when demand is , increases in price result in increases in total revenues, while decreases in price result in decreases in total revenue.group of answer choiceselasticcross-elasticflexibleinelastic

Answer:the set of parametric equations that represents the equation (x + 5)² + (y - 6)² = 16 is:

x = ±√(16 - (y - 6)²) - 5

y = t

Step-by-step explanation:

To determine the set of parametric equations that represents the equation (x + 5)² + (y - 6)² = 16, we can convert the equation into parametric form.

Let's assume the parameter is denoted by t.

(x + 5)² + (y - 6)² = 16

We can rewrite the equation as:

(x + 5)² = 16 - (y - 6)²

Taking the square root of both sides:

x + 5 = ±√(16 - (y - 6)²)

Now, we can introduce the parameter t and write the parametric equations:

x = ±√(16 - (y - 6)²) - 5

y = t

The set of parametric equations that represents (x + 5)^2 + (y - 6)^2 = 16 is x = -5 + 4 * cos(t) and y = 6 + 4 * sin(t).

The equation (x + 5)2 + (y − 6)2 = 16 represents a circle with the center at (-5, 6) and a radius of 4.

Parametric equations for a circle can be written as:

Where (a, b) is the center of the circle and r is the radius. So, the correct set of parametric equations for the given circle would be:

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When a country replaces a sales tax with an income tax that includes a tax on interest income, it increases the tax burden on individuals' interest earnings. Option B is correct.

This change in the tax structure affects the incentives for saving and borrowing, resulting in changes in interest rates and the equilibrium quantity of loanable funds.

With an increased tax on interest income, individuals will have a reduced incentive to save, as a higher portion of their interest earnings is subject to taxation. This leads to a decrease in the supply of loanable funds available for borrowing. As a result, the equilibrium interest rates rise due to the decrease in the supply of loanable funds.

Additionally, the higher interest rates discourage borrowing, leading to a decrease in the demand for loanable funds. Consequently, the equilibrium quantity of loanable funds falls.

Therefore, option B is correct.

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There are 4,368 different ways to select an 11-player soccer team from a group of 16 players.

The combination formula is used to determine the number of ways to select items from a collection where the order of selection is irrelevant.

We can use the combination formula to determine the number of ways to select an 11-player soccer team from a group of 16 players. The combination formula is:

n choose k = n! / (k! * (n - k)!)

where n is the total number of items, k is the number of items to choose, and ! denotes the factorial function (i.e., the product of all positive integers up to and including the argument).

In this case, we want to choose k = 11 players from a group of n = 16 players. Therefore, the number of ways to select an 11-player soccer team from a group of 16 players is:

16 choose 11 = 16! / (11! * (16 - 11)!) = 4368

Therefore, there are 4,368 different ways to select an 11-player soccer team from a group of 16 players.

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The value of composition of function is 26.

The given function is,

f(x) = 3x -9

g(x) = x²

We know that,

A function composition is an operation in which two functions, f and g, generate a new function, h, in such a way that h(x) = g(f(x)). This signifies that function g is being applied to the function x. So, in essence, a function is applied to the output of another function.

Therefore,

gof(x)  = g(f(x))

          = (3x -9)²

          = 9x² -56x + 81

Now put x = 5

Then,

gof(5) = 9x² -56x + 81

         = 26

Hence,

gof(5)  = 26

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a) The cost of one McGriddle is $2.75.

b) The equation that models the scenario is y = $2.75x + $11

c) We can buy a total of 4 McGriddles with the $30 gift card.

We have,

a.

To find the cost of one McGriddle, we can start by subtracting the remaining balance from the initial balance:

$30 - $19 = $11

Since we bought a McGriddle for 4 days, the cost of one McGriddle is:

$11 ÷ 4 = $2.75

b.

We can model this scenario with the linear equation:

y = mx + b

where y represents the remaining balance on the gift card, x represents the number of McGriddles bought, m represents the cost of one McGriddle, and b represents the initial balance.

We know that b = $30, m = $2.75, and y = $19 when x = 4.

Plugging in these values, we get:

$19 = $2.75(4) + $30

Simplifying, we get:

$19 = $11 + $11

So this equation models the scenario:

y = $2.75x + $11

c.

To find the total number of McGriddles we can afford, we can solve the equation for x when y = 0 (meaning we've used up all the money on the gift card).

$0 = $2.75x + $11

Solving for x, we get:

x = $11 ÷ $2.75

x = 4

Thus,

a) The cost of one McGriddle is $2.75.

b) The equation that models the scenario is y = $2.75x + $11

c) We can buy a total of 4 McGriddles with the $30 gift card.

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To solve the equation cosθ - 1 = -1 in the interval [0, 2π), we first add 1 to both sides of the equation to obtain cosθ = 0. Then, we recall that the cosine function equals 0 at π/2 and 3π/2 in the given interval. Thus, the solutions are θ = π/2 and θ = 3π/2.

We can add 1 to both sides of the equation to obtain cosθ = 0. This is because -1 + 1 = 0. Then, we recall the values of the cosine function in the given interval. The cosine function equals 0 at π/2 and 3π/2, so these are the solutions to the equation.

The solutions to the equation cosθ - 1 = -1 in the interval [0, 2π) are θ = π/2 and θ = 3π/2, expressed in radians in terms of π. There are two solutions, separated by a comma.

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By the Angle Bisector Theorem, we know that QT/RP = PW/QV, then W1 = TRQ.

Given: APQR is an equilateral triangle inscribed in a circle.

V is a point on the circle.

QP produced meets RV produced at T.

PR and QV intersect at W.

To prove:.W1 = TRQ

Since APQR is an equilateral triangle, then PQ = QR = RP.

QP produced meets RV produced at T. Therefore, QT = RP.

PR and QV intersect at W. Therefore, PW = QV.

By the Angle Bisector Theorem, we know that QT/RP = PW/QV.

Substituting in the values from step 1, we get QT/RP = PW/QV = 1/1.

Therefore, QT = RP = PW = QV.

Since QT = RP = PW = QV, then W1 = TRQ.

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The solution to the differential equation f '(x) = 3/square root x, where f(16) = 34, is f(x) = 6sqrt(x) + 22.

To solve this differential equation, we first integrate both sides with respect to x, which gives us f(x) = 2x^(3/2) + C. To determine the value of C, we use the initial condition f(16) = 34. Substituting x = 16 and f(x) = 34 into the equation, we get 34 = 2(16)^(3/2) + C. Solving for C, we get C = 22. Thus, the final solution to the differential equation is f(x) = 2x^(3/2) + 22.

Therefore, the function f such that f '(x) = 3/square root x and f(16) = 34 is f(x) = 6sqrt(x) + 22.

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The magnitude of the vector a⃗ is 5.41 m. This means that the length of the vector is 5.41 meters,

The question asks for the magnitude of the vector a⃗ = (4.8 m) x^ + (-2.5 m) y^, which represents a vector in two-dimensional space. The magnitude of a vector represents the length of the vector and is always a non-negative scalar quantity.

To calculate the magnitude of a two-dimensional vector, we can use the Pythagorean theorem. This theorem states that the magnitude of a vector is equal to the square root of the sum of the squares of its components. In this case, the components of the vector a⃗ are (4.8 m) in the x direction and (-2.5 m) in the y direction.

By applying the Pythagorean theorem, we can compute the magnitude of a⃗ as follows:

|a⃗| = sqrt((4.8 m)^2 + (-2.5 m)^2)

|a⃗| = sqrt(23.04 m^2 + 6.25 m^2)

|a⃗| = sqrt(29.29 m^2)

|a⃗| = 5.41 m

Therefore, the magnitude of the vector a⃗ is 5.41 m. This means that the length of the vector is 5.41 meters, and its direction is determined by the angle between the vector and the positive x-axis.

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To find the total area of the six sides of a cube, we can calculate the sum of the areas of each side. Since the cube has equal sides, we only need to find the area of one side and multiply it by 6.

The area of one side of a cube is given by the formula A = s^2, where s represents the length of each side. In this case, the length of each side is x-4. Therefore, the area of one side is (x-4)^2.

To find the total area of the six sides, we multiply the area of one side by 6:

Total area = 6 * (x-4)^2

So, the polynomial that represents the total area of the six sides of the cube with edges of length x-4 is 6 * (x-4)^2.

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The smallest number of people who live in New Jersey as per given data is equal to 3.

The smallest number of people needed to guarantee that there are at least 60 people who live in the same county in New Jersey,

We can consider the worst-case scenario.

Assuming the distribution of people across the counties is such that each county has the same number of people,

Calculate the minimum number of people needed.

Let us assume x is the number of people in each county.

To guarantee that there are at least 60 people in the same county,

Set up the following inequality,

21 × x ≥ 60

Simplifying the inequality,

⇒ x ≥ 60 / 21

⇒ x ≥ 20/7

Since x represents the number of people in each county, it must be a whole number.

The smallest number of people needed is the smallest integer greater than or equal to 20/7.

The smallest integer greater than or equal to 20/7 is 3.

Therefore, smallest number of people needed to guarantee that there are at least 60 people who live in same county in New Jersey is 3.

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To verify the identity sin(θ) / 1-cos^2θ = cosθ, we start by manipulating the left-hand side of the equation using trigonometric identities. We can use the Pythagorean identity cos^2θ + sin^2θ = 1 to rewrite the denominator as 1-sin^2θ. Then, using the reciprocal identity sinθ/cosθ = tanθ, we can simplify the left-hand side to 1/cosθ.

We can start by manipulating the left-hand side of the equation using trigonometric identities:

sin(θ) / (1-cos^2θ)

= sin(θ) / sin^2θ (using the Pythagorean identity cos^2θ + sin^2θ = 1)

= 1/cosθ (using the reciprocal identity sinθ/cosθ = tanθ)

Now, we can simplify the right-hand side using the definition of cosine:

cosθ = cosθ/1 (multiplying numerator and denominator by 1)

= sin^2θ/cosθsinθ (using the definition of sine and cosine: sinθ = opposite/hypotenuse, cosθ = adjacent/hypotenuse)

= sinθ/sin^2θ (using the Pythagorean identity cos^2θ + sin^2θ = 1)

= 1/cosθ (using the reciprocal identity sinθ/cosθ = tanθ)

Therefore, we have shown that:

sin(θ) / (1-cos^2θ) = cosθ

The identity is verified.

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Answer: 0.54

Step-by-step explanation:

13/24 is 0.54166.....

So if you round that by a tenth, it would be 0.54 because 1 is ower than five is its the same

Answer:

0.5

Step-by-step explanation:

13/24 = 0.541666...

by rounding it to the nearest tenth, it will be 0.5 since the succeeding number from the tenth is lower than 5

(a) The combinations are,

Number of 6 player games = 8, if number of 2 player games = 1.

Number of 2 player games = 22, if number of 6 player games = 1.

Number of 6 player games = 7, if number of 2 player games = 4.

Number of 2 player games = 13, if number of 6 player games = 4.

(b) The number of 6 player games is 6 and the number of 2 player games is 7.

Given that total number of athletes = 50

Players needed for 6 player game = 6 and players needed for 2 player games = 2

(a) When number of 2 player games = 1,

Number of athletes left = 50 - (1 × 2) = 48

Number of 6 player games = 48/6 = 8

When number of 6 player games = 1,

Number of athletes left = 50 - (1 × 6) = 44

Number of 2 player games = 44/2 = 22

When number of 2 player games = 4,

Number of athletes left = 50 - (4 × 2) = 42

Number of 6 player games = 42/6 = 7

When number of 6 player games = 4,

Number of athletes left = 50 - (4 × 6) = 26

Number of 2 player games = 26/2 = 13

(b) Let x represents the number of 2 player games and y represents the number of 6 player games.

We get the linear equations,

x + y = 13

AND

2x + 6y = 50

From first equation,

y = 13 - x

Substituting this to second equation,

2x + 6(13 - x) = 50

2x + 78 - 6x = 50

-4x = -28

x = 7

So, y = 13 - 7 = 6

Hence the number of 2 player games played is 7 and the number of 6 player games played is 6.

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Answer:

Step-by-step explanation:

total cashiers 13

total stock clerks 27

total deli personnel 5

total total 45

total married 23

total not married 22

a. 27+11=38

38/45=.84

answer is 84%

b.22/45=49%

c. 13+17=30

30/45=67%

d. 8/23= 35%

e. 15/27= 56%

f. 8/45= 18%

If there will be 6 cheese sections that are 3 1/3 inches long and 5 vegetable sections that are 4 3/8 inches long, the length of the giant sandwich is 41.875 inches.

To find the total length of the sandwich, we need to add the lengths of all the cheese and vegetable sections together.

First, we need to convert the mixed number 3 1/3 to an improper fraction:

3 1/3 = (3 x 3 + 1)/3 = 10/3

Similarly, we need to convert 4 3/8 to an improper fraction:

4 3/8 = (4 x 8 + 3)/8 = 35/8

Now we can calculate the total length of the sandwich by multiplying the length of each section by the number of sections and adding them together:

Total length = (6 x 10/3) + (5 x 35/8)

= 20 + 21.875

= 41.875 inches

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The expression sum of i from 1 to n of sum of j from 1 to n of (i-j) squared can be rewritten as the sum of squares of all the differences (i-j), where i and j range from 1 to n.

The given expression, sum of i from 1 to n of sum of j from 1 to n of (i-j) squared, is equal to n squared times (n - 1) squared divided by 6.

To prove this, we can use the formula for the sum of squares of the first n natural numbers, which is n(n+1)(2n+1)/6. We can rewrite the given expression as the sum of the squares of all the differences (i-j), where i and j range from 1 to n.

Expanding the squares, we get

(i-j)^2 = i^2 - 2ij + j^2. Summing over all i and j,

we obtain the expression 2sum(i^2) - 2sum(ij) + 2sum(j^2).

Using the formulas for the sum of squares and the sum of products of the first n natural numbers, we can simplify this expression to

n(n+1)(2n+1)/3 - n(n+1)^2/2 + n(n+1)(2n+1)/3.

Simplifying further, we get n^2(n+1)^2/4, which is equal to n squared times (n - 1) squared divided by 6, as required.

In summary, the expression sum of i from 1 to n of sum of j from 1 to n of (i-j) squared can be rewritten as the sum of squares of all the differences (i-j), where i and j range from 1 to n. Using the formulas for the sum of squares and the sum of products of the first n natural numbers, we can simplify this expression to n squared times (n - 1) squared divided by 6.

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The expected value of x is e(√(x)) = e(√(2)) ≈ 1.6487.

The number of possible outcomes when tossing an unbiased coin four independent times is 2^4 = 16, and the probability of obtaining x heads is given by the binomial distribution:

P(x) = (4 choose x) * (1/2)^4 = (4!/(x!(4-x)!) * 1/16

Thus, the expected value of x is:

E(x) = Σ[xP(x)] from x=0 to x=4

= 0*(1/16) + 1*(4/16) + 2*(6/16) + 3*(4/16) + 4*(1/16)

= 2

So, e(√(x)) = e(√(2)) ≈ 1.6487.

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The best graphical representation to display the data would be a histogram.

Since the data is categorical (the type of item purchased), a histogram would be the most appropriate way to display the data.

A histogram would show the number of purchases for each category of item purchased, while a pie chart would show the proportion of purchases for each category.

Both of these graphical representations would be easy to read and would allow for easy comparison between the different categories of items purchased.

A box plot, line plot, or stem-and-leaf plot would not be appropriate for this type of data.

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Answer: Approximately 28 copies per minute.

Step-by-step explanation:

To find the number of copies the machine makes per minute, we need to first convert the time to minutes.

4 minutes and 45 seconds can be written as 4 + 45/60 = 4.75 minutes.

Next, we can divide the total number of copies (133) by the total time in minutes (4.75):133 copies / 4.75 minutes ≈ 28 copies per minute

Therefore, the copy machine makes approximately 28 copies per minute.

The element (1 2 3 4 5)(1 2 3 4 5 6 7 8 9 10) in A12 has order 30.:

To find an element in A12 of order 30, we can start by considering the cycle structure of permutations of order 30. Since 30 is a product of distinct primes, the only possible cycle types for permutations of order 30 in S12 are (2,3,5), (2,2,3,5), and (2,2,2,3,3). However, not all of these cycle types are possible in A12, since some permutations of these cycle types will have an odd number of transpositions.

One possible element in A12 of order 30 is (1 2 3 4 5)(1 2 3 4 5 6 7 8 9 10), which is a product of a 5-cycle and a 10-cycle. To see that this element is even, note that it can be expressed as (1 5)(1 4 3 2)(1 10 9 8 7 6 5 4 3 2), which is a product of three transpositions. To see that the order of this element is indeed 30, note that applying this element 30 times results in the identity permutation, and no power less than 30 yields the identity permutation. Therefore, (1 2 3 4 5)(1 2 3 4 5 6 7 8 9 10) is an element in A12 of order 30.

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The statistical method that you are referring to is called multiple regression analysis. This method is used to assess the relationship between two variables while controlling for the effects of other variables, also known as covariates.

Multiple regression analysis is a common tool in social science research and is used to explore and explain the relationships between variables.

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The new wavelength of the light predominantly reflected is 955.08 nm.

and the thickness of film is 230.37nm.

The minimum thickness of the soap film can be found using the equation for constructive interference of reflected light: 2nt = mλ, where n is the refractive index of the soap, t is the thickness of the film, m is an integer .

(in this case m = 1 for the first order maximum), and λ is the wavelength of the reflected light. Solving for t, we get t = (mλ)/(2n) = (1)(622 nm)/(2(1.35)) = 230.37 nm.

When the soap film is on the sheet of glass, the wavelength of the reflected light changes due to the change in refractive index. The equation for the new wavelength can be found using the formula for the index of refraction: n = c/v, where c is the speed of light in a vacuum and v is the speed of light in the medium.

Rearranging this equation, we get v = c/n. Thus, the new wavelength λ' can be found by multiplying the original wavelength by the ratio of the speeds of light in air and in the soap film on the glass: λ' = λ(c/n_air)/(c/n_soap) = λ(n_soap/n_air) = 622 nm(1.54/1) = 955.08 nm.

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The equation represents the linear relationship of x-values and the y-values in the table is b y = -5x - 5

From the question, we have the following parameters that can be used in our computation:

x     y

-1    -11

1     -1

A linear equation is represented as

y = mx + c

Using the points in the table, we have

-m + c = -11

m + c = -1

When the equations are added, we have

2c = -10

So, we have

c = -5

This means that

5 + c = -1

So, we have

c = -6

So, the equation is y = -5x = 6

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The circumference of the swimming pool is 66 feet

The circumference is the perimeter of a circle or ellipse. That is, the circumference would be the arc length of the circle, as if it were opened up and straightened out to a line segment.

The circumference of the circle is expressed as;

C = 2πr

Where c is the circumference, r is the radius, we are yo take π as 22/7

radius = diameter /2. Therefore we can say

C = πd

C = 22/7 × 21

C = 22 × 3

C = 66 feet

therefore the circumference of the pool is 66 feet

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There are 216 different possible combinations for the lock.

What is linear combinations?

In mathematics, a linear combination is a sum of scalar multiples of one or more variables. More formally, given a set of variables x1, x2, ..., xn and a set of constants a1, a2, ..., an, their linear combination is given by the expression:

a1x1 + a2x2 + ... + anxn

Since there are three dials on the combination lock and each dial can be set to one of six numbers, the total number of possible combinations is the product of the number of options for each dial.

Therefore, the total number of combinations is: 6 x 6 x 6 = 216

So there are 216 different possible combinations for the lock.

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Thus, the general solution is y(x) = -x + 2x^3 + c₁x + c₂x^3.

To find the general solution of the differential equation x^2y'' + 3xy' + 3xy = 4x^7, we can use the method of variation of parameters.

Given that {x, x^3} is a fundamental set of solutions of the homogeneous equation x^2y'' - 3xy' + 3y = 0, we can use these solutions to find the particular solution.

Let's assume the particular solution has the form y_p = u(x)x + v(x)x^3, where u(x) and v(x) are unknown functions.

Differentiating y_p:

y_p' = u'x + u + v'x^3 + 3v(x)x^2

Differentiating again:

y_p'' = u''x + 2u' + v''x^3 + 6v'x^2 + 6v(x)x

Substituting these derivatives into the original differential equation, we have:

x^2(u''x + 2u' + v''x^3 + 6v'x^2 + 6v(x)x) + 3x(u'x + u + v'x^3 + 3v(x)x^2) + 3x(u(x)x + v(x)x^3) = 4x^7

Simplifying and grouping like terms:

x^3(u'' + 3v') + x^2(2u' + 3v'' + 3v) + x(u + 3v' + 3v) + (2u + v) = 4x^5

Setting the coefficients of each power of x to zero, we get the following system of equations:

x^3: u'' + 3v' = 0

x^2: 2u' + 3v'' + 3v = 0

x^1: u + 3v' + 3v = 0

x^0: 2u + v = 4

Solving this system of equations, we find:

u = -1

v = 2

Therefore, the particular solution is y_p = -x + 2x^3.

The general solution of the differential equation x^2y'' + 3xy' + 3xy = 4x^7 is given by the sum of the particular solution and the homogeneous solutions:

y(x) = y_p + c₁x + c₂x^3

where c₁ and c₂ are arbitrary constants.

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1. The derivative of y = (4x⁴ - 5)(-x⁴ + x² + 2) is:

(4x⁴ - 5)(-4x³ + 2x) + (-x⁴ + x² + 2)16x³

2. The derivative of y = (x⁴ + 4x² - 4) / (2x³ - 4) is:

[(2x³ - 4)(4x³ + 8x) - (x⁴ + 4x² - 4)6x²] / (2x³ - 4)²

1. The derivative of y = (4x⁴ - 5)(-x⁴ + x² + 2) can be obtain as follow

Let

Thus,

du/dx = 16x³

dv/dx = -4x³ + 2x

Finally, the derivative of y is obtained as follow:

d(uv)/dx = udv/dx + vdu/dx

dy/dx = (4x⁴ - 5)(-4x³ + 2x) + (-x⁴ + x² + 2)16x³

Thus, the derivative of y is (4x⁴ - 5)(-4x³ + 2x) + (-x⁴ + x² + 2)16x³

2. The derivative of y = (x⁴ + 4x² - 4) / (2x³ - 4) can be obtain as shown below:

Let

Thus,

du/dx = 4x³ + 8x

dv/dx = 6x²

Finally, the derivative of y is obtained as follow:

d(uv)/dx = (vdu/dx - udv/dx) / v²

dy/dx = [(2x³ - 4)(4x³ + 8x) - (x⁴ + 4x² - 4)6x²] / (2x³ - 4)²

Thus, the derivative of y is  [(2x³ - 4)(4x³ + 8x) - (x⁴ + 4x² - 4)6x²] / (2x³ - 4)²

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