Answer:
Approximately [tex]3.06 \times 10^{2}\; \rm g[/tex] (approximately [tex]306\; \rm g[/tex].)
Explanation:
Calculate the quantity [tex]n[/tex] of lithium phosphate in [tex]V = 2.5\; \rm L[/tex] of this[tex]c = 1.06\; \rm M = 1.06\; \rm mol \cdot L^{-1}[/tex] lithium phosphate solution.
[tex]\begin{aligned}n &= c \cdot V\\ &= 2.5\; \rm L \times 1.06\; mol \cdot L^{-1}\\ &= 2.65\; \rm mol\end{aligned}[/tex].
Empirical formula of lithium phosphate: [tex]\rm Li_3PO_4[/tex].
Look up the relative atomic mass of [tex]\rm Li[/tex], [tex]\rm P[/tex],and [tex]\rm O[/tex] on a modern periodic table:
[tex]\rm Li[/tex]: [tex]6.94[/tex].[tex]\rm P[/tex]: [tex]30.974[/tex].[tex]\rm O[/tex]: [tex]15.999[/tex].Calculate the formula mass of [tex]\rm Li_3PO_4[/tex]:
[tex]M(\rm Li_3PO_4) = 3 \times 6.94 + 30.974 + 4 \times 15.999 = 115.79\; \rm g \cdot mol^{-1}[/tex].
Calculate the mass of that [tex]n = 2.65\; \rm mol[/tex] of [tex]\rm Li_3PO_4[/tex] formula units:
[tex]\begin{aligned}m &= n \cdot M \\ &= 2.65\; \rm mol \times 115.79\; \rm g\cdot mol^{-1} \\ &\approx 3.06 \times 10^{2}\; \rm g \end{aligned}[/tex].
How many moles of gold atoms do 3.45x10^24 gold atoms constitute?
Answer:
3.45E24
Explanation:
calculator I'm not that great at math but I'm good at science but that isn't really science but it's aix between it tho
HELP ANYONE THERE
At a research lab, a scientist carelessly pours cultures of living microbes down the drain. Which type of pollution is this?
Question 4 options:
toxic
sediment
nutrient
bacterial
A scientist that carelessly pours cultures of living microbes down the drain represents a type of bacterial pollution.
What is bacterial pollution?Bacterial pollution refers to the uncontrolled proliferation of bacteria in the surrounding environment and ecosystems.
Bacterial pollution can be a subject of concern because bacteria may be pathogenic microorganisms.Bacterial pollution may cause serious harm to the public health and the well-being of a population.In conclusion, a scientist that carelessly pours cultures of living microbes down the drain represents a type of bacterial pollution.
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The purification of hydrogen gas by diffusion through a palladium sheet was discussed in Section 5.3. Compute the number of kilograms of hydrogen that pass per hour through a 5-mm-thick sheet of palladium having an area of 0.20 m2 at 500C. Assume a diffusion coefficient of 1.0 108 m2 /s, that the concentrations at the high- and low-pressure sides of the plate are 2.4 and 0.6 kg of hydrogen per cubic meter of palladium, and that steady-state conditions have been attained
This question is incomplete, the complete question is;
The purification of hydrogen gas by diffusion through a palladium sheet was discussed in Section 5.3. Compute the number of kilograms of hydrogen that pass per hour through a 5-mm-thick sheet of palladium having an area of 0.20 m² at 500C.
Assume a diffusion coefficient of 1.0 × 10⁻⁸ m²/s, that the concentrations at the high- and low-pressure sides of the plate are 2.4 and 0.6 kg of hydrogen per cubic meter of palladium, and that steady-state conditions have been attained
Answer:
the number of kilograms of hydrogen that pass per hour through is 2.592 × 10⁻³ kg
Explanation:
Given the data in the question;
thickness of sheet t = 5 mm
Area A = 0.20 m²
Temperature T = 500°C
diffusion coefficient ∝ = 1.0 × 10⁻⁸ m²/s
concentration high pressure side C[tex]_A[/tex] = 2.4
concentration low pressure side C[tex]_B[/tex] = 0.6 kg
from the question, we calculate the concentration gradient
dc/dx = (C[tex]_A[/tex] - C[tex]_B[/tex])/dt
so we substitute
dc/dx = (2.4 - 0.6) / ( - 5 × 10⁻³ )
dc/dx = -360
now, mass of hydrogen per hour that diffuse through a pd sheet
M = -∝AT(dc/dx)
where time t is 1 hour ( 3600 sec )
we substitute
M = -(1.0 × 10⁻⁸) × 0.20 × 3600 (-360)
M = 0.002592
M = 2.592 × 10⁻³ kg per one hour
Therefore, the number of kilograms of hydrogen that pass per hour through is 2.592 × 10⁻³ kg
The number of kilograms of hydrogen that pass per hour through a 5-mm-thick sheet of palladium having an area of 0.20 m² at 500°C is 2.592 × 10⁻³ kg.
Purification: It refers to the process of removing impurities or contaminants from a substance in order to make it cleaner, purer, or more refined. It also involves the elimination or reduction of unwanted substances or components that may be present in the original material.
According to the question, given data is:
Thickness of sheet t = 5 mm
Area A = 0.20 m²
Temperature T = 500°C
Diffusion coefficient ∝ = 1.0 × 10⁻⁸ m²/s
Concentration high pressure side [tex]C_A[/tex] = 2.4
Concentration low pressure side[tex]C_B[/tex]= 0.6 kg
from the question, we calculate the concentration gradient,
[tex]dc/dx = (C _A- C_B)/dt[/tex]
so, we substitute the values,
[tex]dc/dx[/tex] = (2.4 - 0.6)/ ( - 5 × 10⁻³)
[tex]dc/dx = -360[/tex]
Now, mass of hydrogen per hour that diffuse through a Palladium sheet,
M = -∝[tex]AT(dc/dx)[/tex]
where time t is 1 hour (3600 sec)
We substitute,
M = -(1.0 × 10⁻⁸) × 0.20 × 3600 (-360)
M = 0.002592
M = 2.592 × 10⁻³ kg per hour.
Therefore, the number of kilograms of hydrogen that pass per hour through a palladium sheet is approximately 2.592 × 10⁻³ kg.
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This question is incomplete, the complete question is;
The purification of hydrogen gas by diffusion through a palladium sheet was discussed in Section 5.3. Compute the number of kilograms of hydrogen that pass per hour through a 5-mm-thick sheet of palladium having an area of 0.20 m² at 500C.
Assume a diffusion coefficient of 1.0 × 10⁻⁸ m²/s, that the concentrations at the high- and low-pressure sides of the plate are 2.4 and 0.6 kg of hydrogen per cubic meter of palladium, and that steady-state conditions have been attained.
what energy is stored
Answer: potential energy is stored
Explanation:
Calculate how many moles of NO2 form when each
quantity of reactant completely reacts.
2 N2O5(9) + 4NO2(g) + O2(9)
Part B
6.4 mol N205
Express your answer using two significant figures.
VALO
n =
Submit
Request Answer
Part C
16.2 g N205
Express your answer using three significant figurer
Answer:
partB: n=2N205
partc:17.20
K2S(s) + MgI2 (aq) -----> ?
Answer:
MgS + KI = K2S + MgI2
what are causes of students to drop-out from university
Answer:
stress
Explanation:
people cn get stressed and not want to do work
Knowing that Boyle's Law is P1V1 = P2V2, How would we rearrange the formula if we needed to solve for P1?
A. P1 = V1 -P2
B. P1 = P2V2 - V1
C. P1 = P2V2/V1
D. P1= V1/V2
Answer:
your answer is C
Explanation:
because when u make P1 the subject formula then P2 V2 will be divided with V1
Question #37.P.2A.2
Which statement about the periodic table is true?
a. Elements in the same column share similar properties.
b. Elements in the same row share similar properties.
c. Elements on the left have a larger nucleus than elements on the right.
d. Elements at the top of each column have the highest atomic mass in that column.
FIRST CORRECT ANSWER GETS 10 POINTS!!!!
Which explains how the nervous system is typically involved in keeping the body in homeostasis?
It processes the environment and sends out signals.
It controls movement and provides structure.
It physically breaks down and absorbs food.
It puts oxygen in the blood, which is essential for life.
Answer:
Explanation:
It processes the environment and sends out signals.
_BaS + _PtF2 → _BaF2 + _Pts
[tex]\huge\underline\mathbb\pink{ANSWER\::}\\\\[/tex]
_BaS + _PtF2 → _BaF2 + _Pts
Barium Sulfide + Platinum(II) Fluoride = Barium Fluoride + Platinum(II) Sulfide.
=> 1 BaS + 1 PtF2 → 1 BaF2 + 1 PtS
[tex]\\\\\\[/tex]
HOPE IT HELPS
PLEASE MARK ME BRAINLIEST☺️
1. Which kingdom is made up of only autotrophs?
A. Protista
I
B. Animalia
C. Plantae
D. Phylum
Answer: I believe it's C
Hope this helped<3
Can you please make my answer brainly
How many grams are in 8.3 moles of CaCl2?
Answer:
(8.3×40)+(8.3×71)
921.3grames
Answer:
[tex]\Large \boxed{\sf 921.3 \ g}[/tex]
Explanation:
Use formula
[tex]\displaystyle moles=\frac{mass}{M_r}[/tex]
[tex]M_r=40+35.5 \times 2 = 111[/tex]
Solve for mass
[tex]mass=8.3 \times 111=921.3[/tex]
8. A liquid boils when the vapor pressure of the liquid equals the atmospheric pressure on the surface
of the liquid. Using Reference Table H, determine the boiling point of water when the atmospheric
pressure is 90. kPa
Answer:
It is 98 degrees C.
Explanation:
#8 explain and answer
Answer:
B. The limiting reactant determines the maximum amount of product that can be formed.
what are the three components of a chemical formula?
Answer:
The three components of a chemical formula are the empirical formula, the molecular formula, and the structural formula.Hope this answer helps.
What are Renewable Resoures?
Answer:
resources that you can use more than 1 time like rechargeable battery or solar energy
Explanation:
A student said, "You can't see the full Moon during the day because it rises close to sunset."
Which diagram supports this statement? (Diagrams are not to scale. You are looking down from
a north polar view fisa person standing on Earth at sunset.)
Oq. Ooo
Ooo
OD
ОА
OB
ОС
OD
Answer:
I think it would be B.
Explanation:
Which contributes to the polarity of a water molecule?
Oa linear shape along with strong covalent bonds
O deflection of hydrogen atoms by lone pairs of electrons
O no difference in the electronegativity of oxygen and hydrogen
Ohydrogen bond formation between water molecules
Answer:
B
Explanation:
Answer:
B
Explanation:
Edge 2022
A(n) ____________ is a push or a pull.
newton
acceleration
force
momentum
Which of the following is the Brønsted-Lowry definition of an acid?
Answer:
A Brønsted-Lowry acid is any species that can donate a proton (H +) to another molecule. A Brønsted-Lowry base is any species that can accept a proton from another molecule. In short, a Brønsted-Lowry acid is a proton donor (PD), while a Brønsted-Lowry base is a proton acceptor (PA).
Which of the following is the correct definition of "weathering"? *
The movement of rocks
The breakdown of rocks.
The dropping off of rocks
All of the above
When 136g of glycine are dissolved in of a certain mystery liquid , the freezing point of the solution is lower than the freezing point of pure . On the other hand, when of sodium chloride are dissolved in the same mass of , the freezing point of the solution is lower than the freezing point of pure . Calculate the van't Hoff factor for sodium chloride in . Be sure your answer has a unit symbol, if necessary, and round your answer to significant digits.
The given question is incomplete. The complete question is:
When 136 g of glycine are dissolved in 950 g of a certain mystery liquid X, the freezing point of the solution is 8.2C lower than the freezing point of pure X. On the other hand, when 136 g of sodium chloride are dissolved in the same mass of X, the freezing point of the solution is 20.0C lower than the freezing point of pure X. Calculate the van't Hoff factor for sodium chloride in X.
Answer: The vant hoff factor for sodium chloride in X is 1.9
Explanation:
Depression in freezing point is given by:
[tex]\Delta T_f=i\times K_f\times m[/tex]
[tex]\Delta T_f=T_f^0-T_f=8.2^0C[/tex] = Depression in freezing point
[tex]K_f[/tex] = freezing point constant
i = vant hoff factor = 1 ( for non electrolyte)
m= molality =[tex]\frac{136g\times 1000}{950g\times 75.07g/mol}=1.9[/tex]
[tex]8.2^0C=1\times K_f\times 1.9[/tex]
[tex]K_f=4.32^0C/m[/tex]
Now Depression in freezing point for sodium chloride is given by:
[tex]\Delta T_f=i\times K_f\times m[/tex]
[tex]\Delta T_f=20.0^0C[/tex] = Depression in freezing point
[tex]K_f[/tex] = freezing point constant
m= molality = [tex]\frac{136g\times 1000}{950g\times 58.5g/mol}=2.45[/tex]
[tex]20.0^0C=i\times 4.32^0C\times 2.45[/tex]
[tex]i=1.9[/tex]
Thus vant hoff factor for sodium chloride in X is 1.9
A self-aldol or crossed aldol reaction REQUIRES a(n) ___________________. Group of answer choices strong acid only a very, very strong base, such as LDA (lithium diisopropyl amide), NaOH or LiOH won't work acid catalyst a strong base such as LiOH or NaOH
Answer:
[tex]\mathbf{a \ strong \ base \ such \ as\ LiOH \ or \ NaOH.}[/tex]
Explanation:
In the condensation reactions of carbonyl compounds, it is essential to establish the order of events in advance to minimize or suppress the possibilities of self-condensation and the occurrence of cross-condensation, which unfortunately are an obvious threat in these reactions.
Self-condensation:
Any carbonyl compound that has one or more alpha hydrogens, on the carbons adjacent to the carbonyl group, runs the risk of undergoing a self-condensation reaction if the corresponding rigor is not carried out.
Cross-condensation:
Ideally, in the condensation reactions of carbonyl compounds, one of the reacting molecules should quickly enolise, while the other preferably should not have Hα, to ensure that no other by-products are formed.
[tex]\text{To achieve this process;}[/tex] [tex]\text{A self-aldol or crossed aldol requires a strong base such as LiOH or NaOH.}[/tex]