What the answer question

Pls mark me brainliest

Answer:

The correct option is;

A. The total points Shelly earned

Step-by-step explanation:

The given details are;

The number of tasks completed by Shelly and Terrence in the game = x

The total points scored by Terrence = 20 less than the total point scored by Shelly

The expression for Terrence's total point is 90·x - 20

Let the total points Shelly earned = Y

Therefore since the total points scored by Terrence = 20 less than the total point scored by Shelly, we have;

The total points scored by Terrence = Y - 20

Comparing the two expressions for the total points scored by Terrence which are;

90·x - 20 and Y - 20 we have;

90·x - 20 = Y - 20

Adding 20 to both sides of the equation gives;

90·x - 20 + 20= Y - 20 + 20

Which gives;

90·x = Y

Therefore, the first term of the expression 90·x - 20, which is 90·x is equal to Y, which is the total points Shelly earned

The correct option is therefore the total points Shelly earned.

Answer:

A. The total points Shelly earned

Step-by-step explanation:

Hope this helps!

Have a great day! :)

Answer:

see below

Step-by-step explanation:

5^2  means 5*5  not 5*2

5^2 = 5*5 = 25  not 10

Answer:

5*5 = 25

bobby mistake is doing 5*2 = 10

Step-by-step explanation:

Answer: 11136 grams

≈ 11.14 kilograms  

Step-by-step explanation:

Given, Each package has 126 grams of granola, 245 grams of chocolate chip cookies , and 325 grams of nuts in it.

Total weight of each package =  126 grams + 245 grams +  325 grams

= 696 grams

If they have 16 care packages, then total weight of packages = 16 x (Total weight of each package)

= 16 x 696 grams

=  11136 grams

≈ 11.14 kilograms   [ 1 kilogram = 1000 grams]

Answer:

466.7 or 42.003 miles

Step-by-step explanation:

subtract 59.99 from 200.00. Then you have 140.01 and divide or multiply it by 0.30.

[tex]\huge{\sf \left[{x-2y\atop 6x-2z}\:\:\:{4y-3\atop 2y-z}\right]=\left[{-3\atop 4}\:\:\:{5\atop 3}\right]}[/tex]

Creating equations

[tex]\\ \sf\longmapsto x-2y=-3\dots(1)[/tex]

[tex]\\ \sf\longmapsto 4y-3=5\dots(2)[/tex]

[tex]\\ \sf\longmapsto 6x-2z=4\dots(3)[/tex]

[tex]\\ \sf\longmapsto 2y-z=3\dots(3)[/tex]

[tex]\\ \sf\longmapsto 4y-3=5[/tex]

[tex]\\ \sf\longmapsto 4y=5+3[/tex]

[tex]\\ \sf\longmapsto 4y=8[/tex]

[tex]\\ \sf\longmapsto y=\dfrac{8}{4}[/tex]

[tex]\\ \bf\longmapsto y=2[/tex]

[tex]\\ \sf\longmapsto x-2y=-3[/tex]

[tex]\\ \sf\longmapsto x=-3+2y[/tex]

[tex]\\ \sf\longmapsto x=-3+2(2)[/tex]

[tex]\\ \sf\longmapsto x=-3+4[/tex]

[tex]\\ \bf\longmapsto x=1[/tex]

[tex]\\ \sf\longmapsto 2y-z=3[/tex]

[tex]\\ \sf\longmapsto z=2y-3[/tex]

[tex]\\ \sf\longmapsto z=2(2)-3[/tex]

[tex]\\ \sf\longmapsto z=4-3[/tex]

[tex]\\ \bf\longmapsto z=1[/tex]

Answer:

  7/6

Step-by-step explanation:

You have correctly graphed the line, so you know that the rate of change is ...

  ∆d/∆t = 7/6

d changes by 7/6 units for each unit change in t.

Answer:

either 2 or 2 1/2

Step-by-step explanation:

Since the pre-image gets bigger, the scale factor is larger than 1.

Answer:

Step-by-step explanation:

1). [tex]\frac{1}{2}g-4=2g-\frac{1}{2}g+4[/tex]

  [tex]\frac{1}{2}g-4=\frac{3}{2}g+4[/tex]

 Since left side of the given equation is not equal to the right side, there will be one solution to the given equation.

2). -2.1b + 5.3 = b - 3.1b + 5.3

   -2.1b + 5.3 = -2.1b + 5.3

Since left side of the equation is exactly same as right side of the equation.

Equation will have infinitely many solutions.

3). [tex]\frac{3}{4}w+\frac{5}{4}=\frac{10}{4}-\frac{3}{4}w[/tex]

  [tex]\frac{3}{4}w+\frac{5}{4}=\frac{5}{2}-\frac{3}{4}w[/tex]

Since left side of the given equation is not equal to the right side, there will be one solution to the given equation.

4). 5.7c - 1.5 + 3.2c = 7.8c - 1.5 + 1.1c

   8.9c - 1.5 = 8.9c - 1.5

 Left side of the equation is same as right side of the equation.

Therefore, there will be infinitely many solutions of the equation.

Answer:

C and f

Step-by-step explanation:

Hope this helps

Answer:

GCF = x

Step-by-step explanation:

The greatest common factor is "x"

[tex]5\,x^2+3\,x=x\,(5x+3)[/tex]

it is the only common factor we can extract from both terms

Answer:

The formula for the lateral surface area (LSA) of a right cone is:

LSA = π x r x l

where: r as radius, and l as the slant height of the cone

If NASA need to do two coats of the sealant, the number of square feet that they are painting is: 2 x LSA = 2 x π x r x l

Step-by-step explanation:

Answer:

56.5 ft^2

Step-by-step explanation:

After you calulate the the surface area and double it, subtract the area of the circle.

The dilation rule (x,y) --> (1.5x, 1.5y) says to multiply each coordinate by the scale factor 1.5

Point A in blue is located at (5,5). After dilation, it will move to A ' (7.5, 7.5)

Point B is located at (0,2) and it moves to B ' (0,3)

Point C is located at (1,-1) and it moves to C ' (1.5, -1.5)

This all matches with what is shown below, so the answer is choice B

1 inch = 4 feet

11 inches = 44 feet (multiply both sides by 11)

Answer:

Hey there!

A simple way to think about slope is rise over run. Between any two points on this line, the rise is 3, and the run is -1.

3/-1=-3, so  the slope is -3.

Let me know if this helps :)

Answer:

The slope is [tex] -\frac{1}{2} [/tex]

Step-by-step explanation:

With points A(-2, 1), and B(-4, 2), slope (m) of the line can be calculated using the formula [tex] m = \frac{y_2 - y_1}{x_2 - x_1} [/tex],

Where,

[tex] y_2 = 2 [/tex]

[tex] y_1 = 1 [/tex]

[tex] x_2 = -4 [/tex]

[tex] x_1 = -2 [/tex]

Plug in the values into the slope formula:

[tex] m = \frac{2 - 1}{-4 -(-2)} [/tex]

[tex] m = \frac{2 - 1}{-4 + 2} [/tex]

[tex] m = \frac{1}{-2} [/tex]

[tex] m = -\frac{1}{2} [/tex]

Options :

A. Each roll has a 0.117 probability of being divisible by 3.

B. Each roll has a 0.333 probability of being divisible by 3.

C. Each roll has a 0.5 probability of being divisible by 3. D. Each roll has a 0.667 probability of being divisible by 3.

Answer: B. Each roll has a 0.333 probability of being divisible by 3.

Step-by-step explanation:

Sample space for a six-sided number cube :

1, 2, 3, 4, 5, 6

Number of outcomes divisible by 3:

(3, 6) = 2

Probability of an event = Number of required outcomes / total number of possible items

Probability (getting a number divisible by 3):

(Number of outcomes divisible by 3 / total outcomes in sample space)

Probability (getting a number divisible by 3):

2 / 6 = 1/3

= 0.333

Answer: g(x) f(x) h(x)

Step-by-step explanation:

The order of the three functions in order from the fastest decreasing average rate of change to the slowest decreasing average rate of change on the interval [0, 3] is is g(x) >f(x) > h(x)

A function from a set X to a set Y assigns to each element of X exactly one element of Y.

A function whose value is a constant raised to the power of the argument, especially the function where the constant is e.

It is a measure of how much the function changed per unit, on average, over that interval.

Given,

[tex]f(x) = 16(\frac{1}{2})^{x}[/tex]

interval = [0,3]

[tex]f(0)= 16(\frac{1}{2})^{0} =16 \\f(3)= 16(\frac{1}{2})^{3} =2[/tex]

Average rate of change = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

Average rate of change= [tex]\frac{2-16}{3-0}=-4.67[/tex]

Consider the function g(x)

g(0)=21

g(3)=1

Average rate of change = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

Average rate of change =[tex]\frac{1-27}{3-0}=-8.67[/tex]

Consider the exponential function

at x=0 the exponential function h =4

at x=0 the exponential function h =-3

Average rate of change = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

Average rate of change =[tex]\frac{-3-4}{3-0}=-2.33[/tex]

Hence, the order of the three functions in order from the fastest decreasing average rate of change to the slowest decreasing average rate of change on the interval [0, 3] is g(x) >f(x) > h(x)

Learn more about Function, Exponential function and Average rate of change here

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Answer:

The answer is

[tex] \sqrt{65} \: \: \: units[/tex]

Step-by-step explanation:

To find the distance between two points we use the formula

[tex] \sqrt{ ({x1 - x2})^{2} + ( {y1 - y2})^{2} } [/tex]

where

( x1 , y1) and ( x2 , y2) are the points

From the question the points were

(-8,5), (-1.1)

Substitute the values into the above formula

That's

[tex] \sqrt{ ({ - 8 + 1})^{2} + ({5 - 1})^{2} } [/tex]

[tex] \sqrt{ ({ - 7})^{2} + {4}^{2} } [/tex]

[tex] \sqrt{49 + 16} [/tex]

We have the final answer as

[tex] \sqrt{65} \: \: units[/tex]

Hope this helps you

Given: Figure of a plane named Q with a normal [tex]\overleftrightarrow{BF}[/tex] at point B, containing two lines [tex]\overleftrightarrow{AC}[/tex] and [tex]\overleftrightarrow{DE}[/tex] that intersect at point B

To find:

A line is named using any two points lying on it. A plane, on the other hand is named using any three non-collinear points lying on it.

The logic behind this is that there is an unique line passing through any two points. So, any two points lying on a line is sufficient to name the line.

Similarly, an unique plane can be found that passes through any two lines. That is, any two lines lying on a plane is sufficient to name the plane. Since a line can be defined uniquely by two points, two lines can be defined uniquely by two points each, that is, four points. However, if we take a common point, that is, if we take the point of intersection of the two lines as one of our points, then we need at most three points to define a plane.

Note that, we have to take care that the three points be non-collinear, because if they are collinear, they can only give a single unique line which is not sufficient to uniquely give a plane. Indeed, infinite number of planes passes through a single line.

So, we name a line using two points lying on it and a plane using three non-collinear points lying on it.

Now, the line [tex]\overleftrightarrow{AB}[/tex] clearly passes through points A and B. As can be seen from the figure, it also passes through the point C. We name a line using any two points lying on the line.

So, another name for [tex]\overleftrightarrow{AB}[/tex] can be [tex]\overleftrightarrow{AC}[/tex].

The plane Q contains the points A, B, C, D and E of which the points A, B and C, and the points E, B and D are collinear. So, choosing two sets of three points each such that they are non-collinear, we can have points A, E and C, and the points C, D and B.

Equivalently, two other names for the plane Q can be AEC and CDB.

EBD is not an acceptable name for plane Q because the points E, B and D are collinear points, that is they lie on the same line.

So, we have found that another name for [tex]\overleftrightarrow{AB}[/tex] can be [tex]\overleftrightarrow{AC}[/tex], two other names for the plane Q can be AEC and CDB, and EBD is not an acceptable name for plane Q because the points E, B and D are collinear points.

Learn more about naming of lines and planes here:

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Answer:

100, 101, 102, 103, 104

Step-by-step explanation:

Basically, if the units (or ones, it's the same thing) digit of the first number is 0, the units digit of the second number should be 1, then 2, and so on. Therefore, one possible list of numbers is as follows: 100, 101, 102, 103, 104.

Answer:

0.02275

Step-by-step explanation:

We use the z score formula to solve for this

z-score is given as: z = (x-μ)/σ

where x is the raw score,

μ is the population mean

σ is the population standard deviation

In the above question:

mean of μ=500

a standard deviation of SD=100

raw score x = 700

Hence, z score = (700 - 500)/ 100

= 200/100

= 2

z score = 2

Using the z score table of normal distribution to find the Probability of z = 2

P( x = z)

= P(x = 700)

= P( z = 2)

= 0.97725

P(x>700) = 1 - P(x = 700)

= 1 - 0.97725

= 0.02275

Therefore, the probability of randomly selecting an individual from this population who has an SAT score greater than 700 is 0.02275

Answer:

215483 cm³

Step-by-step explanation:

Formula for volume of a cylinder = πr² · h

radius = 1/2diameter

1. Set up the equation

(3.14)(15²)(305)

2. Solve

215482.5

rounded to the nearest cubic centimeter = 215483 cm³

Answer:

215483 cm³

Step-by-step explanation:

credit goes to person up top

find the cost of the painting of a rectangular box of length 6m breadth 4m and height 3m at the rate of rs.25 per meter square

According to the question, first we need to get the T.S.A. or Total Surface Area of the cuboid then dividing it by ₹ 0.25 we can get the cost. After solving the concept will be more clear.

Let's start :

Here,

l represents length

b represents breadth

h represents height

Now, putting the values of all these we get

Now, we are given that cost of every square metre costs ₹ 0.25

So, for 108 m² it will cost = ₹ 108 × 0.25 = ₹ 27

Hence, cost of painting the rectangular box is ₹ 27

Answer:Rs.2700

Step-by-step explanation:step1is 2[6*3]+2[6*4]=84

step2is 2[3*4]=24

24+84=108*25=2700

The measure of angle Q in the triangle QMN is 52.83°

An equation is an expression that shows the relationship between two or more variables and numbers.

For a triangle with sides a, b, c and respective opposite angles A, B, C, cosine rule is:

a² = b² + c² - 2bc * cos(A)

In triangle QMN, QM = 18, MN = 17, QN = 20, hence:

17² = 18² + 20² - 2(18)(20) * cos(Q)

Q = 52.83°

The measure of angle Q in the triangle QMN is 52.83°

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Answer:

53

Step-by-step explanation:

its rounded

Answer:

This is marked evenly from 0 to 100

This means that the total number of possible outcomes is:

D = 101

and the set of possible outcomes is:

O = {0, 1, 2, 3, ..., 100}

Now, the probability to geting between 42 and 72 seconds is equal to the quotient between the number of outcomes between 42 and 72, and the total possible outcomes.

The number of outcomes between 42 and 72 is:

72 - 42 = 30

Then the probability is:

P = 30/101 = 0.297

Then, out of the 100 players, we can expect that:

0.297*100 = 29.7 ≈ 30

(we rounded to the next whole number)

30 of them get between 42 and 72 seconds.

Answer:

Totally number of coaches needed is 12

Step-by-step explanation:

If you like my answer than please mark me brainliest thanks

Answer:

3 chocolate bars, and 2 graham crackers

Someone forgot the marshmallows...... :P

Step-by-step explanation:

Chocolate bars = 8 pack

Graham Crackers = 12pack

To have no crackers or chocolate left over, we need to find LCM

Factors of 8:

8, 16, 24, 32, 40, 48, 56, 72....

Factors of 12:

12, 24, 36, 48, 60, 72

The smallest LCM is 24

Chocolate bars:

24/8 = 3

Graham Crackers:

24/12 = 2

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

Answer:

3 packs of chocolate and 2 packs of crackers

Step-by-step explanation:

the lowest common multiple of 8 and 12 is 24. We can determine this by prime factorization:

Prime factors of 8: 2 x 2 x 2

Prime factors of 12: 2 x 2 x 3

multipyling the bottom rungs of our factor tree we get: 2 x 2 x 2 x 3 = 24.

If you need me to draw the factor tree, just ask.

Answer:

  0

Step-by-step explanation:

Apparently, you want the value of ...

  [tex]\dfrac{1}{3}m-1-\dfrac{1}{2}n = \dfrac{m}{3}-\dfrac{n}{2}-1\\\\=\dfrac{21}{3}-\dfrac{12}{2}-1=7-6-1\\\\=\boxed{0}[/tex]

The value of the given expression for the given variable values is zero.