What would the circuit resistance be if a 7.5 Amp draw was present with the engine running and the charging system producing 15 Volts?

Answers

Answer 1

Answer:

2 ohms

Explanation:

Hi there!

Ohm's law states that [tex]V=IR[/tex] where V is the voltage, I is the current and R is the resistance.

Plug in the given information (I=7.5, V=15) and solve for R

[tex]V=IR\\15=(7.5)R[/tex]

Divide both sides by 7.5 to isolate R

[tex]\frac{15}{7.5}= \frac{7.5R}{7.5} \\2=R[/tex]

Therefore, the circuit resistance would be 2 ohms.

I hope this helps!


Related Questions

A square loop of wire with a small resistance is moved with constant speed from a field free region into a region of uniform B field (B is constant in time) and then back into a field free region to the left. The self inductance of the loop is negligible. True While the loop is entirely in the field, the emf in the loop is zero. False When entering the field the coil experiences a magnetic force to the left. False When leaving the field the coil experiences a magnetic force to the right. True Upon entering the field, a clockwise current flows in the loop.

Answers

Answer:

False, True, False, True

Explanation:

Given a square loop of a wire having a small resistance and moving with a constant sped from the free region to a region having a region having a uniform field B.  It is then moved back to the left in the free field region.

For the following statements :

While the loop is entirely in the field, the emf in the loop is zero.  -- TRUE

The emf of the coil is zero when the coil moves into the field from a free region field to a uniform field region field.

When entering the field the coil experiences a magnetic force to the left   ---- FALSE

According to the Lenz law, a loop entering the field opposes it and moves towards the right.

When leaving the field the coil experiences a magnetic force to the right. --- TRUE

Upon entering the field, a clockwise current flows in the loop.  ---- TRUE

In the field the coil or the loop tries to oppose the magnetic field and forces the current in the loop to move in a clockwise direction.

A 9-V battery is hooked up to a 330-Ω resistor. What current is flowing through this circuit?
Group of answer choices

0.027 A

2970 A

36.6 A

6 A

Answers

Answer:

option a 0.027 A

Explanation:

I = V/R

-> 9/330 = 0.027

How much stronger is the electric force between two protons than the gravitational force between them?

Answers

Answer:

The electric force between two protons is 10^36 times stronger than the gravitational force between them.

Explanation:

Answer:

[tex]F_e=1.23\times 10^{36}\times F_G[/tex]

Explanation:

The charge on proton is [tex]1.6\times 10^{-19}\ C[/tex]

The mass of proton is [tex]1.67\times 10^{-27}\ kg[/tex]

The electric force between two charges is given by :

[tex]F_e=\dfrac{kq^2}{r^2}\ ......(1)[/tex]

The gravitational force between two protons is given by :

[tex]F_G=G\dfrac{m^2}{r^2}\ ......(2)[/tex]

From equations (1) and (2).

[tex]\dfrac{F_e}{F_G}=\dfrac{kq^2}{Gm^2}\\\\=\dfrac{9\times 10^9\times (1.6\times 10^{-19})^2}{6.67\times 10^{-11}\times (1.67\times 10^{-27})^2}\\\\=1.23\times 10^{36}\\\\F_e=1.23\times 10^{36}\times F_G[/tex]

So, the electric force between two protons is [tex]1.23\times 10^{36}[/tex] times that of the gravitational force between them.

A 100-turn, 7.0-cm-diameter coil is made of 0.50-mm-diameter copper wire. A magnetic field is perpendicular to the coil. At what rate must B increase to induce a 2.0 A current in the coil?

Answers

Answer:

The rate of increase of the magnetic field is 0.0311 T/s.

Explanation:

Given;

number of turns of the coil, N = 100 turn

diameter of the coil, D = 7.0 cm = 0.07 m

diameter of the copper wire, d = 0.5 mm = 0.5 x 10⁻³ m

induced current, I = 2.0 A

The induced emf is calculated as;

[tex]emf = IR = NA\frac{dB}{dt}\\\\\frac{dB}{dt} = \frac{IR}{NA} \\\\Where; A \ is \ area \ of \ the \ coil = \frac{\pi D^2}{4}\\\\[/tex]

[tex]\frac{dB}{dt}[/tex] is the rate of increase of the magnetic field, B

R is the resistance of the copper wire

[tex]R = \frac{\rho L}{A} = \frac{\rho D}{A}= \frac{\rho D}{\frac{\pi d^2}{4} }[/tex]

Where; ρ is the resistivity of copper wire = 1.68 x 10⁻⁸ Ωm

[tex]R = \frac{(1.68 \times 10^{-8})(0.07)}{\frac{\pi (0.5\times 10^{-3})^2}{4} } \\\\R = 5.989 \times 10^{-3} \ ohms[/tex]

[tex]\frac{dB}{dt} = \frac{(2)(5.989 \times 10^{-3})}{(100)(\frac{\pi \times (0.07)^2}{4} )} \\\\\frac{dB}{dt} =0.0311 \ T/s[/tex]

Therefore, the rate of increase of the magnetic field is 0.0311 T/s.

A torsional pendulum has a centroidal mass moment of inertia of 0.40 kg·m2 and when given an initial twist and released is found to have a frequency of oscillation of 200 rpm. Knowing that when this pendulum is immersed in oil and given the same initial condition it is found to have a frequency of oscillation of 180 rpm, determine the damping constant for the oil. The damping constant for the oil is

Answers

0.00246914 come to the damping of the constant for the oil

Knowing that when this pendulum is immersed in oil and given the same initial condition it is found to have a frequency of oscillation of 180 rpm,0.00246914 come to the damping of the constant for the oil

what is frequency ?

The frequency can be defined as the  number of oscillation per unit time which is used for defining the cyclic process like rotation, oscillation, wave etc.

The SI unit of the frequency is denoted as  Hertz and the symbol λ represents it where one hertz means the wave completed one cycle in one second.

The frequency which explains the phenomenon of oscillatory and vibration like the mechanical vibration, sound signals, light, frequency waves etc. The  “period” represented as the time required by the wave for one oscillation, i.e., it is inversely proportional to the frequency.

If the flashes, then the period is the time between the two flashes. And the frequency is the total number of flashes per second.

For more details regarding frequency, visit

brainly.com/question/14400059

#SPJ2

How many significant figures are in the number 54,100?

Answers

Answer:

3

Explanation:

The answer must be 3

1. A hydraulic lift is to be used to lift a truck masses 5000 kg. If the diameter of the
small piston and large piston of the lift is 5 cm and 1 m respectively,
a. What gauge pressure in Pa must be applied to the oil?
b. What is the magnitude of the force required on the small piston to lift the truck?​

Answers

Answer:

a)   F = 4.9 10⁴ N,  b)   F₁ = 122.5 N

Explanation:

To solve this problem we use that the pressure is transmitted throughout the entire fluid, being the same for the same height

1) pressure is defined by the relation

           P = F / A

to lift the weight of the truck the force of the piston must be equal to the weight of the truck

          ∑F = 0

          F-W = 0

          F = W = mg

          F = 5000 9.8

          F = 4.9 10⁴ N

the area of ​​the pisto is

          A = pi r²

          A = pi d² / 4

          A = pi 1 ^ 2/4

          A = 0.7854 m²

pressure is

          P = 4.9 104 / 0.7854

          P = 3.85 104 Pa

2) Let's find a point with the same height on the two pistons, the pressure is the same

          [tex]\frac{F_1}{A_1} = \frac{F_2}{A_2}[/tex]

where subscript 1 is for the small piston and subscript 2 is for the large piston

          F₁ = [tex]\frac{A_1}{A_2} \ F_2[/tex]

the force applied must be equal to the weight of the truck

          F₁ = [tex]( \frac{d_1}{d_2} )^2\ m g[/tex]

          F₁ = (0.05 / 1) ² 5000 9.8

          F₁ = 122.5 N

Kendra wonders how she ended up with brown hair, hazel eyes, and is right handed. Using the terms amino acids, genes, proteins, and traits, explain how she ended up with these features.

Answers

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

ᥬ᭄

In a chemical reaction, substances react in a specific ratio. Chemical reactions are used to make many products, including food. For a company that carries out a chemical reaction to make a product, why would it be important to know the ratio of substances?

Answers

Answer: “Chemical equations need to be balanced in order to satisfy the law of conservation of matter, which states that in a closed system matter is neither created nor destroyed. There are some things called mole ratios, which are important because mole ratios allow you change moles of a substance to moles of another substance. The mole ratio is the magic that changes from A to B. The mole ratios come from the chemical formula or equation.”

You need to make sure you have an equal balance so that you don’t make a mistake and mess up the reaction. If anything goes minutely wrong, it may alter the substance. Knowing the ratios of substances can help to make the product as expected.

It is important to know the ratio of substances because:

Mole ratios are important because mole ratios allow you change moles of a substance to moles of another substance. The mole ratio is the magic that changes from A to B. The mole ratios come from the chemical formula or equation.The mole ratios are determined using the coefficients of the substances in the balanced chemical equation. Mole ratios are used as a means of comparison of substances in a balanced chemical equation in order to determine amounts.

Example: 2H₂ + O₂ → 2 H₂O

Learn more:

brainly.com/question/14197404

a car travels a distance of 1600km in 24hr .what was it's speed​

Answers

Answer:

66.66 or 66.67

Explanation:

When we experience positive "g forces", it is as if we have become...

Answers

Answer:

heavier

Explanation:

a 60 kg pupil runs for 600m in 1 minute uniformly calculate kinetic energy​

Answers

velocity = traveled distance ÷ time of the traveled distance is seconds

velocity = 600 ÷ 60

velocity = 10 m/s

_________________________________

Kinetic Energy = 1/2 × mass × ( velocity )^2

KE = 1/2 × 60 × ( 10 )^2

KE = 30 × 100

KE = 3000 j

Four 15 Ω resistors are connected in series with a 45 V battery. What is the current in the circuit?

Answers

Answer:

3A

Explanation:

Resistance=R=15

Voltage=45volts

we know that

[tex]\boxed{\sf Current=\dfrac{Voltage}{Resistance}}[/tex]

[tex]\\ \tt \mapsto \:Current=\dfrac{45}{15}[/tex]

[tex]\\ \tt \mapsto \:Current=\dfrac{3A}[/tex]

The current of the circuit is 0.75 amps

The first step is to write out the parameters

Four resistors of 15 in series

15+15+15+15

= 60

voltage= 45

Current= 45/60

= 0.75

Hence the current is 0.75 amps

Please see the link below for more information

https://brainly.com/question/3712069?referrer=searchResults

How can you use PE in music class and how can you use music in PE class?

Answers

Answer:

fa fe fi fo fu hhhhhjjjjjkhvg

A 10kg block is Pulled along a horizontal
Surfact by a fores of son at an ansie
of 37° with the horizontal If the
coefficient of sliding friction 6/n the
block ound the surface is 0.2
(8-10 mis? Sin 37=016 and cos 37.2008)
of what frictional for acting on the block
b what is the acceleration of the block?​

Answers

Answer:

Explanation:

I hate these kinds of problems,  luckily I can't understand how much the kinetic friction is for this ,  the words are all mixed around.  and don't read well.  Maybe this went through a translator program?   My suggestion draw the free body diagram.   so you can see where the forces are, and how they are acting.   getting the free body diagram right.. usually makes these problems pretty straight forward.   just do the steps and you get the answer.

Answer:

I cant understand the question well but i will tell u how to solve it

first apply f = ma eqaulation vertically...then u will get an r = mg which means normal upward force = weight of the object (to find weight multiply mass by 9.81)

[tex]f = ma \\ r - mg = 0 \\ r = mg[/tex]

after that use friction eqaution which is

[tex]f = \mu \times r [/tex]

(mu) is the coefficient of friction and (r) is the vertical normal force then by substituting value you can get an answer for the friction

the use

[tex]f = ma \\ f \cos(37) - fr = ma[/tex]

by using the above eqaution you can get an answer for acceleration...

hope you can understand...

NEED HELP PLZ!!! ASAP

Which of the following happens during a solar eclipse?

The moon appears red.
The moon casts a shadow on Earth.
Earth, the moon, and the sun form a triangle.
Earth comes between the sun and the moon.

Ok so I'm Confused, that last answer- Shouldnt that say the moon comes between the sun and the earth? This is what it says on my test instead..

Answers

U r correct mate it's the right answer.

Hope it helps u

Plz mark me brainlest

Velocity is the speed at which an object moves in a specific direction. It's measured in meters per second, minute or hour in a particular direction—like miles per hour going north, kilometers per minute west or meters per second up. Velocity tells us both the speed and direction we are traveling. Acceleration is a change in velocity. It's measured by subtracting the object's starting velocity from the final velocity, divided by the time this change in velocity took. We usually think of acceleration as speeding up, but it can also mean slowing down. We call this negative acceleration or deceleration. If a car was driving 45 miles per hour northeast, and is now driving 30 miles per hour north, A the car’s velocity decelerated. B the car’s velocity accelerated. C the car’s velocity remained unchanged. D the car’s acceleration is 30 miles per hour.

Answers

Answer:

Option A. The car’s velocity decelerated

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 45 mph Northeast

Final velocity (v) = 30 mph North

Now, if we take the difference between the car's final velocity and it's Initial velocity, we shall obtained:

Difference in velocity = v – u

Difference in velocity = 30 – 45

Difference in velocity = –15 mph

Since the difference between the final velocity and the initial velocity of the car is negative, it implies that the car's velocity decelerated.

Thus, option A gives the correct answer to the question

A piece of plastic with a mass of 15 g is
placed in a graduated cylinder. The water
level in the graduated cylinder rises from
30 mL to 55 mL when the plastic is added.
Find the density of the plastic.

Answers

Answer:

The density of plastic is equal to 0.6 g/mL.

Explanation:

Given that,

The mass of piece of plastic, m = 15 g

It is placed in a graduated cylinder. The water  level in the graduated cylinder rises from  30 mL to 55 mL when the plastic is added.

We need to find the density of plastic.

Rise in volume = 55 mL - 30 mL

= 25 mL

The density of an object is given by :

[tex]d=\dfrac{m}{V}\\\\d=\dfrac{15\ g}{25\ mL}\\\\d=0.6\ g/mL[/tex]

So, the density of plastic is equal to 0.6 g/mL.

its un1) It is unofficial, but a strong rumor that the world will end in two years' time due to the arrival of a huge comet and its subsequent impact with Earth. You have two years to live, to get the most out of life. How would you react? What would you do? Discuss.​

Answers

Answer:

I'll try my utmost best to get the most out of life...I'd do the things have always wanted to do

Sometimes it might get to me knowing fully well that in two years time the world will end but i will shake it off because the time i spend thinking about it...It will be enough to make some memories.

Hope this help anyways

A pair of slits, separated by 0.150 mm, are illuminated by light with a wavelength of 643 nm. An interference pattern is observed on a screen at 140 cm from the slits. Consider a point seen on the screen that is located 1.80 cm to the right of the central bright fringe. Will the point be a minimum (destructive) point, a maximum (constructive) point or somewhere in between

Answers

Answer:

Explanation:

slit separation d = .15 mm

screen distance D = 1.4 m

wavelength of light used λ= 643 x 10⁻⁹ m

position of n th bright fringe x

x = n x λ D / d

1.8 x 10⁻² = n x 643 x 10⁻⁹ x 1.4 / .15 x 10⁻³

1.8 x 10⁻² = n x 6 x 10⁻³

n = 3

So 3 rd bright fringe will be formed at a point 1.8 cm from the central bright fringe .

What would happen if I removed the battery from the circuit?

Answers

Answer:

The current would stop

Explanation:

Electric currents are interesting because they carry little to no momentum. As soon as you remove a power source, the whole current halts.

A ball has a mass of 0.046kg. Calculate the change in gravitational potential energy when the ball is lifted through a vertical height of 2.05 m.


The mass of a ball is 0.046kg. The ball is released. Calculate the kinetic energy of the ball when the speed of the ball is 3.5 m/s

Answers

Answer:

PE=0.92414J and KE=0.28175J

Explanation:

Gravitational potential energy=mass*gravity*height

PE=mgh

Data,

M=0.046kg

H=2.05m

g=9.8m/s^2

PE=0.046kg * 9.8m/s^2 * 2.05m

PE =0.92414J

KE=1/2mv^2

M=0.046kg

V=3.5m/s

KE=[(0.046kg)*(3.5m/s)^2]\2

KE=0.28175J

The Hall effect is to be used to find the sign of charge carriers in a semiconductor sample. The probe is placed between the poles of a magnet so that magnetic field is pointed up. A current is passed through a rectangular sample placed horizontally. As current is passed through the sample in the east direction, the north side of the sample is found to be at a higher potential than the south side. Make a sketch of the situation, then decide if the number density of charge carriers is positively or negatively charged.

Answers

Answer:

the sign of these carriers is POSITIVE

Explanation:

In the effect, he found the charge carriers that were subjected to two forces, one electric and the other magnetic.

        F = F_e + F_m = q E + q v x B

bold indicates vectors

The electric field goes to the east, therefore the current also has this direction, the vector product of the velocity of the charge carriers towards the east and the magnetic field upwards, using the right hand rule a magnetic force is created towards the north if the carriers are positive.

In the exercise they indicate that the north side has a higher potential than the south side, therefore there must be an accumulation of carriers on this side that create an electric field (Hall) that is put to the magnetic force until reaching equilibrium when the total force is zero.

Therefore the sign of these carriers is POSITIVE

help PLEASEEEEEEEEEEE

Answers

The answer is a

Explanation : a
the answer for this one is A

A large truck of mass 4M is traveling at a speed of V when it collides with a small car of mass M that is at rest. The truck and car stick together after the collision. When the truck and car stuck together after the collision, the speed of the center of mass of the truck-car system is Vf. If the truck and car have an elastic collision, the speed of the center of mass of the truck-car system is Vf2. Which of the following expressions for Vf2 must be true?

a. 4/5 V
b. 1/5 V
c. V
d. 5/4 V
e. 5V

Answers

Answer: (a)

Explanation:

Given

Mass of large truck is 4M with velocity V

Mass of small car is M which is at rest

After the collision car and truck stick together

Conserving momentum

[tex]\Rightarrow 4MV+M(0)=5M\times V_f\\\\\Rightarrow V_f=\dfrac{4}{5}V[/tex]

For elastic collision, the velocity of the center of mass remains the same as the momentum is conserved and there is no acceleration involved.

So, for elastic collision velocity [tex]V_f_2=\frac{4}{5}V[/tex]

As a result of collision when there is no loss in the kinetic energy of the object then the collision is said to be elastic and the kinetic energy and the momentum of the objects are conserved.

The momentum is written as:

[tex]\rm m_{1}v_{1}+m_{2}v_{2} = m_{1}v_{1}'+m_{2}v_{2}'[/tex]

Where, mass = m and velocity = v

The following option is true:

Option a.  [tex]\dfrac{4}{5} \rm V[/tex]

The momentum can be estimated by:

Given,

Mass of large truck = 4M

Mass of small car = M

The velocity of truck = V

After the collision the conserving momentum will be:

[tex]\begin{aligned}\rm 4MV + M(0) &= 5\rm M \times V_{f}\\\\\rm V_{\rm f} &= \dfrac{4\rm MV}{5\rm M}\\\\\rm V_{f} &= \dfrac{4}{5V}\end{aligned}[/tex]

There will be no acceleration as the momentum is conserved and the center of mass is the same.

Therefore, elastic collision will have a momentum of  [tex]\dfrac{4}{5} \rm V[/tex].

To learn more about momentum and elastic collision follow the link:

https://brainly.com/question/8169285

How high off the ground is a 5.5 kg object that has a gravitational potential energy of 8500 DE=mah​

Answers

Answer:

h = 157.70 meters

Explanation:

Given the following data;

Mass = 5.5 kg

Gravitational potential energy = 8500 Joules

We know that acceleration due to gravity is equal to 9.8 m/s².

To find the height of the object;

Gravitational potential energy (GPE) is an energy possessed by an object or body due to its position above the earth.

Mathematically, gravitational potential energy is given by the formula;

[tex] G.P.E = mgh[/tex]

Where;

G.P.E represents potential energy measured in Joules.

m represents the mass of an object.

g represents acceleration due to gravity measured in meters per seconds square.

h represents the height measured in meters.

Substituting into the formula, we have;

8500 = 5.5*9.8*h

8500 = 53.9h

h = 8500/53.9

h = 157.70 m

A red horse and a black horse raced on a 1-mile long circular racetrack. The red horse
completed the race in 120 seconds, and the black horse completed the race in 150
seconds. Which choice correctly describes the speed of the horses?
A- Only the red horse ran at a constant speed
B- The red horse's average speed was greater than the black horse's average speed.
C- The black horse's average speed was greater than the red horse's average speed.
D- Only the black horse ran at a constant speed.

Answers

Answer

your format is incorrect!!

Explanation:

there is no such thing as a red horse. there are chestnuts, bays and red roans, just no reds. usually though, blacks are faster scientifically than red roans.

If unlike magnetic poles attract, how does a magnet attract an un-magnetized piece of metal such as a piece of iron?
A
It does this via a process called magnetic induction which temporarily makes a magnet of the metal.

B
It can only do this if the piece of metal already is a magnet internally.

C
What actually happens is that the un-magnetized metal attracts the magnet rather than the other way around.

D
Only powerful electro-magnets, such as are found in wrecking yards, can attract unmagnetized metals.

Answers

Answer:

A

Explanation:

The lets say the magnet is is facing the north and a piece of iron is near it. The iron will become magnetized since the protons will be repelled leaving only the electrons creating a magnetic field. Or in other words a temporary magnet is made, this is only as long a the actual magnet is close enough to the iron.

2. A piece of alloy has a measured mass of 86g in air and 73 g when immersed in water. Find its
(a) volume
(b) density​

Answers

Answer:

Hello There!!

Explanation:

a)The volume is 13 cc.(i think)

b)The density is 86/13 = 6.62.

hope this helps,have a great day!!

~Pinky~

What is the derivation for Newtons Law of universal gravitation?​

Answers

Answer:

In symbols, the magnitude of the attractive force F is equal to G (the gravitational constant, a number the size of which depends on the system of units used and which is a universal constant) multiplied by the product of the masses (m1 and m2) and divided by the square

Other Questions
Find the volume of the solid figure shown below. The area of the base is 40 square inches, and the height of the figure is 7 inches. 280 in. 3 68 in. 3 47 in. 3 108 in. 3 NEED HELP PLZ!!! ASAP!! (someone else deleted my question) Which of the following happens during a solar eclipse?The moon appears red.The moon casts a shadow on Earth.Earth, the moon, and the sun form a triangle.Earth comes between the sun and the moon.Ok so I'm Confused, that last answer- Shouldn't that say the moon comes between the sun and the earth? This is what it says on my test instead.. Select the correct answer.What type of media is/are only used for one-time backups?A. internal hard diskB. external hard diskC. DVD, optical media, and removable mediaD. remote shared folderE. tape For this assignment, you will research and create a map and a three-dimensional model of a specific landform found on Earth. After mapping and modeling the landform, you will create a profile of your landform. help i dont understand Solve for x x= [ ]* pls help please answer correctly !!!!! Will mark Brianliest !!!!!!!!!!!!!! Find the volume. No links please NO LINKS, WILL GIVE BRAINLIESTWhat is the area of the rectangle? (rectangle is 5/7 ft wide and 3 1/2 ft long)Enter your answer as a mixed number in simplest form in the box.ft2 what is formula of perimeter of half circle Do any of the peeps out there watch boku no hero or toilet bound hanako kunnn A local boys club sold 136 bags of mulch and made a total of $521. It sold two types of mulch: hardwood for $4.00 a bag and pine bark for $3.75 a bag. How many bags of each kind of mulch did it sell ? 5(y+25)=13 what is y please helpp!! ill mark brainly How did this document of southern literary messenger contribute to Uncle Toms Cabin leading to the outbreak of the Civil War? How many kilojoules of heat are required to heat 2550 grams of water from 17.5C to 100.0C? Enter the decimal equivalent of 53/100 The graph of F(x) below resembles the graph of G(x) = x?, but it has beenchanged somewhat. Which of the following could be the equation of F(x)?Fix) =>Gix) = x2A. F(x) - x-2B. F{X) = 4x2+2C. Fx) = - - 2D. FN-4222 Is the relationship linear, exponential, or neither? A gas occupies 11.2 L at a pressure of 35.0 mm . What is the volume of the gas if it is Increased to a pressure of 64.0 mm Hg?A) 6.13 LB) 110.2 LC) 200.0 KD) 20.5 L which statement is not true about the data shown?66,89,90,55,92,82The range is 37.there is no mode. the median is 82.the mean is 79. a circle is inscribed in a equilateral triangle. A point in the figure is selected at random. Find the probability that the point will be in the part that is NOT shaded.