when creating a hypothesis,it must be written as an “if...then...” statement.

True or false

Answer:

A)        d = 6.1857 10⁻⁵ m

Explanation:

In the double-slit experiment the constructive interference is given by the expression

          d sin θ = m λ

          d =[tex]\frac{m \lambda }{sin \theta}[/tex]

let's use the relationship between speed, wavelength and frequency

          c = λ f

          λ = c / f

          λ = 3 10⁸ / 5.60 10¹²

          λ = 5.357 10⁻⁵ m

I do not know India in order of interference, we will assume that  m= 1

          d = 1  5,357 10⁻⁵ / sin 60

          d = 6.1857 10⁻⁵ m

Answer: its d

Explanation:

Answer:

Explanation:

Given that:

[tex]mass \ m_ 1 = 11.0 \ kg[/tex]

[tex]mass \ m_2 = 19.0 \ kg[/tex]

[tex]mass \ of \ the \ pulley\ M = 7.90 \ kg[/tex]

[tex]Radius \ of \ the \ pulley = 0.200\ m[/tex]

1) Provided that the mass in [tex]m_2[/tex] is greater than the mass we have in [tex]m_1[/tex], then likewise the tension we have in [tex]T_2[/tex] will be greater than the tension in [tex]T_1[/tex]

Using Newton's second law to mass [tex]m_1[/tex], we have:

[tex]m_2g - T_2 = m_2 a \\ \\ T_1 = m_1 g +m_1 a \\ \\ T_1= m_1 (g+a) --- (1)[/tex]

By using the second law, we have:

[tex]m_2g - T_2 = m_2a \\ \\ T_2 = m_2 (g-a)---(2)[/tex]

For the pulley, let's use the torque equation, so we have:

[tex]T_2 r -T_1 r = I \alpha \\ \\ T_2r -T_1r = \Big ( \dfrac{Mr^2}{2}\Big) \dfrac{a}{r} \\ \\ T_2 -T_1 = \dfrac{Ma}{2} ---- (3)[/tex]

Altogether, from equation (1)(2) and (3), we have:

[tex]m_2(g-a) -m_1 (g+a) = \dfrac{Ma}{2} \\ \\ m_2g -m_2a -m_1g-m_1a = \dfrac{Ma}{2} \\ \\ a = \dfrac{(m_2 -m_1) g}{(m_1 + m_2 + \dfrac{M}{2})} \\ \\ a = \dfrac{(19.0 \ kg - 11.0 \ kg ) ( 9.8 \ m/s^2)}{(19.0 \ kg + 11.0 \ kg + \dfrac{7.90 \ kg }{2} )}[/tex]

[tex]a = 2.31 \ m/s^2[/tex]

Also; from equation (1), the tension in the string is:

[tex]T_1[/tex] = (11.0 kg ) ( 9.8 + 2.31) m/s²

[tex]T_1[/tex] = 133.21 N

[tex]T_1[/tex] ≅ 133 N

From equation (2):

[tex]T_1[/tex] = m_2(g-a)

[tex]T_1[/tex] = (19.0 kg) ( 9.8 - 2.31) m/s²

[tex]T_1[/tex] = 142.31 N

[tex]T_1[/tex]  = 142 N

Answer: c is correct

Explanation: i did this

Answer:

2.72*10^-7m

Explanation:

Using the formula

v = fλ

v is the speed

f is the frequency

λ is the wavelength

Substitute for λ

λ = v/f

λ = 2.05 x 10^8/7.55 x 10^14

λ = 2.05/7.55 * 10^{8-14}

λ = 0.272 * 10^-6

λ = 2.72*10^-7m

Hence the wavelength of the wave in carbon tetrachloride is 2.72*10^-7m

Answer:

1st speed 2.velocity 3.speed4.velocity5.velocity6.speed

Answer:

v = 1.48 m / s

Explanation:

This is an exercise in conserving the moment. Let's define a reference system made up of the student, the scooter and the collected mass. For this system the forces during the collection are internal and element and conserves

initial interim. Before picking up the merchandise

       p₀ = M v₀

final instant. After picking up the object

       p_f = (M + m ') v

how the moment was created

        p₀ = p_f

       M v₀ = (M + m) v

let's calculate

       v = [tex]\frac{M}{m+ M}[/tex]  vo

       v = 78.2 / (6.4 +78.2) 1.60

       v = 1.48 m / s

Answer:

R = (18 ± 2) 10¹ Ω

ΔR = 2 10¹ Ω

Explanation:

Ohm's law relates voltage to current and resistance

           V = i R

            R = [tex]\frac{V}{i}[/tex]V / i

the absolute error of the resistance is

           ΔR = | [tex]| \frac{dR}{DV} | \ \Delta V + | \frac{dR}{di} | \ \Delta i[/tex]

the absolute value guarantees the worst case, maximum error

           ΔR = [tex]\frac{1}{i} \Delta V+ \frac{V}{i^2} \Delta i[/tex]

The error in the voltage let be approximate, if we use a scale of 10 V, in general the scales are divided into 20 divisions, the error is the reading of 1 division, let's use a rule of direct proportion

          ΔV = 1 division = 10 V / 20 divisions

          ΔV = 0.5 V

The current error must also be approximate, if we have the same number of divisions

           Δi = 50 mA / 20 divisions

           Δi = 2.5 mA

let's calculate

          ΔR = [tex]\frac{1}{45.5 \ 10^{-3}} \ 0.5 + \frac{8.2}{(45.5 \ 10^{-3})^2 } \ 2.5 \ 10^{-3}[/tex]

          ΔR = 10.99 + 9.9

          ΔR = 20.9 Ω

The absolute error must be given with a significant figure

          ΔR = 2 10¹ Ω

the resistance value is

          R = 8.2 / 45.5 10-3

          R = 180 Ω

the result should be

          R = (18 ± 2) 10¹ Ω

Answer:

Displacement and Velocity

Answer:

I am calculating the total area of a solar panel for a particular load demand by ... designing according to energy demand for a day then how will it affect total solar area? ... Total Power Output=Total Area x Solar Irradiance x Conversion Efficiency ... would need is a 1 m2 solar panel to produce 1000 Watts of electrical energy.

Explanation:

Answer:

I would say color.

Explanation:

Because for me most of the time the warm color mean It hot. and the cool color most likily to mean cold  

Answer:

Color

Explanation:

The temperature of a star is determined by the color. lol :)

Answer:

the magnetic field experienced by the electron is 0.0511 T

Explanation:

Given the data in the question;

Wavelength λ = 21 cm = 0.21 m

we know that Bohr magneton μ[tex]_B[/tex] is 9.27 × 10⁻²⁴ J/T

Plank's constant h is 6.626 × 10⁻³⁴ J.s

speed of light c = 3 × 10⁸ m/s

protein spin causes magnetic field in hydrogen atom.

so

Initial potential energy = -μ[tex]_B[/tex]B × cos0°

= -μ[tex]_B[/tex]B × 1

= -μ[tex]_B[/tex]B

Final potential energy = -μ[tex]_B[/tex]B × cos180°

= -μ[tex]_B[/tex]B × -1

= μ[tex]_B[/tex]B

so change in energy will be;

ΔE = μ[tex]_B[/tex]B - ( -μ[tex]_B[/tex]B )

ΔE = 2μ[tex]_B[/tex]B

now, difference in energy levels will be;

ΔE = hc/λ

2μ[tex]_B[/tex]B = hc/λ

2μ[tex]_B[/tex]Bλ = hc

B = hc /  2μ[tex]_B[/tex]λ

so we substitute

B = [(6.626 × 10⁻³⁴) × (3 × 10⁸)]  /  [2(9.27 × 10⁻²⁴) × 0.21 ]

B = [ 1.9878 × 10⁻²⁵ ]  /  [ 3.8934 × 10⁻²⁴ ]

B = 510556326.09

B = 0.0511 T

Therefore, the magnetic field experienced by the electron is 0.0511 T

Answer:

d.) form supernovas

Explanation:

Learned this in physical school last year

Explanation:

[tex]let \: coefficient \: of \: friction \: be \: \gamma \\ from \: third \: law \: of \: solid \: friction \\friction \: force = \gamma \times normal \: reaction \\ F = \gamma R \\ but \: R = mg = 240N \\ \gamma = \frac{ F}{R} \\ \gamma = \frac{12}{240} \\ \gamma = \frac{1}{20} [/tex]

Answer:

I cheated on

Spanish

ELA

history

Explanation:

Answer:

thx

Explanation:

Answer:

The answer is C, I just guessed and got it right lol

Explanation:

The complete options are;

A. The average kinetic energy of their particles is the same.

B. The total kinetic energy of their particles is equal.

C. Heat flows from the larger object to the smaller object.

D. Heat flows from the object with higher potential energy to the object with lower potential energy.

Answer:

Explanation:

From the relationship between average kinetic energy and temperature, we have the formula;

E_k = (3/2)kT

Where;

k is a constant known as boltzmann constant.

T is known as temperature

We can see that at the same temperature (T), kinetic energy will remain the same because from the formula, E_k depends km only the temperature.

Thus, average kinetic energy of their particles saying that.

Answer:

-33750 N

Explanation:

Use coulomb's law: [tex]\frac{k(q1)(q2)}{r^{2} } = \frac{(9x10^{9})(-5x10^{-6})(3x10^{-6})}{0.002^{2} } = -33750 N[/tex]

Answer:

The magnitude of the angular acceleration of the wheel is 14.53 rad/s².

Explanation:

The angular acceleration can be found by using the following equation:

[tex] \omega_{f}^{2} = \omega_{0}^{2} + 2\alpha \Delta \theta [/tex]  (1)

Where:

[tex] \omega_{f}[/tex]: is the final angular velocity = 18 rad/s

[tex]\omega_{0}[/tex]: is the initial angular velocity

α: is the angular acceleration =?

Δθ = 19 rev*(2π/1 rev) = 119.4 rad

The initial angular velocity can be found knowing that the wheel turns through 19 revolutions during a 3 s time interval:

[tex] \omega_{f} = \omega_{0} + \alpha t [/tex]

Where:  

t: is the time = 3 s

By solving the above equation for ω₀ we have:

[tex] \omega_{0} = \omega_{f} - \alpha t [/tex]   (2)

Now, by entering equation (2) into (1) we have:

[tex] \omega_{f}^{2} = (\omega_{f} - \alpha t)^{2} + 2\alpha \Delta \theta [/tex]                        

[tex] \omega_{f}^{2} = \omega_{f}^{2} - 2\omega_{f} \alpha t + (\alpha t)^{2} + 2\alpha \Delta \theta [/tex]                              

[tex](9\alpha)^{2} + 130.8 \alpha = 0[/tex]  

By solving the above equation for "α" we have:

α = -14.53    

The minus sign means that the wheel is decelerating.

Hence, the angular acceleration of the wheel is -14.53 rad/s².                                                                                            

I hope it helps you!

Answer:

A) q_o = 0.001 C

B) I = 0.001•e^(-t)

C) V_c = 1000e^(-t)

D) V_r = 1000e^(-t)

E) P = e^(-2t) watts

Explanation:

A) We are given;

Initial stored energy; U_o = 0.5 J

Capacitance; C = 1.0μF = 1 × 10^(-6) F

To find the charge, we will use the formula for energy in capacitors which is given by;

U = q²/2C

Thus, since we are dealing with initial energy, U is U_o and q is q_o

Making q the subject, we have;

q_o = √2CU_o

q_o = √(2 × 1 × 10^(-6) × 0.5)

q_o = 0.001 C

B) The charge as a function of time is expressed as;

q = q_o•e^(-t/RC)

Now the current is gotten by differentiating the charge function. Thus;

I = (q_o/RC)•e^(-t/RC)

Where;

R is Resistance = 1.0MΩ = 1 × 10^(6) Ω

C is capacitance = 1 × 10^(-6) F

(q_o/RC) is the initial current = 0.001/(1 × 10^(6) × 1 × 10^(-6))

(q_o/RC) = 0.001 A

Thus;

I = 0.001•e^(-t/(1 × 10^(6) × 1 × 10^(-6)))

I = 0.001•e^(-t)

C) Formula for potential difference across the capacitor is;

V_c = IR

I = 0.001•e^(-t)

R = 1 × 10^(6) Ω

Thus;

V_c = 1 × 10^(6) × 0.001•e^(-t)

V_c = 1000e^(-t)

D) Potential difference across the resistor will be the same as that across the capacitor because the resistor is connected in parallel to the capacitor.

Thus;

V_r = V_c = 1000e^(-t)

E) rate at which thermal energy is produced is basically the power.

Thus;

P = (V_r)²/R

P = (1000²e^(-2t))/1 × 10^(6)

P = e^(-2t) watts

Answer:

Explanation:

The light waves in the reflected sunlight are horizontally polarized, which illustrates that they oscillate at a [tex]90^o[/tex] angle related to a vertical line.

Depending on the condition of the height of the light, the glare can be almost entirely horizontally polarized. Furthermore, all reflections from over-water surfaces are partially polarized. The water becomes more translucent when using polarized sunglasses.

If polarized sunglasses are to be efficient against solar glare, the transmission axis should be positioned at an angle of [tex]\theta = 45^{o}[/tex]

Answer:

sum of volumes = (16.6 ± 0.03) cm³

and difference of volumes = (3.8 ± 0.03) cm³

Explanation:

Here,

V₁ = (10.2 ± 0.02) cm³ and V₂ = (6.4 ± 0.01) cm³.

Now,

∆V = ± (∆V₁ + ∆V₂)

= ± (0.02 + 0.01) cm³

= ± 0.03 cm³

V₁ + V₂ = (10.2 + 6.4) cm³ = 16.6 cm³ and

V₁ - V₂ = (10.2 - 6.4) cm³ = 3.8 cm³

Thus, sum of volumes = (16.6 ± 0.03) cm³

and difference of volumes = (3.8 ± 0.03) cm³

-TheUnknownScientist

Answer:

I hope it's helpful .............

Answer:

After a little online search, I've found the graph of this question, the graph can be seen below.

a) The displacement is defined as the distance between the final position and the initial position.

In the graph, the vertical axis represents the distance. We also can see that both of the lines start in position 0, so at any given time, the displacement of the objects is given by the vertical position in the graph.

Thus, at t = 2 seconds, both lines have the same y-value, this means that the displacements have the same magnitude.

b) The velocity is related to the slope of the curve,

We can clearly see that the slope of graph A and the slope of gaph B are different at t = 2 seconds (graph A is steeper) then we can conclude that the velocities do not have the same magnitude.

c) By Newton's second law, we know that F = m*a

Force equals mass times acceleration.

Acceleration is the rate of change of velocity. When the position graph is a straight line, in any point of the line the slope will be the same, thus the object has always the same velocity, thus the object is not accelerated.

If we do not have a straight line (like in graph A) then the velocity is changing, then we have acceleration, then we have a force.

Then object A has a greater net force (because object B has a net force equal to 0)

d) It is already explained in point c.

Answer:

Who is liang

Explanation:

i need more info if i'm going to help you out

He is most likely trying to figure out how to upload the picture to Brainly.

He knows that his question cannot be answered as long as nobody can see the picture.

Answer: I like your profile picture

Explanation:

Answer:

The base of taller buildings are made broader because it reduces the pressure exerted on the ground so that they do not sink in due to the extremely high pressure of the building.

Explanation:

hope thiss helpss~!

A broad base is used to engage or recruit a diverse range of individuals to broad-based environmentalism.

Find out more about the broader base here:

brainly.com/question/14313691

Answer:

B. As gravity increases weight increases and as gravity decreases weight decreases

Explanation:

Option B is the correct answer.

From the information given, we can deduce that as the gravity increases, the weight also increases and as the gravity decreases, the weight decreases as well.

This is true from the  given table. On earth, the gravity of the man was 9.8m/s² and his weight 588N. But get to space, moon precisely, the gravity reduced to 1.62m/s². Then we discover that such decrease in his gravity also led to the sharp decrease in the weight. The weight decreased from 588N on earth to 96N on the moon.

This actually reveals that weight and gravity are related in a way. Weight of an object is known to be the force of gravity on the object. The weight actually vary as a result of varying gravity.

Answer: b

since the pull of gravity on the moon is less we weigh less.