What’s 5+5 i need help

Answer:

jajajajjajajajjajajajjajajb mucho men

Step-by-step explanation:

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Problem 1

Answer: No, it is not a statistical question

Explanation:

This is because the question is directed at a specific family, your family in particular. If the surveyor is only asking one person, then there's no need for statistics since a sample isn't formed.

If the question is posed to many people taking a survey, then it would be statistical in nature. However, no further context or clarification is given, so I'll assume that the question is directed at one person, or one family, only. I think your teacher would say "During which month do families take vacation?" to be more general and involve statistics.

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Problem 2

Answer: The statistical variable is the number of tv sets owned, and this variable is quantitative

Explanation:

The variable is what we want to figure out, and it's random in nature. Hence the name "random variable". It takes on nonnegative whole numbers 0,1,2,3,... so we can see the data set is discrete. The term "discrete" in math means that there aren't infinitely many numbers between two values. For example, if we pick 2 and 5, we can see the values 3,4 are between them and that's it. Contrast this with a continuous data set and there are infinitely many real numbers between 2 and 5 (eg: 2.78912 and 3.412)

While it might be tempting to think of a discrete number set as finite, that's not entirely true. We have infinitely many nonnegative whole numbers to work with. Though of course, there's a realistic limit that we arrive to and someone having 277 televisions is completely out of the ordinary, if not impossible.

The data variable "Number of TV sets owned" is not only discrete, but it's also ordinal, interval and ratio data as well. Here's a breakdown of what I mean

Since we have many terms apply to this, it sometimes helps to pick just one and try to have it describe the others implicitly. So we go for ratio data since that encapsulates interval and ordinal data types as well. If something is ratio, then automatically it must be ordinal and interval. Division depends on the numbers being well ordered, and that gaps between values make sense and are consistent.

To recap, the data type is quantitative, discrete, and we have a ratio scale.

The variable "number of tv sets owned" is not categorical since the choices to pick from 0,1,2,3,... aren't names; instead they are numbers in which we can perform math operations on and have it make sense. So that's why we go for quantitative data instead of categorical. If it asked "what brand of TV are owned by families?", then the categories of the various brand names would be the answer choices, and lead to categorical data.

Side note: categorical data is always qualitative

Answer:

d. and e.

Step-by-step explanation:

i did the test

Option A and Option D represents the equation of area of rectangular piece which are A=4×[tex]2\frac{1}{2}[/tex] and A=4×5/2.

The area of Rectangle is length times of width.

Given that A rectangular piece of glass is shown.

The length is measured as 4 feet.

The width is measured as 2 and one-half feet.

We have to find the  equations can be used to find the area of the piece of glass.

Area=Length×width

Area=4 feet × 2 and one-half feet

=4×[tex]2\frac{1}{2}[/tex]

=4×5/2

Hence, Option A and Option D represents the equation of area of rectangular piece which are A=4×[tex]2\frac{1}{2}[/tex] and A=4×5/2.

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Answer:

12 square units

Step-by-step explanation:

The area of a given figure is the measure of space occupied by the figure on a 2 dimensional plane.

Area of a triangle = [tex]\frac{1}{2}[/tex] x base x height

From the given grid, the following can be observed for triangle STU.

base SU = 6 units

height = 4 units

Thus,

area of triangle STU =  [tex]\frac{1}{2}[/tex] x base x height

                                  =  [tex]\frac{1}{2}[/tex] x 6 x 4

                                  = 3 x 4

area of triangle STU = 12 square units

The required area of triangle STU is 12 square units.

Answer:

$25

Step-by-step explanation:

she received$12 five times

12×5=60 ...(1)

she earned$5 two times for yard work

5×2=10....(2)

(1)+(2).... 60+10=70

Bought dog food and ticket

30+15=45

70-45=25

Answer $25 is what she is left with at the end of the month

Answer:

She would have 5 dollars left

Step-by-step explanation:

Answer:

02920

Step-by-step explanation:

92823

Answer: Please rewrite your question or send a pic. It is not clear what you are asking.

Step-by-step explanation:

Answer:

Step-by-step explanation:

the answer is in the pic open it

hope it help mark me as a brill please

Answer:

x≥1

Step-by-step explanation:

Answer:

your answer will be option B

Step-by-step explanation:

[tex]\frac{10}{12} =\frac{a}{38} \\\\a=\frac{(10) (38)}{12} \\\\=31.6[/tex]

Answer:

I don't know

Ich bin fett

I'm just a fat boy watching ph once a month

Step-by-step explanation:

bobo Ampt

Answer:

0.8x or 0.2x

Step-by-step explanation:

20% of x = 20/100 × x = 0.2x

So discount price = x - 0.2x = 0.8x

Answer:

A =greatest amount

Step-by-step explanation:

Answer:19

Step-by-step explanation:perimeter is everything added since it’s a rectangle 10 on both length sides will be 20 so 58-20 is 38 divide that by 2 and that’s your answer.

Answer:

Speed = distance / time

= 6/3 =2 ft/sec

Time = distance / speed

= 60/2

= 30 seconds

Answer:

11. 78

12. 4x² - 3x - 1

Step-by-step explanation:

11. Sum of n whole numbers = ½(n² + n)

Multiply

½*n² + ½*n

= n²/2 + n/2

To find the sum of the first 12 whole number, substitute 12 for n into the equation.

= 12²/2 + 12/2

= 144/2 + 12/2

= 72 + 6

= 78

12. Area of trapezoid = ½(a + b)*h

Where,

a = 5x - 4

b = 3x + 2

h = x + 1

Area = ½(5x - 4 + 3x + 2)*(x + 1)

Area = ½(8x - 2)*(x + 1)

Area = ½[8x(x + 1) -2(x + 1)]

= ½[8x² + 8x - 2x - 2]

Add like terms

= ½(8x² - 6x - 2)

= ½(8x²) - ½(6x) - ½(2)

= 4x² - 3x - 1

Answer:

27

Step-by-step explanation:

Carlotta can feed 3 times her dog with leftover in this bag of dog food

The unitary method is a method for solving a problem by the first value of a single unit and then finding the value by multiplying the single value. If an event can occur in m different ways and if following it, a second event can occur in n different ways, then the two events in succession can occur in m × n different ways.

WE have been given that Carlotta has 2/3 of a bag of dog food  and She gives her dog 2/9 of the bag at each feeding.

The bag of dog food = 2/3

Let she feed her dog with leftover in this bag of dog food = X

Therefore, X = 2/3 × 9/2

X = 18 / 6

X = 3

Hence, Carlotta can feed 3 times her dog with leftover in this bag of dog food

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Answer:

b

Step-by-step explanation:

9514 1404 393

Answer:

  Chun is correct

Step-by-step explanation:

The angle bisector divides the sides of the triangle proportionally. Any proportion that is written should equate ratios of corresponding sides.

Chun's proportion correctly relates the top-side measures to their corresponding bottom-side measures:

  top short : bottom short = top long : bottom long

  5 / 8 = 15 / x

__

Traci's error is that she mixes top-side and bottom-side measures. Her incorrect relation is ...

  top short : bottom long = bottom short : top long

She has used top:bottom for short measures and bottom:top for long measures. This mixing will give Traci an incorrect solution.

__

Chun's proportion correctly gives x=24.

Answer:

Step-by-step explanation:

Chun; by the Triangle Angle Bisector Theorem, the correct proportion is  58=15x.

(5x + 2) + (4x + 5)

= 5x + 2 + 4x + 5

= 5x + 4x + 5 + 2

= 9x + 7

Answer:

x = 30 y = 70 z = 80

Step-by-step explanation:

Answer:

(-1.875, -1.625)

Step-by-step explanation:

We want to find the point on the equation 2*x + 6*y + 1 = 0 which is closest to the point (-5, -3)

Remember that the distance between two points (a, b) and (c, d) is:

D = √( (a - c)^2 + (b - d)^2)

First we can write our equation as a line in the slope intercept form:

y = -(2/6)*x - 1

Now we could minimize the equation:

D = √( (x - (-5))^2 + (y - (-3))^2) = √( (x + 5)^2 + (y + 3)^2)

D = √(  ( x + 5)^2 + (  -(2/6)*x - 1 + 3) ^2)

Then we can minimize:

D^2 = (x + 5)^2 + ( -(2/6)*x + 2)^2

       = x^2 + 10*x + 25  + (4/36)*x^2  - (8/6)*x + 4

       =  (1 + 4/36)*x^2 + (10 - 8/6)*x + 29

        = (40/36)*x^2 + (52/6)*x + 29

This is a quadratic equation whose leading coefficient is positive, then the minimum of this equation is at the vertex.

The vertex is at the x-value such that (D^2)' = 0

Then:

(D^2)' = 2*(40/36)*x + (52/6)

This needs to be zero then:

0 = 2*(40/36)*x + (52/6)

-52/6 = (80/36)*x

(-52/6)*(36/80) = x

-1.875 = x

And the y-value when x = -1.875 is:

y = -(2/6)*-1.875 - 1

y = -1.625

Then the point on the line 2x+6y+1=0 that is closest to (-5,-3) is the point (-1.875, -1.625)

Answer:

pretty sure youre right kiddo

Answer:

b is the correct answer

Step-by-step explanation:

btw can i have brainliest please

Step-by-step explanation:

perimeter is (pi×diameter)/2

perimeter =(3.14×3.5)/2

perimeter =5.49m

Answer:

Keiko sent 17 messages, Dale sent 10 messages, and Tony sent 68 messages

Step-by-step explanation:

Let x represent the number of messages that Keiko sent.

Since Dale sent 7 less than Keiko, his number can be represented by x - 7

Since Tony sent 4 times as many as Keiko, his number can be represented by 4x

Using these variables, create an equation:

(x) + (x - 7) + (4x) = 95

Add like terms and solve for x:

6x - 7 = 95

6x = 102

x = 17

So, Keiko sent 17 messages.

Subtract 7 from this to find how many Dale sent:

17 - 7

= 10

Multiply it by 4 to find how many Tony sent:

17(4)

= 68

So, Keiko sent 17 messages, Dale sent 10 messages, and Tony sent 68 messages

Answer:

[tex]x\\[/tex] ± [tex]\frac{s}{\sqrt{n}}[/tex] = [tex]9.78[/tex] ± [tex]\frac{10.45}{\sqrt{60}}[/tex]

Step-by-step explanation:

x is the value of our population/sample mean. Given that it's 98.75, we substitute x for 98.75.

We follow this pattern for s and n, which are the standard deviation and sample size respectively, to fill out the rest of our equation. This means that s is 10.45 and n is 60

Since we know the formula is [tex]x\\[/tex] ± [tex]\frac{s}{\sqrt{n}}[/tex], we can input our new values.

This gives us our answer of [tex]9.78[/tex] ± [tex]\frac{10.45}{\sqrt{60}}[/tex]

TL;DR

I took the test and the answer was right

The interval in which the population mean $98.75 with standard deviation of $10.45 with a sample size of 60 is given by its lower and upper limit as given by: 98.75 ± 10.45/(√(60))

According to the empirical rule, also known as 68-95-99.7 rule, the percentage of values that lie within an interval with 68%, 95% and 99.7% of the values lies within one, two or three standard deviations of the mean of the distribution.

[tex]P(\mu - \sigma < X < \mu + \sigma) \approx 68\%\\P(\mu - 2\sigma < X < \mu + 2\sigma) \approx 95\%\\P(\mu - 3\sigma < X < \mu + 3\sigma) \approx 99.7\%[/tex]

where we had  where mean of distribution of X is [tex]\mu[/tex]  and standard deviation from mean of distribution of X is [tex]\sigma[/tex] (assuming X is normally distributed).

Suppose X has has a distribution with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], then, the distribution of the mean of samples of size n, drawn from the values of X, is normally distributed with mean equal to the mean of X, and standard deviation equal to [tex]\sigma/\sqrt{n}[/tex]

Symbolically, we write it as:

[tex]X \sim N(\mu, \sigma) \implies \overline{X} \sim N(\mu,\sigma/\sqrt{n} )[/tex]

(for large enough samples, n > 30)

For this case, we're specified that:

Then, the distribution of the sample mean is approximately normal distribution with mean $98.75 and standard deviation approximately [tex]10.45/\sqrt{60}[/tex]

Symbolically, we get:

[tex]X \sim N(98.75, 10.45/\sqrt{60})[/tex]

Then, using empirical rule, we find the limits for sample mean for which we're 68% sure that the sample mean will lie in that interval as one standard deviation (of the sample mean) away from its mean.

[tex]P\left( 98.75 - 10.45/\sqrt{60} < \overline{X} < 98.75 + 10.45/\sqrt{60}\right) \approx 68\%[/tex]

So, limits are:

[tex]98.75 \pm \dfrac{10.45}{\sqrt{60}}[/tex]

Thus, the interval in which the population mean $98.75 with standard deviation of $10.45 with a sample size of 60 is given by its lower and upper limit as given by: 98.75 ± 10.45/(√(60))

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