What number must be subtracted from negative 5 for the difference to be negative 2

Answer:

distribute the 3

Step-by-step explanation:

follow pemdas ill put a brainpop link below

its the answer highlighted in yellow

Answer:

the 4th option is the right answer

subtract the constants

hope this helped you

please mark as the brainliest (ㆁωㆁ)

5 = -2 (x –  1)  (remove the parantheses)

5 = -2x + 2 (move the terms)

2x = 2 - 5 (calculate)

2x = -3 (divide both sides)

x= -3/2

5= -2x + 2 (move the terms)

2x = 2 - 5 (calculate)

2x = -3 (divide both sides)

x= -3/2

-2 + n = -8(1 - 8n) + 6

Distribute the -8

-2 + n = -8 + 64n + 6

Combine like terms.

-2 + n = 64n - 2

Add 2 to both sides and subtract n from both sides.

0 = 63n

Divide both sides by 63

0 = n

Answer: -24

Step-by-step explanation:

-2 * 8 = -16

-16 * -6 = 96

Answer:

24 Please give brainliest

Step-by-step explanation:

-2 x 8

-16 x -6

96/4

24

Answer:

this is the answer x=-1

Answer:

$2.25

Step-by-step explanation:

73.80/32.8

Answer:

[tex]x=\log_3{(15+ 4\sqrt{14})}\approx3.0949\text{ or } \\x=\log_3{(15- 4\sqrt{14})}\approx-3.0949[/tex]

Step-by-step explanation:

So we have the equation:

[tex]3^{1-x}+3^{1+x}=90[/tex]

First, note that this is the same as:

[tex]3\cdot 3^{-x}+3\cdot 3^x=90[/tex]

Factor out a 3:

[tex]3(3^{-x}+3^{x})=90[/tex]

Divide both sides by 3:

[tex]3^{-x}+3^x=30[/tex]

Change the negative exponent into a fraction:

[tex]\frac{1}{3^x}+3^x=30[/tex]

Multiply both sides by 3^x:

[tex]3^x(\frac{1}{3^x}+3^x)=(30)(3^x)[/tex]

Distribute:

[tex](1)+(3^x)^2=30(3^x)[/tex]

Let u equal 3^x. So:

[tex]1+u^2=30u[/tex]

Subtract 30u from both sides:

[tex]u^2-30u+1=0[/tex]

This is a quadratic. Solve using the quadratic formula. A is 1, b is -30, and c is 1. So:

[tex]u=\frac{-b\pm \sqrt{b^2-4ac}}{2a}[/tex]

Substitute:

[tex]u=\frac{-(-30)\pm \sqrt{(-30)^2-4(1)(1)}}{2(1)}[/tex]

Simplify:

[tex]u=\frac{30\pm \sqrt{900-4}}{2}[/tex]

Subtract:

[tex]u=\frac{30\pm \sqrt{896}}{2}[/tex]

Simplify:

[tex]u=\frac{30\pm 8\sqrt{14}}{2}[/tex]

Simplify:

[tex]u=15\pm 4\sqrt{14}[/tex]

Substitute back u:

[tex]3^x=15\pm 4\sqrt{14}[/tex]

Take the log to base 3 of both sides:

[tex]\log_3{3^x}=\log_3{15\pm 4\sqrt{14}}[/tex]

The left side cancels:

[tex]x=\log_3{15\pm 4\sqrt{14}}[/tex]

So, our solutions are:

[tex]x=\log_3{(15+ 4\sqrt{14})}\approx3.0949\text{ or } \\x=\log_3{(15- 4\sqrt{14})}\approx-3.0949[/tex]

And we're done!

Answer:

[tex]g(f(3))=-2[/tex]

Step-by-step explanation:

So we have the two functions:

[tex]g(x)=4x+2\text{ and } f(x)=3x-10[/tex]

And we want to find g(f(3)).

So, let's find f(3) first:

[tex]f(3)=3(3)-10[/tex]

Multiply:

[tex]f(3)=9-10[/tex]

Subtract:

[tex]f(3)=-1[/tex]

Therefore, we can substitute -1 for f(3):

[tex]g(f(3))=g(-1)[/tex]

Now, find g(-1):

[tex]g(-1)=4(-1)+2[/tex]

Multiply:

[tex]g(-1)=-4+2[/tex]

Add:

[tex]g(-1)=-2[/tex]

And we're done!

So:

[tex]g(f(3))=-2[/tex]

Answer:

4750

Step-by-step explanation:

950x

950× 5

4750

varying directly with number of days

Answer:

-8  7/9

Step-by-step explanation:

-9x+1=80

-9x+1-1=80-1

-9x=79

-9x=79

-9   -9

x= -8  7/9

Answer:

Step-by-step explanation:

If E and F are complementary I means that the sum of their angles add up to 90° since all complementary angles have the sum of their angles equal to 90°

To find m[tex]\angle[/tex]F add m[tex]\angle[/tex]E and m[tex]\angle[/tex] F and equate it to 90 to find x then substitute it into the expression for m[tex]\angle[/tex]F

Thats

m[tex]\angle[/tex]E + m[tex]\angle[/tex]F = 90

[tex]\rarr[/tex] 9x - 38 + 2x + 40 = 90

[tex]\rarr[/tex] 11x + 2 = 90

[tex]\rarr[/tex] 11x = 90 - 2

[tex]\rarr[/tex] 11x = 88

Divide both sides by 11

x = 8

Now we have

if m [tex]\angle[/tex]F = 9x - 38

m[tex]\angle[/tex] F = 9( 8) - 38

m[tex]\angle[/tex]F = 72 - 38

We have the final answer as

Hope this helps you

Answer:

c

Step-by-step explanation:  3 is not bigger than 9 so it can't bump it up so it stays like that.

Answer:

Option B (second one to the right)

Step-by-step explanation:

Solving this equation:

-1/2(30)= -15

-1/2 x 30 = -15

(2 days = 1 inch lost)

Step-by-step explanation:

4x³ - 14x² + 12x

= 2x[2x² - 7x + 6]

= 2x[(2x-3)(x-2)]

= 2x(2x-3)(x-2)

≈ 63.30 ft²

Heron formula

A = √p(p - a)(p - b)(p - c)

a = 9 ; b = 15 ; c = 20

p = (a + b + c)/2 = (9 + 15 + 20)/2 = 44/2 = 22

A = √22(22-9)(22-15)(22-20)

= √22×13×7×2

= √4004

≈ 63,27

≈ 63.30 ft²

Answer:

√

36

=

6

lies between consecutive odd integers  

5

and  

7

.

Step-by-step explanation:

"The" square root of  

36

is itself an integer, namely  

6

, since  

6

2

=

36

. So it does not lie between consecutive integers.

It does lie between consecutive odd integers  

5

and  

7

.

Note that  

36

has another square root, namely  

−

6

, since  

−

6

satisfies:

(

−

6

)

2

=

36

Answer:

-5

Step-by-step explanation:

Answer:

-5

Step-by-step explanation:

hope it helped!! Brainliest? I need em

Step-by-step explanation:

Hey there!!!!

Your required answer is option A.

The reason is.

When we solve it through elimination method we need to multiply second equation by "2" and then subtract to get "-4y" in 1st equation and "+4y" in 2nd equation cancelled.(As when we multiply equation 2 by 2 and subtract we get "-2y" as "+4y".)

So, it the equation seems like,

[tex]12 {x}^{2} + 4 {y}^{2} = 22[/tex]

Now, this equation is made after multiplying it by 2 and subtracting the 1st and 2nd equation to solve the equation s.

So, the answer is option A.

Hope it helps...

Answer:

y=3x+6, y=5x,

Step-by-step explanation:

Answer:

2x^2-18x

Step-by-step explanation:

Answer:

96

Step-by-step explanation:

multiply by 12 because thats how many inches are in a foot

There are 96 inches in 8 feet.

There are 60 inches in 5 feet. Therefore,

5 feet = 60 inches

8 feet = ?

cross multiply

length in inches = 60 × 8 / 5

length in inches = 480 / 5

length in inches = 96 inches.

Therefore, there are 96 inches in 8 feet.

learn more on length here: https://brainly.com/question/23044923?referrer=searchResults

1. Positional Notation

2. Doubiling

3. An Online Converter

Step-by-step explanation:

Hey there!!!

We generally multiply using base 2 and keep power that starts from 0 and goes on increasing and add all them at last to convert binary to decimal.

For example:

011110

To convert into decimal follow the steps.

1st step: Multiply with base 2 and keep power from right side starting from 0.

[tex]0 \times {2}^{5} + 1 \times {2}^{4} + 1 \times {2}^{3} + 1 \times {2}^{2} + 1 \times {2}^{1} + 0 \times {2}^{0} [/tex]

2nd step: solve powers and multiply with binary numbers.

This implies;

= 0 + 16 + 8 + 4 + 2 +0

= 30.... is your answer.

Hope it helps....

Answer:

29i

Step-by-step explanation:

https://socratic                 .org/questions/how-do-you-evaluate-2-5i-p-q-i-when-p-2-and-q-5i#304498

If you want a description, copy that into your browser and take out the spaces between "socratic" and ".org".

Answer:

A

Step-by-step explanation:

Answer:

TU = 5

Step-by-step explanation:

Since, U is the midpoint of TV.

[tex]\therefore TV = 2 \times TU \\ 3x - 23 = 2(x - 6) \\ 3x - 23 = 2x - 12 \\ 3x - 2x = 23 - 12 \\ x = 11 \\ \\ TU = x - 6 \\ TU = 11 - 6 \\ \huge \red { \boxed{TU = 5}}[/tex]

Answer:

Senn needs to give Ms. Lady 4.6 minutes  head start

Senn needs to give Ms. Beetle 18.4 minutes  head start

The equation for each bug are;

For Senn, the equation for the experiment is 5 × t₁ = 92 feet

For Ms. Lady, the equation for the experiment is 4 × (t₁ + 4.6) = 92 feet

For Ms. Beetle , the equation for the experiment is 4 × (t₁ + 18.4) = 92 feet

Please find attached the required graph and table of values

Step-by-step explanation:

The given parameters are;

The average crawling time of Ms. Lady = 4 feet per minute

The average crawling time of Ms. Beetle = 2.5 feet per minute

The average crawling time of Senn = 5 feet per minute

The distance to the rose bush = 92 feet

Therefore, we have;

The time, t, duration for Senn to arrive at the Rose bush is given by the following relation,

Time, t = Distance, d/(Speed, s)

Given that the speed of the bugs is equal to their average crawling time, we have

For Senn

Time, t = 92/(5 ft/Min) = 18.4 minutes

For, Ms. Lady

Time, t = 92/(4 ft/Min) = 23 minutes

For, Ms. Beetle

t = 92/(2.5 ft/Min) = 36.8 minutes

Therefore;

Senn needs to give Ms. Lady 23 - 18.4 = 4.6 minutes head start

Similarly, Senn needs to give Ms. Beetle 36.8 - 18.4 = 18.4 minutes  head start

The equation for each bug are therefore;

For Senn, the equation for the experiment is given as follows ;

5 × t₁ = 92 feet

For Ms. Lady, the equation for the experiment is given as follows;

4 × (t₁ + 4.6) = 92 feet

For Ms. Beetle , the equation for the experiment is given as follows;

4 × (t₁ + 18.4) = 92 feet.

Answer:

$3.50

Step-by-step explanation:

Answer:

14

Step-by-step explanation:

Here's where you'll use the infamous PEMDAS, which just means how to solve the equation in order.

P means parentheses

E means exponents

M means multiplication

D means division

A means addition

S means subtraction

So start with P. Here we have (2+1) so that becomes 3. Which then turns the equation into: 3 - 4 × 5 + 31. Next Is E but since there are no exponents here you skip that step. Next is M. You have 4 × 5 which is 20 so the equation then becomes: 3 - 20 + 31. Next is D but since there's nothing to divide you can skip that too. You can actually go right ahead and solve it here because in PEMDAS you can actually just do all MD problems together from left to right, same as and AS problems in order from left to right, instead of doing M and then D or A and then S.

(I made a careless mistake in the original post, this should be the correct answer)