Answer:
441 N
Explanation:
weight = mass x gravity
w = m x g.
We know that gravity = 9.8 m/s^2 and mass = 45 kg.
w = 45 kg x 9.8 m/s^2
w = 441 N
So the weight of the object is 441 N (newtons).
Answer:441 N.
Explanation:
The weight of 45 kg at rest on the surface of the Earth is about 45 * 9.8 N = 441 N.
a transformer with an input emf of 240volts and output of 960volts has 720 turns in the secondary coil. what is the number of coil in the primary coil?
Answer:
180 turns
Explanation:
Given data
Vi= 240 volts
Vo= 960volts
Ns= 720 turns
Required
The amount of Primary turns Np
The expression relating voltage and turns in a transformer is given as
Np/Ns= Vi/Vo
substitute
Np/720= 240/960
cross multiply
720*240= Np*960
172800= Np*960
Np= 172800/960
Np= 180
Hence the primary turns is 180 turns
A team of scientists is researching the best way to use tides to produce energy. One team includes environmental
scientists.
Which other branch of Earth science would these scientists most likely represent?
-geology
-astronomy
-meteorology
-oceanography
Answer:
agree with above answer
1 point) One of Kepler's three laws of planetary motion states that the square of the period, P, of a body orbiting the sun is proportional to the cube of its average distance, d, from the sun. The Earth has a period of 365 days and its distance from the sun is approximately 93,000,000 miles. (a) Find P as a function of d. P(d)
Answer:
P = √1.66 * 10^-19 days^2miles^-3d^3
Explanation:
The mathematical statement of Kepler's third law is;
P^2 α d^3
Where;
P = Period of the body orbiting the sun
d = its average distance from the sun
Introducing a constant of proportionality K, known as Kepler's constant then;
P^2 = Kd^3
K = P^2/d^3
P=365 days
d = 93,000,000 miles
K = (365)^2/(93,000,000)^3
K=1.66 * 10^-19 days^2miles^-3
P = √1.66 * 10^-19 days^2miles^-3d^3
A 800-w iron is left on the ironing board with the base exposed to the air. About 85 percent of the heat generated by iron dissipate through its base with surface area of 0.15 ft2 . Calculate the amount of heat the iron dissipates in 2 hours, the heat flux on the surface of iron and total cost of electricity wasted in 2 hours if unit cost of electricity to be $0.11kwh.
Answer:
ΔQ = 4896 KJ
Heat Flux = 57407.55 W/m²
Cost = $ 0.176
Explanation:
The amount of heat dissipated in two hours can be given as:
[tex]Heat\ Dissipation = \Delta Q = Pt\eta[/tex]
where,
P = Power of Iron = 800 W
t = time taken = 2 hrs
η = Conversion efficiency = 85% = 0.85
[tex]\Delta Q = (800\ W)(7200\ s)(0.85)\\\\[/tex]
ΔQ = 4896 KJ
Now, for heat flux:
[tex]Heat\ Flux = \frac{P}{Surface\ Area}\\\\Heat\ Flux = \frac{800\ W}{0.15\ ft^{2}}\frac{1\ ft^{2}}{0.092903\ m^{2}}[/tex]
Heat Flux = 57407.55 W/m²
Now, for total heat energy in KWhr in two hours:
[tex]Heat\ Energy = (Power)(Time)\\\\Heat\ Energy = (0.8\ KW)(2\ hr)\\\\Heat\ Energy = 1.6\ KWh[/tex]
Now, for the cost:
[tex]Cost = (Heat\ Energy)(Unit\ Cost)\\Cost = (1.6\ KWh)(\$ 0.11\ /KWh)[/tex]
Cost = $ 0.176
can someone help me :(
Answer:
1. This is a speed graph.
2. The slope represents how much the item/ thing is moving at how much distance it moved and the minutes it takes it too move how much distance, but the slope is representing the decrease and increase of it.
3. Increasing, kind of rapidly going up since the slope is rising not falling.
An fm radio station broadcast electromagnetic waves at a frequency of 94.5 MHz(9.45x10^7 Hz) these radio waves have a wavelength of 3.17 m. What is the speed of the waves?
Answer:
94,5 x 3,17 = 299,565 m/s
Explanation:
To find the speed of waves (V), you just need to multiply wavelength with frequency. That's all.
The speed of the given electromagnetic waves is equal to 3 × 10⁸ m/s.
What are frequency and wavelength?The frequency can be described as the number of oscillations of a wave in 1 second. The S.I. units of the frequency can be represented as per second or hertz.
The wavelength can be described as the distance between the two points in phase on the wave w.r.t. each other. The separation between two crests or two troughs on a wave is known as wavelength.
The relation between the wavelength (λ) of the wave, frequency (ν), and speed of the wave (V) can be written as:
V = νλ
Given, the frequency of the wave, ν = 94.5 MHz = 94.5 ×10⁶ s⁻¹
The wavelength of the waves, λ = 3.17 m
The speed of the waves can determine from the above-mentioned relationship:
V = λν = 3.17 × 94.5 ×10⁶ = 3 × 10⁸ m/s
Therefore, the speed of the wave is equal to 3 × 10⁸ m.
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Can anyone help me with the Wet Lab Guide - Coulomb's Law report? I'm really having trouble with it. I have attached the worksheet
Answer:
Coulomb's law of Electrostatic Force states that a charged particle attracts or repels other charged particles with a force which is directly proportional to the product of their charges and inversely proportional to the square of the distance between their centers.
Explanation:
What is the IMA of an inclined plane that is 5m long and 2m high?
A. 0.4
B. 2.5
C. 0.4m
D. 2.5m
Answer:
B. 2.5
not 2.5m because IMA is unitless.
The identical mechanical advantage of the inclined plane is 2.5.
What is mechanical advantage of inclined plane ?The concept of work, which asserts that work produced through a basic machine (the lever) is equal to the work input, forms the basis for the mechanical advantage of the inclined plane. The length of the slope divided by the height of the inclined plane represents the inclined plane's mechanical advantage.
Given parameters:
Length of the inclined plane; d = 5 m.
Height of the inclined plane; h = 2 m.
So, identical mechanical advantage (IMA) of the inclined plane is = Length of the inclined plane ÷ Height of the inclined plane
= 5 m/2 m
= 2.5.
Hence, the identical mechanical advantage (IMA) of an inclined plane that is 5m long and 2m high is 2.5.
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What distance will a car cover while uniformly accelerating from 12 m/s to 26 m/s in 14 seconds?
Answer:
266 m
Explanation:
Two sprinters A and B of mass 70kg ad 55kg respectively are running with the
same speed in the same direction. Which of the following is NOT true?
1) A has a greater Kinetic energy
Greater force is needed to stop A
The momentum of A is greater than B
iv)
B will finish the race before A
V B has greater kinetic energy
A. ii) and iv) only B. v) only C. iii), iv )and v) only D. iv) and v) only
5 points
A ball is thrown upward from y=0, with an initial velocity vo and then slows down with constant acceleration due to
the Earth's gravity. The ball comes to rest at a height h. Which one of the following formulas correctly states the
distance, h, to the top of the trajectory in terms of the initial velocity?
Answer:
[tex] \frac{{v}^{2} g}{2 } [/tex]
If a large number of waves pass by a certain point in a given time, the waves have a low frequency. none of the above. a high frequency. it doesn't affect frequency.
Answer:
Another term used to describe a wave is frequency. Since waves are moving, we define frequency as the number of waves that pass a given point in a specified unit of time. The unit commonly used is Hertz which is the number of wave cycles pass a point in one second. So one cycle per second equals one Hertz
You are standing on a street corner with your friend. You then travel 14.0 m due west across the street and into your apartment building. You travel in the elevator 22.0 m upward to your floor, walk 12.0 m north to the door of your apartment, and then walk 6.0 m due east to your balcony that overlooks the street. Your friend is standing where you left her.
Now how far are you from your friend?
Express your answer with the appropriate units.
Answer:
Explanation:
We shall express each displacement vectorially , i for each unit displacement towards east , j for northward displacement and k for vertical displacement .
14 m due west = - 14 i
22.0 m upward in the elevator = 22 k
12 m north = 12 j
6.00 m east = 6 i
Total displacement = - 14 i + 22 k + 12 j + 6 i
D = - 8 i + 12 j + 22 k
magnitude = √ ( 8² + 12² + 22² )
= √ ( 64 + 144 + 484 )
= √ 692
= 26.3 m
Net displacement from starting point = 26.3 m .
Suppose that 6 J of work is needed to stretch a spring from its natural length of 28 cm to a length of 43 cm. (a) How much work is needed to stretch the spring from 33 cm to 38 cm
Answer:
Workdone = 0.67 Joules
Explanation:
Given the following data;
Workdone = 6J
Extension = 43 - 28 = 15cm to meters = 15/100 = 0.15m
The workdone to stretch a string is given by the formula;
Workdone = ½ke²
Where;
k is the constant of elasticity.
e is the extension of the string.
We would solve for string constant, k;
6 = ½*k*0.15²
6 = ½*k*0.0225
Cross-multiplying, we have;
12 = 0.0225k
k = 12/0.0225
k = 533.33N/m
a. To find the workdone when e = 33, 38.
Extension = 38 - 33 = 5 to meters = 5/100 = 0.05m
Workdone = ½*533.33*0.05²
Workdone = 266.67 * 0.0025
Workdone = 0.67 Joules
Therefore, the amount of work (in J) needed to stretch the spring from 33 cm to 38 cm is 0.67.
Different satellites orbit the earth with a vast range of altitudes, from just a couple hundred km, all the way to tens of thousands of km above the surface. The international space station (ISS) is in a low earth orbit, just 400km above the surface (you can see it with the naked eye at sunset and sunrise as a bright, moving dot). At this altitude, the acceleration due to gravity has a value of 8.69m/s Assuming that the radius of the earth is 6400km).
1. What is the speed of the ISS? Express your answer to three significant figures and include the appropriate units.
2. What is the orbital period (T) of the ISS in minutes?
Answer:
a) v = 7.69 10³ m / s, b) T = 92.6 min
Explanation:
a) For this exercise we use the centripetal acceleration ratio, which in itself assumes a circular orbit, is equal to the acceleration of gravity
a = v² / r
v = [tex]\sqrt{a r}[/tex]
the distance to the ISS is
r = R_earth + d
r = 6400 10³ + 400 10³
r = 6800 10³ m
we calculate
v = [tex]\sqrt{8.69 \ 6800 \ 10^3}[/tex]Ra (8.69 6800 103)
v = [tex]\sqrt{59.09 \ 10^6}[/tex]
v = 7.687 10³ m / s
the result with the correct significant figures
v = 7.69 10³ m / s
b) The speed of the ISS is constant, so we can use the uniform motion relationships
v = d / t
if distance is the orbit distance
d = 2π r
time is called period
v = 2π r / T
T = 2π r / v
let's calculate
T = 2π 6800 10³ /7,687 10³
T = 5.558 10³ s
let's reduce the period to minutes
T = 5.558 10³ s (1 min / 60s)
T = 9.26 10¹ min
T = 92.6 min
Water boils to power a steam engine. Which statement best describes the changes in the water as it boils?
Option B
kskmsnsnsmjsjsn
Answer:
C. The potential energy of the particles increases as the intermolecular forces are overcome
Explanation:
Explain how to identify a starting position on a line.
Answer:
We can easily find out the beginning point of the line by using dot representation. When it comes to position vector, it expresses the exact position of certain object from the starting point of the coordinate system. The vector is a straight line that has a certain end which is fixed to its body.
Position vectors are used to determine the starting position of a line with reference to the origin or starting point of the coordinate system
Position vectors start at the origin and terminate at any arbitrary point.
In terms of position of a line, position vectors depict the exact position of a line from the starting point of the coordinate system.
In terms of direction of the line, the direction of the position vector points from the starting point of the coordinate system towards the given point.
Thus, we can conclude that position vectors are used to determine the starting position of a line with reference to the origin or starting point of the coordinate system.
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Two dump trucks each have a mass of 1,500 kg. The distance of the dump truck
is 50m. What will the new gravitational force be between them?
Answer:
6.00 x 10⁻⁸N
Explanation:
Given parameters:
Mass of each dump trucks = 1500kg
Distance between them = 50m
Unknown:
New gravitational force between them = ?
Solution:
From Newton's law of universal gravitation,
F = [tex]\frac{G m1 m2}{r^{2} }[/tex]
F is the gravitational force
G is the universal gravitation constant
m is the mass
r is the distance
F = [tex]\frac{6.67 x 10^{-11} x 1500 x 1500}{50^{2} }[/tex] = 6.00 x 10⁻⁸N
You are walking down a straight path in a park and notice there is another person walking some distance ahead of you. The distance between the two of you remains the same, so you deduce that you are walking at the same speed of 1.17 m/s. Suddenly, you notice a wallet on the ground. You pick it up and realize it belongs to the person in front of you. To catch up, you start running at a speed of 2.75 m/s. It takes you 14.5 s to catch up and deliver the lost wallet. How far ahead of you was this person when you started running
Answer:
Δx = 23.0 m
Explanation:
Since we know the time passed from the moment you picked up the wallet till you catch the other person up, and assuming that he continued moving at 1.17 m/s, we can find the distance traveled by him during this time, applying the definition of average speed, and rearrranging terms as follows:[tex]x_{2} = v_{2} * t = 1.17m/s * 14.5 s = 17.0 m (1)[/tex]
Now, as we know the speed at which you started to run, assuming that the speed kept constant during all the time since you picked the wallet up, we can find the total distance till you got to deliver the wallet, as follows:[tex]x_{1} = v_{1} * t = 2.75 m/s * 14.5 s = 40.0 m (2)[/tex]
the distance that you were behind the other person when you started running, is just the difference between (2) and (1):Δx = x₂ - x₁ = 40.0 m - 17.0 m = 23.0 m (3)Which of the models most accurately represents the structure of DNA?
A
B.
G
Answer:
It's A.
Explanation:
DNA is a double helix.
Model which accurately displays structure of DNA is model A as DNA is a double helical structure.
What is DNA?
DNA is a hereditary material which is present in human beings as well as all other living organisms. Every cell which is present in an organism's body has DNA which is the same. Most of the DNA is situated in the cell's nucleus and small amount of it can be found in the cell's mitochondria as well.
Information which is stored in DNA is stored as codes made up of four chemical bases namely, adenine, thymine , cytosine and guanine.Human DNA consists of 3 billion bases .The order of the bases determines information which is required for building and maintaining an organism.
DNA bases are capable of pairing up with each other. Adenine pairs with thymine and guanine pairs up with cytosine .Each base is also attached to a sugar molecule and a phosphate group. A base, phosphate sugar are together called as nucleotides.
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Bearing in mind that a sound reflects off an object if the object is larger than the wavelength of the sound, calculate the wavelength of a sound in the air for a sound in the middle of the human hearing range. Then calculate the wavelength for a sound in the middle of the bat hearing range. If you had to use echolocation to detect an insect, which sound has an advantage
Answer:
mucilage can detect objects the size of millimeters, whereas humans can only detect objects larger than centimeters
Explanation:
The human ear can detect sound in the range of 20 to 20000hz, we are asked to find the mid-range wavelength of the ear at f = 10000 Hz
let's use the relationship between wave speed, wavelength and frequency
v = λ f
λ= v / f
λ = 343/10000
λ = 3.43 10⁻² m
the sound range of a bat is between 25 10³ Hz and 100 10³ Hz, they also ask for the wavelength in the middle range
f = (100 10³ + 25 10³) / 2
f = 62.5 10³ Hz
λ = 343 / 62.5 10³
λ = 5.5 10⁻³ m
Therefore the size of the object that a bat can detect is much smaller than the size that a human can detect, therefore the bat is capable of detecting insects, but humans.
The mucilage can detect objects the size of millimeters, whereas humans can only detect objects larger than centimeters
Coulomb's law for the magnitude of the force FFF between two particles with charges QQQ and Q′Q′Q^\prime separated by a distance ddd is
|F|=K|QQ′|d2|F|=K|QQ′|d2,
where K=14πϵ0K=14πϵ0, and ϵ0=8.854×10−12C2/(N⋅m2)ϵ0=8.854×10−12C2/(N⋅m2) is the permittivity of free space.
Consider two point charges located on the x axis: one charge, q1q1q_1 = -11.5 nCnC , is located at x1x1x_1 = -1.675 mm ; the second charge, q2q2q_2 = 40.0 nCnC , is at the origin (x=0.0000)(x=0.0000).
What is the force exerted by these two charges on a third charge q3q3q_3 = 48.0 nCnC placed between q1q1q_1 and q2q2q_2 at x3x3x_3 = -1.215 mm ?
Your answer may be positive or negative, depending on the direction of the force.
Express your answer numerically in newtons to three significant figures.
Answer:
F_total = -65.5 N
Explanation:
Coulomb's law is
F = [tex]k \frac{q_1 q_2}{r^2}[/tex]k q1q2 / r2
In this exercise the force on the charge q3 is asked, for this we use that the force is a vector
F_total = F₁₃ + F₂₃
let's look for every force
F₁₃ = [tex]k \frac{q_1 q_3}{r_{13}^2}[/tex]
it is indicated that charge 1 is equal to q₁ = -11.5 nC = -11.5 10⁻⁹ C, located at x₁ = -1.675 mm = -1.675 10⁻³ m and charge q₃ = 48.0 nC = 48.0 10⁻⁹ C located at x₃ this position is not written in the exercise, suppose the position x₃ = -0.5 mm = 0.5 10⁻³ m
the distance is
r₁₃ = [tex]\sqrt{(x_3 - x_1 )^2}[/tex]
r₁₃ = [tex]\sqrt{(0.5-1.675)^2} \ 10^{-3}[/tex]
r₁₃ = 1.175 10⁻³ m
we calculate
F₁₃ = [tex]\frac{9 \ 10^{9} 11.5\ 10^{-9} 48.0\ 10^{-9} }{(1.175 10^{-3})^2 }[/tex]
F₁₃ = 3.598 N
as the charge q₁ is negative and the charge q₃ is positive the force is attractive directed to the right
we look for F₂₃, where q₂ = 40 nC = 40.0 10⁻⁹ C located at x₂ = 0
F₂₃ = [tex]k \frac{q_2q_3}{r_{23}^2}[/tex]
r₂₃ = [tex]\sqrt{(x_3-x_2)^2}[/tex]
r₂₃ = [tex]\sqrt{(0.5 -0)} \ 10^{-3}[/tex]RA (-0.5 0) 2 103
r₂₃ = 0.5 10⁻³ m
F₂₃ = [tex]\frac{9 \ 10^{9}\ 40\ 10^{-9} \ 48.0\ 10^{-9} x}{(0.5 \ 10^{-3})^2 }[/tex]
F₂₃ = 6.912 10¹ N
F₂₃ = 69.12 N
as the two charges are of the same sign, the force is repulsive, therefore it is directed to the left
the total force is
F = total = 3.598 - 69.12
F_total = -65.5 N
the negative sign indicates that the force is to the left
the feather experiences 0.075 N of downward force. Assuming it is on earth, what is its mass?
Answer:
The mass of the feather would be 0.0075 kg.
Explanation:
If the feather were to be on earth, it would have experienced the gravitational pull of the earth downwards. So that from Newton's second law of motion,
F = mg
where f is the force on the object, m is the mass of the object and g is the acceleration due to gravity of the earth.
But, F = 0.075 N, g = 10 m/[tex]s^{2}[/tex].
So that,
0.075 = m x 10
m = [tex]\frac{0.075}{10}[/tex]
= 0.0075 kg
The mass of the feather would be 0.0075 kg.
A very long, solid cylinder with radius R has positive charge uniformly distributed throughout it, with charge per unit volume r. (a) Derive the expression for the electric field inside the volume at a distance r from the axis of the cylinder in terms of the charge density r. (b) What is the electric field at a point outside the volume in terms of the charge per unit length l in the cylinder
Answer:
Explanation:
From the given information.
The charge density of the cylinder can be computed as:
[tex]\rho = \dfrac{Q_t}{V_t}[/tex]
where:
[tex]Q_t[/tex] = total charge on cylinder
[tex]\rho[/tex] = density of the cylinder
[tex]V_t =[/tex] net volume on cylinder
Considering the charge enclosed by the Gaussian surface; we have:
Q = ρV
Now, determining the volume of the cylinder at a distance r from the axis of the cylinder as follows:
[tex]\int Edsn = \dfrac{q}{\varepsilon_o}[/tex]
Here;
[tex]\hat E \ \ and \ \ \hat n[/tex] are in the same direction;
If we replace [tex]\int Edsn[/tex] with [tex]E ( 2 \pi rl)[/tex] and q with [tex]\rho \pi r^2 l[/tex]; Then:
[tex]E ( 2 \pi rl ) = \dfrac{\rho \pi r^2 l}{\varepsilon _o}[/tex]
By rearrangement;
[tex]E = \dfrac{\rho \pi r^2 l}{ ( 2 \pi rl ) \varepsilon _o}[/tex]
[tex]\mathbf{E = \dfrac{\rho r}{ 2 \varepsilon _o}}[/tex]
(b)
Using the same formula:
[tex]\int Edsn = \dfrac{q}{\varepsilon_o}[/tex]
where;
[tex]\hat E \ \ and \ \ \hat n[/tex] are in the same direction;
If we replace [tex]\int Edsn[/tex] with [tex]E ( 2 \pi rl)[/tex] and [tex]Q_t[/tex] with q;
Then:
[tex]E ( 2 \pi rl ) = \dfrac{Q_t}{\varepsilon _o}[/tex]
[tex]E = \dfrac{Q_t}{( 2 \pi R l ) \varepsilon _o}[/tex]
Replacing [tex]\lambda[/tex] for [tex]\dfrac{Q_t}{l}[/tex].
From above [tex]\lambda[/tex] = the charge per unit length
∴
[tex]\mathbf{E = \dfrac{\lambda}{ 2 \pi R \varepsilon _o}}[/tex]
g Light is a traveling wave! The oscillations are oscillations of electric fields. The electric fields oscillate in the y-direction while the light travels in the x direction, so we can create a wave equation Ey(x,t); Ey is the y-component of the electric field, x is position in meters, and t is time in seconds. Consider light with a wave length of 550 nanometers, a wave speed of 3.00 x 108 m/s , and an amplitude of 10 V/m (volts/meters). Construct the traveling wave equation for this light if at t = 0 seconds, the light is at its maximum positive value and is traveling in the negative x-direction. Your equation, Ey(x,t) , should only have the variables x and t (i.e. calculate the values of the relevant traveling wave quantities to three sig figures and use those in the equation you are constructing, do not use the symbols in your final answer).
Answer:
[tex]E_{y} (x,t)[/tex]= 10 cos (1.15 10⁻¹¹ x - 3.427 10¹⁵ t)
Explanation:
The general equation of a traveling wave on the x-axis is
[tex]E_{y}(x,t)[/tex] = E₀ cos (kx -wt)
the amplitude of the wave is E₀ = 10 V / m
the wave number is
k = 2π /λ
indicate the value of λ = 550 nm = 550 10⁻⁹ m
we substitute
k = 2π / 550 10⁻⁹
k = 1.15 10⁻¹¹ m⁻¹
angular velocity is related to frequency
w = 2πf
the speed of light is related to the wavelength and frequency
c = λ f
f = c /λ
we substitute
w = [tex]2\pi \frac{c}\lambda }[/tex]
w = 2π 3 10⁸/550 10⁻⁹
w = 3.427 10¹⁵ rad / s
we substitute in the electric field equation
[tex]E_{y} (x,t)[/tex]= 10 cos (1.15 10⁻¹¹ x - 3.427 10¹⁵ t)
Let's test the value of this wave for t = 0 at the point x = 0, the wave is worth
Ey (0,0) = 10
which corresponds to its maximum positive value, therefore this is the expression of the traveling wave
A 0.85 N force exists between a 7.1 * 10 ^ - 6 * C charge 5.4 m away. What is the magnitude of the second charge ? Please show work
Answer:
Explanation:
Force between charge is given by the following expression
F = k Q₁ Q₂ / R² , k = 9 x 10⁹ , Q₁ and Q₂ are charges , R is distance between charges .
Putting the given values ,
.85 = 9 x 10⁹ x 7.1 x 10⁻⁶ x Q₂ / 5.4²
Q₂ = .85 x 5.4² / (9 x 10⁹ x 7.1 x 10⁻⁶ )
= .38788 x 10⁻³ C .
= 387.88 x 10⁻⁶ C .
How do I fix my task bar thing
Answer:
go to settings and find what your looking for
Explanation:
if a particle with a charge of +4.3 C is attracted to another particle by a force of 6.5 N, what is the strength of the electric field at this location?
Answer: 1.5 N/C
Explanation:
The equation is derived from Coulomb's Law, but is not exactly Coulomb's Law:
F = qE
q is the test charge
E is the electrical field produced by the source charge
F is the force in Newtons
In this problem, we were given the value of the test charge q, and the force acting on it due to the electric field from the source charge.
E = F/q
E = 6.5N/4.3C
E = 1.5 N/C
A 12 volt battery will increase the potential energy of 4 coulombs of charge by _____ Joules.
Question 8 options:
16 J
3 J
.33J
48 J
Answer:
Explanation:
Given parameters:
Voltage = 12V
Quantity of charge = 4C
Unknown:
Potential energy = ?
Solution:
Within this circuit, the value of the potential energy can be found using the expression below:
Potential energy = [tex]\frac{1}{2}[/tex] c v²
c is the quantity of charge
v is the voltage
Potential energy = [tex]\frac{1}{2}[/tex] x 4 x 12² = 288J
For a conductor in electrostatic equilibrium, which of the following properties are true? Choose all that apply. For a conductor in electrostatic equilibrium, which of the following properties are true? Choose all that apply. The electric field inside is zero. The entire conductor is at the same potential. Any excess charge is uniformly spread throughout the volume of the conductor.
Answer:
The entire conductor is at the same potential.
The electric field inside is zero.
Explanation:
For a conductor in electrostatic equilibrium, the properties are:
The electric field inside is zero.The entire conductor is at the same potential. What is electrical conductor?A conductor is an object or kind of material that permits the movement of charge (electric current) in one or more directions. This term is used in both physics and electrical engineering. Metal-based materials are frequently used as electrical conductors.
It is not essential for one charged particle to move from the component creating the current (the current source) to those consuming it for current to flow within a closed electrical circuit (the loads).
Instead, all that is required of the charged particle is a small amount of nudging from its neighbor, who in turn will nudging its neighbor, and so on, until a particle gets nudged into the consumer, so supplying it with power.
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