What step occurs first in a scientific investigation and in the development of a new technology?
-Findings are communicated to others.
-A problem or need is identified
-A series of tests are analyzed.
-Information is researched

Answers

Answer 1

Answer:

B. A problem or need is identified

Explanation:

hoep this helps

Answer 2

Answer:

B

Explanation:

edge


Related Questions

If a 400-mm diameter pipe with a pipe roughness coefficient of 100 flows full of pressurized water with a head loss of 0.4 ft per 1,000 ft of pipeline, what is the flow rate? Use the Hazen-Williams method

Answers

Answer:

Q = 913.9 gpm

Explanation:

The Hazen Williams equation can be written as follows:

[tex]P = \frac{4.52\ Q^{1.85}}{C^{1.85}d^{4.87}}[/tex]

where,

P = Friction Loss per foot of pipe = [tex]\frac{0.4}{1000\ ft}[/tex] = 4 x 10⁻⁴

Q = Flow Rate in gallon/min (gpm) = ?

d = pipe diameter in inches = (400 mm)(0.0393701 in/1 mm) = 15.75 in

C = roughness coefficient = 100

Therefore,

[tex]4\ x \ 10^{-4} = \frac{4.52\ Q^{1.85}}{(100)^{1.85}(15.75)^{4.87}}\\\\Q^{1.85} = \frac{4\ x \ 10^{-4}}{1.33\ x\ 10^{-9}} \\\\Q = (300384.75)^\frac{1}{1.85}[/tex]

Q = 913.9 gpm

Two identical thermally insulated spherical tanks, A and B, are connected by a valve. Initially tank A contains 20mol of an ideal diatomic gas, tank B is evacuated, and the valve is closed.
If the valve is opened and the gas expands isothermally fromA to B, what is the change in the entropy of the gas?

Answers

Answer:

Explanation:

Volume of gas is doubled isothermally . Let the temperature of the gas be T .Work done by the gas

W = 2.303 nRT log 2 V / V

Since expansion is isothermal , Δ E = 0

Q = ΔE + W

Q = W

Q = 2.303 nRT log 2 V / V

Q / T = 2.303 n R log 2

Change in entropy = ΔS = Q / T = 2.303 n R log 2

= 2.303 x 20 x 8.3 x .3010 J T⁻¹.

= 115  J T⁻¹.

The required change in the entropy of the gas is 115 J/K.

Given data:

The number of moles of diatomic gas in tank A is, n = 20 mol.

The expansion takes place isothermally, which means the volume is doubled at the constant temperature. Therefore, work done during the isothermal expansion is,

W = 2.303 nRT log 2 V / V

Since expansion is isothermal , Δ E = 0. Then by using the first law of thermodynamics as,

Q = ΔE + W

Q = W

Q = 2.303 nRT log 2 V / V

Q / T = 2.303 n R log 2

Also, we that the expression for the change in Entropy is,

 ΔS = Q / T = 2.303 n R log 2

Solving as,

ΔS = 2.303 x 20 x 8.3 x .3010

ΔS = 115  J/K

Thus, we can conclude that the required change in the entropy of the gas is 115 J/K.

Learn more about the entropy change here:

https://brainly.com/question/1301642

The maximum allowable resistance for an underwater cable is one hundredth of an ohm per
meter and the resistivity of copper is 1.54 x 10-80m.
a) Calculate the smallest cross sectional area of copper cable that could be used.​

Answers

Answer:

A = 1.54 x 10⁻⁵ m² = 15.4 mm²

Explanation:

The resistance of a wire can be given by the following formula:

[tex]R = \frac{\rho L}{A}\\\\A = \frac{\rho L}{R} = \frac{\rho}{\frac{R}{L} }[/tex]

where,

A = smallest cross-sectional area = ?

ρ = resistivity of copper = 1.54 x 10⁻⁸ Ωm

[tex]\frac{R}{L}[/tex] = resistance per unit length of wire = 0.001 Ω/m

Therefore,

[tex]A = \frac{1.54\ x\ 10^{-8}\ \Omega m}{0.001\ \Omega/m}[/tex]

A = 1.54 x 10⁻⁵ m² = 15.4 mm²

An automobile traveling at a speed of 28.3 m/s applies its brakes and comes to a stop in 4.9 s. If the automobile has a mass of 1.1 x 103 kg, what is the average horizontal force exerted on it during braking? Assume the road is level.

Find Magnitude and direction
WILL GIVE BRAINLIEST​

Answers

Answer:

i say it would be 32.5 m if the brakes comes and stops.  the road is 3.7 x 105

Explanation:

HELP PLEASE!!!!!!!!!!!!!!

Answers

B. convex lens forms larger virtual image, is the correct answer.

In A. C. motor capacitor is used
p.Can dicouly [BPKIHS 2000
to reduce ripples b. to decrease A. C.
c. to increase A. C. d. to decrease D. C.
a.
34​

Answers

Answer:

d. to decrease D. C.

Explanation:

d. to decrease D. C.

54. Which of the following behaviors is most closely
associated with the foot-in-the-door phenomenon?
(A) Beth continues to participate in class because
she is positively reinforced.
(B) Adam is sleeping while the rest of his
classmates are working on their group
project
(C) Sutan asks his father for $5, and when he
agrees, Sutan asks him for $15 more.
(D) James feels pressure to go to the movies with
his friends even though he prefers to go
bowling.
(E) Diana feels guilty because she did not help
her family clear the table after dinner.

Answers

Answer:

C

Explanation:

Foot-in-the-door technique is a compliance tactic that aims at getting a person to agree to a large request by having them agree to a modest request first

The behavior that should be closely associated is option c. Sutan asks his father for $5, and when he agrees, Sutan asks him for $15 more.

What is the foot-in-the-door phenomenon?

It is a tactic of compliance that focuses on agreeing on the person by having a request.

It shows the connection that lies between the person who is asking for a request and the person who is being asked.

So based on this, option c is correct.

learn more about behavior here: https://brainly.com/question/15661050

12. 2007: The figure below show two identical trollbys with loads A and B. The
loads are identical in shape and size.
D
Given that the density of A is greater than that of B, explain why the
trolley in figure 3 (in) is more stable​

Answers

Answer:

you need to provide a figure that came with the problem.

The Earth orbits the Sun at a speed of 30 km/s. At that speed it completes one path around the Sun every year. Of course, as that happens we are heading toward a different place in space constantly, always accelerating toward the Sun to stay on the circular path. Suppose at a paritcular instant we are headed in the direction of a distant star and we measure the speed of the light from that star as it arrives on Earth. In the vacuum of space we would measurea. 299,792,458 m/sb. 299,792,428 m/sc. 299,792,488 m/sd. 0 m/s

Answers

Answer:

a. 299,792,458 m/s

Explanation:

Since the speed of light in a vacuum is invariant and has the value of 299,792,458 m/s, we would measure this value of 299,792,458 m/s for the speed of light from the star as it arrives on Earth.

A 200kg car is driving at 20m/s down the road when he sees a red light. He slows to a stop.

The car's initial momentum is ___kg m/s


The car's final momentum is ___kg m/s


The car's impulse is
___kg m/s

Answers

Answer:

Initial Momentum - 4000 kg*m/s

Final Momentum - 0 kg*m/s

Impulse: -4000 kg*m/s

Explanation:

The equation for momentum is P = mv

Initial Momentum

200kg * 20m/s = 4000 kg*m/s

Final Momentum

200kg * 0m/s = 0kg*m/s

Impulse = ΔP

Pfinal - Pintial = Impulse

0-4000 = -4000 kg*m/s

what must happen for a electromagnet to have a magnetic field

Answers

By simply wrapping wire that has an electrical current running through it around a nail, you can make an electromagnet. When the electric current moves through a wire, it makes a magnetic field. If you coil the wire around and around, it will make the magnetic force stronger, but it will still be pretty weak.

The diagram shows two
charged objects, X and Y.
Based on the field lines, what are the charges of the
objects?
X: positive
Y: negative
O X: negative
Y: positive
O x: negative
Y: negative
O x: positive
Y: positive

Answers

Answer:

X: positive

Y: positive

Explanation:

The electrical field lines have a specified direction based upon the sign of the charge. The electrical field lines have a direction coming out of the charge if the sign of the charge is positive. While the electrical field lines have a direction going inside the charge if the sign of the charge of negative.

It can be clearly seen in the diagram that the electric field lines are coming out of both charges. Therefore, both the charges are positive.

Hence, the correct option is:

X: positive

Y: positive

When an object is put into a liquid, it experiences a buoyant force that is equal to the weight of the liquid the object displaces. The force on the wire is given as the block is slowly lowered into the liquid (position is given in "centimeters", which you have to change to "meters") and force is given in "newtons"). Choose a mass of the block between 0.125 kg and 0.375 kg and a density of the liquid between 500 kg/m^3 and 1000 kg/m^3. The object is in static equilibrium when the clock stops.

Required:
a. What is the weight of the block and the tension, F, in the string when the block is in the liquid?
b. What is the volume of the block in the liquid—either the submerged part of the block if the block is partially submerged when you paused it or the entire block if it is completely submerged (the dimension of the block that is into the screen is 5.00 cm = 0.0500m)?
c. What is the volume of the water that is displaced by the block (the dimension of both water containers into the screen is 10.00 cm = 0.100m)?

Answers

Answer:

A) F = 1.8375 N, B) V = 1.25 10⁻⁴ m³, C) V= 1.25 10⁻⁴ m³

Explanation:

This exercise should select some values ​​such as the weight of the block m=0.250 kg and the density of the liquid ρ = 500 kg / m³ (water); with these values ​​answer the question, for this we use the static equilibrium relations.

          Σ F = 0

          F + B - W = 0

the expression for thrust is

          B = ρ g V_liquid

A) the weight of the block is

          W = m g

          W = 0.250 9.8

          W = 2.45 N

Let's look for the maximum push

           V_body = V_liquid

            B = 500 9.8 0.05³

           B = 0.6125 N

we substitute

          F = W - B

          F = 2.45 - 0.6125

          F = 1.8375 N

B) As the body is totally submerged, the volume of the liquid and the body are equal

           V = l³

           V = 0.05³

           V = 1.25 10⁻⁴ m³

C) the volume of water displaced is equal to the volume of the body

           V_liquid = 1.25 10⁻⁴ m³

1The specific heat of substance (X) is greater than that for substance (Y). If equal amounts of heat are added to both these substances, the one reaching the higher temperature(assuming no phase change occurs for either) will be:

1. substance X
2. substance Y
3.there will be no difference in the final temperature.
4.both X and Y

Answers

Answer:

Substance Y

Explanation:

A substance with a high specific heat capacity can absorb a large quantity of heat before it will raise in temperature.  A substance with a low specific heat requires relatively little heat to raise its temperature. Thus, if the same amount of energy was added to both substances, substance Y will reach the higher temperature, while substance X would require more energy to reach high temperatures.

Answer:

2. substance Y

Explanation:

specific heat is how much heat is needed to warm up something. Y has smaller specific heat means it warm up more w/ same amount of heat.

After rolling halfway down an incline a marble's kinetic energy is
A. impossible to determine
B. the same as its potential energy
C. greater than its potential energy
D. less than its potential energy

Answers

It’s c …………. Your welcome


A bicyclist at the top of a hit begins to coast without pedaling. The bicycle speeds up as it descends to the bottom of the hill and then slows down as it continues
up a second, where it stops. Which of these sequences best describes the energy change of the bicycle from the top of the hill until it stops?

A.potential - kinetic-kinetic

B.Kinetic -potential -potential

C.Kinetic -potential -Kinetic

D.potent - Kinetic -potential

Answers

It goes potential, then kinetic, then potential. So D.

Photons with the highest frequency have the lowest _____.
A. wavelength
B. speed
C. color
D. energy​

Answers

Answer:

a wavelength

Explanation:

a spring has a spring constant of 330 n/m. how far is the spring compressed when 150 newtons of force are used?
a. 0.0014 meters
b. 0.45 meters
c. 2.2 meters
d. 5.0 meters
show your work.​

Answers

Answer:

b. 0.45 meters

Explanation:

Given the following data;

Spring constant, k = 330 N/m

Force = 150 N

To find the extension of the spring;

Mathematically, the force exerted on a spring is given by the formula;

Force = spring constant * extension

Substituting into the formula, we have;

150 = 330 * extension

Extension, e = 150/330

Extension, e = 0.45 meters

4. In the display window of the toy store at the local mall, a battery-powered plane is suspended from a string and flying in a horizontal circle. The 631 gram plane makes a complete circle every 2.15 seconds. The radius of the circle is 0.950 m. Determine the velocity, angular velocity, acceleration, and net force acting upon the plane.

Answers

Answer:

The solution is given below

Explanation:

The computation is shown below:

Given that

Mass of plane, m is 631 g = 0.631 Kg

The Time period for one circle is 2.15 s

The Radius of circle = 0.95 m

Now the velocity of the plane, v = rω

where,

angular velocity, ω = (θ ÷ t)

For one complete circle, θ = 2π

and Time period T is provided = 2.15 s

Thus, ω = 2π ÷ T = 2π  ÷ 2.15

So, velocity, v = rω

= r × ( 2π  ÷ 2.15 )

= 0.95 × (2π ÷2.15)

= 2.776 m/s

The Acceleration of the plane, a = rω^2

= 0.95 × (2π ÷ 2.15)^2

= 8.114 m/s^2

The Net force acting upon the plane, F = Centripetal force i.e.

= mv2 ÷  r

F = mv2 / r

= (0.631 × 2.7762) ÷ 0.95

= 5.118 N

63. Which of the following types of validity is estab-
‘lished by demonstrating that there is a correlation
between scores on a test and later academic
performance?
(A) Content
(B) Predictive
(C) Face
(D) Concurrent
(E) Test-retest
Help I beg someone please help please

Answers

Answer:

Content

Explanation:

The type of validity that is established by demonstrating a correlation between scores on a test and later academic performance is known as CONTENT VALIDITY

The above statement is true because Content validity is a form of validity testing used to assess whether the outcome of a test is a precise measure of the fundamental aspect or domain of the construct.

Hence, to provide a credible result, content validity ensures it covers all suitable parts of the content or topic it attempts to measure.

How much energy is needed to melt 150 g of ice at 0°C to water? (1)(Lf =3.34˟ 10⁵ J/Kg)
50 100 000J
50.1J
50 100J
501000 J
5 min

Answers

Answer:

5.01×10⁴ J.

Explanation:

Applying,

q = Cm....................... Equation 1

Where q = amount of heat needed to melt the ice, m = mass of the ice, C = specific latent heat of ice.

From the question,

Given: m = 150 g = (150/1000) kg = 0.15 kg, C = 3.34×10⁵ J/kg

Substitute these values into equation 1

q = (0.15×3.34×10⁵)

q = 0.501×10⁵ J

q = 5.01×10⁴ J.

How far would a horse that rides at 9.8 m/s travel in 9.8 minutes? ​

Answers

Answer:  

distance = 96.04 m

Explanation:

velocity is distance over time when velocity is multiplied by time, the time in the numberator is canceled by the time in the denomiator leaving only distance.

distance = velocity * time

distance = 9.8[m/s] * 9.8[s]

distance = 9.8 * 9.8 [m]

Starting from rest, a car takes 2.4 s to travel the first 15 m. Assuming a constant acceleration, how long will it take the car to travel the next 15 m?

Answers

Answer:

The time it will take the car to travel the next 15 m is 1 s.

Explanation:

Given;

initial velocity of the car, u = 0

time of motion, t = 2.4 s

initial distance traveled, d = 15 m

determine the constant acceleration of the car;

d = ut  +  ¹/₂at²

15 = 0  +  (0.5 x 2.4²)a

15 = 2.88a

a = 15 / 2.88

a = 5.21 m/s²

The velocity of the car at the end of the first 15 m

v - u + at

v = 0 + 5.21 x 2.4

v = 12.5 m/s

The time to cover the next 15 m;

d₂ = vt  + ¹/₂at²

15 = 12.5t  +  (0.5 x 5.21)t²

15 = 12.5t  +  2.61t²

0 = 2.61t²  +   12.5t   -  15

Use the formula method to solve the above quadratic equation.

a = 2.61

b = 12.5

c = -15

[tex]t = \frac{-b \ \ +/- \ \ \sqrt{b^2 - 4ac} }{2a} \\\\t = \frac{-12.5 \ \ +/- \ \ \sqrt{12.5^2 - (4\times 2.61 \times -15)} }{2\times 2.61}\\\\t = 0.9937 \ s \ \ \ or \ \ \ -5.78 \ s\\\\time \ can \ only \ be \ positive;\\\\t \approx \ 1\ s[/tex]

Therefore, the time it will take the car to travel the next 15 m is 1 s.

1 pts
Harry spent his summer playing guitar on the corner trying to earn some extra money. He would keep his guitar
case open for people to drop extra change into. Sometimes people would put money in the case and sometimes
people would be rude. Putting money in the hat is a to Harry's behavior.
Tir
Atte
1M
Negative reinforcement
Positive reinforcement
O Negative punishment
Positive punishment
Question 2
1 pts
O
SIC
acer

Answers

Answer:

Positive reinforcement

Compare two vectors that are of the same magnitude but are in opposite direction. Write 4 points to do this.

Answers

Answer:

jsuxgbqnqozygxnwkisgx

Explanation:

jducgsjqkzhxbbekxochdbjsixgwjdk

Answer the following question according to formal grammatical rules.

Which of the following sentences corrects the pronoun errors in this sentence?

If a person wants to help their community, they should research opportunities.

A. If a person wants to help their community, you should research opportunities.
B. If you want to help your community, a person should research opportunities.
C. If people want to help their community, they should research opportunities.
D. If a person wants to help it, they should research opportunities.

Answers

If people want to help their community, they should research opportunities corrects the pronoun errors in this sentence.

What is a Pronoun?

This is defined as a word which is used instead of a noun and examples include he, she etc.

In this scenario, the word 'people' agrees with the possessive adjective 'their' and the personal pronoun 'they', which is referred to the third-person plural hence the reason why option C is the most appropriate choice.

Read more about Pronoun here https://brainly.com/question/26257764

Answer:

D

Explanation:

D

Who serves as the presiding officer of the Senate?

Answers

Who serves as the presiding officer of the Senate?

[tex]{ \bf{ \underbrace{Answer :}}}[/tex]

The [tex]\sf\purple{Vice\:President}[/tex] of the United States serves as the presiding officer of the Senate.

At present, [tex]\sf\red{Kamala\:Harris}[/tex] is the president of the Senate.

[tex]\bold{ \green{ \star{ \orange{Hope\:it\:helps.}}}}⋆[/tex]

A physics student was studying falling bodies and decided to drop a water balloon from an outdoor stairwell to measure its speed. If the balloon was dropped a distance of 6 meters and it only took 1.1 seconds to fall, how fast was the balloon traveling on average? A. 0.2 m/s B. 6.6 m/s C. 5.5 m/s D. 66 m/s

WILL NAME BRAINLIEST

Answers

Answer:

C. 5.5 m/s

Explanation:

How fast the balloon travels is determined from the velocity or v

The formula is v = s/t or velocity equals distance divided by time

So, v = 6 meters divided by 1.1 seconds = 5.5 meters per second

Answer:

C. 5.5 m/s

Explanation:

How fast the balloon travels is determined from the velocity or v

The formula is v = s/t or velocity equals distance divided by time

So, v = 6 meters divided by 1.1 seconds = 5.5 meters per second

When a species has no members left that are alive

Answers

Answer:

it means that species is extinct.

Explanation:

have a good day :)

I think the answer is extinct, since there are no member left that are alive of that kind of species.

A 1.6-lb collar is attached to a spring and slides without friction along a circular rod in a vertical plane. The spring has an unstretched length of 6 in. The collar is released from being held at A, and it passes ponit B with a speed of 16.0 ft/s. Determine the spring constant. The circular rod is kept from moving.

Answers

Answer:

k = 652 lb/ft

Explanation:

Given :

Weight of the collar = 1.6 lb

The upstretched length of the spring = 6 in

Speed  = 16 ft/s

PA = 8 + 10

     = 18 inch

Let the initial elongation be [tex]$\Delta x_i$[/tex]

∴ [tex]$\Delta x_i$[/tex] = 18 - 6

         = 12 inch = 1 foot

[tex]$PB = \sqrt{13^2+5^2}$[/tex]

      = 13.925 inch

Final elongation in the spring

[tex]$\Delta x_B = 7.928 $[/tex] inch = 0.66 feet

Applying the conservation of the mechanical energy between A and B is

[tex]$K.E_A+P.E_{g,A}+P.E_{sp,A}= K.E_B+P.E_{g,B}+P.E_{sp,B} $[/tex]

[tex]$0+mg_r+\frac{1}{2}k(\Delta x_i)^2=\frac{1}{2}mv_B^2+0+\frac{1}{2}k(\Delta x_B)^2$[/tex]

[tex]$\frac{1}{2}k[(1)^2-(0.66)^2]=\frac{1.6}{2}\times (16)^2-1.6 \times 32 \times \frac{5}{12}$[/tex]

[tex]0.281 \ k =204.8-21.33[/tex]

k = 652 lb/ft

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