What volume of a 3.00M KL stock solution would you use to make 0.300 L of a 1.25M Kl solution?
Answers
Answer:
0.125L or 125 mL
Explanation:
See the image for steps!
0.125L of 3.00M KI stock solution is required to make 0.300 L of a 1.25M KI solution.
What is solution?A solution is a homogeneous mixture of one or more solutes dissolved in a solvent.
What is stock solution?A stock solution is a concentrated solution that will be diluted to a solution of lower concentration.
stock solution = diluted solution
What do you mean by dilution?Dilution is the process of decreasing the concentration of a stock solution by adding more solvent to the solution. The solvent added is the water. The more the solvent you add, the more dilute the solution is.The equation for dilution is M1V1=M2V2Where, M1 = concentration in molarity (moles/Litres) of the concentrated solution
V2 = volume of the concentrated solution,
M2 = concentration in molarity of the dilute solution
V2 = volume of the dilute solution.
The volume of 3.00M KI solution can be calculated using the dilution equation:
Given:
M1 = 3.00M, M2 = 1.25M, V1 = x, V2 = 0.300L
M1V1 = M2V2
3.00M(x) = 1.25M(0.300L)
x = 0.125L
Hence, 0.125L of 3.00M KI stock solution is required to make 0.300 L of a 1.25M KI solution.
To learn more about dilution here
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