What value could you write in after 3x that would make the equation true for all values of x?
3x+12 = 3x+

Answer: X = 1

Y= 5

Step-by-step explanation:

Plug in y = 3x + 2 in the Y coordinate to find X

-4x + 4(3x + 2) = 16

Now you can solve for X

X = 1

Then plug in 1 in the X coordinate to find Y

-4(1)+ 4y= 16

Now you can solve for Y

Y= 5

YOUR WELCOME

Answer:

can't find answer sorry

Answer:

27.95 and 34.05 are compatible because when you add up the decimals, the equal 0, which makes it easier to add. 27. 95 + 34.05 = 61.00.

Same with 19.37 and 21.63, it adds up to 40.00

The answer to all of this would be 101.00

Answer:

24

Step-by-step explanation:

x = 8, y = 3, z = 2

(1/4) x {8[2(3)+3(2)]}

(1/4) x {8(6 + 6)}

(1/4) x {48 + 48} (by distributing)

1/4 x 96

= 24

Answer:

k = i√ 5 , -i√ 5

Step-by-step explanation:

3 + kx^2 + 2 = ?

3 + k(1)^2 + 2 = ?

5 + k(1)^2 = ?

5 + k^2 = ?

k^2 = -5

k = i√ 5 , -i√ 5

Step-by-step explanation:

[tex] \underline{ \underline{ \text{Given}}}[/tex] :

[tex] \underline{ \underline{ \text{To \: prove}}} : [/tex]

[tex] \tt{ \sqrt{ab} - \sqrt{bc} - \sqrt{cd} = \sqrt{(a - b - c)(b - c - d)} } [/tex]

[tex] \underline{ \underline{ \text{Solution}}} : [/tex]

Left hand side ( L.H.S ) :

[tex] \tt{ \sqrt{ab} - \sqrt{bc} - \sqrt{cd}} [/tex]

⟶ [tex] \tt{ \sqrt{d {k}^{3} \cdot \: d {k}^{2} } - \sqrt{d {k}^{2} \cdot \: dk } - \sqrt{dk \cdot \: d} }[/tex]

⟶ [tex] \tt{ \sqrt{ {d}^{2} {k}^{5} } - \sqrt{ {d}^{2} {k}^{3} } - \sqrt{ {d}^{2}k } }[/tex]

⟶ [tex] \tt{ \sqrt{ {d}^{2} \cdot \: {k}^{2} \cdot \: {k}^{2} \cdot \: k } - \sqrt{ {d}^{2} \cdot \: {k}^{2} \cdot \: k \: } - \sqrt{ {d}^{2}k } }[/tex]

⟶ [tex] \tt{ \sqrt{ {d}^{2} } \cdot \sqrt{ {k}^{2} } \cdot \: \sqrt{ {k}^{2} } \cdot \: \sqrt{k} } - \sqrt{ {d}^{2} }\cdot \: \sqrt{ {k}^{2}} \cdot \: \sqrt{k} \: - \sqrt{ {d}^{2} } \cdot \: \sqrt{k} [/tex]

⟶ [tex] \tt{d {k}^{2} \sqrt{k} - dk \sqrt{k} - d \sqrt{k} }[/tex]

⟶ [tex] \tt{ d\sqrt{k} \: ( {k}^{2} - k - 1) } [/tex]

Right Hand Side ( R.H.S) :

[tex] \tt{ \sqrt{(a - b - c)(b - c - d)}} [/tex]

⟶ [tex] \tt{ \sqrt{(d {k}^{3} - d {k}^{2} - dk)( d{k}^{2} - dk - d)} }[/tex]

⟶ [tex] \tt{ \sqrt{ \{dk( {k}^{2} - k - 1) \} \: \{d( {k}^{2} - k - 1) \}} }[/tex]

⟶ [tex] \tt{ \sqrt{ {d}^{2}k( {k}^{2} - k - 1) ^{2} } } [/tex]

⟶ [tex] \tt{ \sqrt{ {d}^{2}k } \cdot \: \sqrt{ {( {k}^{2} - k - 1)}^{2} } } [/tex]

⟶[tex] \tt{ \sqrt{ {d}^{2} } \cdot \: \sqrt{k} \cdot \: \sqrt{( {k}^{2} - k - 1) ^{2} } }[/tex]

⟶ [tex] \tt{d \sqrt{k} \: ( {k}^{2} - k - 1) } [/tex]

L.H.S = R.H.S

Hence , Proved !

Hope I helped ! ♡

Have a wonderful day / night ! ツ

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Answer:

wht

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..

.

Answer:

The two points are (0,1) and (0.75, 0)

Step-by-step explanation:

I hope this helped and if it did I would appreciate it if you marked me Brainliest. Thank you and have a nice day!

We know these triangles are congruent with the missing side, N would be equal to 15.

Two triangles are said to be congruent if the length of the sides is equal, a measure of the angles are equal and they can be superimposed.

We know these triangles are congruent.

To find the missing side, N

ΔABC ≅ΔQRS

AC/QS = BC/RS

2/5 = 6/n

n = 6 x 5/2

n = 30/2

n = 15

Thus, the value of N is 15.

Learn more about triangles;

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Answer:

[tex]\frac{1}{2\sqrt{5} }[/tex]

Step-by-step explanation:

Let, [tex]\text{sin}^{-1}(\frac{x}{6})[/tex] = y

sin(y) = [tex]\frac{x}{6}[/tex]

[tex]\frac{d}{dx}\text{sin(y)}=\frac{d}{dx}(\frac{x}{6})[/tex]

[tex]\frac{d}{dx}\text{sin(y)}=\frac{1}{6}[/tex]

[tex]\frac{d}{dx}\text{sin(y)}=\text{cos}(y)\frac{dy}{dx}[/tex] ---------(1)

[tex]\frac{1}{6}=\text{cos}(y)\frac{dy}{dx}[/tex]

[tex]\frac{dy}{dx}=\frac{1}{6\text{cos(y)}}[/tex]

cos(y) = [tex]\sqrt{1-\text{sin}^{2}(y) }[/tex]

          = [tex]\sqrt{1-(\frac{x}{6})^2}[/tex]

          = [tex]\sqrt{1-(\frac{x^2}{36})}[/tex]

Therefore, from equation (1),

[tex]\frac{dy}{dx}=\frac{1}{6\sqrt{1-\frac{x^2}{36}}}[/tex]

Or [tex]\frac{d}{dx}[\text{sin}^{-1}(\frac{x}{6})]=\frac{1}{6\sqrt{1-\frac{x^2}{36}}}[/tex]

At x = 4,

[tex]\frac{d}{dx}[\text{sin}^{-1}(\frac{4}{6})]=\frac{1}{6\sqrt{1-\frac{4^2}{36}}}[/tex]

[tex]\frac{d}{dx}[\text{sin}^{-1}(\frac{2}{3})]=\frac{1}{6\sqrt{1-\frac{16}{36}}}[/tex]

                   [tex]=\frac{1}{6\sqrt{\frac{36-16}{36}}}[/tex]

                   [tex]=\frac{1}{6\sqrt{\frac{20}{36} }}[/tex]

                   [tex]=\frac{1}{\sqrt{20}}[/tex]

                   [tex]=\frac{1}{2\sqrt{5}}[/tex]

Answer:

11

Step-by-step explanation:

2w = 2×8 - (-2×3)

2w = 16 - (-6)

2w = 22

w = 11

Answer:

3x

7-k

m/4

(5x)+12

Step-by-step explanation:

most of the words like and are just fillers. and basically means together in this instance

Answer:

$115.2

Step-by-step explanation:

Step one:

Given data

A store used to sell an MP3 for $72 and we are told that this 50% of the wholesale price.

Therefore the wholesale price is

72*2= $144

Required:

The special sales cost at 20% discount

Step two:

We are told that the special sale is at a 20% discount on the wholesale

= 20/100*144

=0.2*144

=$28.8

Therefore the special sales price is

= 144-28.8

=$115.2

Answer:

-1/24 < x < 0

Step-by-step explanation:

Answer:

P(white ball)=0.29

Step-by-step explanation:

12 yellow balls

5 red balls

7 white balls

12+5+7=24

so 24 balls in the bag

[tex]\frac{7}{24}[/tex]=0.2916

rounded to the nearest is 0.29

Answer:

Intersection

Step-by-step explanation:

The intersection of two set A and B is defined as the elements which can be found in both set A and set B.

For instance :

A = {1, 3, 5, 7, 9, 11}

B = {2, 4, 6, 7, 8, 9, 10}

The intersection of the two sets A and B denoted as ;

AnB = {7, 9}

Answer:

Grace's brother has $47.

Answer:

B - The values of both x and y will be real numbers greater than or equal to 0.

The answer choice that best describes the values of x and y is B - The values of both x and y will be real numbers greater than or equal to 0.

Given that peaches are being sold for $2 per lb.

If we define x as the number of pounds that you buy, and y as the cost of these peaches, we can write the function:

y = $2*x

Therefore, the best description of the values of x and y is found in option B. The value of x can be any real number greater than or equal to 0, but the value of y must be an integer greater than or equal to 0.

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Answer:

14 × (19 + 6)

hope it helps

The expression represents the total number of cans of beans Mr. Jenkins is, (19+6)×14, So Option B is correct.

An expression is a sentence with at least two numbers or variables having mathematical operation. Math operations can be addition, subtraction, multiplication, division.

For example, 2x+3

Given that,

Mr. Jenkins has 19 cases of beans

He also has 6 cases of beans in the stock room

There are 14 cans of beans in each case

Expression for total number of beans = ?

Total number of beans  = Total number of cases ×beans in each case

Total number of beans = (beans in grocery store+beans in stock room)×14

Total number of beans = (19 +6) × 14

Hence, the expression is  (19 +6) × 14

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Answer:

  [tex]\sqrt{\frac{2x^{5} }{18} }[/tex]   = [tex]\frac{\sqrt{x^{5} } }{3}[/tex]

Step-by-step explanation:

Given expression

            [tex]\sqrt{\frac{2x^{5} }{18} }[/tex]

we know that the algebra formula

[tex]\sqrt{\frac{a}{b} } = \frac{\sqrt{a} }{\sqrt{b} }[/tex]

[tex]\sqrt{\frac{2x^{5} }{18} } = \frac{\sqrt{2} \sqrt{x^{5} } }{\sqrt{18} } = \frac{\sqrt{2} \sqrt{x^{5} } }{\sqrt{9} \sqrt{2} }[/tex]

          = [tex]\frac{\sqrt{x^{5} } }{3}[/tex]

Answer: "reduced by a factor of One-third."

Step-by-step explanation:

Suppose that the original magazine has a length L and a width W.

If it is photocopied using a scale factor of K, then the measures of the photocopy will be:

length = K*L

Width = K*W

In this case, the scale factor is K = 1/3, then the measures of the photocopy will be:

length = (1/3)*L = L/3

Width = (1/3)*W = W/3

For usual notation:

When k > 1, we have an enlargement by a factor k

when 0 < k < 1, we have a reduction by a factor k

in this case, k = 1/3, then:

We have a reduction by a factor of 1/3

The correct option is:

"reduced by a factor of One-third."

Answer: D-reduced by a factor 1/3

Step-by-step explanation:

got it correct on edge 2021

Step-by-step explanation:

AB = 72 so, then FB would be half of that

so 72 divided by 2 would be 36

5x+1=36 then do substitution

-1 from both sides (from +1 you gotta do the inverse)

5x = 35

divide 5 from both sides because in between 5 and x is a times so the inverse of that is divide

x = 7

Answer:

Ice cream

Step-by-step explanation:

During the 1787 convention in Philadelphia when the constitution was being formed by the founding fathers, their sessions would usually end in heated arguments and disagreements.

To calm the delegates after the draining sessions, Benjamin Franklin who was then mostly in his home and 81 years old at that time, came up with the idea of entertaining the delegates in his home with the cold cream. His idea was helpful in reducing tensions.

Answer:

An air cooling he has invented

Step-by-step explanation:

Answer:

[tex]\displaystyle \int {\frac{1}{\sqrt{x} \sqrt{1-x} } } \, dx = 2arcsin(\sqrt{x}) + C[/tex]

General Formulas and Concepts:

Calculus

Step-by-step explanation:

Step 1: Define

[tex]\displaystyle \int\limits {\frac{1}{\sqrt{x} \sqrt{1-x} } } \, dx[/tex]

Step 2: Identify

Set up variables for u-substitution and integral trig.

[tex]\displaystyleu = \sqrt{x}\\a = 1\\du = \frac{1}{2\sqrt{x}}dx[/tex]

Step 3: integrate

We are given the expression:                                                                              

[tex]\int\limits {\frac{1}{\sqrt[]{x} }*\frac{1}{\sqrt[]{ 1-x^{2}}} } \, dx[/tex]

U-substitution:                                                                                                      

let u = [tex]x^{1/2}[/tex]             [So, x = u²]

[tex]\frac{du}{dx} = \frac{1}{2\sqrt[]{x}}[/tex]                 [differentiating both sides wrt x]

dx = du*2√(x)

dx = 2u(du)            [Since u = √x]

Finding the Integral:                                                                                              

Plugging these values in the given expression:

[tex]\int\limits {u^{-1}*(1-u^{2})^{-1/2} } \, 2\sqrt[]{x}*du[/tex]

[tex]\int\limits {\frac{1}{u}*\frac{1}{\sqrt[]{ 1-u^{2}}}*2u } \, du[/tex]

The 'u' in the numerator and denominator will cancel out

[tex]\int\limits {\frac{1}{\sqrt[]{ 1-u^{2}}}*2 } \, du[/tex]

Since 2 is a constant

[tex]2\int\limits {\frac{1}{\sqrt[]{ 1-u^{2}}} } \, du[/tex]

Using the property: [tex]\int\limits {\frac{1}{\sqrt[]{1-x^{2}} }} \, dx[/tex] = ArcSin(x) + C

2*ArcSin(u) + C

Since u = √x :

2*ArcSin(√x) + C

Answer:

Is there a picture for this one and also you didn't mention the slope of the red line is?

Step-by-step explanation:

Answer:

The slope of the Green line should be the same as the red line- but a negative number instead of a positive.

Step-by-step explanation:

This is the inverse of the line

So by reflecting it over the y-axis, the slope remains the same but will change from positive to negative and vise versa

9514 1404 393

Answer:

  36

Step-by-step explanation:

"Varies directly" means the relationship is proportional:

  y/9 = 16/4

  y = 9·16/4 = 36

The value of y is 36 when x = 9.

Step-by-step explanation:

-70x^4 + 30x

= 10x(-7x^3 + 3)

ANSWER: 10x(-7x^3 + 3)

Answer:

Step-by-step explanation:

Given costs:

Sum of the costs:

Average cost is sum divided by number: