What number must you add to complete the square?
X^2 + 8x= 11
A. 12
B. 16
c. 8
D. 4​

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How I got that answer:

We have gone from 54 websites to 793 websites. This is a change of 793-54 = 739 new websites. This is over a timespan of 2004-1995 = 9 years.

Since we have 739 new websites over the course of 9 years, this means the rate of change is 739/9 = 82.1111... where the '1's go on forever. Rounding to the nearest whole number gets us roughly 82 websites a year.

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You could use the slope formula to get the job done. This is because the slope represents the rise over run

slope = rise/run

The rise is how much the number of websites have gone up or down. The run is the amount of time that has passed by. So slope = rise/run = 739/9 = 82.111...

In a more written out way, the steps would be

slope = rise/run

slope = (y2-y1)/(x2-x1)

slope = (793 - 54)/(2004 - 1995)

slope = 739/9

slope = 82.111....

Answer

1. (a) (3,4,5)--3^2 +4^2=9+16=25=5^2

2. (b) 25--172-82=50/2=25

3. (c) 5,000 kg--1,000 kg in 1 tonne

4. (a) 0.4--1-0.6=0.4

5. (d) kilometer

6. (c) hypotenuse

7. (a) grams

8. i think it is (a) 58--5+8+2=15~~8/15 =0.53~closest answer is 58

9. (c) tonne

10. (b) 15 tonnes--1000 kg in 1 tonne

11. (a) #7,600--38000*20%, or 0.20, =7,600

12. (a) 7:30 pm

13. (c) right angle

(c) metric system

Part B

1. True

2. 0.8

3. 30,000 dollars--20,000 +0+5,000+5,000=30,000

4. Planting/watering trees--20 dollars

5. Collecting/burning rubbish--0 dollars

Answer:

[tex]approx. = 85.28 {ft}^{2} [/tex]

Step-by-step explanation:

You can think of this as adding the area of the rectangular portion of the deck (length x width) and the semicircular portion (πr^2)/2.

(l×w)+(πr^2)/2

(10×7)+((π2^2)/2

79+2π

[tex]approx. = 85.28 {ft}^{2} [/tex]

Answer:

y=-1/3x-1

Step-by-step explanation:

We have the information y=3x-5, the lines are perpendicular, and the new line passes through (6,-3). The slopes of perpendicular lines are negative reciprocals so you need to find the negative reciprocal of 3, so flip it to 1/3 and multiply by -1, we get the slope of the new line as -1/3. So far we have the equation y=-1/3x+b. We are given a point on the line, (6,-3), so we can plug these into the equation as x and y to solve for the y-intercept, b. You set it up as -3=-1/3(6)+b. First you multiply to get -3=-2+b, then you add 2 to both sides to isolate the variable and you get b=-1. Then you can use b to complete your equation with y=-1/3x-1.

Answer:

Step-by-step explanation:

Given:

AB║DC and BC║AE

To prove:

[tex]\frac{\text{BC}}{\text{EA}}=\frac{\text{BD}}{\text{EB}}[/tex]

                Statements                  Reasons

1). ∠ABE ≅ ∠CDB                    1). Alternate interior angles

2). ∠AEB ≅ ∠CBD                  2). Alternate interior angles

3). ΔCBD ~ ΔAEB                   3). AA property of similarity

4). [tex]\frac{\text{BC}}{\text{EA}}=\frac{\text{BD}}{\text{EB}}[/tex]                             4). Property of similarity [Corresponding sides                                                          of two similar triangles are proportional]

Answer:

[tex] Conf= 0.80[/tex]

With the confidence level we can find the significance level:

[tex]\alpha =1-0.8=0.2[/tex]

And the value for [tex]\alpha/2=0.1[/tex]. Then we can use the normal standard distribution and we can find a quantile who accumulates 0.1 of the area on each tail and we got:

[tex] z_{\alpha/2}= \pm 1.28[/tex]

Step-by-step explanation:

For this problem we have the confidence level given

[tex] Conf= 0.80[/tex]

With the confidence level we can find the significance level:

[tex]\alpha =1-0.8=0.2[/tex]

And the value for [tex]\alpha/2=0.1[/tex]. Then we can use the normal standard distribution and we can find a quantile who accumulates 0.1 of the area on each tail and we got:

[tex] z_{\alpha/2}= \pm 1.28[/tex]

Answer:

I believe it is D

Answer:

  The sum of 3 and the quotient of y and 2.

Step-by-step explanation:

The order of operations requires that you evaluate the expression ...

  3 + y ÷ 2

by first performing the division, then the addition. So, the addition gives you the sum of 3 and a quotient, because the quotient must be evaluated first.

The quotient is of y and 2 (not 2 and y), because the wording "the quotient of a and b" is always interpreted to mean a÷b.

So, the expression can be described as ...

  the sum of 3 and the quotient of y and 2.

Answer:

c = 730cm

Step-by-step explanation:

The first thing we would do is to draw the diagram using th given information.

Find attached the diagram.

a = 714 cm

the measure of angle A = 78°

To determine c, we would apply sine rule. This is because we know the opposite and we are to determine the hypotenuse

sin78 = opposite/hypotenuse

sin 78 = 714/c

c = 714/sin 78 = 714/0.9781

c= 729.99

c≅ 730 cm ( nearest cm)

Answer:

Step-by-step explanation:

16x^2 + 9 = 25

16x^2 = 16

x^2 = 1

x = 1, -1

Answer: 136

Step-by-step explanation:

An= A1+(n-1)d

A1=16, d=8, and n=16

A16= 16 +(16-1)(8)

A16= 16(15)(8)

A16= 16+120

A16=136

Hey there! :)

Answer:

f(16) = 136 seats.

Step-by-step explanation:

This situation can be expressed as an explicit function where 'n' is the row number.

The question also states that the number of seats increases by 8. Use this in the equation:

f(n) = 16 + 8(n-1)

Solve for the number of seats in the 16th row by plugging in 16 for n:

f(16) = 16 + 8(16-1)

f(16) = 16 + 8(15)

f(16) = 16 + 120

f(16) = 136 seats.

Answer:

The statistic is misleading because Christopher collects his sample from a population (voters in his state) and make inferences about another population (voters in his city).

Step-by-step explanation:

The statistic is misleading because Christopher collects his sample from a population (voters in his state) and make inferences about another population (voters in his city).

He should make inferences about the population that is well represented by his sample (voters in his state), or take a sample only from voters from his city to make inferences about them.

Answer:

The approximate probability that the market will have a proportion of fish with dangerously high levels of mercury that is more than two standard errors above 0.15 is 0.95.

Step-by-step explanation:

According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

 [tex]\mu_{\hat p}=0.15[/tex]

The standard deviation of this sampling distribution of sample proportion is:

 [tex]\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}[/tex]

As the sample size is large, i.e. n = 150 > 30, the central limit theorem can be used to approximate the sampling distribution of sample proportion by the normal distribution.

Compute the mean and standard deviation as follows:

[tex]\mu_{\hat p}=0.15\\\\\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.15(1-0.15)}{150}}=0.0292[/tex]

So, [tex]\hat p\sim N(0.15, 0.0292^{2})[/tex]

In statistics, the 68–95–99.7 rule, also recognized as the empirical rule, is a shortcut used to recall that 68%, 95% and 99.7% of the Normal distribution lie within one, two and three standard deviations of the mean, respectively.

Then,

                                  P (µ-σ < X < µ+σ) ≈ 0.68

                                  P (µ-2σ <X < µ+2σ) ≈ 0.95

                                  P (µ-3σ <X < µ+3σ) ≈ 0.997

Then the approximate probability that the market will have a proportion of fish with dangerously high levels of mercury that is more than two standard errors above 0.15 is 0.95.

That is:

[tex]P(\mu_{\hat p}-2\sigma_{\hat p}<\hat p<\mu_{\hat p}+2\sigma_{\hat p})=0.95\\\\P(0.15-2\cdot0.0292<\hat p<0.15+2\cdot0.0292)=0.95\\\\P(0.092<\hat p<0.208)=0.95[/tex]

Answer:

For this case we know that the price after the 12% of discount is 156 and we want to findd the net price so then we can use the following proportional rule:

[tex] \frac{x}{100} = \frac{156}{100-12}[/tex]

Where x represent the net price. And if we solve for the value of x we got:

[tex] x= 100 *\frac{156}{88}= 177.273[/tex]

So then the net price for this case would be $ 177.273

Step-by-step explanation:

For this case we know that the price after the 12% of discount is 156 and we want to findd the net price so then we can use the following proportional rule:

[tex] \frac{x}{100} = \frac{156}{100-12}[/tex]

Where x represent the net price. And if we solve for the value of x we got:

[tex] x= 100 *\frac{156}{88}= 177.273[/tex]

So then the net price for this case would be $ 177.273

Answer:

A

Step-by-step explanation:

Answer:

"But even this is admitting more than is true, for I answer roundly, that America would have flourished as much, and probably much more, had no European power had any thing to do with her."

Step-by-step explanation:

Checked 2021

Answer:

Yes.

Step-by-step explanation:

In the future, simply plug both equations into Desmos.

Answer:

The 68% confidence interval is (6.3, 6.7).

The 95% confidence interval is (6.1, 6.9).

The 99.7% confidence interval is (5.9, 7.1).

Step-by-step explanation:

The Central Limit Theorem states that if we have a population with mean μ and standard deviation σ and take appropriately huge random-samples (n ≥ 30) from the population with replacement, then the distribution of the sample-means will be approximately normally distributed.

Then, the mean of the sample means is given by,

[tex]\mu_{\bar x}=\bar x[/tex]

And the standard deviation of the sample means (also known as the standard error)is given by,

[tex]\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}} \ \text{or}\ \frac{s}{\sqrt{n}}[/tex]

The information provided is:

[tex]n=400\\\\\bar x=6.5\\\\s=4[/tex]

As n = 400 > 30, the sampling distribution of the sample-means will be approximately normally distributed.

(a)

Compute the 68% confidence interval for population mean as follows:

[tex]CI=\bar x\pm z_{\alpha/2}\cdot \frac{s}{\sqrt{n}}[/tex]

    [tex]=6.5\pm 0.9945\cdot \frac{4}{\sqrt{400}}\\\\=6.5\pm 0.1989\\\\=(6.3011, 6.6989)\\\\\approx (6.3, 6.7)[/tex]

The 68% confidence interval is (6.3, 6.7).

The margin of error is:

[tex]MOE=\frac{UL-LL}{2}=\frac{6.7-6.3}{2}=0.20[/tex]

(b)

Compute the 95% confidence interval for population mean as follows:

[tex]CI=\bar x\pm z_{\alpha/2}\cdot \frac{s}{\sqrt{n}}[/tex]

    [tex]=6.5\pm 1.96\cdot \frac{4}{\sqrt{400}}\\\\=6.5\pm 0.392\\\\=(6.108, 6.892)\\\\\approx (6.1, 6.9)[/tex]

The 95% confidence interval is (6.1, 6.9).

The margin of error is:

[tex]MOE=\frac{UL-LL}{2}=\frac{6.9-6.1}{2}=0.40[/tex]

(c)

Compute the 99.7% confidence interval for population mean as follows:

[tex]CI=\bar x\pm z_{\alpha/2}\cdot \frac{s}{\sqrt{n}}[/tex]

    [tex]=6.5\pm 0.594\cdot \frac{4}{\sqrt{400}}\\\\=6.5\pm 0.392\\\\=(5.906, 7.094)\\\\\approx (5.9, 7.1)[/tex]

The 99.7% confidence interval is (5.9, 7.1).

The margin of error is:

[tex]MOE=\frac{UL-LL}{2}=\frac{7.1-5.9}{2}=0.55[/tex]

Answer:

a) P(X∩Y) = 0.2

b) [tex]P_1[/tex] = 0.16

c) P = 0.47

Step-by-step explanation:

Let's call X the event that the motorist must stop at the first signal and Y the event that the motorist must stop at the second signal.

So, P(X) = 0.36, P(Y) = 0.51 and P(X∪Y) = 0.67

Then, the probability P(X∩Y) that the motorist must stop at both signal can be calculated as:

P(X∩Y) = P(X) + P(Y) - P(X∪Y)

P(X∩Y) = 0.36 + 0.51 - 0.67

P(X∩Y) = 0.2

On the other hand, the probability [tex]P_1[/tex] that he must stop at the first signal but not at the second one can be calculated as:

[tex]P_1[/tex] = P(X) - P(X∩Y)

[tex]P_1[/tex] = 0.36 - 0.2 = 0.16

At the same way, the probability [tex]P_2[/tex] that he must stop at the second signal but not at the first one can be calculated as:

[tex]P_2[/tex] = P(Y) - P(X∩Y)

[tex]P_2[/tex] = 0.51 - 0.2 = 0.31

So, the probability that he must stop at exactly one signal is:

[tex]P = P_1+P_2\\P=0.16+0.31\\P=0.47[/tex]

Answer:

It's written as

[tex]6.83 \times {10}^{ - 2} [/tex]

Hope this helps you

Answer:

6.83 × 10 -2

hopefully this helped :3

Hey there!

To solve this, we need to plug each of our answer options into the inequality and see if it is true. Which ever one doesn't make the inequality true when plugged in is the answer.

OPTION A

(x,y)=(-3,0)

We plug our values into the inequality.

0≥ I-3I+3

You may have noticed the bars surrounding the negative three.. If you didn't know, this is called absolute value. Absolute value is how far the number is from 0 on the number line. -7 is 7 away from 0 on a number line, so the absolute value of -7 is 7. The absolute value of 7 is 7. The absolute value of 0 is 0. Absolute value is signified by these bars. Le'ts finish evaluating.

0≥6

As you can see, zero is not greater than or equal to six. So, option A is false.

Since A is not a solution, we already know that that is the answer, so we don't even need to check B and C. But, we can still evaluate them if you want.

OPTION B

6≥I-3I+3

6≥6

This is true.

OPTION C

4≥I0I+3

4≥3

This is also true.

Therefore, the answer is A. (-3,0)

Have a wonderful day!

Answer:

Step-by-step explanation:

3x2−5x−2=0

For this equation: a=3, b=-5, c=-2

3x2+−5x+−2=0

Step 1: Use quadratic formula with a=3, b=-5, c=-2.

x= (−b±√b2−4ac )2a

x= (−(−5)±√(−5)2−4(3)(−2) )/2(3)

x= (5±√49 )/6

x=2 or x= −1 /3

Answer:

x=2 or x= −1/ 3

The solutions to the equation are x = -1/3 and x = 2.

Here are the steps on how to solve [tex]3x^{2}[/tex] – 5x – 2 = 0:

First, we need to factor the polynomial. The factors of 3 are 1, 3, and the factors of -2 are -1, 2. The coefficient on the x term is -5, so we need to find two numbers that add up to -5 and multiply to -2. The two numbers -1 and 2 satisfy both conditions, so the factored polynomial is (3x + 1)(x - 2).

Next, we set each factor equal to 0 and solve for x.

(3x + 1)(x - 2) = 0

3x + 1 = 0

3x = -1

x = -1/3

x - 2 = 0

x = 2

Therefore, the solutions to the equation [tex]3x^{2}[/tex] – 5x – 2 = 0 are x = -1/3 and x = 2.

Here is the explanation for each of the steps:

Step 1: In order to factor the polynomial, we need to find two numbers that add up to -5 and multiply to -2. The two numbers -1 and 2 satisfy both conditions, so the factored polynomial is (3x + 1)(x - 2).

Step 2: We set each factor equal to 0 and solve for x. When we set 3x + 1 equal to 0, we get x = -1/3. When we set x - 2 equal to 0, we get x = 2. Therefore, the solutions to the equation are x = -1/3 and x = 2.

Learn more about equation here: brainly.com/question/29657983

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Answer:

18.2 :)

Have a great day!!!

Answer:

B. Tanisha sold the CDs for $2 each.

Step-by-step explanation:

Answer:

2

Step-by-step explanation:

Answer:

I hope it will help you....

Answer:

  33 units²

Step-by-step explanation:

A (graphing) calculator shows you that f(4) ≈ 8, and f(8) ≈ 8.5. The curve is almost a straight line between, so the area is approximately ...

  A = (1/2)(8 + 8.5)(4) = 33

__

If you do the integration, it gets a bit messy.

  [tex]\displaystyle\dfrac{5}{7}\int_4^8{x^{2/7}}\,dx+\dfrac{1}{2}\int_4^8{x^{4/9}}\,dx+\int_4^8{6}\,dx\\\\=\left.\left(\dfrac{5}{9}x^{9/7}+\dfrac{9}{26}x^{13/9}+6x\right)\right|_4^8\approx 33.16[/tex]

The appropriate answer choice is 33 square units.

Answer:

The percent of increase is 25%

Step-by-step explanation:

Percentage increase = increase in price/original price × 100 = ($250 - $200)/$200 × 100 = $50/$200 × 100 = 25%

Answer:

4

Step-by-step explanation:

25% of 25

0.25 × 25 = 6.25

15% of 15​

0.15 × 15 = 2.25

Find the difference.

6.25 - 2.25

= 4

━━━━━━━☆☆━━━━━━━

▹ Answer

Answer = b. 13/5

▹ Step-by-Step Explanation

|4 - 5| ÷ 9 × 3³ - 2/5

|-1| ÷ 9 × 3³ - 2/5

1 ÷ 9 × 3³ - 2/5

1/9 × 3³ - 2/5

1/3² × 3³ - 2/5

3 - 2/5

Answer = 13/5

Hope this helps!

- CloutAnswers ❁

Brainliest is greatly appreciated!

━━━━━━━☆☆━━━━━━━

Answer:

[tex] \boxed{\sf b. \ \frac{13}{5}} [/tex]

Step-by-step explanation:

[tex] \sf Simplify \: the \: following: \\ \sf \implies \frac{ |4 - 5| }{9} \times {3}^{3} - \frac{2}{5} \\ \\ \sf 4 - 5 = - 1 : \\ \sf \implies \frac{ | - 1| }{9} \times {3}^{3} - \frac{2}{5} \\ \\ \sf Since \: - 1 \: is \: a \: negative \: constant, \: |-1| = 1: \\ \sf \implies \frac{1}{9} \times {3}^{3} - \frac{2}{5} \\ \\ \sf {3}^{3} = 3 \times {3}^{2} : \\ \sf \implies \frac{ \boxed{ \sf 3 \times {3}^{2}} }{9} - \frac{2}{5} \\ \\ \sf {3}^{2} = 9 : \\ \sf \implies \frac{3 \times 9}{9} - \frac{2}{5} \\ \\ \sf \frac{9}{9} = 1 : \\ \sf \implies 3 - \frac{2}{5} [/tex]

[tex] \sf Put \: 3 - \frac{2}{5} \: over \: the \: common \: denominator \: 5 : \\ \sf \implies 3 \times \frac{5}{5} - \frac{2}{5} \\ \\ \sf \implies \frac{3 \times 5}{5} - \frac{2}{5} \\ \\ \sf 3 \times 5 = 15 : \\ \sf \implies \frac{ \boxed{ \sf 15}}{5} - \frac{2}{5} \\ \\ \sf \implies \frac{15 - 2}{5} \\ \\ \sf 15 - 2 = 13 : \\ \sf \implies \frac{13}{5} [/tex]

Answer:    20,736

Step-by-step explanation:

Math and History and Chemistry and Biology and Subjects

  3!     x        4!        x          3!          x        1!          x        4!       = 20,736

Answer:

a. 0.67

b. 1.31

Step-by-step explanation:

We have the following information n = 20, mean (m) = 10 and standard deviation (sd) = 3

a.

SE (m) = sd / n ^ (1/2)

replacing we have:

SE (m) = 3/20 ^ (1/2) = 0.67

Therefore the standard error of the mean is 0.67

b.

the critical value is obtained as shown below:

the level of sifnificance is alfa = 1 - 0.95 = 0.05

the critical value with level of significance alfa / 2 = 0.05 / 2 = 0.025

and to this value corresponds z = 1.96 (z table)

The margin of error with 95 confidence is calculated as follows:

E = z * SE

E = 1.96 * 0.67

E = 1.31

Therefore the margin of error is 1.31

(a) The standard error will be "0.67".

(b) The margin of error will be "1.31".

According to the question,

Standard deviation,

Sample size,

(a)

As we know,

→ The Standard error,

= [tex]\frac{sd}{\sqrt{n} }[/tex]

= [tex]\frac{3}{\sqrt{20} }[/tex]

= [tex]0.67[/tex]

(b)

As we know,

→ The margin of error,

= [tex]Z_{a/2}\times \frac{sd}{\sqrt{n} }[/tex]

By substituting the values, we get

= [tex]Z_{a/2}\times \frac{3}{\sqrt{20} }[/tex]

= [tex]1.96\times 0.67[/tex]

= [tex]1.31[/tex]

Thus the above response is right.

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https://brainly.com/question/10501147