What will be the change in "velocity" of a 991 kg car if a force of 31,770 N is applied to it for 0.4 seconds?

Answer:

20V

Explanation:

Given: I=2A

           R=10Ω

Solution: V = I × R

                  =(2A)×(10ohm)

                  =20V

P = 7.3 × 10^-13 Watt

Explanation:

First of all, are you sure that what you have is the right answer?

Anyway, the definition of power dissipated is given by

P = I^2×R

where I is the current and R is the resistance. But we also know from Ohm's law that

V = IR

so we can rewrite the equation for power P as

P = I^2R = I(IR) = VI

= (0.0054 volt)(1.35 × 10^-10 A)

= 7.3 × 10^-13 Watt

Answer:

Solution given:

any three applications of electromagnetic waves are:

2.

Solution given;

power [P]=100W

Current [I]=5A.

Voltage [V]=?

we have

P=IV

100=5*V

V=[tex] \frac{100}{5} [/tex]=20V

the voltage of the battery used in the car is 20V.

Answer:

Explanation:

1. Electromagnetic waves are used to broadcast radio and TV signals. It is also used for wireless charging cell phones. Cell phone itself uses electromagnetic waves for its cell signal.

See attached drawing for ray diagram.

2. Given: the power of a bulb of car is 100 W and 5A current flows through the filament of the bulb.

Power of a bulb is given by voltage * current.

So 100W = voltage * 5A

Voltage = 100/5 = 20V

Answer:

Gravity.

Rocket ships.

Ball.

Basketball.

Explanation:

Gravity has to do a lot with air. It puts the planets in there area.

Rocket Ship has to do a lot with air. If i'm right, they calculate the area, weather, about the air.

A ball gets throwed in the air, which gravity comes into place.

Basketball is also a similar example to a ball.

Answer:

N = 198.3 N,  fr = 126.98 N and    μ = 0.64

Explanation:

For this exercise we must use the translational equilibrium condition.

Let's set a reference system with the x-axis horizontally and the y-axis vertical. Let's use trigonometry to decompose the applied force

      cos θ = Fₓ / F

      sin θ = F_y / F

      Fₓ = F cos θ

      F_y = F sin θ

      Fₓ = 159 cos 37 = 126.98 N

      F_y = 159 sin 37 = 95.69 N

Y axis  

    N + F_y - W = 0

    N = W - F_y

    N = 294 - 95.69

    N = 198.3 N

X axis

    Fₓ -fr = 0

     Fₓ = fr

     fr = 126.98 N

the expression for the friction force is

       fr = μ N

       μ = fr / N

       μ = 126.98 / 198.3

       μ = 0.64

Answer:

The parallel plate capacitor is the simplest form of capacitor. ... The property of a capacitor to store charge on its plates in the form of an electrostatic field is called the Capacitance of the capacitor. Not only that, but capacitance is also the property of a capacitor which resists the change of voltage across it.

Explanation:

credits :- adultsscience

Explanation:

Capacitance exists wherever conductive material is separated by insulating material. 

Capacitive structures have the ability to store energy as an electric field;

when a capacitive structure has been designed as an electrical component that has a specified amount of capacitance, it is called a capacitor.

Capacitance symbol is C

you can get a meter for Capacitance

Capacitance formula is C = ε(A/d) where ε represents the absolute permittivity of the dielectric material being used.

simple piece of wire has very low capacitance

[tex]ke = \frac{1}{2} m {v}^{2} [/tex]

[tex]44 = \frac{m {4}^{2} }{2} \\ \frac{88}{16} = m \\ 5.5 = m[/tex]

Answer:

C. The student should make a concave lens model because it directs light away from the center of the lens

Explanation:

The student should make a concave lens model because it directs light away from the center of the lens.

A lens that has at least one inward-curving surface is said to be concave. Since it is a divergent lens, light rays that have been bent by it are dispersed. Short-sightedness is treated by concave lenses, which are thinner in the center than the borders (myopia).

The earliest known usage of a corrective lens is mentioned in Pliny the Elder's writings (23–79). Pliny claims that Emperor Nero used an emerald, perhaps concave formed to adjust for myopia, to watch gladiatorial matches.

After passing through the lens, light beams appear to originate from a spot known as the primary focus.

Therefore, The student should make a concave lens model because it directs light away from the center of the lens.

To learn more about Concave lens, refer to the link:

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Answer:hereeee for pointssss only

Explanation:

The acceleration of gravity on Ganymede will be [tex]g=0.35\ \frac{m}{s^2}[/tex]

It is given that for a simple pendulum on Ganymede

Lenth= 1.00 m

the time period  T= 10.5 sec

The formula for a time period of simple pendulum will be

[tex]T=2\pi\sqrt{\dfrac{l}{g} }[/tex]

By rearranging the formula

[tex]g=l\times (\dfrac{2\pi}{T} )^2[/tex]

[tex]g=1\times (\dfrac{2\pi}{10.5} )^2=0.3577\frac{m}{s^2}[/tex]

[tex]g=0.3577\ \frac{m}{s^2}[/tex]

Thus the acceleration of gravity on Ganymede will be [tex]g=0.35\ \frac{m}{s^2}[/tex]

To know more about simple pendulums follow

https://brainly.com/question/26449711

Answer:

Explanation:

In the chloroplast, photosynthesis occur. The chloroplast capture light energy from the sun and use it with carbondioxide and water to produce glucose and oxygen. Chloroplasts is found in plant cells only

But mitochondria is refer as the power House of the cell. It's break down fuel molecules and produce energy in cellular respiration. Mitochondria is found in both plant and animal cell.

Answer:

It is 3 m/s² downward.

Explanation:

The mass of an object, m = 30 kg

Upward force, F = 200 N

Downward force, F' = -300 N

We need to find the magnitude and direction of its acceleration.

Net force = F+F'

= 200+(-300)

= -100 N

We know that,

Force, F = ma, a is acceleration of the object

[tex]a=\dfrac{F}{m}\\\\a=\dfrac{-100}{30}\\\\a=-3.33\ m/s^2\approx -3\ m/s^2[/tex]

Hence, the acceleration is -3 m/s² and it is acting in the downward direction.

Explanation:

Efficiency is often measured as the ratio of useful output to total input, which can be expressed with the mathematical formula r=P/C, where P is the amount of useful output ("product") produced per the amount C ("cost") of resources consumed.

i dont know what the answer really is but this is what i think

mB = 45 kg

Explanation:

Using conservation of linear momentum,

mAvA + mbvB = (mA + mB)v

(60 kg)(5.5 m/s) + (2.0 m/s)mB = (60 kg + mB)(4.0 m/s)

(330) + 2mB = 240 + 4mB

2mB = 90

mB = 45 kg

Answer: • Fewer teens admitted to drinking and driving in 2013 than in 2004.

• In 2013, about one in five teens admitted to riding with a driver who had been drinking.

Explanation:

The conclusions about alcohol and teen driving that are supported by the data provided will be:

• Fewer teens admitted to drinking and driving in 2013 than in 2004.

• In 2013, about one in five teens admitted to riding with a driver who had been drinking.

Other options are incorrect as the conclusion wasn't gotten from the data that was orovufed

Answer:

Fewer teens admitted to drinking and driving in 2013 than in 2004.

In 2013, about one in five teens admitted to riding with a driver who had been drinking.

Explanation:

Answer:

81.81 kg

Explanation:

[tex]m_1[/tex] = Mass of person = 78.4 kg

[tex]m_2[/tex] = Mass of canister

[tex]u_1[/tex] = Initial velocity of person = 0

[tex]u_2[/tex] = Initial velocity of canister = 3.5 m/s

[tex]v_1[/tex] = Final velocity of person = 2.4 m/s

[tex]v_2[/tex] = Final velocity of canister = 1.2 m/s

The momentum balance in the system is given by

[tex]m_1u_1+m_2u_2=m_1v_1+m_2v_2\\\Rightarrow 78.4\times 0+m_2\times 3.5=78.4\times 2.4+m_2\times 1.2\\\Rightarrow m_2=\dfrac{78.4\times 2.4}{3.5-1.2}\\\Rightarrow m_2=81.81\ \text{kg}[/tex]

Mass of the canister is 81.81 kg.

Answer:

η = 2.2

Explanation:

The index of refraction is given by the following formula:

[tex]\eta = \frac{Sin\ \theta_i}{Sin\ \theta r}[/tex]

where,

η = index of refraction of cubic zirconia = ?

[tex]\theta_i[/tex] = angle of incidence = 56°

[tex]\theta_r[/tex] = angle of refraction = 22°

Therefore,

[tex]\eta = \frac{Sin\ 56^o}{Sin\ 22^o}\\\\\eta = \frac{0.829}{0.375}[/tex]

η = 2.2

Answer: 3300 m/s

F = ma; units: N = kg(m/s/s); where F and a are both vectors, while m, t, and v (speed) are scalars

We are given the mass, force, and the time; however, speed is our unknown.

[F = 16500 N]  [m = 10 kg]  [t = 2 s]  [v = unknown]

What we can do is use kinematics in order to relate v and t with F and m:

For example, we can use V = V₀ + at

Since F = ma can equal a = F/m, we can replace the a variable within the kinematics equation with F/m, so that:

V = V₀ + at

V = V₀ + (F/m)t

In this problem, we can assume the initial value V to equal 0, giving us:

V = (F/m)t

Plugging in the quantities we get:

V = [tex]\frac{16500 N}{10kg}[/tex]· 2s

V = 3300 m/s

To further check whether this is the right manipulated equation to use, we can use dimensional anaylsis to determine that:

V = [tex]\frac{kg(m/s/s) }{kg}[/tex]· s

V = m/s

I hope this helped!

The correct option is: "none of these statements is true".

To find out the correct option among all the options, we need to know more about the electron and proton.

Thus, we can conclude that the option (e) is correct.

Learn more about electron and proton here:

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Answer:

[tex]1.78\:\mathrm{m}[/tex]

Explanation:

Kinematics equations used:

[tex]v_f=v_i+at,\\\\\Delta y = v_it+\frac{1}{2}at^2,\\\\v_f^2=v_i^2+2a\Delta x[/tex]

Other equations used:

[tex]\Delta x =v_i\cdot t,\\\text{-basic trigonometry for right triangles},\\\text{-application of physics concepts}[/tex]

By finding the horizontal component of the projectile's initial launch, we can find how long it will take for the projectile to reach the hill.

Since the projectile is launched at 12 m/s 30 degrees above the horizontal, we can use basic trig for a right triangle to find the horizontal component of the launch:

[tex]\cos 30^{\circ}=\frac{x}{12},\\x=12\cos 30^{\circ}\approx 10.3923048454\:\text{m/s}[/tex]

Now we can use [tex]\Delta x =v_x\cdot t[/tex] to find the time it will take to reach the hill:

[tex]7.5=10.3923048454\cdot t,\\t=\frac{7.5}{10.3923048454}\approx 0.72168783648\:\text{s}[/tex]

To find the total flight time the projectile would take if it were to land back to the same height it started out with, we can use the following kinematics equation:

[tex]v_f=v_i+at[/tex]

We'll use basic trig for a right triangle again to find the vertical component of the velocity at launch:

[tex]\sin 30^{\circ}=\frac{y}{12},\\y=12\sin 30^{\circ}=6\:\text{m/s}[/tex]. (recall [tex]\sin 30^{\circ}=\frac{1}{2}[/tex])

Now plugging this value in:

*Note: the projectile will hit the ground with a vertical velocity equal in magnitude but opposite in direction than the projectile's initial vertical velocity at launch

[tex]-6=6+(-9.8\cdot t),\\t=\frac{-12}{-9.8},\\t=1.22448979592\:\text{s}[/tex]

^This is the total flight time the projectile would take if it were to land back to the same height it started with. Since acceleration is constant, we can divide this time by two to find the time it would take to reach maximum height.

[tex]1.22448979592\div 2=0.61224489795\:\text{s}[/tex]

Thus, it will take [tex]0.61224489795\:\text{s}[/tex] to reach maximum height, meaning that it will take [tex]0.72168783648 - 0.61224489795=0.10944293853\:\text{s}[/tex] to land on the hill after reaching maximum height. Now that we've found this, we can use the following kinematics equation to find the vertical displacement from the projectile's max height to the hill:

[tex]\Delta y =v_it+\frac{1}{2}at^2[/tex]

At maximum height, the projectile's vertical velocity will be zero. Therefore, [tex]v_i=0[/tex] and we have:

[tex]\Delta y =\frac{1}{2}at^2[/tex]

Plugging in values , we have:

[tex]\Delta y =\frac{1}{2}\cdot 9.8\cdot 0.10944293853^2=0.05869100829\:\text{m}[/tex]

This means that the hill is [tex]0.05869100829\:\text{m}[/tex] lower than the max. height the object will reach.

To find the height of the hill from the ground, we will use the following kinematics equation:

[tex]v_f^2=v_i^2+2a\Delta x,\\-6^2=0+2\cdot-9.8\cdot\Delta x,\\36=-19.6\Delta x,\\\Delta x =\frac{36}{-19.6},\\\Delta x =-1.83673469388\:\text{m}[/tex]

Therefore, the max. height that the object will reach is [tex]1.83673469388\:\text{meters}[/tex].

Thus, the hill's height is [tex]1.83673469388-0.05869100829=1.77804368559\:\text{m}\approx\boxed{1.78\:\mathrm{m}}[/tex].

Answer:

it will obviously be decreased by 40p

Answer:

do we have to choose 2 answers here?

Answer:

most probably it's C

Explanation:

alveoli is surrounded by capillaries and whit that option small intestines is also there

Answer:

Given that refractive index of the material is √2. i.e. n = √2. Hence, critical angle for the material is 45°

Answer:

I think 75 m

Explanation:

tell if it was correct

Answer:

This is because it is derived from newtons and metres as shown in the expression;

Explanation:

[tex]pressure = \frac{force}{area} \\ P= \frac{F}{A} \\ P= \frac{newtons}{ {m}^{2} } \\ = pascals[/tex]

Answer:

Unit of pascal is called derived unit because it involves three fundamental units i.e.meter,kg,and second.

Explanation:

formula of pascal=kg/m/s^2

Answer:

 μ= 0.0375,  kinetic

Explanation:

For this exercise we set a reference system with the x axis parallel to the chord

Y axis  

      N - W = 0

      N = W

X axis

      T - fr = 0

the expression for the friction force is

      fr = μ N

we substitute

       T - μ W = 0

       μ = T / W

we calculate

         μ = 1.5 / 40

        μ= 0.0375

coefficient of kinetic friction

Answer:

6.67

Explanation: