What’s the answer to this question?

Answer:

see below

Step-by-step explanation:

9 dollars / 33 lbs = .272727 dollars per lb

.39 / 1 lbs = .39 per lb

The large bag is less expensive

Step-by-step explanation:

33lb bag = $9.00

1lb = $0.39

$9.00 bag per pound is $.0.27 per pound

If I bought 33, 1 pound bags it would cost $12.87

cheaper by $ 3.87 to buy the 9lb bag.

Answer:

$200

I hope this helps!

Answer:

200rupees

Step-by-step explanation:

according to the question ,kajol has 75 rupees

amount earned=3/8* amount earned

                        =75/3*8

                         =200 rupees

Answer:78.14cm^2

Step-by-step explanation:

Answer:  c) rotation of 180° & shift right 1 unit and down 2 units

Step-by-step explanation:

Rotation of 180° changes the signs of x and y

(x, y)   →   (-x, -y)

Shift right one unit adds 1 to x, Shift two down subtracts 2 from y

(-x, -y)   →   (-x + 1, -y - 2)

  (x, y)          (-x + 1, -y - 2)  

(-1, -2)    →       (2, 0)

(-4, -1)    →       (5, -1)

(-4, -3)   →       (5, 1)

Answer:

D. Quadratic parent function.

Step-by-step explanation:

Answer:

75435912

Step-by-step explanation:

1495486+73940426

= 75435912

Answer:

75,435,912

Step-by-step explanation:

=> 1495486 + 73940426

Using Calculator

=> 75,435,912

Answer:

Answer is Y

Step-by-step explanation:

Answer:

The answer is option B.

Step-by-step explanation:

Using the expression

[tex] {e}^{ ln(x) } = x[/tex]

[tex] {e}^{ ln(4) } = 4[/tex]

Hope this helps you

Answer:

Step-by-step explanation:

Let the five courses with their corresponding credit hours be represented as shown;

FST 201 = 4

FST 203 = 5

FST 112 = 1

FST 219 = 5

FST 223 = 4

If a student earned grades of​ B, B,​ A, C, and D respectively in those courses with the following grading system  A =​4, B =​3, C =​2, D =​1, and F =0, before we can get the student GPA, we need to know the total credit point for the five courses.

Credit point for each course = Number of credit hour * point for each grade

FST 201 = 4 * 4 = 16points (A)

FST 203 = 5 * 4 = 20points (A)

FST 112 = 1 * 4  = 4points (A)

FST 219 = 5 * 4 = 20points (A)

FST 223 = 4 * 4 = 16points (A)

Total credit point = 16+20+4+20+16 = 76points

Total credit point gotten by the student is calculated as thus;

FST 201 = 4 * 3 = 12points (B)

FST 203 = 5 * 3 = 15points (B)

FST 112 = 1 * 4  = 4points (A)

FST 219 = 5 * 2 = 10points (C)

FST 223 = 4 * 1 = 4points (D)

Total credit point gotten by the student = 45points.

student's Grade Point Average​ (GPA) = Total credit point/Total credit point gotten by the student = 76/45 = 1.69 (to 2dp)

Answer:

99% chance tommy has it

Step-by-step explanation:

cuz do da math

Answer:

Well a shape reflecting across the x axis will look like some thing in the image below.

Look at both images.

Answer:

this lesson, we will investigate the relationship between the distance traveled, the rate or speed or travel, and the time that it takes to travel that distance at that rate.  We will also look at a few other related products.

Distance  =  (Rate)(Time)

The equation that relates distance, rate, and time is

        d  =  rt

Where d is the distance traveled, r is the rate, and t is the time.  On the CAHSEE exam, you will be given two of these and will be asked to use the above equation to find

Answer:

2.5 hours

Step-by-step explanation:

First, try rewriting Jenny's speed in it's fraction form: 6 mi/hr

Next, use the units to set up an equation that relates Jenny's speed to the distance they want to travel. Let's call the unknown time t:

6mi/hr=15mi/t

1/t=6/15 (mi/hr•1/mi)

t=15/6 (hrs/mi•mi)= 15/6 (hrs•mi/mi)= 15/6 hrs

t=2.5hrs

So it'd take Jenny 2.5hrs at 6mph to go 15 miles. The key here is to keep track of the units. You can treat them like fractions and reduce them away as if they were numbers or variables.

Answer:

7.75

Step-by-step explanation:

6-4=2

2 times the square root of 3=3.46410161514

square root of 5 times 3.46410161514=7.74596669242

to 2dp=7.75

Answer:

No solutions.

Step-by-step explanation:

5x = 8x^-1/3

Divide 8 into both sides.

5/8x = x^-1/3

Divide both sides by x.

5/8 = x^-4/3

Multiply both sides by the exponent -3/4.

5/8^-3/4 = x

1.422624 = x

Plug in 1.422624 for x to check.

It does not work. There are no real solutions.

Answer:

a) The 95% CI for the true average porosity is (4.51, 5.19).

b) The 98% CI for true average porosity is (4.11, 5.01)

c) A sample size of 15 is needed.

d) A sample size of 101 is needed.

Step-by-step explanation:

a. Compute a 95% CI for the true average porosity of a certain seam if the average porosity for 20 specimens from the seam was 4.85.

We have that to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:

[tex]\alpha = \frac{1-0.95}{2} = 0.025[/tex]

Now, we have to find z in the Ztable as such z has a pvalue of [tex]1-\alpha[/tex].

So it is z with a pvalue of [tex]1-0.025 = 0.975[/tex], so [tex]z = 1.96[/tex]

Now, find the margin of error M as such

[tex]M = z*\frac{\sigma}{\sqrt{n}}[/tex]

In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.

[tex]M = 1.96*\frac{0.78}{\sqrt{20}} = 0.34[/tex]

The lower end of the interval is the sample mean subtracted by M. So it is 4.85 - 0.34 = 4.51

The upper end of the interval is the sample mean added to M. So it is 4.35 + 0.34 = 5.19

The 95% CI for the true average porosity is (4.51, 5.19).

b. Compute a 98% CI for true average porosity of another seam based on 16 specimens with a sample average of 4.56.

Following the same logic as a.

98% C.I., so [tex]z = 2.327[/tex]

[tex]M = 2.327*\frac{0.78}{\sqrt{16}} = 0.45[/tex]

4.56 - 0.45 = 4.11

4.56 + 0.45 = 5.01

The 98% CI for true average porosity is (4.11, 5.01)

c. How large a sample size is necessary if the width of the 95% interval is to be 0.40?

A sample size of n is needed.

n is found when M = 0.4.

95% C.I., so Z = 1.96.

[tex]M = z*\frac{\sigma}{\sqrt{n}}[/tex]

[tex]0.4 = 1.96*\frac{0.78}{\sqrt{n}}[/tex]

[tex]0.4\sqrt{n} = 1.96*0.78[/tex]

[tex]\sqrt{n} = \frac{1.96*0.78}{0.4}[/tex]

[tex](\sqrt{n})^{2} = (\frac{1.96*0.78}{0.4})^{2}[/tex]

[tex]n = 14.6[/tex]

Rounding up

A sample size of 15 is needed.

d. What sample size is necessary to estimate the true average porosity to within 0.2 with 99% confidence?

99% C.I., so z = 2.575

n when M = 0.2.

[tex]M = z*\frac{\sigma}{\sqrt{n}}[/tex]

[tex]0.2 = 2.575*\frac{0.78}{\sqrt{n}}[/tex]

[tex]0.2\sqrt{n} = 2.575*0.78[/tex]

[tex]\sqrt{n} = \frac{2.575*0.78}{0.2}[/tex]

[tex](\sqrt{n})^{2} = (\frac{2.575*0.78}{0.2})^{2}[/tex]

[tex]n = 100.85[/tex]

Rounding up

A sample size of 101 is needed.

Answer:

Area to the right is 0.813

Step-by-step explanation:

Since the area under the full normal distribution should render "1" (one), then the area to the right of x  should be:

1 - area to the left of x = 1 - 0.187 = 0.813

The area to the right of x in this normal distribution will be 0.813.

The majority of the observations are centered around the middle peak of the normal distribution, which is a continuous probability distribution that is symmetrical around its mean.

The probabilities for values that are farther from the mean taper off equally in both directions. Extreme values in the distribution's two tails are likewise rare.

Not all symmetrical distributions are normal, even though the normal distribution is symmetrical. 

We know that the total area described in a normal distribution is 1.

Given, that the area to the left of x in a normal distribution is 0.187.

So, the area to the right of x will be,

1 - 0.187.

= 0.813.

learn more about normal distribution here :

https://brainly.com/question/15103234

#SPJ2

Answer:

56 cats

88 dogs

Step-by-step explanation:

x=cats

x+32=dogs

x+x+32=144

2x=144-32

2x=112

x=112/2

x=56 (56 cats)

x+32=88 (88 dogs)

Answer:

56

Step-by-step explanation:

In order to solve this question you need to subtract 32 by 144 then divide that answer by 2.

So we know that they're 32 more dogs then cats and there is 144 dogs and cats all together.

[tex]144 - 32 = 112[/tex]

Divide it in half

[tex]112 \div2=56[/tex]

[tex]56+32 = 88[/tex]

[tex]= 56[/tex]

Therefore they're 56 cats in the pet store.

Hope this helps.

Answer:

y= -2x+3

Step-by-step explanation:

Point slope form= y=mx+b

The m is the slope.

So, we have an incomplete equation right now: y= -2x+b

We want to find b. We can do that by plugging in values for the x and y coordinates. Fortunately, we do have a set of coordinates, (1, 1)!

We plug them in:

1= -2(1)+b

1= -2+b

b=3

So, since we have the slope and the b, also called the y-intercept, we can form an equation!

y= -2x+3

Answer:

[tex]P(a=31,b=39,c=7,d=23) = 0.000668[/tex]

Step-by-step explanation:

Sample space, n = 100

Let the number of students signed up for CSE 311 = a

Let the number of students signed up for CSE 312 = b

Let the number of students signed up for CSE 331 = c

Let the number of students signed up for CSE 332 = d

Probability of taking CSE 311, [tex]P_a[/tex] = 0.3

Probability of taking CSE 312, [tex]P_b[/tex] = 0.4

Probability of taking CSE 331, [tex]P_c[/tex] = 0.1

Probability of taking CSE 332, [tex]P_d[/tex] = 0.2

[tex]P(a,b,c,d) = \frac{n!}{a! b! c! d!} p_a^{a} p_b^{b} p_c^{c} p_d^{d} \\P(a=31,b=39,c=7,d=23) = \frac{100!}{31! 39! 7! 23!} * 0.3^{31} * 0.4^{39} * 0.1^{7} 0.2^{23}\\P(a=31,b=39,c=7,d=23) = \frac{4.58*10^{111}}{2.13*10^{56}* 5040 }* (1.57*10^{-55})\\P(a=31,b=39,c=7,d=23) = 0.000668[/tex]

Answer:

Option (A)

Step-by-step explanation:

Given:

LM ≅ OP

MN ≅ PQ

∠M ≅ ∠P

To Prove:

ΔLMN ≅ ΔOQP

                   Statements                      Reasons

1). LM ≅ OP                                   1). Given

2). MN ≅ PQ                                 2). Given

3). ∠P ≅  ∠M                                3). Given

4). ΔLNM ≅ ΔOQP                      4). By the SAS postulate of congruence.

                                                         [Side - Angle - Side]                          

Therefore, Option (A) will be the answer.

Answer:

352 cm/s

Step-by-step explanation:

circ = 44pi

speed = distance * time

distance = circ * 4 = 176pi

speed = 176pi/0.5

Answer:

≈ 1106 cm/s

Step-by-step explanation:

linear speed = angular speed x radius of the rotation

v = ωr

v = linear speed (m/s)

ω = angular speed (radians/s)

r = radius of the rotation (m)

------------

Given:

Linear speed is:

Answer:

140

Step-by-step explanation:

The maximum is the furthest the line that goes out the furthest, the minimum would be about 83-84

Answer:

the other person is correct!

Step-by-step explanation:

Answer:

ABC = 88

Step-by-step explanation:

Angle Formed by Two Chords  = 1/2( sum of Intercepted Arcs)

ABD = 1/2 ( 131+ 53)

ABD = 1/2 (184)

       =92

ABC = 180 -ABD

ABC = 88

Answer:

(5x + 6) (x² + 5)

Step-by-step explanation:

5x³ + 6x² + 25x + 30

= x² (5x + 6) + 25x + 30    -- Group 5x³ and 6x²

= x² (5x + 6) + 5 (5x + 6)    -- Group 25x and 30

= (5x + 6) (x² + 5)  -- Both terms have a common factor of 5x + 6

Answer:

The pro is Political Control, the cons, however, are many.

Step-by-step explanation:

However, A Socialist Economy cons outweigh its pros. The only thing that is a PRO is you dictating it, preventing people from success. Wanna know the cons? The Cons are more Regulations, to which chokes more businesses of their money, they function, & motive. To which it has a chain reaction of: The Businesses not employing people, more people are out of work, which means more people ain't buying stuff to support the businesses, which means the businesses are out of business, they shut down.

The Economy ain't something that you can stop, or go, & it ain't statistics. An Economy is just.. people, that's it. It's just people, they are the ones that work, run businesses & factories, they are the ones that buy N' sell. They create, craft, invent, innovate, etc.

Here's a quote that I have: "The more you choke it from breathing in, the less it breathes out". That's my stance on regulation & Socialism, to which Socialism is just Voluntary Communism, & A Permanent Ideological belief that Big government Involvement is the way to go.

To which, it's not!

Answer:

a. 10295472 ways

b. 4272048 ways

c. 6023424 ways

Step-by-step explanation:

Given that:

Camera shop stocks ----- 8 different types of batteries

one of which is ---- A76

Assume that there are ------ at least 30 batteries of each type.

a.

How many ways can a total inventory of 30 batteries be distributed among the eight different types.

The number of ways a total inventory of 30 batteries be distributed is :

[tex]= \left \{ {{30+8-1} \atop {30}} \right. \}[/tex]

[tex]= \left \{ {{37} \atop {30}} \right. \}[/tex]

[tex]=\dfrac{37!}{30! *7!}[/tex]

[tex]= \dfrac{37*36*35*34*33*32*31*30!}{30!*7*6*5*4*3*2*1}[/tex]

[tex]= \dfrac{37*36*35*34*33*32*31}{7*6*5*4*3*2*1}[/tex]

= 10295472 ways

b.

How many ways can a total inventory of 30 batteries be distributed among the eight different types if the inventory must include at least four A76 batteries?

If we must include 4  A76 batteries; then the number of ways a total inventory of 30 batteries can be distributed among eight different types of batteries will be:

30 - 4 = 26 batteries

Now;

[tex]= \left \{ {{26+8-1} \atop {26}} \right. \}[/tex]

[tex]= \left \{ {{33} \atop {26}} \right. \}[/tex]

[tex]=\dfrac{33!}{26! \ \ 7!}[/tex]

[tex]=\dfrac{33*32*31*30*29*28*27*26!}{26! \ * \ 7*6*5*4*3*2*1}[/tex]

[tex]=\dfrac{33*32*31*30*29*28*27}{ \ 7*6*5*4*3*2*1}[/tex]

= 4272048 ways

c. If we must include at most three A7b batteries. the number of ways that a total inventory of 30 batteries can be distributed among eight different types of inventory is:

[tex]= \sum \limits ^3 _{x=0} \left \{ {{(30-x)+7-1} \atop {30-x}} \right. \} \\ \\ \\ = \sum \limits ^3 _{x=0} \left \{ {{(30-0)+7-1} \atop {30-0}} \right. \} = (^{36}_{30})+(^{35}_{29})+ (^{34}_{28})+ (^{33}_{27})[/tex]

[tex]= \dfrac{36!}{30! * 6!} + \dfrac{35!}{29! * 6!} + \dfrac{34!}{28! * 6!} + \dfrac{33!}{27! * 6!}[/tex]

= 1947792 + 1623160 + 1344904 + 1107568

= 6023424 ways

Answer: a. 1320

b.495

Step-by-step explanation:

Complete question is provided in the attachment.

Total members on the board = 12

a. Persons to chose : chairperson, first vice​ chairperson, second vice​ chairperson, and​ secretary

i.e. Total 3 posts in an order.

Number of ways to choose 3 persons from 12 in an order = [tex]^{12}P_3[/tex]  [By permutation]

[tex]=\dfrac{12!}{(12-3)!}\\\\=\dfrac{12!}{7!}\\\\=12\times11\times10\\\\=1320[/tex]

hence, 1320 different slates of candidates are​ possible .

b. number of ways to choose 4 members out of 12 ( order not matters)=[tex]^{12}C_{4}[/tex] [By combinations]

[tex]=\dfrac{12!}{4!8!}\\\\=\dfrac{12\times11\times10\times9}{24}\\\\=495[/tex]

Hence, the number of different subcommittees are​ possible =495

Answer:

Given:

A right triangle in which an altitude is drawn from the right angle vertex

To find: value of X

We have leg rule in similarity in right triangle as:

[tex] \frac{leg}{part} = \frac{hypotenuse}{leg} \\ [/tex]

Plugging the given values,

[tex] \frac{z}{3} = \frac{3 + 27}{z} \\ z \times z = 3(3 + 27) \: \: (cross \: multiplication) \\ {z}^{2} = 9 + 81 \\ {z}^{2} = 90 \\ z = \sqrt{90} \\ z = 3 \sqrt{10} [/tex]

Hope this helps...

Good luck on your assignment..

Answer:

-12+28i+3i-7i-65i+28

14 -41i