What is the
mass
density
of an object of
equal to 100 grams and volume of 20 cubic
centimeter​

Answer:

Virtual

Explanation:

Answer:

B. Virtual

Good Luck!

Answer:

Explanation:

The answer is c. I am very sure

Answer:

i think its b

Explanation:

im not very sure

Answer:

the focal length of the eyepiece is 17.23 cm

Explanation:

The computation of the focal length of the eyepiece is shown below:

= Focal length of objective lens ÷ angular magnification magnitude

= 86.3 ÷ -5.01

= 17.23 cm

Hence, the focal length of the eyepiece is 17.23 cm

We simply divided the angular magnification magnitude from the focal length of objective lens so that the focal length of the eyepiece could come

Answer:

a = 640 m/s²

Explanation:

From work-kinetic energy principles,

The net force acting on the second object is the gravitational force and the electric force due to the first object.

So, the gravitational force on the mass is F₁ = Gm₁m₂/r² since m₁ = m₂ = m, U = -Gm²/r²

Also, the electric force on the charge is F₂ = kq₁q₂/r² since q₁ = q₂ = q, U = kq²/r²

The net Force F = ma

So, -F₁ + F₂ = F     (F₁ is negative since it is an attractive force in the negative x -direction and F₂ is positive since it is a repulsive force in the positive x- direction)

-Gm²/r² + kq²/r² = ma

ma = -Gm²/r² + kq²/r²

a = (-Gm²/r² + kq²/r²)/m

a = (-G + kq²/m²)m/r²

Since m = 0.250 kg, q = 4.00 μC = 4.00 × 10⁻⁶ C, r = 3.00 cm = 3.00 × 10⁻² m, G = 6.67 × 10⁻¹¹ Nm²/kg², k = 9 × 10⁹ Nm²/C² and a = acceleration of second mass.

Substituting the variables into the equation, we have

a = (m/r²)(-G + k(q/m)²)]

a = (0.250 kg/{3.00 × 10⁻² m}²)(-6.67 × 10⁻¹¹ Nm²/kg² + 9 × 10⁹ Nm²/C²(4.00 × 10⁻⁶ C/0.250 kg)²)

a = (0.250 kg/9.00 × 10⁻⁴ m)(-6.67 × 10⁻¹¹ Nm²/kg² + 9 × 10⁹ Nm²/C²(16 × 10⁻⁶ C/kg)²)]

a = (0.250 kg/9.00 × 10⁻⁴ m)(-6.67 × 10⁻¹¹ Nm²/kg² + 9 × 10⁹ Nm²/C²(256 × 10⁻¹² C²/kg²)]

a = (0.250 kg/9.00 × 10⁻⁴ m)(-6.67 × 10⁻¹¹ Nm²/kg² + 2304 × 10⁻³ Nm²/kg²  ]

a = (0.250 kg/9.00 × 10⁻⁴ m)(2.304 Nm²/kg²)

a = 0.576 Nm²/kg /9.00 × 10⁻⁴ m²

a = 0.064 × 10⁴N/kg

a = 64 × 10 N/kg)

a = 640 m/s²

Answer:

The potential difference between the ends of a wire is 60 volts.

Explanation:

It is given that,

Resistance, R = 5 ohms

Charge, q = 720 C

Time, t = 1 min = 60 s

We know that the charge flowing per unit charge is called current in the circuit. It is given by :

I = 12 A

Let V is the potential difference between the ends of a wire. It can be calculated using Ohm's law as :

V = IR

V = 60 Volts

So, the potential difference between the ends of a wire is 60 volts. Hence, this is the required solution.

The unit called horsepower is defined based on the amount of work a horse can do in 1 minute.

James Watt used the horsepower unit for the first time in 1782. According to the account, James Watt used a pony to charge coal from the mines. According to the narrative, he needed a unit to measure the force of one of these animals.

He discovers that they can move 22.000 lbs per minute and decides to (arbitrarily) boost this metric by 50%. Having been the unit 33.000 lb/ft per minute, horsepower is an engine's output horsepower rating, whereas brake horsepower is an engine's input brake horsepower.

Brake horsepower measures an engine's power without accounting for power losses, whereas HP accounts for power losses. Horsepower of the brakes

Therefore, the horsepower unit is defined by the amount of work a horse can do in one minute.

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Answer:

fffffgggggggggggggghhh

Answer:

are nearby and bright i hope this helps

Answer:

Friction.

Explanation:

Answer:

Not all appliances run on energy. Some of them run on gas. Some both. It just depends on the age of the appliance, the make of the appliance, and the company who made it.

Answer:

"13.48 Kwhr" is the right solution.

Explanation:

The given values are:

Average rate of heat energy,

= 0.063 W/m²

Diameter,

= 8m

Efficiency of conversion,

= 50%

Now,

The area of hotspot will be:

⇒  [tex]A=\frac{\pi}{4} d^2[/tex]

On substituting the values, we get

⇒      [tex]=\frac{3.14}{4} (8)^2[/tex]

⇒      [tex]=0.785\times 64[/tex]

⇒      [tex]=50.24 \ m^2[/tex]

Total heat generation rate will be:

⇒  [tex]Q=q\times A[/tex]

        [tex]=0.063\times 50.24[/tex]

        [tex]=3.16 \ W[/tex]

hence,

The electricity generation capacity will be:

⇒  [tex]P=\eta Q t[/tex]

On substituting the values, we get

⇒      [tex]=0.5\times 3.16\times 8760[/tex]

⇒      [tex]=13840.8 \ Whr[/tex]

On converting into Kwhr, we get

⇒      [tex]=13.84 \ Kwhr[/tex]

Answer:

Homogeneous mixtures

Explanation:

I think so because homogeneous means mixed mixtures

This question is incomplete, the complete question is;

The entropy of an ?-ideal gas changes in the following way as a function of temperature and volume:

ΔS = nRln(V[tex]_f[/tex]/V[tex]_i[/tex]) + ∝nRln(T[tex]_f[/tex]/T[tex]_i[/tex])

For an adiabatic process, the change in T is determined by the change in V. In this problem you will compute the contributions to S from the V and T terms separately, then add them up to find the total entropy change for an adiabatic process.

Argon gas, initially at pressure 100 kPa and temperature 300 K, is allowed to expand adiabatically from 0.01 m³ to 0.026 m³ while doing work on a piston.

1) What is the change in entropy due to the volume change alone, ignoring any effects of changing internal energy? ΔS = ? J/K

2) For this adiabatic expansion, what is the final temperature?  T[tex]_f[/tex] =  ? K

Answer:

1) the change in entropy due to the volume change alone, ignoring any effects of changing internal energy is 3.185 J/K.

2) the final temperature is 158.66 K

Explanation:

Given the data in the question;

ΔS = nRln(V[tex]_f[/tex]/V[tex]_i[/tex]) + ∝nRln(T[tex]_f[/tex]/T[tex]_i[/tex])

P[tex]_i[/tex] = 100 kPa = 100000 Pa

V[tex]_i[/tex] = 0.01 m³

V[tex]_f[/tex] = 0.026 m³

T[tex]_i[/tex] = 300 K

1)  the change in entropy due to the volume change alone

from the question; ΔS = nRln(V[tex]_f[/tex]/V[tex]_i[/tex]) + ∝nRln(T[tex]_f[/tex]/T[tex]_i[/tex])

so change in entropy due to the volume change alone is;

ΔS = nRln(V[tex]_f[/tex]/V[tex]_i[/tex])

we know that, from ideal gas law; PV = nRT

so, nR = P[tex]_i[/tex]V[tex]_i[/tex]/T[tex]_i[/tex]  ---- let this be equation 1

∴ ΔS = P[tex]_i[/tex]V[tex]_i[/tex]/T[tex]_i[/tex] × ln(V[tex]_f[/tex]/V[tex]_i[/tex])

we substitute

ΔS = [( 100000 Pa ×  0.01 m³) / 300 K ] × ln(0.026m³ / 0.01m³ )

ΔS = 3.185 J/K  

Therefore, the change in entropy due to the volume change alone, ignoring any effects of changing internal energy is 3.185 J/K.

2)  Final temperature

we know that, in an adiabatic expansion;

[tex]PV^Y[/tex] = K

where Y = 5/3

so

[tex]P_i[/tex][tex]V_i^{(5/3)[/tex] = [tex]P_f[/tex][tex]V_f^{(5/3)[/tex]

[tex]P_f[/tex] = [tex]P_i[/tex][tex]( \frac{V_i}{V_f})^{(5/3)[/tex]

we substitute

[tex]P_f[/tex] = ( 100000 Pa) [tex]( \frac{0.01 m^3}{0.026 m^3})^{(5/3)[/tex]

[tex]P_f[/tex] = 20341.255 Pa

Also from ideal gas law;

PV = nRT

T = PV / nR

so

T[tex]_f[/tex] = P[tex]_f[/tex]V[tex]_f[/tex] / nR

but from equation 1; nR = PV/T

so

T[tex]_f[/tex] = (P[tex]_f[/tex]V[tex]_f[/tex]) / (P[tex]_i[/tex]V[tex]_i[/tex]/T[tex]_i[/tex] )

T[tex]_f[/tex] = ( P[tex]_f[/tex]V[tex]_f[/tex]T[tex]_i[/tex] / P[tex]_i[/tex]V[tex]_i[/tex] )

we substitute

T[tex]_f[/tex] = ( 20341.255 Pa × 0.026 m³ ×  300 K) / 100000 Pa × 0.01 m³ )

T[tex]_f[/tex] = 158.66 K

Therefore, the final temperature is 158.66 K

Answer:

A fundamental theory that provides a description of the physical properties of nature at the scale of atoms and subatomic particles.

Explanation:

Answer:

a.It is bulb A

b.They will have less light, because they are in series

c.It will have more light because all tge current will flow to one bulb which is A

a)Light bulb A will be brightest.

b)Because they are connected, they will have less light if light bulb A is removed.

c)Bulb A and B will light more. If light bulb C is removed.

An electric bulb is a gadget that uses electricity to create visible light. It is the most popular type of artificial lighting and is necessary for modern society.

When one bulb in a series circuit burns, out, the rest of the bulbs will light. Hence, the following result is obtained;

a)Light bulb A will be brightest.

b)Because they are connected, they will have less light if light bulb A is removed.

c)Bulb A and B will light more. If light bulb C is removed.

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Answer:

manage your weight better, have stronger bones, have lower blood pressure, less risk of a heart attack, etc.

Answer:

You become healthier, your body starts regulating better, you get stronger bones and muscles, and you lower the risk of diabetes,heart problems and other diseases.

The amount of heat absorbed by the water will be 8368 J.

Heat gain is defined as the amount of heat required to increase the temperature of a substance by some degree of Celsius. While heat loss is inverse to heat gain.

It is given by the formula as ;

[tex]\rm Q= mcdt[/tex]

The given data in the problem is;

Equilibrium temperature = 30°C.

mass of water  = 50 g  ,

Temperature change = 70ºC

The specific heat of water =4.184 J//g °C

The amount of heat absorbed by the water is;

[tex]\rm Q= mcdt \\\\ Q=50 \times 4.184 \times (70^0 -30^0)C\\\\ Q= 8368 J[/tex]

Hence, the amount of heat absorbed by the water will be 8368 J.

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Answer:

the correct answue are  B, A, C, C, B

Explanation:

1) The electric field is requested, let's approximate the membrane by a parallel plate with surface charge density

         E = [tex]\frac{\sigma }{2 \epsilon_o }[/tex]

         E = [tex]\frac{ 10^{-5}}{2 \ 8.85 \ 10^{-12}}[/tex]

         E = 5.65 10⁵ N / C

the correct answer is B

2) A calcium ion has two positive charges, so the force applied by each side of the membrane (plate)

         F = q E

         F = 2  1.6 10⁻¹⁹  5.65 10⁵

         F = 1.8 10⁻¹³ N

the total force is the sum of the force of each membrane and the two forces go to the same side

         F = total = 2 F

         F_total = 3.6 10⁻¹³ N

the correct answer is A

3) the field and the electric potential are related

          ΔV = - E s

          ΔV = - 5.65 10⁵  10 10⁻⁹

          ΔV = - 5.65 10⁻³ V

          the correct answer is C

4) In the exercise they indicate that the outer wall has a positive charge, therefore, as they indicate that we approximate the system to a capacitor, the inner wall must be negatively charged.

The electric field goes from the positive to the negative charge, which is why it goes from the outer wall to the inner wall

the correct answer is C

5) For this part we use conservation of energy

starting point. On the inside wall, brown

            Em₀ = U = qV

final point. On the outside

             Em_f = K

energy is conserved

           Em₀ = Em_f

           q V = K

            K = 3 10⁻¹⁵  5.65 10⁻³

            K = 1.7 10⁻¹⁷ J

the correct answer is B

Answer:

(A) The total resistance of the circuit is 25 Ω

(B) The current through each resistor is 4.4 A

(C) For 10Ω: Potential drop = 44 V

     For 15Ω: Potential drop = 66 V

Explanation:

Given;

potential difference, V = 110V

resistors in series, = 10Ω and a 15Ω

(A) The total resistance of the circuit is calculated as follows;

Rt = 10Ω + 15Ω = 25Ω

(B) The current through each resistor;

Same current will flow through the two resistors since they are in series.

I = V/Rt

I = 110 / 25

I = 4.4 A

(C) The voltage drop across each resistor;

For 10Ω: Potential drop = IR₁ = 4.4 x 10 = 44 V

For 15Ω: Potential drop = IR₂ = 4.4 x 15 = 66 V

Answer:

Yes, the value will be the same.

Explanation:

Yes, or at least to some degree, that value of K will remain the same. You're looking for a difference in absorbance, and the difference should be visible at all wavelengths, not only at the limit. That being said, resolution varies, and if we don't read the value to the maximum, we can get a less accurate reading.

Answer:

[tex]-180.38\ \text{N}[/tex]

Explanation:

[tex]q_1=-53\ \mu\text{C}[/tex]

[tex]q_2=105\ \mu\text{C}[/tex]

[tex]q_3=-88\ \mu\text{C}[/tex]

r = Distance between the charges

[tex]r_{12}=0.5\ \text{m}[/tex]

[tex]r_{23}=0.95\ \text{m}[/tex]

[tex]r_{13}=1.45\ \text{m}[/tex]

k = Coulomb constant = [tex]9\times 10^9\ \text{Nm}^2/\text{C}^2[/tex]

Net force is given by

[tex]F=F_{12}+F_{13}\\\Rightarrow F=\dfrac{kq_1q_2}{r_{12}^2}+\dfrac{kq_1q_3}{r_{13}^2}\\\Rightarrow F=kq_1(\dfrac{q_2}{r_{12}^2}+\dfrac{q_3}{r_{13}^2})\\\Rightarrow F=9\times 10^9\times (-53\times 10^{-6})(\dfrac{105\times 10^{-6}}{0.5^2}+\dfrac{-88\times 10^{-6}}{1.45^2})\\\Rightarrow F=-180.38\ \text{N}[/tex]

The force on the particle [tex]q_1[/tex] is [tex]-180.38\ \text{N}[/tex].

Answer:

The answer sir would be 180.38

Explanation:

Put in 180.38 trust

Answer:

the distance is 315.3696 m

Explanation:

The computation of the distance is given below:

Given that

Sound intensity = 1.67 × 10^-6 W/m^2

And, the distance = 233 m

Now as we know that

Power = Intensity × surface area

1.67 × 10^-6 × 4π(233)^2 = 1.67 × 10^-6 ÷ 2× 4π × d^2

d^2 = 2 × (223)^2

= √2 × 223

= 315.3696 m

Hence, the distance is 315.3696 m

Answer:

correct answer is A

Explanation:

The diagram shows a series circuit with three resistors and two power sources.

In a series circuit the current through the entire circuit is constant and the resistance is the sum of the resistances in the circuit.

When the power sources are placed in opposite position the voltage between them is subtracted.

     V_b - 30 = I (10 + 4 + 6)

     V_b = I (20) - 30

      V_b = 30 - 2 20

       V_b = 10 V

the correct answer is A

Answer:

Nuclear fusion

Explanation:

This is because main sequence of star is powered by fusion of hydrogen to helium atoms together and this process releases energy. The energy released when the gas collapse into a protostar make the center of the protostar to be extremely hot. When the core becomes very hot, nuclear fusion can start.

Answer:

[tex]P=7.35\times 10^{3}\ W[/tex]

Explanation:

Given that,

Mass, [tex]m=1.5\times 10^2\ kg[/tex]

It lifts to a height of 15 m in 3 s

We need to find the power of the motor. The formula for power is given by :

[tex]P=\dfrac{W}{t}\\\\P=\dfrac{mgh}{t}\\\\P=\dfrac{1.5\times 10^2\times 9.8\times 15}{3}\\\\P=7.35\times 10^{3}\ W[/tex]

So, the power of the motor is equal to [tex]7.35\times 10^{3}\ W[/tex].

Answer:

The units of kinetic energy are mass times the square of speed, or kg⋅m2/s2 kg ⋅ m 2 /s 2. But the units of force are mass times acceleration, kg⋅m/s2 kg ⋅ m/s 2, so the units of kinetic energy are also the units of force times distance, which are the units of work

Explanation:

EDGE 2021