high precision
c. high accuracy and low precision
d. high precision
Answers
Hydrolysis of the compound B5H9 forms boric acid, H3BO3. Fusion of boric acid with sodium oxide forms a borate salt, Na2B4O7. Part A Without writing complete equations, find the mass (in grams) of B5H9 required to form 148 g of the borate salt by this reaction sequence.
Answers
Answer:
37.09 g of B₅H₉ is required to form 148 g of borate salt( Na₂B₄O₇ )
Explanation:
Given the data in the question;
B₅H₉ → H₃BO₃ → Na₂B₄O₇
find the mass (in grams) of B5H9 required to form 148 g of the borate salt by this reaction sequence.
S M.W
B₅H₉ 63
H₃BO₃ 62
Na₂B₄O₇ 201
So, moles of Na₂B₄O₇ = 148 / 201 = 0.736
Since Boron will be conserved,
Moles of Boron atoms in Na₂B₄O₇ will be;
⇒ 4 × 0.736 = 2.944
Now, Moles of Boron in Na₂B₄O₇ = Moles of Boron in H₃BO₃ = Moles of Boron in B₅H₉
Hence,
Moles of Boron in B₅H₉ = 2.944
Moles of B₅H₉ = 2.944 / 5 = 0.5888
Mass of B₅H₉ = 0.5888 × 63 = 37.09 g
Therefore, 37.09 g of B₅H₉ is required to form 148 g of borate salt( Na₂B₄O₇ )
What is the general trend in electro negativity as you move from left to right across the periodic table
Answers
Answer:
On the periodic table, electronegativity generally increases as you move from left to right across a period and decreases as you go down a group. As a result, the most electronegative elements are found on the top right of the periodic table, while the least electronegative elements are found on the bottom left.
Explanation:
Answer:
The Electronegativity increases
Explanation:
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What is the chemical equation for F2 + At- -->
Answers
Answer:
F₂ + 2At --> 2AtF
Explanation:
Astatine is a halogen but is not diatomic. It's possible oxidation states are 1⁺, 1⁻, or 5⁺. Fluorine only has the possible oxidation states of 1⁺ or 1⁻.
At 1115 degrees Celcius, where iron is still a solid (melting point 1538 degrees Celcius), the unit cell for the most stable crystal lattice of the metal is face- centered cubic (fcc) with an edge length of 362 pm. What is the atomic radius of iron at this temperature?
Answers
Answer: The atomic radius of iron is 128 pm.
Explanation:
To calculate the radius of the metal having FCC crystal lattice, the relationship between edge length and radius follows:
[tex]4r=\sqrt{2}a[/tex]
Where,
a = edge length = 362 pm
r = atomic radius of iron = ?
Plugging values in above equation, we get:
[tex]r=\frac{\sqrt{2}\times 362}{4}\\\\a=128pm[/tex]
Hence, the atomic radius of iron is 128 pm.
Determine which of these properties would distinguish these two substances: (a) boiling point; (b) combustion analysis results; (c) molecular weight; (d) density at a given temperature and pressure. You can check on the properties of these two compounds
Answers
Answer:
(a) boiling point
(d) density at a given temperature and pressure.
Explanation:
Isomers are compounds that have the same molecular formula but different structural formulas. They differ in chemical and physical properties depending on the type of isomerism displayed by the compounds.
The compounds stated here are structural or constitutional isomers hence they possess different boiling points and densities at a given temperature and pressure owing to structural differences in the molecules.
Since they have the same molecular formula, they must yield the same result during combustion analysis and they must have the same molecular weight.
Substance
Number of Protons
Number of
Electrons
2.
3
lithium
fluorine
9
10
19
potassium
sulfur
19
18
16
19. Which substance is electrically neutral?
A. lithium
B. fluorine
Β
C. potassium
D. sulfur
20. Which substance has an overall I'charge?
Answers
Answer:
lithium 3
Explanation:
This is because lithium has three protons
the first liquid that comes out of a woman's breast after delivery is called?
Answers
The first liquid (milk) that comes out of a woman's breast after delivery is called [tex]\sf\purple{colostrum}[/tex].
[tex]\large\mathfrak{{\pmb{\underline{\orange{Happy\:learning }}{\orange{!}}}}}[/tex]
how many grams of zinc sulfide are used to produce 1.28 grams of zinc oxide?
Answers
Answer:
0.012288122055459
Explanation:
i might be wrong
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