MnO4 - is a stronger oxidizing agent than ReO4 - . Both ions have charge-transfer (LMCT) bands; however, the charge-transfer band for ReO4 - is in the ultraviolet, whereas the corresponding band for MnO4 - is responsible for its intensely purple color. Are the relative positions of the charge-transfer absorptions consistent with the oxidizing abilities of these ions? Explain
Answer:
[tex]$MnO^-_4$[/tex] is a strong oxidizing agent.
Explanation:
The 5d orbitals of Re are higher in energy than 3 d orbitals of Mn. So an LMCT ligand to metal charge transfer excitation requires more energy of [tex]$ReO^-_4$[/tex].
Also, since the molecular orbitals are derived primarily from 3d orbitals of [tex]$MnO^-_4$[/tex] are lower in energy than the corresponding MO's of [tex]$ReO^-_4$[/tex], [tex]$MnO^-_4$[/tex] is better able to accept the electrons.
So it is a better oxidizing agent.
The ligand to metal charge transfer band in ReO4- occurs in the near UV region hence ReO4 - appears colorless.
The electron configuration of Re is Xe 4f14 5d5 6s2 and the electron configuration of Mn is [Ar] 3d5 4s2. We can see that Mn^7+ and Re^7+ have empty d orbitals.
The color of MnO4 - must result from ligand to metal charge transfer hence the purple color of MnO4 -. In the case of ReO4 -, the ligand to metal charge transfer occurs at a much higher energy owing to the fact that 5d orbitals are involved. This transition occurs in the near UV region hence ReO4 - appears colorless. The ligand to metal charge transfer in MnO4- involves lower energy 3d orbitals hence it occurs in the visible region of the spectrum.
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4. What is the maximum no. of electrons that can be associated with the following set of
quantum numbers?
n=4, l=1, m=-1
a) 10
b) 6
d) 2
c) 4
Answer:
d) 2
Explanation:
We are given;
n = 4, l = 1, m = -1
We can tell that is is an orbital with sub shell as 3P.
Now, from Paul's exclusion principle, each orbital will have maximum of 2 electrons of each π with a spin of +½ and -½.
Since the maximum is seen to be 2, then option D is correct.
H.w. balance the following equations:
a) Iron + chlorine → Iron (iii) chloride
b) Nitrogen + hydrogen → Ammonia
c) Phosphoric acid + sodium carbonate → sodium phosphate + water + carbon dioxide
d) Nitrogen dioxide + water + oxygen → Nitric acid
Answer:
3iron + chlorine=iron3 chloride
nitrogen +3hydrogen
Answer:
a) Iron + chlorine → Iron (iii) chloride
3fe+cl__fe3cl
b) Nitrogen + hydrogen → Ammonia
2N+3h2------2NH3
c) Phosphoric acid + sodium carbonate → sodium phosphate + water + carbon dioxide
2H3PO3+3Na2CO3-----2Na3PO4+3H2O+3CO2
d) Nitrogen dioxide + water + oxygen → Nitric acid
NO2+H2O+O2--NOH
sorry if mistake
On the basis of the information above, a buffer with a pH = 9 can best be made by using
A pure NaH2PO4
B H3PO4 + H2PO4–
C H2PO4– + PO42–
D H2PO4– + HPO42–
E HPO42– + PO43
Answer:
D H2PO4– + HPO42–
Explanation:
The acid dissociation constant for [tex]\mathbf{H_3PO_4 , H_2PO^{-}_4 , HPO_4^{2-}}[/tex] are [tex]\mathbf{7\times 10^{-3}, \ \ 8\times 10^{-8} ,\ \ 5\times 10^{-13}}[/tex] respectively.
[tex]\mathbf{pka (H_3PO_4) = -log (7\times 10^{-3} )=2.2}[/tex]
[tex]\mathbf{pka (H_2PO_4^-) = -log (8\times 10^{-8} )=7.1}[/tex]
[tex]\mathbf{pka (HPO_4^{2-}) = -log (5\times 10^{-13} )=12.3}[/tex]
The reason while option D is the best answer is that, the value of pKa for both
[tex]\mathbf{H_2PO^{-}_4 ,\ \& \ HPO_4^{2-}}[/tex] lies on either side of the desired pH of the buffer. This implies that one is slightly over and the other is slightly under.
Using Henderson-Hasselbach equation:
[tex]\mathbf{pH = pKa + log \Big( \dfrac{HPO_4^{2-}}{H_2PO_4^-} \Big)}[/tex]
The compounds that are used for the formulation of the pH 9 buffer are [tex]\rm H_2PO_4^-\;and\;HPO_4^+[/tex]. Thus, option D is correct.
The buffers are the solutions of acids and base of appropriate pH, that are able to limit the change in pH in the reaction mixture.
Which compound is used for pH 9 buffer?The buffer pH is adjusted with the compounds that has been able to add base or acid to the solution.
For the formulation of buffer of specific pH, the acid and base solutions are required.
The compounds that are used for the formulation of the pH 9 buffer are [tex]\rm H_2PO_4^-\;and\;HPO_4^+[/tex], as they are able to provide acid and base to the solution.
Thus, option D is correct.
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Which elements make up 95 percent (by weight) of the human body?
What is the voltage in a circuit is the current is 3 amps and the resistance is 3 ohms
Answer:
9
Explanation:
V=I*R
3*3
Thats the answer
Select the option that best represents recycling food waste
O turning food scraps into biogas
O donating unused food to food pantries
O incinerating leftover food
O feeding scraps to livestock
Answer:
feeding leftover or scraps to livestock
Explanation:
Because feeding leftover healthy food instead of leaving livestock to eat garbage is good for health of the animals and they give good quality of milk, eggs, meat, etc in return
What is the electronegativity and bond polarity like in the "head" vs. the "tail" ends of soap?
Answer:
gay
Explanation:
very gay
What is the half life of the graphed material?
Answer:
3 hours
Explanation:
To know the the correct answer to the question given above, it is important we know the definition of half-life.
The half-life of a substance is simply defined as the time taken for half the substance to decay.
Considering the diagram given above, the initial mass of the substance is 100 g.
Half of the initial mass = 100 / 2 = 50 g
Now, we shall determine the time from the graph taken to get to 50 g.
Considering the diagram given above, the time taken to get to 50 g is 3 hours.
Therefore, the half-life of the material is 3 hours.
When the number of molecules, atoms, or ions of a particular type (here we consider H ions) is in the hundreds of millions, we can confidently speak of concentrations and analyze an average behavior.
a. True
b. False
Answer:
True.
Explanation:
When the number of molecules, atoms or ions of any element is in the hundreds of millions, we can safely speak of concentrations and analyze a standard behavior, and can even specify the different dilutions used, if there are dilutions. This allows analyzes to be clearly understood by any individual. However, it is not possible to do this if the number of molecules, atoms and ions is very small.
5. Write the two resonance hybrids for the carbocation that would be formed by protonation at C-1 of 2-methyl-1,3-pentadiene. Without doing a calculation, would you expect C-2 or C-4 (the two end carbons of the allylic cation) to have the most positive charge on it
Answer:
Follows are the solution to this question:
Explanation:
Please find the complete solution in the attached file.
The percentage by mass of oxygen in a compound containing potassium, chlorine, and oxygen was determined experimentally. The technique used follows. solid (KClo compound is weighed. Then it is heated in a crucible. The The solid decomposes to produce oxygen gas and a salt. Because the oxygen escaping, mass of the original solid decreases. From the mass of oxygen lost and mass is the the percentage by mass of oxygen in of the original the original compound is determined. KClyo. (s) salt (s) O (g A student performs five trials and determines the following by mass of oxygen in the compound (KCLO) by mass of oxygen Trial in the compound 38.933 38,940 38,892 38.900
a. Determine the average experimental percentage oxygen in the compound. by mass of 30.933
b. If the actual value of the percentage by mass ofoxygen in this compound is 39.13 determine the percentage error.
Answer:
See explanation
Explanation:
The percentage by mass of oxygen is defined as;
Mass of oxygen/ molar mass of the compound * 100/1
The average percentage by mass of oxygen = 38.933 + 38.940 + 38.871 + 38.892 + 38.900/5
The average percentage by mass of oxygen = 38.907
Percentage Error = (|accepted value – experimental value| \ accepted value) x 100%
Percentage Error = 39.13 - 38.907 / 39.13 * 100
Percentage Error = 0.57%
The fertilization in __________happens outside the female's body
Answer:
Frogs
Explanation:
Answer:
Hello there! I'm assuming frog and or dog :)
The temperature of an oxyacetylene torch flame can reach as high as 3137 °C. What is this temperature in Fahrenheit and Kelvin? Please show work.
Answer:
A)3410K
B)5678.6 °F
Explanation:
✓ To convert Celcius to Kelvin expression below can be used
K= °C + 273
We were given T=3137 °C
= 3137 + 273= 3410K
✓To convert Celcius to Fahrenheit, expression below can be used
°F =(°C × 9/5) + 32
We were given T=3137 °C
°F= (3137 × 9/5) + 32
= 5646.6+32
=5678.6 °F
1. How many molecules are in 4.5 moles?
Answer:
depends on what molecule you are looking for
Explanation:
In one mole of stuff (atoms, molecules, eggses), there are NA individual items of that stuff. So, there are 4.5 × NA BCl3 molecules; i.e. 4.5 × 6.022×1023 ≅ 27×1023 individual molecules of BCl3
what information is shown in the infographics?
Answer:
An infographic is a collection of imagery, charts, and minimal text that gives an easy-to-understand overview of a topic. As in the example below, infographics use striking, engaging visuals to communicate information quickly and clearly. Infographics are a valuable tool for visual communication.
The hybridisation of the central atom in ICL-2
a) sp.
b) sp2
c) sp3d d)sp3
Explanation:
For ICl²-, the central iodine atom is bonded to the 2 chlorine atoms and has 3 lone electron pairs.
Altogether it has 5 electron domains, which means it is sp3d hybridized. (C)
Describe how naturally
acidic rainwater can affect a
mountain of limestone.
Answer:
The naturally acidic rain will gradually wear the mountain of limestone away.
Hope it helps!
The pain reliever morphine contains 17.900 g C, 1.680 g H, 4.225 g O, and 1.228 g N. Determine the empirical Formula.
Answer: The empirical formula is [tex]C_{17}H_{19}O_3N[/tex]
Explanation:
Mass of C= 17.900 g
Mass of H = 1.680 g
Mass of O = 4.225 g
Mass of N = 1.228 g
Step 1 : convert given masses into moles.
Moles of C =[tex]\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{17.990g}{12g/mole}=1.5moles[/tex]
Moles of H =[tex]\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{1.680g}{1g/mole}=1.680moles[/tex]
Moles of O =[tex]\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{4.225g}{16g/mole}=0.264moles[/tex]
Moles of N =[tex]\frac{\text{ given mass of N}}{\text{ molar mass of N}}= \frac{1.228g}{14g/mole}=0.087moles[/tex]
Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.
For C = [tex]\frac{1.5}{0.087}=17[/tex]
For H = [tex]\frac{1.680}{0.087}=19[/tex]
For O =[tex]\frac{0.264}{0.087}=3[/tex]
For N = [tex]\frac{0.087}{0.087}=1[/tex]
The ratio of C : H: O: N = 17: 19: 3: 1
Hence the empirical formula is [tex]C_{17}H_{19}O_3N[/tex]
No pain no gain . which figure of speech is this
Answer:
No pain, no gain is a proverb that means in order to make progress or to be successful, one must suffer. This suffering may be in a physical or mental sense. The phrase no pain, no gain was popularized in the 1980s by the American actress, Jane Fonda.
A chemistry graduate student is studying the rate of this reaction:
NH4OH(aq)→NH3(aq)+H2O(aq)
She fills a reaction vessel with and measures its concentration as the reaction proceeds:
Time (minutes) NH4OH
0 0.200M
1.0 0.0895M
2.0 0.577M
3.0 0.0426M
4.0 0.0337M
Use this data to answer the following questions.
a. Write the rate law for this reaction.
b. Calculate the value of the rate constant.
Answer:
Rate = k[NH₄OH]²
k = 6.17
Explanation:
We have concentrations of NH₄OH along with the given times. To determine the rate law of the reaction we need to determine first the order of reaction. This reaction can be order zero, first or second order. The expressions for each are the following:
Zero order:
k = [A₀] - [A] / t
First order:
k = 1/t * ln([A₀]/[A])
Second order:
k = (1/t) * (1/[A₀] - 1/[A])
And from here, the next part is easier. We just need to determine hat order is, calculating the value of k at two different times. If the value of k is constant, then we can say that the reaction is of that order.
Let's suppose its order zero (t = 1 and t = 2, [A₀] = 0.200 M):
k1 = 0.2 - 0.0895 / 1 = 0.1105
k2 = 0.2 - 0.577 / 2 = -0.1885
From this results we can conclude it's not zero order.
Let's suppose its order 1:
k1 = ln(0.2/0.0895) / 1 = 0.8041
k2 = ln(0.2/0.577) / 2 = 0.1733
It's not first order either, so we can conclude that this reaction is of 2nd order and the rate law would be:
Rate = k[NH₄OH]²Now that we know it's a second order reaction, we can determine the value of k using its expression:
k = (1/t) (1/[A] - 1/[A₀])
k = ln(1/0.0895 - 1/0.2) (1/1)
k = 6.17
And to confirm this value, let's calculate k for t = 2 s
k = (1/2) (1/0.0577 - 1/0.2)
k = 6.17The value is constant, so this is the true value of k.
Hope this helps
Describe what an Ionic Substance is....
Answer:
Ionic Substance is....
Explanation:
In chemistry, an ionic compound is a chemical compound composed of ions held together by electrostatic forces termed ionic bonding. The compound is neutral overall, but consists of positively charged ions called cations and negatively charged ions called anions.
A certain liquid X has a normal boiling point of 129.90°C and a boiling point elevation constant =Kb= 1.67°C·kgmol^−1. Calculate the boiling point of a solution made of 90.g of iron(III) chloride (FeCl3) dissolved in 650.g of X.
Answer:
Boiling T° of solution = 135.6°C
Explanation:
Formula for elevation boiling point is:
ΔT = Kb . m . i
ΔT = Boiling point of solution - Boiling point of pure solvent
Kb = Boiling point elevation constant
m = molality → moles of solute in 1kg of solvent
i = numbers of ions dissolved
FeCl₃ → Fe³⁺ + 3Cl⁻
In the dissociation of the ionic salt, we determined 4 moles of ions dissolved.
3 for chlorides and 1 for iron. Then i = 4
m → We convert the mass of solute to moles:
90 g . 1mol / 162.2g = 0.555 moles
650 g of solvent = 0.650 kg of solvent
m = 0.555 mol/0.650kg → 0.85
We replace data at formula
Boiling T° of solution - 129.90°C = 1.67°C . kg/mol . 0.85 mol/kg . 4
Boiling T° of solution = 1.67°C . kg/mol . 0.85 mol/kg . 4 + 129.90°C
Boiling T° of solution = 135.6°C
Given this balanced equation:
1 Cu + 1 H2SO4 -> 1 CuSO4 + 1 H2
If you have 22.45 moles of H2SO4 , how many mole of CuSO4 can you make?
Answer value
The average adult heart pumps about 84./mLs of blood at 72 beats per minute. Suppose you need to calculate how long it would take the average heart to circulate 1700.mL of blood. Set the math up.
Answer:
1700 mL / 84 mLs
Explanation:
Given that:
Volume of blood pumped per minute = 84 /mLs
Time it takes to circulate 1700 mL of blood :
Time taken = Volume of blood circulate / Rate
Hence, to circulate 1700 mL of blood :
Time taken = 1700 mL / 84 mLs
Tengo que resolver con procedimiento
1. Un automóvil viaja a una velocidad de 100 Km/h durante dos horas. Calcular la distancia recorrida.
2. Un automóvil viaja a una velocidad de 68 Km/h durante tres horas. Calcular la distancia recorrida.
3. Un auto recorre 154 Km en dos horas. ¿Cuál fue su velocidad?
4. Un auto recorre 1500 Km, si lo hace a una velocidad de 70 Km/h, ¿cuánto tardo en hacerlo?.
Answer:
Distance = 200 km
Distance = 204 km
Speed = 77 km/h
Time = 21.42 h
Explanation:
Given:
A.
Speed = 100 km/h , Time = 2 h
Find:
Distance
B.
Speed = 68 km/h , Time = 3 h
Find:
Distance
C.
Distance = 154 km , Time = 2 h
Find:
Speed
D.
Distance = 1500 km speed = 70 km/h
Find:
Time
Computation:
Speed = distance / time
A.
Distance = 100 x 2
Distance = 200 km
B.
Distance = 68 x 3
Distance = 204 km
C.
Speed = 154 / 2
Speed = 77 km/h
D.
Time = 1500 / 70
Time = 21.42 h
Enter the electron configuration for I+ using noble gas shorthand notation.
In the first box enter the noble gas (notice the brackets). In the following boxes enter the number that goes in front of the orbital followed by the superscript.
For example, the electron configuration for sulfur is: [Ne]3s2 3p4
so the first box would have Ne in it followed by 3, then 2, then 3 then 4.
If you do not need an orbital, just enter 0 (zero) in the boxes for the coefficient and superscript.
[ ] s f d p
Find the element in the periodic table and count over
to the right the number of negative charges on your anion.
This element has the same electron configuration as your anion.
Which noble gas precedes the element? Knowing the s, p, d, and f blocks
of elements in the periodic table, deduce the the electron configuration
of the element from the preceding noble gas. Remember that the
1p 1d, 2d, 1f, 2f, and 3f orbitals are forbidden energy levels (they do not exist).
Answer:
[Kr] 4d10 5s2 5p4
Explanation:
The Symbol I represents Iodine. It has atomic number of 53. The full electronic configuration is given as;
1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d10 5s2 5p5
However the question requested for the configuration of I+.
I+ is a cation and it simply refers to an iodine atom that has lost a single electron. The electronic configuration of I+ is given as;
1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d10 5s2 5p4
Using Noble gas shorthand representation, we have;
[Kr] 4d10 5s2 5p4
According to the graph, what is the instantaneous speed of the object at 5 seconds? *
Captionless Image
4 m/s
7 m/s
0.25 m/s
3 m/s
Answer:4m/s
Explanation:The reason why that the answer is because I am Smart.
Which of the following statements about steroid hormones is true?
A. They bind with receptor proteins in the plasma membrane.
B. They bind to carrier proteins in order to be transported in the blood to
their target cells.
C. They are synthesized from epinephrine in the adrenal gland.
D. They are mostly derivatives of the amino acid tyrosine.
Answer:
B. They bind to carrier proteins in order to be transported in the blood to
their target cells.
Explanation:
Steroid hormones are belongs to the class of chemical compound called steroid. Steroid hormones are majorly secreted by three glands - ovaries, testes and adrenal cortex.
Steroid hormones are released in the blood and are allowed to bind to the specific carrier proteins such as corticosteroid-binding globulin and albumin which helps them to carry to the target cells for the functioning.
The steroid hormone binds to receptor proteins in the target cell and not in the plasma membrane
Hence, the correct answer is "B. They bind to carrier proteins in order to be transported in the blood to their target cells."
plz need help right away !
Explanation:
1 mole = 6.02 x 10^23 atoms (Avogadro’s number)
Step 1) Determine how many grams of a substance are in the problem
Step 2) Find the amount of grams in 1 mole of the substance
3) Multiply step one by step two