What would happen to a satellite if its orbit speed doubled?

Answers

Answer 1

Answer:

The radius of orbit will decrease by 1/4, the satellite will come closer to Earth

Explanation:

The orbital speed of any body revolving in an orbit around another boyd is given by:

v (orbital) = √(G · M(central body)/R)

Where G is the gravitation constant.

If the body, e.g satellite is moving around the Earth, then the mass of central body M will also be a constant. Therefore, the only thing on which the orbital velocity will depend on will be Radius of the orbit R.

v ∝ 1/√R

√R ∝ 1/v

Take square:

R ∝ 1/v²

If the velocity of satellite will doubles, then:

R' ∝ 1/ (2v)²

R' ∝ 1/4v²

R' ∝ (1/4)(1/v²)

R' ∝ (1/4)(R)

The radius of orbit will decrease by 1/4, the satellite will come closer to Earth


Related Questions

An airplane with a total mass of 850 kg has an engine malfunction, causing it
to provide a constant horizontal force of 4000 N. The pilot, who has a mass
of 80 kg, decides to eject from the airplane. With the reduced total mass,
what is the new approximate acceleration of the airplane?
A. 3.1 m/s2
B. 5.2 m/s2
C. 2.8 m/s2
D. 3.7 m/s2

Answers

Answer:

B

Explanation:

If  the pilot, who has a mass of 80 kg, decides to eject from the airplane. With the reduced total mass,then the new approximate acceleration of the airplane will be 5.2 m/s²

What is Newton's second law?

Newton's Second Law states that The resultant force acting on an object is proportional to the rate of change of momentum.

The mathematical expression for Newton's second law is as follows

F = m*a

where F represents the force applied

m is the mass of the object

a is the acceleration of the object

The initial acceleration of an airplane with a total mass of 850 kg has an engine malfunction, causing it to provide a constant horizontal force of 4000 N.

F =m*a

4000 N = 850×a

a= 4.7 m/s²

An acceleration of airplane when the pilot, who has a mass of 80 kg, decides to eject from the airplane. With the reduced total mass,

the horizontal force is the same 4000 N, now the total reduced mass the airplane is 770 kg

F =m*a

4000 =770×a

a = 5.2 m/s²

Learn more about Newton's second law, here

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