What lets the computer's hardware and software work together?

Answer:

See explanation

Explanation:

An instance of such program written in python is

isum = 0

for i in range(1,11):

isum = isum + i

print(sum)

One of the ways the program can give a wrong result is when someone alters the program source program before it's complied and executed.

Take for instance.

Changing

isum = 0 to isum = 4

will alter the result by additional 4

Another way is if an outside program or process alters the program execution.

Answer:

b) Select the whole document by pressing Ctrl+a.

Explanation:

The correct answer is b. If you do not select the whole document or parts of the document you wish to change the proofing language for, it will only be applied to the word your cursor is positioned in.

ig:ixv.mona :)

Answer:

B) Select the whole document by pressing Ctrl+A.

Answer:

this is AC b/c.... cos is a periodic function.. think waves... the voltage is going to vary between positive 5 and negative 5 volts... so it's a low voltage signal, but still AC,   the W is for how fast it's varying and the  +2 is the off set of the wave.  

Explanation:

Answer:

Explanation:

Motherboard

A motherboard is the main printed circuit board in general-purpose computers and other expandable systems. It holds and allows communication between many of the crucial electronic components of a system, such as the central processing unit and memory, and provides connectors for other peripherals

Answer:

The program written in Java without comment is as follows

import java.util.*;

public class MyClass {

   public static void main(String args[]) {

       Scanner input = new Scanner(System.in);

       System.out.print("Year: ");

       int y = input.nextInt();

       int a = y%19;

       System.out.println("a = "+a);

       int b = y / 100;

       System.out.println("b = "+b);

       int c = y%100;

       System.out.println("c = "+c);

       int d = b / 4;

       System.out.println("d = "+d);

       int e = b%4;

       System.out.println("e = "+e);

       int g = (8 * b + 13)/25;

       System.out.println("g = "+g);

       int h = (19 * a + b - d - g + 15)%30;

       System.out.println("h = "+h);

       int j = c/4;

       System.out.println("j = "+j);

       int k = c%4;

       System.out.println("k = "+k);

       int m = (a + 11 * h)/319;

       System.out.println("m = "+m);

       int r = (2 * e + 2 * j - k - h + m + 32)%7;

       System.out.println("r = "+r);

       int n = (h - m + r + 90)/25;

       System.out.println("n = "+n);

       int p = (h - m + r + n + 19)%32;

       System.out.println("p = "+p);

   }

}

Explanation:

I've added the full source code as an attachment where I use comments to explain difficult lines

Answer:

C- applying picture styles

Explanation: ;)

Answer:

applying picture styles

Explanation:

edge/canvas test review

Answer:

the answer is B. find the average of four numbers

Explanation:

Answer:

Kill

lie

fight

..

..

.

..

Answer:

Here is the JAVA program:

public class Main {  //class name

public static void main(String[] args) {   //start of main method

//sets all boolean type variables spades, hearts diamonds and clubs to false initially

   boolean spades = false;  

   boolean hearts = false;

   boolean diamonds = false;

   boolean clubs = false;  

   String[] deck = new String[4];  //to store card sequence

   int index = 0;  //to store index position

   int NoOfPicks = 0;  //to store number of picks (picks count)

   while (!spades || !hearts || !diamonds || !clubs) {   //loop starts

       String card = printCard(getRandomCard());  //calls printCard method by passing getRandomCard method as argument to it to get the card

       NoOfPicks++;   //adds 1 to pick count

       if (card.contains("Spades") && !spades) {  //if that random card is a card of Spades and spades is not false

           deck[index++] = card;  //add that card to the index position of deck

           spades = true;  //sets spades to true

       } else if (card.contains("Hearts") && !hearts) {  //if that random card is a card of Hearts and hearts is not false

           deck[index++] = card;  

           hearts = true;   //sets hearts to true

       } else if (card.contains("Diamond") && !diamonds) {  //if that random card is a card of Diamond and diamonds is not false

           deck[index++] = card;

           diamonds = true;  //sets diamonds to true

       } else if (card.contains("Clubs") && !clubs) {  if that random card is a card of Clubs and clubs is not false

           deck[index++] = card;

           clubs = true;         }     }   //sets clubs to true

   for (int i = 0; i < deck.length; i++) {  //iterates through the deck i.e. card sequence array

       System.out.println(deck[i]);     }  //prints the card number in deck

   System.out.println("Number of picks: " + NoOfPicks);  }   //prints number of picks

public static int getRandomCard() {  //gets random card

   return (int) (Math.random() * 52); }   //generates random numbers of 52 range

public static String printCard(int cardNo) {   //displays rank number and suit

   String[] suits = { "Spades", "Hearts", "Diamonds", "Clubs", };  //array of suits

   String[] rankCards = { "Ace", "2", "3", "4", "5", "6", "7", "8", "9", "10",

           "Jack", "Queen", "King" };   //array of rank

  int suitNo = cardNo / 13;  //divides card number by 13 and stores to suitNo

 int rankNo = cardNo % 13;   //takes modulo of card number and 13 and store it to rankNo

   return rankCards[rankNo] + " of " + suits[suitNo];  }}  //returns rankCard at rankNo index and suits at suitNo index

Explanation:

The program is explained in the comments attached with each line of code. The screenshot of the program along with its output is attached.

Answer:

The answer is

d. Use the Sort function to organize the data based on date order.

Explanation:

Most accurate one.

The option that she should use to most efficiently complete this task is to use the Sort function to organize the data based on date order. The correct option is D.

It is "a piece of paper used to record work schedules, working hours, special instructions, etc. a sheet of paper used to jot down problems, ideas, or the like in draft form." A worksheet used in education could have questions for pupils and spaces for them to record their responses.

A single spreadsheet called an Excel Worksheet is made up of cells arranged in rows and columns. A worksheet always starts in row 1 and column A. A formula, text, or number can be entered into each cell. Additionally, a cell can point to a different cell on the same worksheet, in the same workbook, or in a different workbook.

Therefore, the correct option is D. Use the Sort function to organize the data based on date order.

To learn more about the worksheet, refer to the link:

https://brainly.com/question/1024247

#SPJ6

Answer:

hi

Explanation:

89

Answer:

I would say it is more engaging and helps the user remember the content better as multimedia is more memorable than just plain text. It can also display things that plain text is unable to, such as sounds and detailed pictures.

Explanation:

Answer:

hope i get brainliest

Explanation:

Emerging Technologies

Abstract

The purpose of this paper is to summarize the advantages of computers/software and the use of computer technology in investigations. Summarize the disadvantages to law enforcement with respect to the advancements of computers. Real cases will be researched in order to understand how computers can be utilized in criminal activities, as well as a case that the use of a computer was beneficial to the prosecution in a criminal case. A final conclusion paragraph will address my personal subjective opinion as to whether these technologies, in an overall sense are a benefit or hindrance to law enforcement efforts.

Introduction

Since computers have become such a big part of our…show more content…

From utilizing computers in cars so officers could run a license plate and social security number to see if there are any warrants out for the person they stopped, to more advances such as carrying cell phones, GPS tracking systems in cars, crime mapping tools, information sharing between state and local law enforcement, to even sharing information across countries. Technology has come a long way in helping officers and other agents within the criminal justice system do their job.  

Just a bit more about the advantages of the things mentioned above and time to move on. The most interesting thing is Geographic Information Systems (GIS), which has become a most important tool for law enforcement agencies. GIS, other mapping software and desktop computers now are capable of mapping and data analysis that is way above and beyond what used to be possible with backroom mainframe computers (Rubley, 2011).

Another great advancement is the widespread use of everyone using mobile devices. Many officers now use two to three cell phones.

Answer:

b

Explanation:

Explanation:

1.

the answer to the first question is organizational unit. this is because in this scenario that we have before us, cost is a deciding factor. a unit as this can adapt to changes, it is flexible and also not very complex

2.

answer to question 2 is PDC emulator. this emulator can perform the function synchronization of time across every domain controller that is in the domain. other of its functions are, authentication and changing of passwords.

3.

the answer to the 3rd question is child domain. It is a factor in this scenario because it works well in a situation where there is an issue of slow network connection.

Answer:

...............fp......

Answer:

I think a exabyte, if not its probably a terabyte

Explanation:

Answer:

to add a main loop

Explanation:

Answer:

Here is the Hello class:

public class Hello { //class name

     private String name; //to store the name

      public Hello (String names) //parameterized constructor

      { name = names;  }  

      public void English() { //method to greet user in english

           System.out.print("Hello "); //displays Hello on output screen

           System.out.print(name); //displays user name

           System.out.println("!");  }  //displays exclamation mark symbol

           public void Spanish(){ //method to greet user in spanish

               System.out.print("Hola "); //displays Hello on output screen

               System.out.print(name); //displays user name

               System.out.println("!"); } //displays exclamation mark symbol

         public void French() { //method to greet user in french

              System.out.print("Bonjour "); //displays Hello on output screen

              System.out.print(name);  //displays user name

              System.out.println("!");  } } //displays exclamation mark symbol

Explanation:

Here is the HelloTester class:

import java.util.Scanner; //to accept input from user

public class HelloTester { //class name

 public static void main (String[]args)  { //start of main method

String name; //to store the name of user

Scanner input = new Scanner(System.in);  //creates Scanner class object

System.out.println("Enter name?" );  //prompts user to enter name

 name = input.nextLine(); //scans and reads the name from user

 Hello hello = new Hello(name); //creates Hello class object and calls constructor by passing name

hello.English(); //calls English method using object hello to greet in english

hello.Spanish(); //calls Spanish method using object hello to greet in spanish

hello.French(); } }  //calls French method using object hello to greet in french

The output of the program is:

Enter name?                                                                                                                    user                                                                                                                           Hello user!                                                                                                                    Hola user!                                                                                                                    Bonjour user!  

The screenshot of the program along with its output is attached.

Java is one of the most popular programming languages that is being widely used in the IT industry. It is simple, robust, and helps us to reuse the code.

The required program is,

\\import java.util.Scanner;

class Hello

{

private String name;

public Hello(String yourName)

{

name=yourName;

}

public void english()

{

System.out.print("Hello ");

System.out.print(name);

System.out.println("!");

}

public void spanish()

{

System.out.print("Holla ");

System.out.print(name);

System.out.println("!");

}

public void french()

{

System.out.print("Bonjour ");

System.out.print(name);

System.out.println("!");

}

public void german()

{

System.out.print("Hallo ");

System.out.print(name);

System.out.println("!");

}

public void russian()

{

System.out.print("Privet ");

System.out.print(name);

System.out.println("!");

}

public void chinese()

{

System.out.print("Ni hao ");

System.out.print(name);

System.out.println("!");

}

}

public class HelloTester

{

public static void main(String[] args)

{

Scanner input=new Scanner(System.in);

String name;

//Accepting the name

System.out.print("\nEnter your name: ");

name=input.next();

/creating an object of Hello class

Hello hello=new Hello(name);

System.out.println("\nGreeting in English: ");

System.out.println("-------------------------------------");

hello.english();

//calling the methods to greet in different languages

System.out.println("\nGreeting in Spanish: ");

System.out.println("-------------------------------------");

hello.spanish();

System.out.println("\nGreeting in French: ");

System.out.println("-------------------------------------");

hello.french();

System.out.println("\nGreeting in German: ");

System.out.println("-------------------------------------");

hello.german();

System.out.println("\nGreeting in Russian: ");

System.out.println("-------------------------------------");

hello.russian();

System.out.println("\nGreeting in Chinese: ");

System.out.println("-------------------------------------");

hello.chinese();

System.out.print("\n");

}

}

\\

So, the output is attached below:

Learn more about the topic Java Program:

https://brainly.com/question/19271625

Answer:

Contextual tab Picture Tools > Format in the Adjust group

Explanation:

edge/canva test review

Suzanne finds the options in the contextual tab Picture Tools > Format in the Adjust group. The correct option is B.

When a specific event occurs in the Office document, a contextual tab, which is a hidden tab control in the Office ribbon, is presented in the tab row. For instance, when a table is selected in Excel, the Table Design tab is displayed on the ribbon.

The contextual command tabs have the capabilities and commands you need to operate in a certain situation. The contextual tabs, for instance, provide actions that are only applicable while working with a table in the Design view when you open a table in that view.

Therefore, the correct option is B. Contextual tab Picture Tools > Format in the Adjust group.

To learn more about the contextual tab, refer to the link:

https://brainly.com/question/26680062

#SPJ2

Answer:

Ductility

Explanation:

Answer:

import java.util.Scanner;

public class LabProgram{

    public static void main(String []args){

       Scanner input = new Scanner(System.in);

       int red,blue,green,smallest;

       System.out.print("Enter three numbers between 0 and 255 (inclusive): ");

       red =input.nextInt();

       green =input.nextInt();

       blue =input.nextInt();

       if(red <= blue && red <= green){

       smallest = red;

       }

       else if(green <= red && green <= blue){

           smallest = green;

       }

       else{

            smallest = blue;

       }

       System.out.print((red - smallest)+" "+(green - smallest)+" "+(blue - smallest));

}

}

Explanation:

This line declares necessary variables

int red,blue,green,smallest;

This line prompts user for input of 3 numbers

System.out.print("Enter three numbers between 0 and 255 (inclusive): ");

The next three lines gets user inputs

       red =input.nextInt();

       green =input.nextInt();

       blue =input.nextInt();

The following iteration checks for the smallest for red, green, blue

       if(red <= blue && red <= green){

       smallest = red;

       }

       else if(green <= red && green <= blue){

           smallest = green;

       }

       else{

            smallest = blue;

       }

This line prints the required output

       System.out.print((red - smallest)+" "+(green - smallest)+" "+(blue - smallest));

Answer:

hope this helps...

Explanation:

A computer can only make a decision if it has been instructed to do so. In some advanced computer systems, there are computers that have written the instructions themselves, based on other instructions, but unless there is a “decision point”, the computer will not act on its own volition.

PLEASE THANK MY ANSWER

Answer:

The solution to this question can be defined as follows:

Explanation:

please find the complete question in the attached file:

In point a:

It utilizes multiple algorithms based on machine learning can understand the attributes or transform their probability into projections. Its algorithms could be used, including such neural computer systems or artificial neural networks. Whenever the input, as well as the target outcome, are taken their possibilities are converted in forecasts, so that if the input, as well as the corresponding results, are balanced.

In point b:

The operating curves of its receiver is indeed a plot of its true positives for its incorrect positive rate. It could be used in different tests for treatment. It indicates the variations of its responsiveness between all the two components and also the accuracy. Line slopes supply LR with a value.

this answering question interface is bleh

The concept of boolean variables is that; variables declared as boolean type can only take any of two values. The variable can either be true or false. Such variable cannot take any other value apart from these two.

The short quiz program is as follows.

Please note that comments are used to explain difficult lines.

import java.util.*;

public class shortQuiz{

public static void main(String[] args) {

 Scanner input = new Scanner(System.in);

//This declares the variables that represent correct answers as boolean data type; the variables are also initialized

 boolean q1 = true, q2 = false, q3 = true;

//This declares the response to each question as boolean data type

 boolean q1response, q2response, q3response;

//This prints the first question

 System.out.print("Java is a programming language, true or false? ");

//This gets input for the first response

 q1response = input.nextBoolean();

//This prints the second question

 System.out.print("Only numbers can be stored by variables in Java, true or false? ");

//This gets input for the second response

 q2response = input.nextBoolean();

//This prints the third question

 System.out.print("There are only 2 possible values which can be held by a boolean variable, true or false? ");

//This gets input for the third response

 q3response = input.nextBoolean();

//This prints your first response, alongside the correct answer to the first question

 System.out.println("Question 1 - Your answer: "+q1response+". Correct answer: "+q1);

//This prints your second response, alongside the correct answer to the second question

 System.out.println("Question 2 - Your answer: "+q2response+". Correct answer: "+q2);

//This prints your third response, alongside the correct answer to the third question

 System.out.println("Question 3 - Your answer: "+q3response+". Correct answer: "+q3);

//The program ends here

}

}

See attached image for program sample run.

The above program initializes the correct answers using boolean variables. The correct answers are then printed, after the user answers the three questions.

Read more about boolean variables at:

https://brainly.com/question/16843003

Answer:

The program needs one true answer to run

after the If statement is false

Explanation:

Else-if statements are attached to If statements. They run if the If statement is false, and have their own condition. If their condition passes, they run their own block of code.

Answer:

the answer is D :)

Answer:

Here is the C program:

#include <stdio.h>  //to use input output functions

int main(void) {   //start of main function

 int arrowBaseHeight = 0;  //stores value for arrow base height

int  arrowBaseWidth = 0;  //stores value for arrow base width

 int arrowHeadWidth = 0 ;  //stores value for arrow head width

 int i, j;  //to traverse through the rows and columns

 printf("Enter arrow base height:\n");  //prompts user to enter arrow base height value

 scanf("%d", &arrowBaseHeight);  //reads input value of arrow base height

 printf("Enter arrow base width:\n");  //prompts user to enter arrow base width value

 scanf("%d", &arrowBaseWidth);  //reads input value of arrow base width

 while (arrowHeadWidth <= arrowBaseWidth)  {   //iterates as long as the value of arrowHeadWidth is less than or equals to the value of arrowBaseWidth  

     printf("Enter arrow head width:\n");   //prompts user to enter arrow head width value

     scanf("%d", &arrowHeadWidth);   //reads input value of arrow head width

     printf("\n"); }

 for (i = 0; i < arrowBaseHeight; i++)    {   //iterates through rows

     for (j = 0; j < arrowBaseWidth; j++)  {   //iterates through columns

         printf("*");       }   //prints asterisks

     printf("\n");   }   //prints a new line

 for (i = arrowHeadWidth; i > 0; i--)    {   //loop for input length

     for (j = i; j > 0; j--)        {   //iterates for triangle ( to make arrow head)

         printf("*");       }   //prints asterisks

     printf("\n");   }  } //prints new line

Explanation:

The program asks to enter the height of the arrow base, width of the arrow base and the width of arrow head. When asking to enter the width of the arrow head, a condition is checked that the arrow head width arrowHeadWidth should be less than or equal to width of arrow base arrowBaseWidth. The while loop keeps iterating until the user enters the arrow head width larger than the value of arrow base width.  

The loop is used to output an arrow base of height arrowBaseHeight.

The nested loop is being used which as a whole outputs an arrow base of width arrowBaseWidth. The inner loop draws the stars and forms the base width of the arrow, and the outer loop iterates a number of times equal to the height of the arrow.

The last nested loop is used to output an arrow head of width arrowHeadWidth. The inner loop forms the arrow head and prints the stars needed to form an arrow head.  

The screenshot of output is attached.