What volume of hydrogen iodide is produced when 118 liters of hydrogen gas react according to the following reaction? (All gases are at the same temperature and pressure.) hydrogen(g) + iodine(s) hydrogen iodide(g) liters hydrogen iodide

Answer:

E) n=4 l=2 ml=1 ms= 1/2

Explanation:

Arsenic is a member of group 15 in the periodic table. Its electronic configuration is;

1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p3. Its condensed electronic configuration can be written as [Ar]4s2 3d10 4p3. This electronic configuration shown here can now enable us to consider each option given in the question in order to meaningfully arrive at a logical answer.

If we look at option E, the data given for that electron is; n=4 l=2 ml=1 ms= 1/2. This refers to an electron in a 4d orbital. In the ground state configuration of arsenic shown above, there is no 4d orbital, hence option E must be the correct answer.

Explanation:

It is given that,

The electron in a hydrogen atom, originally in level n = 8, undergoes a transition to a lower level by emitting a photon of wavelength 3745 nm. It means that,

[tex]n_i=8[/tex]

[tex]\lambda=3745\ nm[/tex]

The amount of energy change during the transition is given by :

[tex]\Delta E=R_H[\dfrac{1}{n_f^2}-\dfrac{1}{n_i^2}][/tex]

And

[tex]\dfrac{hc}{\lambda}=R_H[\dfrac{1}{n_f^2}-\dfrac{1}{n_i^2}][/tex]

Plugging all the values we get :

[tex]\dfrac{6.63\times 10^{-34}\times 3\times 10^8}{3745\times 10^{-9}}=2.179\times 10^{-18}[\dfrac{1}{n_f^2}-\dfrac{1}{8^2}]\\\\\dfrac{5.31\times 10^{-20}}{2.179\times 10^{-18}}=[\dfrac{1}{n_f^2}-\dfrac{1}{8^2}]\\\\0.0243=[\dfrac{1}{n_f^2}-\dfrac{1}{64}]\\\\0.0243+\dfrac{1}{64}=\dfrac{1}{n_f^2}\\\\0.039925=\dfrac{1}{n_f^2}\\\\n_f^2=25\\\\n_f=5[/tex]

So, the final level of the electron is 5.

Answer:

1. 0.421 g (C₄H₁₀), 1.51 g (O₂), 1.28 g (CO₂), 0.653 g (H₂O)

2. 4.92 g (C₄H₁₀), 17.6 g (O₂), 14.9 g (CO₂), 7.63 g (H₂O)

3. 6.63 g (C₄H₁₀), 23.7 g (O₂), 20.12 g (CO₂), 10.3 g (H₂O)

4. 7.12 g (C₄H₁₀), 12.1 g (O₂), 10.2 g (CO₂), 8.84 g (H₂O)

5. 252 mg (C₄H₁₀), 903 mg (O₂), 763 mg (CO₂), 390 mg (H₂O)

6. 65 mg (C₄H₁₀), 234 mg (O₂), 198 mg (CO₂), 101 mg (H₂O)

Explanation:

1. First of all, we determine the moles of each reactant.

For the first case:

1.51 g . 1 mol/32 g = 0.0472 moles

Ratio is 13:2, 13 moles of oxygen needs 2 moles of C₄H₁₀ for the combustion,

Therefore 0.0472 mol will react with (0.0472 . 2)/13 = 7.26×10⁻³ mol.

Now we convert the moles to mass:

7.26×10⁻³ mol . 58 g/ 1mol = 0.421 g

Now we use stoichiometry to find the mass of the products.

Ratio is 13:8:10.

13 moles of oxygen can produce 8 moles of CO₂ and 10 moles of water

Then, 0.0472 mol would produce:

(0.0472 . 8)/13 = 0.0290 mol

We convert the moles to mass → 0.0290 mol . 44g /mol = 1.28 g

(0.0472 . 10)/13 = 0.0363 mol

We convert the moles to mass → 0.0363 mol . 18 g /1mol = 0.653 g

2. 4.92 g / 58 g/mol = 0.0848 moles of C₄H₁₀

2 moles of C₄H₁₀ react with 13 moles of O₂

So, 0.0848 moles will react with (0.0848 . 13) / 2 = 0.551 moles

We convert to mass: 0.551 mol . 32 g /mol = 17.6 g

Now we use stoichiometry to find the mass of the products.

Ratio is 13:8:10.

0.551 moles of O₂ will produce:

(0.551 . 8)/13 = 0.339 mol of CO₂

We convert to mass: 0.339 mol . 44g / mol =  14.9 g

(0.551 . 10)/13 = 0.424 mol of H₂O

0.424 mol . 18 g /mol = 7.63 g

3. In this case, we have the mass of one of the product

20.12 g . 1mol / 44 g = 0.457 moles of CO₂

According to stoichiometry:

8 moles of CO₂ are produced by the reaction of 13 moles of O₂ and 2 moles of C₄H₁₀

Then, 0.457 moles of CO₂ would be produced by:

(0.457 . 13)/ 8 = 0.743 moles of O₂

We convert to mass: 0.743 mol . 32 g/1mol = 23.7 g

(0.457 . 2)/8 = 0.114 moles of C₄H₁₀

We convert to mass: 0.114 mol . 58g/mol = 6.63g

Now we can determine, the mass of produced water:

(0.743 . 10)/13 = 0.571 mol of H₂O . 18g /mol = 10.3 g

4. We convert the moles of water:

8.84 g / 18g/mol = 0.491 moles

According to stoichiometry: 10 moles of water are produced by 13 moles of O₂ and 2 moles of C₄H₁₀

Then 0.491 moles will be produced by:

(0.491 . 10)/ 13 = 0.378 moles of O₂

We convert to mass: 0.378 mol . 32 g/1mol = 12.1 g

(0.491 . 2)/8 = 0.123 moles of C₄H₁₀

We convert to mass: 0.123 mol . 58g/mol = 7.12g

Now we can determine, the mass of produced carbon dioxide:

(0.378 . 8)/13 = 0.232 mol of CO₂ . 44g /mol = 10.2 g

5. Mass of mg, must be converted to grams

252 mg . 1 g/1000 mg = 0.252 g

It is the same as 2.

0.252 g of C₄H₁₀ . 1mol/58 g = 4.34×10⁻³ mol

2 mol of C₄H₁₀ react to 13 moles of O₂ then,

4.34×10⁻³ mol will react with (4.34×10⁻³ mol . 13) / 2 = 0.0282 mol

We convert the grams → 0.0282 mol . 32 g/mol = 0.903 g (903 mg)

0.0282 mol of oxygen will produced:

(0.0282 . 8)/13 = 0.0173 mol of CO₂

We convert to mass: 0.0173 mol . 44g / mol =  0.763 g (763 mg)

(0.0282 . 10)/13 = 0.0217 mol of H₂O

0.0217 mol . 18 g /mol = 0.390 g  (390 mg)

6. We define the mass of CO₂ → 198 mg . 1g/1000 mg = 0.198 g

0.198 g / 44g/mol = 4.5×10⁻³ moles of CO₂

According to stoichiometry:

8 moles of CO₂ are produced by the reaction of 13 moles of O₂ and 2 moles of C₄H₁₀

Then, 4.5×10⁻³ moles of CO₂ would be produced by:

(4.5×10⁻³ . 13)/ 8 = 7.31×10⁻³ moles of O₂

We convert to mass: 7.31×10⁻³ . 32 g/1mol = 0.234 g (234 mg)

(4.5×10⁻³ . 2)/8 = 1.125×10⁻³ moles of C₄H₁₀

We convert to mass: 1.125×10⁻³ mol . 58g/mol = 0.065 g (65 mg)

Now we can determine, the mass of produced water:

(7.31×10⁻³ . 10)/13 = 5.62×10⁻³ mol of H₂O . 18g /mol = 0.101 g (101 mg)

Answer:

14.3 mL  

Explanation:

Assume the student used 0.113 g ascorbic acid  and 0.0900 mol·L⁻¹ NaOH.

1. Balanced chemical equation.

The formula of ascorbic acid is H₂C₆H₆O₆ (MM = 176.12 g/mol).

However, for the balanced equation, let's write it as H₂A.

[tex]\rm H_{2}A + 2NaOH \longrightarrow Na_{2}A + 2H_{2}O[/tex]

2. Moles of ascorbic acid

[tex]\text{Moles of H$_{2}$A} =\text{0.113 g H$_{2}$A} \times \dfrac{\text{1 mmol H$_{2}$A}}{\text{0.176 12 mg H$_{2}$}A} = \text{0.6416 mmol H$_{2}$A}[/tex]

3. Moles of NaOH

The molar ratio is 2 mmol NaOH:1 mmol H₂A.

[tex]\text{Moles of NaOH}= \text{0.6416 mmol H$_{2}$A} \times \dfrac{\text{2 mmol NaOH}}{\text{1 mmol H$_{2}$A}} =\text{1.283 mmol NaOH}[/tex]

4. Volume of NaOH

[tex]V = \text{1.283 mmol NaOH}\times \dfrac{\text{1 mL NaOH}}{\text{0.0900 mmol NaOH}} = \textbf{14.3 mL NaOH}\\\\\text{The student will need $\large \boxed{\textbf{14.3 mL NaOH}}$}[/tex]

Answer:

The two products of this reaction, Sodium Chloride and Potassium Sulfate, are both soluble in water, hence, there's no precipitate formed from this reaction.

Explanation:

Sodium sulfate is Na₂So₄

Potassium Chloride is KCl

When they both react, theres a double displacement where ions and radicals are exchanged

Na₂SO₄ + KCl → NaCl + K₂SO₄

The products are

NaCl - Sodium Chloride

K₂SO₄ - Potassium Sulfate

The two products are soluble in water, hence, there's no precipitate formed from this reaction.

And we would need numerical values of the number of moles of the two reactants mixed to obtain the number of moles of products formed and then the number of molecules from Avogadro's constant.

Hope this Helps!!!

Answer: Thus 234 kJ of energy are required to produce 1.00 kilogram of iron metal

Explanation:

To calculate the number of moles , we use the equation:

[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]  

Putting values , we get:

[tex]\text{Moles of iron}=\frac{1000g}{56g/mol}=17.8moles[/tex]    (1.00kg=1000g)

The balanced chemical reaction is:

[tex]Fe_2O_3(s)+2CO(g)\rightarrow 2Fe(s)+3CO_2(g)[/tex]   [tex]\Delta H=+26.3kJ[/tex]

Given :

Energy released when 2 moles of [tex]Fe[/tex] is produced = 26.3 kJ

Thus Energy released when 17.8 moles of [tex]Fe[/tex] is produced =

= [tex]\frac{26.3kJ}{2}\times 17.8=234kJ[/tex]

Thus 234 kJ of energy are required to produce 1.00 kilogram of iron metal

Answer:

e) 4-bromo-3,8-dimethylbicyclo[5.2.0]nonane

Explanation:

The missing image of the the  compound we are to name is attached below.

Before we can name an organic compound; It is crucial we know the guiding rules in naming them.

1. Select the longest continuous carbon chain as the root hydrocarbon and name according to the number of carbon atoms it contains, adding appropriate suffix to indicate the principal substituent group.

2. Number the carbon atoms in the root hydrocarbon from the end which gives the lowest number to the substituents.

3. If the same substituent is present two  or more times  in a molecule; the number of this substituent is indicated by the prefix di -(2), tri - (3) , tetra - (4) etc attached to the substituent name.

4. If there is more than one type of substituent in the molecule ; the substituents are named according to the alphabetical order but where  there are mixed substituents ; the inorganic are named first.

5. In selecting and numbering the longest continuous chain, the functional groups are given preference over substituents., i.e the functional group is given the smallest possible number.

In the light of the above guiding rules; we were able to name the given compound because the compound contains nine carbons in the ring form which result to root name nonane. The two methyl are on the third and eight carbon; bromine is on the fourth carbon ; there are two cyclic ring present in the compound where we have 5 carbons in one structure, another 2 carbons in the second structure and zero carbon in the bridge structure which eventually result to the correct  name:

4-bromo-3,8-dimethylbicyclo[5.2.0]nonane

Answer:

Volume of NaOH, aka V2 = 6.32 mL to 3 sig. fig.

A chemistry student weighs out 0.0941 g of hypochlorous acid (HClo) into a 250. ml. volumetric flask and dilutes to the mark with distilled water. He plans to titrate the acid with 0.2000 M NaOH solution. Calculate the volume of NaOH solution the student will need to add to reach the equivalence point. Round your answer to 3 significant digits mL.

Explanation:

1 mole HClO = 74.44g

0.0941g = [tex]\frac{0.0941}{74.44}[/tex] = 0.00126 moles

Concentration = no. of moles/volume in L

Hence, Concentration of HClO = 0.00126/ 0.250L

= 0.005M.

C1V1 =C2V2

0.005 × 250 mL = 0.2 × V2

Volume of NaOH, aka V2 = 6.32 mL to 3 sig. fig.

Answer:

[tex]m_{solution}=470g[/tex]

Explanation:

Hello,

In this case, a solution is formed when a solute is completely dissolved in a solvent, thus, for this situation, the sugar is the solute and the water the solvent but in addition to them we find spices which are also considered in the total mass of the solution. In such a way, for computing the total mass we must add the mass of three constituents (115 g sugar, 350 g water and 5 g spices) as shown below:

[tex]m_{solution}=115g+350g+5g\\\\m_{solution}=470g[/tex]

Best regards.

Answer:

Oxygen is more electronegative than carbon.

Explanation:

Electronegativity increases from left to right across the periodic table. Since oxygen is further right than carbon, it is more electronegative. Also, if you look at a chart of electronegativity, oxygen has an electronegativity of 3.44 while carbon has an electronegativity of 2.55.

So oxygen is more electronegative than carbon. Hope this helps.

Answer:

- Addition of NH₃(g)

- Removal of N₂(g)

- Increase of temperature

- Pressure decrease

Explanation:

According to Le Chatelier's principle, if we apply an stress to a reaction at equilibrium, the system will try to shift the equilibrium in order to decrease the stress. If we add reactants, the equilibrium will shift toward the formation of more products (to the consumption of reactants) and vice versa.

The stresses we can apply to this equilibrium are the following:

- Addition of NH₃(g) : it is a product, thus its addition will result in a shift toward reactants.

- Removal of N₂(g): it is a reactant, thus its removal from the reaction mixture will result in a shift toward reactants.

- Increase of temperature: the reaction is exothermic, so it releases energy. Energy is a product. If we add energy (increase the temperature), we are adding a product, so the equilibrium will shift toward the reactants.

- Pressure decrease: because both reactants and products are in the gas phase. A decrease in pressure shifts an equilibrium to the side of the reaction with greater number of moles of gas. In this case, the reactants side has greater number of moles of gas (1 mol + 3 moles= 4 moles) than the products side (2 moles). Thus, the equilibrum will shift toward reactants.

Answer:

The methyl group will already be present  

Explanation:

You want to make 1-methyl-4-nitrobenzene.

The question is, "Do I start with the methyl group on the ring and then nitrate, or do I start with the nitro group on the ring and then add the methyl group?"

The methyl group is activating and ortho, para directing.

The nitro group is deactivating and meta directing.

You want a para-substituted product, so you choose to nitrate toluene, as in the reaction scheme below.

Answer:

Use a ratio of 0.44 mol lactate to 1 mol of lactic acid  

Explanation:

John could prepare a lactate buffer.

He can use the Henderson-Hasselbalch equation to find the acid/base ratio for the buffer.

[tex]\text{pH} = \text{pK}_{\text{a}} + \log\dfrac{\text{[A$^{-}$]}}{\text{[HA]}}\\\\3.5 = 3.86 + \log\dfrac{\text{[A$^{-}$]}}{\text{[HA]}}\\\\\log\dfrac{\text{[A$^{-}$]}}{\text{[HA]}} = 3.5 - 3.86 = -0.36\\\\\dfrac{\text{[A$^{-}$]}}{\text{[HA]}} = 10^{-0.36} = \mathbf{0.44}[/tex]

He should use a ratio of 0.44 mol lactate to 1 mol of lactic acid.

For example, he could mix equal volumes of 0.044 mol·L⁻¹ lactate and 0.1 mol·L⁻¹ lactic acid.

Answer:

See the explanation

Explanation:

Our reactions for this question are:

a) Cr+3(aq) + 3e- → Cr(s) ________

b) Ag(s) → 1e- + Ag+1(ag) ________

c) Mn(s) → 5e- + Mn+5(aq) ________

d) Sn+2(aq) + 2e- → Sn(s) ________

Now, we have to remember the definition of oxidation and reduction. In a reduction reaction,  the substance will gain electrons, in other words: "The electrons would be placed on the left side, in the side of the reagents. In an oxidation reaction, the substance will lose electrons, in other words: "The electrons would be placed on the right side, in the side of the products".

With this in mind we will have:

a) Cr+3(aq) + 3e- → Cr (s)(Reduction)

b) Ag(s) → 1e- + Ag+1(ag) (Oxidation)

c) Mn(s) → 5e- + Mn+5(aq) (Oxidation)

d) Sn+2(aq) + 2e- → Sn(s) (Reduction)

I hope it helps!

Answer:

The BaSO₄ precipitates as a solid.

Explanation:

In order to determine the precipitation, we need to look at the reactants, we have: Ba(NO₃)₂ and Li₂SO₄

Salts from nitrate are all soluble and sulfates can make precipitate if they react to elements from group 2. (Solubility rules) So this reaction, has a precipitate but we can predict it, if we look at the reaction and we take acount the Kps:

Ba(NO₃)₂ (aq) + Li₂SO₄ (aq)  →  2LiNO₃ (aq)  +  BaSO₄ (s) ↓

Let's find out the moles of each ion:

Ba(NO₃)₂ (aq) →  Ba²⁺  (aq)  +  2NO₃⁻  (aq)

0.8 L . 0.0002 M = 1.6×10⁻⁴ moles. These are the moles of Ba²⁺ in 1 L of solution, so [Ba²⁺] = 1.6×10⁻⁴ M

Li₂SO₄ (aq) →  2Li⁺ (aq)  +  SO₄⁻² (aq)

0.2 L . 0.0005 M = 1×10⁻⁴ M. These are the moles of sulfate, in 1 L of solution so [SO₄⁻²] =  1×10⁻⁴ M

BaSO₄ (s)  ⇆   Ba²⁺  (aq) + SO₄⁻² (aq)      Kps = 1.08×10⁻¹⁰

We need to compare Kps to [ Ba²⁺] . [SO₄⁻²]

[ Ba²⁺] . [SO₄⁻²] = 1.6 ×10⁻⁸ >  Kps →  Precipitate.

If  [Ba²⁺] . [SO₄⁻²] = Kps  → Solution is saturated

If [ Ba²⁺] . [SO₄⁻²] < Kps → There is no precipitate formed, or if it is formed, it will be quickly dissolved to reach saturation.

Answer:

[tex]Fe_2O_3+3CO\Rightarrow \:2Fe+3CO_2[/tex]

Explanation:

[tex]Fe_2O_3+CO\Rightarrow \:2Fe+CO_2\\\\Fe_2O_3+3CO\Rightarrow \:2Fe+3CO_2[/tex]

Best Regards!

Answer:

calcium chloride dihydrate

Answer:

Ge: [Ar] 3d10 4s2 4p2 => 6 electrons in the outer shell

Br: [Ar] 3d10 4s2 4p5 => 7 electrons in the outer shell

Kr: [Ar] 3d10 4s2 4p6 => 8 electrons in the outer shell

Explanation:

The electron affinity or propension to attract electrons is given by the electronic configuration. Remember that the most stable configuration is that were the last shell is full, i.e. it has 8 electrons.

The closer an atom is to reach the 8 electrons in the outer shell the bigger the electron affinity.

Of the three elements, Br needs only 1 electron to have 8 electrons in the outer shell, so it has the biggest electron affinity (the least negative).

Ge: needs 2 electrons to have 8 electrons in the outer shell, so it has a smaller (more negative) electron affinity than Br.

Kr, which is a noble gas, has 8 electrons and is not willing to attract more electrons at all, the it has the lowest (more negative) electron affinity of all three to the extension that really the ion is so unstable that it does not make sense to talk about a number for the electron affinity of this atom.

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Answer:

remain the same

Explanation:

The pH of the buffer system remain the same when 0.030 moles of strong acid are added because buffer system has the property to resist any change in the pH  when acid or base is added to the solution. In buffer system, one molecule is responsible for neutralizing the pH of the solution by giving H+ or OH-.This molecule is known as buffer agent. If more base is added, the molecule provide H+ and when more acid is added to the solution, then the molecule add OH- to the solution.

Answer:

Here's what I find  

Explanation:

Sodium vapour produces mostly yellow light.

Mercury vapour produces mostly blue light.

A white car reflects all colours back to our eyes.

A coloured car, say green, absorbs all the other colours and reflects the green.

Under a sodium light, a white or a yellow car will appear yellow. A red car will be nearly black because there is no red light to reflect.

Under a mercury light, a white or a blue car will appear blue. A yellow car will be quite dark, but there will be a yellowish tinge because there is some yellow in the Hg spectrum for it to reflect.  

The picture below shows a red car and a black car under sodium light. Can you tell which is which?

Answer: [tex]2HCl(aq)+Zn(s)\rightarrow ZnCl_2(aq)+H_2(g)[/tex]

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products formed must be equal to the mass of reactants taken.

In order to get the same mass on both sides, the atoms of each element must be balanced on both sides of the chemical equation.

A single replacement reaction is one in which a more reactive element displaces a less reactive element from its salt solution.

The salts which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) after their chemical formulas. Gases are represented by (g) after their chemical formulas.

Thus  2 hydrogen chloride molecules in aqueous solution react with solid zinc. The reaction produces zinc chloride in aqueous solution and hydrogen gas is represented as :

[tex]2HCl(aq)+Zn(s)\rightarrow ZnCl_2(aq)+H_2(g)[/tex]

-lg[H+]=1.5

which means that [H+]=0.03M

pOH=14-pH=14-1.5=12.5

-lg[H+]=1.5

which means that [H+]=0.03M

pOH=14-pH=14-1.5=12.5

the hydroxide ion concentration. is 12.5.

The hydronium ion concentration can be found from the pH by the reverse of the mathematical operation employed to find the pH. [H3O+] = 10-pH or [H3O+] = antilog (- pH) Example: What is the hydronium ion concentration in a solution that has a pH of 8.34? On a calculator, calculate 10-8.34, or "inverse" log ( - 8.34).

For a 0.025 M HCl solution the concentration of the hydrogen ions, [H+] , is 0.025 moles/liter (i.e. 0.025 M). pH is defined as −log[H+] . Substituting 0.025 into the equation for pH we find that the 0.025 M HCl solution has a pH of -log(0.025) = 1.60.

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Answer:

The concentration of the borax solution is 0.1066 M

Explanation:

Step 1: Dtaa given

Volume of a sample of aqueous borax solution = 20.00 mL = 0.020 L

Molarity of H2SO4  = 1.03 M

Volume of the H2SO4 = 2.07 mL = 0.00207 L

Step 2: The balanced equation

Na2B4O7*10H2O(borax) + H2SO4 ⇆ Na2SO4 + 4 H3BO3 + 5 H2O

Step 3: Calculate molarity of borax solution

b*Ca*Va = a * Cb*Vb

⇒with B = the coefficient of H2SO4 = 1

⇒with Ca = the concentration of borax = TO BE DETERMINED

⇒with Va = the volume of borax = 0.020 L

⇒with a = the coefficient of borax = 1

⇒with Cb = the concentration of H2SO4 = 1.03 M

⇒with Vb = the volume of H2SO4 = 0.00207 L

Ca*0.020 L = 1.03 M * 0.00207 L

Ca = (1.03 * 0.00207) / 0.020

Ca = 0.1066 M

The concentration of the borax solution is 0.1066 M

Answer: [tex]1s^22s^22p^63s^23p^64s^2[/tex]

Explanation:

Electronic configuration represents the total number of electrons that a neutral element contains. We add all the superscripts to know the number of electrons in an atom.

The electrons are filled according to Afbau's rule in order of increasing energies where orbital with higher value of (n+l) has higher energy as compared to orbital having lower (n+l) value. Thus the electronic configuration for calcium with atomic number of 20 and hence containing 20 electrons is :

[tex]Ca:20:1s^22s^22p^63s^23p^64s^2[/tex]

Answer:

Explanation:

the forces between the molecules are stronger in solid than in liquids

Answer:

3-Pentyn-1-ol

Explanation:

tripple bond is at 3 postion from alochol

carbon are 5 atoms so pent

yn becauese its alkyne

Answer:

pH = 7.0

Explanation:

When HCl reacts with NaOH, H₂O and NaCl are produced, thus:

HCl + NaOH → H₂O + NaCl

At equivalence point, all HCl reacts with NaOH. The only you will have is water.

Equilbrium of water is:

H₂O(l) ⇄ H⁺(aq) + OH⁻(aq)

K = 1x10⁻¹⁴ = [H⁺] [OH⁻]

As H⁺ = OH⁻ because both are produced from the same water-

1x10⁻¹⁴ = [H⁺]²

1x10⁻⁷M = [H⁺]

As pH = -log= [H⁺]

-The pH at equivalence point in the titration of a strong acid with a strong base is always 7.0-

Answer:

Well hey there!

There isn't any info on what you need help with!

Sorry...

Answer:

If 51.8 of Pb is reacting, it will require 4.00 g of O2

If 51.8 g of PbO is formed, it will require 3.47 g of O2.

Explanation:

Equation of the reaction:

2 Pb + O2 → 2 PbO

From the equation of reaction, 2 moles of lead metal, Pb, reacts with 1 mole of oxygen gas, O2, to produce 2 moles of lead (ii) oxide, PbO

Molar mass of Pb = 207 g

Molar mass of O2 = 32 g

Molar mass of PbO = 207 + 32 = 239 g

Therefore 2 × 207 g of Pb reacts with 32 g of O2 to produce 2 × 239 g of PbO

= 414 g of Pb reacts with 32 g of O2 to produce 478 g of PbO

Therefore, formation of 51.8 g of PbO will require (32/478) × 51.8 of O2 = 3.47 g of O2.

If 51.8 of Pb is reacting, it will require (32/414) × 51.8 g of O2 = 4.00 g of O2

Answer:

distance = 7 miles

displacement = 5 miles

Explanation:

Distance is a scalar quantity as it takes account of magnitude traveled but not the direction traveled from starting point.

The distance traveled is the sum total of distances moved

distance = 4 + 3 = 7 miles

Displacement however, is a vector and measure the shortest possible distance traveled in a given direction from the starting point.

The path of Elvis' walking forms a right-angle triangle with the hypotenuse being the displacement and the other two sides being the distance traveled west and south.

Using Pythagoras' theorem; c² = a² + b²

where c = hypotenuse and a and b are the other two sides

c² = 4² + 3²

c² = 16 + 9 = 25

√c² = √25

c = 5

Therefore, displacement = 5 miles