what is transactive memory​

Answers

Answer 1

Here is a copy+pasted definition...

Transactive memory is a psychological hypothesis first proposed by Daniel Wegner in 1985 as a response to earlier theories of "group mind" such as groupthink.[1] A transactive memory system is a mechanism through which groups collectively encode, store, and retrieve knowledge. Transactive memory was initially studied in couples and families where individuals had close relationships but was later extended to teams, larger groups, and organizations to explain how they develop a "group mind",[1] a memory system that is more complex and potentially more effective than that of any of its individual constituents. A transactive memory system includes memory stored in each individual, the interactions between memory within the individuals, as well as the processes that update this memory. Transactive memory, then, is the shared store of knowledge.

In simple terms...

A transactive memory is a psychological hypothesis. It is a system in the brain which allows human's to encode, store, or get information.

For example...

let's say I learn 5 colors when I'm younger. My "transactive memory" will store it and will allow my brain to "retrieve" the information to allow me to remember colors I previously "stored".

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Related Questions

What is cutoff wavelength?

Answers

Answer:

The cutoff wavelength is the minimum wavelength in which a particular fiber still acts as a single mode fiber. Above the cutoff wavelength, the fiber will only allow the LP01 mode to propagate through the fiber (fiber is a single mode fiber at this wavelength).

Explanation:

Work is done on an object when
A) The displacement is not zero
B) The force and the displacement are perpendicular
C) The displacement is zero
D) The force is zero

Answers

Answer:

Incomplete question but the closest ans is

A) The displacement is not zero

Explanation:

For work to be done, the direction of force has to be parallel to or in the same direction as the displacement, this can then be calculated by

[tex]W=Fs \ cos[/tex]θ

Where θ is the angle between direction of force and direction of displacement

By this equation,

if Force is zero, W is zero

if displacement is zero, W is zero

if force and displacement are perpendicular θ=90, cosθ = 0

So A is the cloest choices

An equipotential surface that surrounds a point charge q has a potential of 536 V and an area of 1.20 m2. Determine q.

Answers

Answer:

q = 1.84×10^-8coulombs

Explanation:

Surface area = 4πr²

r is the distance

1.2 = 4(3.14)r²

1.2 = 12.56r²

r² = 1.2/12.56

r² = 0.0956

r = √0.0956

r = 0.309m

Get the charge C

V = kq/r

536 = 9.0×10^9q/0.309

536×0.309 = 9×10^9q

165.73 = 9×10^9q.

q = 165.73/9×10^9

q = 1.84×10^-8coulombs

A 2[kg] rock and a 4[kg] rock are lifted to a height of 10[m].
How much PE does each rock have?

Answers

Answer:

See below

Explanation:

Potential Energy = mgh

      for 2 rock = 2 * 9.81 * 10 = 196.2 j

      for 4 rock = 4 * 9.81 * 10 = 392.4 j

I have a problem in this questions?

Answers

Answer:

8.46E+1

Explanation:

From the question given above, the following data were obtained:

Charge 1 (q₁) = 39 C

Charge 2 (q₂) = –53 C

Force (F) of attraction = 26×10⁸ N

Electrical constant K) = 9×10⁹ Nm²/C²

Distance apart (r) =?

The distance between the two charges can be obtained as follow:

F = Kq₁q₂ / r²

26×10⁸ = 9×10⁹ × 39 × 53 / r²

26×10⁸ = 1.8603×10¹³ / r²

Cross multiply

26×10⁸ × r² = 1.8603×10¹³

Divide both side by 26×10⁸

r² = 1.8603×10¹³ / 26×10⁸

r² = 7155

Take the square root of both side

r = √7155

r = 84.6 m

r = 8.46E+1 m

man is walking due east at the rate of of 4kmph and the rain is falling 30° east of vertical with a velocity of 6kmph the velocity of rain relative to the man will be?

Answers

Answer:

No answer

Explanation:

no explanation

What is the acceleration of a car that goes from 0 MS to 60 MS and six seconds

Answers

a = Δv/Δt
a = v2-v1/t2-t1
a = 60MS - 0MS / 6 seconds
a = 60 MS/ 6 seconds
a = 10 m/s^2

pdf
Due date: February 22, 2021
10:00 AM EST
5: Holt SF 05Rev 43 - 10.0 pts possible
A 0.290 kg block on a vertical spring with a
spring constant of 4.65 x 103 N/m is pushed
downward, compressing the spring 0.0500 m.
When released, the block leaves the spring
and travels upward vertically.
The acceleration of gravity is 9.81 m/s.
How high does it rise above the point of
release?
Answer in units of m.
x x

Answers

Mass of block(m)=0.290 kg
Spring Constant k = 4.65×10³ N/m
Initial elongation =0.0500 m=5 cm

Thus Initial Potential Energy stored =Final Potential Energy stored in Block


Pi = kx² / 2

Pi = (4.65×10³) (25×10−⁴) / 2

Pi = 5.81 J

Pf = m g h

Pf = (0.290) (9.81) (h)

Pi = Pf

5.81 = 0.29×9.81×h

h = 2.04 m

If a truck has a mass of 7,692 kg and travels at a speed 51 m/s what is the momentum of the truck

Answers

Answer:

Explanation:

Given the following data;

Velocity = 51 m/s

Mass = 7,692 kg

To find the momentum;

Momentum can be defined as the multiplication (product) of the mass possessed by an object and its velocity. Momentum is considered to be a vector quantity because it has both magnitude and direction.

Mathematically, momentum is given by the formula;

[tex] Momentum = mass * velocity [/tex]

Substituting into the equation, we have;

Momentum = 7692 × 51

Momentum = 392292 Kgm/s

Static Friction
Now let’s examine the static case. Remain on the “Force graphs” tab at the top of the window. Make sure the box labeled “Ffriction” is checked at the left of the screen, this will allow us to measure to force of friction experienced by an object as it slides down the ramp.

Draw a free body diagram for an object sitting on the incline at rest, assuming the incline is at the maximum angle BEFORE the object starts to move. Be sure to include friction and stipulate whether it is kinetic or static. ​

Answers

name the element and explain why it is unusual:
a)A liquid metal
b)A non-metal that conducts electricity

Why is the total solar eclipse important for scientists? explain​

Answers

Answer:

hello

Explanation:

For scientists, they offer a unique opportunity to study aspects of the sun like its corona, the layer of plasma surrounding the star. ... By studying the inner regions of the corona that we can generally only see and photograph well during a total solar eclipse, scientists can learn more about how weather works in space.

have a nice day

hope it helps

byee

Answer:

For scientists,they offer a unique opportunity to study aspects of the sun like it's Corona, the layer of plasma surrounding the star......By studying the inner regions of the Corona that we can generally only see and photograph well during a total solar eclipse, scientists can learn more about how weather works in space

During sexual reproduction, each parent contributes

Answers

Answer:

each parents contributes the dad gives the seed and the mom gives the egg

Explanation:

and then you are born

When driving across Death Valley in the summertime, it is recommended that you release some air from your tires before making the crossing. Using the principles of Kinetic Molecular Theory (KMT), explain why it is a good idea to follow this recommendation.

Answers

According to the ideal gas law, pressure will rise as a gas's temperature rises. There is a limit to how much the tire can expand before the rubber gives in to the pressure build-up.

What the principles of Kinetic Molecular Theory?

For every 10 degrees that the temperature drops, the inflation pressure in tires typically decreases by 1 to 2 psi. Moreover, as the tire pressure heats up during the first 15 to 20 minutes of driving, it will increase by one psi every five minutes.      

The ideal gas law states that pressure will increase as a gas's temperature increases. Before the rubber gives in to the pressure build up, the tire can only expand so far.

Therefore, The pressure in your tires will increase due to the increased particle movement in hot air, which will cause the centre of the tread to bow out and wear out first. Increasing the demand for new tires.

Learn more about Molecular Theory here:

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You and a friend each hold a lump of wet clay. Each lump has a mass of 30 grams. You each toss your lump of clay into the air, where the lumps collide and stick together. Just before the impact, the velocity of one lump was < 3, 3, -3 > m/s, and the velocity of the other lump was < -4, 0, -4 > m/s. What is the velocity of the stuck-together lump just after the collision

Answers

Answer:

[tex]<-0.5, 1.5, -3.5>\ \text{m/s}[/tex]

Explanation:

[tex]u_1[/tex] = Velocity of one lump = [tex]3x+3y-3z[/tex]

[tex]u_2[/tex] = Velocity of the other lump = [tex]-4x+0y-4z[/tex]

m = Mass of each lump = [tex]30\ \text{g}[/tex]

The collision is perfectly inelastic as the lumps stick to each other so we have the relation

[tex]mu_1+mu_2=(m+m)v\\\Rightarrow m(u_1+u_2)=2mv\\\Rightarrow v=\dfrac{u_1+u_2}{2}\\\Rightarrow v=\dfrac{3x+3y-3z-4x+0y-4z}{2}\\\Rightarrow v=-0.5x+1.5y-3.5z=<-0.5, 1.5, -3.5>\ \text{m/s}[/tex]

The velocity of the stuck-together lump just after the collision is [tex]<-0.5, 1.5, -3.5>\ \text{m/s}[/tex].



The lever shown above can be used to move the
bowling ball off the shelf. Pushing down at what
point on the lever would require you to apply the
least amount of force to move the ball?
A. 1
B. 2
C. 3
D. 4

Answers

Answer:

C your answer would be C

Explanation:

It should be right

The monkey experiment is an example of what?

A. top down processing
B. bottom up processing
C. inattentional blindness
D. sensory adaption

Answers

Answer:

D.) Sensory adaptation

Explanation:

Assuming you are talking about the cloth and metal monkey experiment performed in the field of psychology (not physics), the monkey formed an attachment to the cloth mother because it felt closer to it, as it was more appealing to its senses.

A storage tank has the shape of an inverted circular cone with height 12 m and base radius of 4 m. It is filled with water to a height of 10 m. Find the work required to empty the tank by pumping all of the water to the top of the tank. (The density of water is 1000 kg/m3. Assume g

Answers

Answer:

Work required to empty the tank by pumping all of the water to the top of the tank = 1674700 Kgm/s^2

Explanation:

Volume of Circular cone = V = (1/3)πr2h

where r is the radius in meters

and h is the height in meters

Substituting the given values in above equation, we get -

V = [tex]\frac{1}{3} * 3.14 * 4^2 * 10 = 167.47[/tex] cubic  meters.

The force required will be equal to the mass of water in the cone

[tex]= 167.47 * 1000[/tex]

= 167470 Kg

Weight = Mass * g

= 167470 * 10

= 1674700 Kgm/s^2

- .
?



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(っ◔◡◔)っ ♥ chose the answer with the question marks ♥

Answers

Answer:

okay I'm a bit confused but I like the little emoji dudw

Answer:

?

Explanation:

.

The torque required to turn the crank on an ice cream maker is 4.50 Nm. How much work does it take to turn the crank through 300 full turns?
A) 4240 J
B) 8480 J
C) 2120 J
D) 1350 J
E) 2700 J

Answers

Answer:

B) 8480 J

Explanation:

From the question,

The work required to turn the Crank in on turn is

W = 2πT................ Equation 1

Where W = work, T = torque.

Given: T = 4.50 Nm, π = 3.14

Substitute into equation 1

W = 4.5(2)(3.14)

W = 28.26 J per turn.

For 300 full tern,

W = 28.26×300

W = 8476 J

Hence,

W≈ 8480 J.

The right answer is B) 8480 J

Mr. Voytko wants to know how high in meters he can lift an 0.3 kg apple with 7.35 joules?

Answers

Answer:

the height above the ground through Mr. Voytko lifted the apple is 2.5 m.

Explanation:

Given;

energy of Mr. Voytko, E = 7.35 J

mass of the apple, m = 0.3 kg

Apply the principle of conservation of energy.

Energy of Mr. Voytko = Potential energy of the apple due to its height above the ground.

E = mgh

where;

h is the height above the ground through Mr. Voytko lifted the apple.

g is acceleration due to gravity = 9.8 m/s²

h = E / (mg)

h = 7.35 / (0.3 x 9.8)

h = 2.5 m

Therefore, the height above the ground through Mr. Voytko lifted the apple is 2.5 m.

Two charges, one +Q and the other −Q, are held a distance d apart. Consider only points on the line passing through both charges and clearly explain your answers to the following: [You can answer this problem without any calculations]. Do not consider any points at infinite distance from the charges. [5 points](a) Find the location of all points, if any, where the electric potential is zero.(b) Find the location of all points, if any, where the electric field is zero.

Answers

Answer:

a. d/2 mid-way between the charges.

b. d/2 mid-way between the charges.

Explanation:

(a) Find the location of all points, if any, where the electric potential is zero.

Since the charges are of equal magnitude and opposite charge and separated by a distance, d, the electric potential due to the +Q charge is V = kQ/x and that due to the -Q charge is V' = -kQ/(d - x) where x is the point of zero electric potential.

The potential is zero when  V + V' = 0, and this can only be midway between the charges. This is shown below

So, kQ/x + [-kQ/(d - x)] = 0

kQ/x - kQ/(d - x) = 0

kQ/x = kQ/(d - x)

1/x = 1/(d - x)

(d - x) = x

d = x + x

d = 2x

x = d/2 which is mid-way between the charges.

(b) Find the location of all points, if any, where the electric field is zero.

Since the charges are of equal magnitude and opposite charge and separated by a distance, d, the electric field due to the +Q charge is E = kQ/x² and that due to the -Q charge is E' = -kQ/(d - x)² where x is the point of zero electric field.

The electric field is zero when  E + E' = 0 and this can only be midway between the charges. This is shown below.

So, kQ/x² + [-kQ/(d - x)²] = 0

kQ/x² - kQ/(d - x)² = 0

kQ/x² = kQ/(d - x)²

1/x² = 1/(d - x)²

(d - x)² = x²

d - x = ± x

d = x ± x

d = x - x or x + x

d = 0 or 2x

d = 0 or d = 2x

Since d ≠ 0, d = 2x ⇒ x = d/2 which is midway between the charges.

.................,,,,,,,,,,,

Answers

Answer:

B

Explanation:

Motion is movement, the teacher's movement is motion

unpolarized light of intensity Io is incident on an ideal linear polariser (no absorption) . what is the transmitted intensity?​

Answers

Answer:

A Polarizing sheet transmits only the component of light polarized along a particular direction and absorbs the component perpendicular to that direction.

Consider a light beam in the z direction incident on a Polaroid which has its transmission axis in the y direction. On the average, half of the incident light has its polarization axis in the y direction and half in the x direction. Thus half the intensity is transmitted,and the transmitted light is linearly polarized in the y direction.

Suppose the particle is placed at the 40V equipotential surface along the line connecting the two central positive and negative charges.
(Hint: The electric field can be obtained using the 40V and 30V potential difference lines.)

1. What is the force on the charged particle if q=80μC? (mN) (m-milli 10-3)

2. What is the force on the charged particle if it is now located at the 0V potential difference line? (mN)

Answers

Answer:

Hello some part of your question is missing below is the missing part

2.  What is the force on the charged particle if it is now located at the 0V potential difference line? (mN) (hint: The electric field can be obtained as above using the 0V and -10V equipotential lines.)

answer :

1) 0.8 mN

2) 0.8 mN

Explanation:

Given data:

1) Calculate the force on the charged particle

q = 80 μC , Va = 30v , Vb = 40v, ∝ = 1 m

E = ( Δv ) / ∝

   = ( Vb - Va ) / ∝

F = qE

  = 80 μC * ( 40 - 30 ) / 1 m

  = 800 μC

F = 0.8 mN

2) Calculate the force on the charged particle when it is located at 0V

Va = -10V , Vb = 0V, q = 80 μC,  ∝ = 1 m

F = qE

   where E = ( 0 - ( -10 ) / 1  

F = 80 μC *  ( 0 - ( -10 ) / 1

  = 800 μC = 0.8 mN

Which pair of labels is correct? A: Maximum kinetic energy C: Maximum gravitational potential energy B: Maximum kinetic energy D: Maximum gravitational potential energy A: Maximum gravitational potential energy C: Maximum kinetic energy B: Maximum gravitational potential energy D: Maximum kinetic energy

Answers

Maximum kinetic enerygy

Answer: C. A:Maximum gravitational potential energy C: Maximum kinetic energy

Explanation:

Jeni walks 100 meters east and then 50 meters north. How big is Jeni's displacement from the starting point?
a. 100 meters
b. 150 meters
c. 50 meters
d. About 112 meters

Answers

Answer:

d. About 112 meters.

Explanation:

From the question, John's displacement forms a right angle triangle as below.

Using Pythagoras theorem,

a² = b²+c²....................... Equation 1

Where a = John's displacement from the starting point, b = 100 m, c = 50 m

Substitite these values into equation 1

a² = 100²+50²

a² = 10000+2500

a² = 12500

a = √12500

a = 111.8 meters.

a = about 112 meters.

The right answer is d. About 112 meters.

A ball is thrown straight up into the air. Which of the following best describes the energy present at various stages?
There is more energy at the top of the ball's path than there is at the bottom.
The total amount of energy varies, with more energy at the bottom and less at the top of the path.
At the very top, most of the energy is potential and just before it hits the ground, most of the energy is kinetic.
At the very top, most of the energy is kinetic and just before it hits the ground, most of the energy is potential.

Answers

Answer:

Uhh 2 one

Explanation

Integrate your expressions for dEx and dEy from θ=0 to θ=π. The results will be the x-component and y-component of the electric field at P

.

Express your answers separated by a comma in terms of some, all, or none of the variables Q

and a and the constants k and π.

Answers

Answer:

hello your question is incomplete below is the missing part

Ex = 0

Ey = [tex]\frac{-2kQ}{\pi a^2}[/tex]

Explanation:

Attached below is a detailed solution showing the integration of the expression dEx and dEy from ∅ = 0 to ∅ =π

Ex = 0

Ey = [tex]\frac{-2kQ}{\pi a^2}[/tex]

How much energy is required to move 2 electrons through a potential difference of 1.0 x 10^ 2 volts?

Answers

charge of electron = 1.6×10−¹⁹

(1.6×10−¹⁹)(1×10²) (2e)

= 3.2×10−¹⁷ J

The energy required to move 2 electrons through a potential difference of 1.0 x 10² volts is -3.2 x 10⁻¹⁷ joules.

What is the potential difference?

The potential difference, also known as voltage, is the difference in electrical potential energy per unit of charge between two points in an electrical circuit or an electric field.

In simpler terms, the potential difference is the amount of energy required to move a unit of electric charge from one point to another in an electric field or an electrical circuit. It is measured in volts (V) and can be calculated using the equation:

V = W/Q

Where V = is the potential difference,

W =  is the work done in moving the charge Q from one point to another,

Q =is the amount of charge that is moved.

Potential difference is an essential concept in electrical engineering and physics, as it governs the flow of electric current in a circuit and determines the behavior of electrical devices such as resistors, capacitors, and batteries.

Here in this question,

The energy required to move an electron through a potential difference is given by the formula:

E = qV

Where

E = is the energy required,

q = is the charge of the electron,

V = is the potential difference.

The charge of one electron is -1.6 x 10⁻¹⁹coulombs.

Therefore, for two electrons, the total charge is:

q = 2 x (-1.6 x 10⁻¹⁹coulombs) = -3.2 x 10⁻¹⁹ coulombs

The potential difference is given as 1.0 x 10² volts.

Now, the energy required to move 2 electrons through a potential difference of 1.0 x 10² volts is:

E = (-3.2 x 10⁻¹⁹ coulombs) x (1.0 x 10² volts) = -3.2 x 10⁻¹⁷ joules.

Note: that the negative sign indicates that the electrons lose potential energy as they move through the potential difference.

Therefore, The required energy is -3.2 x 10⁻¹⁷ joules.

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An object is dropped from a bridge. A second object is thrown downwards 1.0 s later. They both reach the water 20 m below at the same instant. What was the initial speed of the second object? Neglect air resistance.

Answers

Answer:

Explanation:
Kinematics equation for first Object:

but:
The initial velocity is zero

it reach the water at in instant, t1, y(t)=0:


Kinematics equation for the second Object:
The initial velocity is zero

but:

it reach the water at in instant, t2, y(t)=0. If the second object is thrown 1s later, t2=t1-1=1.02s


The velocity is negative, because the object is thrown downwards
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