What is the volume of a cylinder, in cubic in, with a height of 11in and a base diameter
of 4in? Round to the nearest tenths place​ ​

Answer:

Solution,

Hypotenuse(h)= 25

Base(b)= 20

perpendicular (p)= X

Now,

Using Pythagorean theorem:

[tex] {p}^{2} = {h}^{2} - {b}^{2} \\ {x}^{2} = {25}^{2} - {20}^{2} \\ {x}^{2} = 625 - 400 \\ {x}^{2} = 225 \\ x = \sqrt{225} \\ x = \sqrt{ {15}^{2} } \\ x = 15 [/tex]

Hope this helps...

Good luck on your assignment..

Answer:

x = 15

Step-by-step explanation:

Using Pythagoras' identity in the right triangle.

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is

x² + 20² = 25² , that is

x² + 400 = 625 ( subtract 400 from both sides )

x² = 225 ( take the square root of both sides )

x = [tex]\sqrt{225}[/tex] = 15

Answer:

Area = πr²

= π * 2²

= 3.14 * 4

= 12.6

Answer:

[tex] \boxed{\sf Area = 12.6 \: {cm}^{2}} [/tex]

Given:

Radius of circle (r) = 2 cm

To Find:

Area of circle

Step-by-step explanation:

[tex] \sf Area \: of \: circle = \pi {r}^{2} \\ \\ \sf \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 3.14 \times {2}^{2} \\ \\ \sf \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: =3.14 \times 4 \\ \\ \sf \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: =12.56 \: {cm}^{2} \\ \\ \sf \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \approx 12.6 \: {cm}^{2} [/tex]

Answer:

-15y^6z^{10}+35y^4z^6

Step-by-step explanation:

used an equation calculator

Answer:

3

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Here (h, k) = (2, - 4) , thus

y = a(x - 2)² - 4

To find a substitute (3, - 1 ) into the equation

- 1 = a(3 - 2)² - 4 ( add 4 to both sides )

3 = a

Thus

y = 3(x - 2)2 - 4 ← equation in vertex form

   = 3(x² - 4x + 4) + 4

    = 3x² - 12x + 12 + 4

     = 3x² - 12x + 16 ← equation in standard form

with coefficient of x² term = 3

Answer: c) 27:8

Step-by-step explanation:

As volume of cube is side^3

volume of cube with side 2a is 8.a^3

volume of cube with side  3a is 27.a^3

ration of volumes is 27:8

one pump, let's call it A, fills the reservoir by 1/60 every hour. Now, B fills it by 1/80 every hour. C empties it by 1/90 every hour. All three are on, so now we combine them into one function: t(1/60 + 1/80 - 1/90) = 1, where t = the time it takes to fill it, and 1 is just our "reservoir finally filled" marker.

isolate t onto one side and we see t = 720/13 exactly, or approximately 55.38 hours. let me know if this is the wrong answer but I'm pretty sure it is correct!

Answer:

1/time needed = 1/time of 1st pump + 1/time of 2nd pump - 1/time of 3rd pump

1/t = 1/t1 + 1/t2 - 1/t3

1/t = 1/60 + 1/80 - 1/90

1/t = 12/720 + 9/720 - 8/720

1/t = 13/720

t = 720/13 hours = 55.38 hours = 55 hours 23 minutes

Answer:

[tex]1.\ 10+x+ 8 = 18+ x[/tex]

[tex]2.\ 9(3x) = 27x[/tex]

[tex]3.\ \frac{1}{2}(10x) + 7 - 3 = 5x + 4[/tex]

[tex]4.\ -5(4x) = -20x[/tex]

[tex]5.\ 10 - 2 (8x) - 3 = 7 - 16x[/tex]

[tex]6.\ 3(7x) + 3 (-5) = 21x -15[/tex]

Step-by-step explanation:

Required

Solve each expression

[tex]1.\ 10+x+ 8[/tex]

Start by collecting like terms

[tex]10+ 8+x[/tex]

Add like terms

[tex]18+x[/tex]

The expression can't be solved further

Hence; [tex]10+x+ 8 = 18+ x[/tex]

[tex]2.\ 9(3x)[/tex]

Open the bracket

[tex]9 * 3x[/tex]

[tex]27x[/tex]

The expression can't be solved further

Hence, [tex]9(3x) = 27x[/tex]

[tex]3.\ \frac{1}{2}(10x) + 7 - 3[/tex]

Open bracket

[tex]\frac{1}{2} * 10x + 7 - 3[/tex]

[tex]5x + 7 - 3[/tex]

[tex]5x + 4[/tex]

The expression can't be solved further;

Hence, [tex]\frac{1}{2}(10x) + 7 - 3 = 5x + 4[/tex]

[tex]4.\ -5(4x)[/tex]

Open the bracket

[tex]-5 * 4x[/tex]

[tex]-20x[/tex]

The expression can't be solved further

Hence, [tex]-5(4x) = -20x[/tex]

[tex]5.\ 10 - 2 (8x) - 3[/tex]

Open Bracket

[tex]10 - 2 *8x - 3[/tex]

[tex]10 - 16x - 3[/tex]

Collect like terms

[tex]10 - 3 - 16x[/tex]

[tex]7 - 16x[/tex]

The expression can't be solved further

Hence, [tex]10 - 2 (8x) - 3 = 7 - 16x[/tex]

[tex]6.\ 3(7x) + 3 (-5)[/tex]

Open both brackets

[tex]3*7x + 3 * -5[/tex]

[tex]21x -15[/tex]

The expression can't be solved further

Hence, [tex]3(7x) + 3 (-5) = 21x -15[/tex]

Hey there! :)

Answer:

y = 0, also known as the x-axis.

Step-by-step explanation:

The equation [tex]f(x) = \frac{2}{3} ^{x}[/tex] is an exponential function.

There is an asymptote at y = 0, or the x-axis because:

[tex]\frac{2}{3} ^{x}\neq 0[/tex]

An exponential function, unless containing a vertical shift, can never cross the x-axis resulting in an asymptote at y = 0.

Answer:

{ x ≠ ±6 ∪ x ≠ ± 6}

Step-by-step explanation:

x cannot be zero even though x can be cancelled in this expression.  Furthermore, x^2 - 36 cannot be zero, and thus x ≠ ±6.

Domain is { x ≠ ±6 ∪ x ≠ ± 6}

Answer: C)  [tex](-\dfrac{1}{2},\dfrac{3}{2})[/tex]

Step-by-step explanation:

The given system of equations :

[tex]2(y-x) = 5+2x\ \ ...(i)\\\\ 2(y+x)=5-2y\ \ ..(ii)[/tex]

Simplify left side, we get

[tex]2y-2x=5+2x\Rightarrow\ 2y-4x=5\ \ ...(iii)\\\\ 2y+2x=5-2y\Rightarrow\ 4y+2x=5\ \ ...(iv)[/tex]

Multiplying 2 on equation (iii), we get

[tex]4y-8x=10\ \ ...(v)[/tex]

Subtracting (v) from (iv) , we get

[tex]2x-(-8x)=5-10\\\\\Rightarrow\ 2x+8x=-5\\\\\Rightarrow\ 10x=-5\\\\\Rightarrow\ x=-\dfrac{5}{10}=-\dfrac{1}{2}[/tex]

Put value of [tex]x=-\dfrac{1}{2}[/tex] in (v), we get

[tex]4y-8(-\dfrac{1}{2})=10\\\\\Rightarrow \ 4y+4=10\\\\\Rightarrow\ 4y=10-4=6\\\\\Rightarrow\ y=\dfrac{6}{4}=\dfrac{3}{2}[/tex]

hence, the solution to the system is [tex](x,y)=(-\dfrac{1}{2},\dfrac{3}{2})[/tex]

Answer:

The correct answer is:

[tex]g(x) = x+1[/tex]

Step-by-step explanation:

Given that:

[tex]h(x) = f\circ g(x)= \sqrt[3]{x+3}[/tex]

[tex]f(x) = \sqrt[3]{x+2}[/tex]

To find:

[tex]g(x) = ?[/tex]

Solution:

Let [tex]g(x) = m[/tex]

We have

[tex]f\circ g(x)= \sqrt[3]{x+3}\\OR\\f( g(x))= \sqrt[3]{x+3}[/tex]...... (1)

Now, we have let:

[tex]g(x) = m\\\therefore f(g(x)) = f(m)[/tex]

Putting x = in f(x), we get

[tex]f(x) = \sqrt[3]{x+2}\\\Rightarrow f(m) = \sqrt[3]{m+2}[/tex]....... (2)

Comparing equation (1) and (2):

[tex]\sqrt[3]{x+3} =\sqrt[3]{m+2}[/tex]

Taking cubes both sides:

[tex]x+3=m+2\\\Rightarrow m = x+3-2\\\Rightarrow m = x+1[/tex]

[tex]\therefore g(x) = x+1[/tex]

Hence,

The correct answer is:

[tex]g(x) = x+1[/tex]

Answer:

Option a

Step-by-step explanation:

This is a nice simple problem!

Given that the function f( x ) is equivalent to 3x + 400, respectively g( x ) = 5x + 200, all we are being asked to do is find their difference. Substitute the given values as such -

h( x ) = f( x ) - g( x )

⇒ h( x ) = ( 3x + 400 ) - ( 5x + 200 ) - Distribute negative sign, taking out ( )

⇒ h( x ) = 3x + 400 - 5x + 200 - Combine like elements

⇒ h( x ) = - 2x + 200

And there you have it! Our solution should be option a ( h( x ) = - 2x + 200 )

If you would like, there is a graph of the function in the attachment below.

Answer:

It's B on edge!

Answer:

? = 21

Step-by-step explanation:

Parallel lines cut off proportional segments on transversals.

27/? = 18/14

18 * ? = 27 * 14

2 * ? = 3 * 14

? = 3 * 7

? = 21

Answer:

21

Step-by-step explanation:

The range of the data is 10.

Box plot, which is also known as box and whisker plot, is a method of graphically representing the measures like minimum, maximum and the quartiles of the data set.

Given is a box plot.

Range of a data set is the difference between the highest and the lowest point.

The highest and lowest point of the data set is the points where the whiskers of the box plot extends to.

Here, whiskers extends from 5 to 15.

Range = Maximum - Minimum

          = 15 - 5

          = 10

Hence the range of the data set is 10.

Learn more about Box Plots here :

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Answer:

road side cabins

Step-by-step explanation:

Answer:

x - 2y + 6 = 0  

Step-by-step explanation:

Going from (-2, 2) to (4, 5), we see that x (the 'run') increases by 6 and that y (the 'rise') increases by 3.  Thus, the slope of the line through these two points is m = rise / run = 3/6, or m = 1/2.

Starting with the slope-intercept formula y = mx + b, and using the x and y values from the point (-2, 2), we get

2 = (1/2)(-2) + b, or 4 = -2 + 2b, or 6 = 2b, or b = 3.  Then the slope-intercept form of the desired equation is y = (1/2)x + 3.  To obtain the standard form, we multiply all three terms of this result by 2, obtaining 2y = x + 6, or

x - 2y + 6 = 0                                                                        

Answer:

[tex]-4(a + b = 6)[/tex]

Step-by-step explanation:

Given

[tex]a + b = 6[/tex]

[tex]4a + 2b = 19[/tex]

Required

Eliminate a

Multiply the first equation by -4

[tex]-4(a + b = 6)[/tex]

Add to the second equation

[tex]-4(a + b = 6) + (4a + 2b = 19)[/tex]

Solve brackets

[tex](-4a -4b = -24) + (4a + 2b = 19)[/tex]

Open bracket

[tex]-4a + 4a -4b + 2b = -24 + 19[/tex]

[tex]-4b + 2b = -24 + 19[/tex]

At this point, a has been eliminated;

From the list of given options, the option that answers the question is [tex]-4(a + b = 6)[/tex]

Answer:

The answer is B. 30 seconds

Answer:

[tex]\huge\boxed{C.\ \dfrac{kg}{m^3}}[/tex]

Step-by-step explanation:

[tex]density=\dfrac{mass}{volume}\\\\\text{the unit of mass is}\ kg\\\text{the unit of volume is}\ m^3\\\\\text{therefore the unit of density is}\ \dfrac{kg}{m^3}[/tex]

Answer:

The answer is solution D.

Step-by-step explanation:

130 + 12.50p ≤ 1500

The 130 is the setup fee

The 12.50 is the amount to pay per person

p means the number of people

The symbol ≤ means smaller than or equal to so it could be either of those

The 1500 is the max amount of money that they could spend for the party.

Answer:

3000

Step-by-step explanation:

First find the 4 digit numbers that have all odd digits

Possible Odd digits  =5(1,3,5,7,9)  

So, total number of 4 digit numbers with odd digits can be calculated as  =5×5×5×5=625

Now find all the 4 digits numbers with at least 3 odd digits and the first digit as either 2,4,6,8 ( 0 would make it a 3 digit number)

The first digit can be 2,4,6,8

=4×5×5×5=500

Now find all the 4 digits numbers with at least 3 odd digits and the second digit as either 0,2,4,6,8

=5×5×5×5=625

Now find all the 4 digits numbers with at least 3 odd digits and the third digit as either 0,2,4,6,8

Now find all the 4 digits numbers with at least 3 odd digits and the second digit as either 0,2,4,6,8

=5×5×5×5=625

Now find all the 4 digits numbers with at least 3 odd digits and the fourth digit as either 0,2,4,6,8

=5×5×5×5=625

Add them together

625+500+625+625+625=3000

Answer:

3000

Step-by-step explanation:

4*5*5*5+5*5*5*5+5*5*5*5+5*5*5*5+5*5*5*5 = 3000

Answer:25

Step-by-step explanation:

Answer:

70

Step-by-step explanation:

Answer:

Option 2 and option 4

Step-by-step explanation:

option 2:

(2,2) ; (2*2 , 2*2)= (4,4) ;  (2*3, 2*3) = (6 , 6)

Option 4:

(4 ,1 ) ; (4*2 , 1*2) = (8 , 2) ;  (4*3 , 1*3) = (12 , 3)

Answer:

y - 7 = (1/10)(x - 5)

Step-by-step explanation:

Next time please share the possible answers.  Thank you.

Any line perpendicular to y = -10x + 1 has the slope +1/10, which is the negative reciprocal of -10.

Using the point-slope formula, we get:

y - 7 = (1/10)(x - 5)

Answer:

x = 25

Step-by-step explanation:

Since it is an equilateral triangle it means that all the sides are 50. Each side is equal so, if you divide 150 by 3 you get 50. (and since perimeter is the adding of each side)

Now you want to try to figure out what the altitude is of the triangle so you divide it in half. Making the bottom side length now 25 because half of 50 is 25. You now have to use Pythagoreans theorem to figure out the altitude:

c^2 - a^2 = b^2

50^2 - 25^2 = b^2

2500 - 625 = b^2

1875 = b^2

√1875 = b

43.30127019

now you put that into the expression: x√3:

x√3 = 43.30127019

x = (43.30127019) ÷ (√3)

x = 25

Hope this helped!

Answer:

There are 243 ways but the balls in the boxes.

Step-by-step explanation:

There are 109375 ways to put 5 balls in 2 boxes when the balls and boxes are distinguishable by using counting principles and combinatorics

To solve this problem,  use the concept of the multiplication principle, also known as the multiplication rule of counting.

Here's a step-by-step explanation:

Determine the number of choices for each ball: Since the balls are distinguishable, we have 5 choices for the first ball, 5 choices for the second ball, and so on, until we have 5 choices for the fifth ball. This can be represented as:

[tex]5 \times 5 \times 5 \times 5 \times 5.[/tex]

Determine the number of choices for each box: Since the boxes are distinguishable, each ball can be placed in either box 1 or box 2. Thus, there are 2 choices for each ball. This can be represented as:

[tex]2 \times 2 \times 2 \times 2 \times 2.[/tex]

To find the total number of ways, we multiply the number of choices for each ball with the number of choices for each box:

Total number of ways [tex]= (5 \times 5 \times5 \times5 \times5) \times(2 \times2 \times2 \times2 \times2)[/tex]

On multiply gives:

=  3125\times 32 = 109,375.

Therefore, there are 109375 ways to put 5 balls in 2 boxes when the balls and boxes are distinguishable.

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Answer:

f, g, and h only

Step-by-step explanation:

The letters are the variables.