Answer: The value of [tex]\Delta G[/tex] is -602.96 kJ/mol at 292 k for a reaction in which [tex]\Delta H[/tex] = 92 kj/mol and [tex]\Delta S[/tex] = 2.38 kj/mol K.
Explanation:
Given: Temperature = 292 K
[tex]\Delta H[/tex] = 92 kJ/mol
[tex]\Delta S[/tex] = 2.38 kJ/mol
Formula used to calculate the value of [tex]\Delta G[/tex] is as follows.
[tex]\Delta G = \Delta H - T\Delta S[/tex]
Substitute the values into above formula as follows.
[tex]\Delta G = \Delta H - T\Delta S\\= 92 kJ/mol - (292 K \times 2.38 kJ/mol K)\\= 92 kJ/mol - 694.96 kJ/mol\\= - 602.96 kJ/mol[/tex]
Thus, we can conclude that the value of [tex]\Delta G[/tex] is -602.96 kJ/mol at 292 k for a reaction in which [tex]\Delta H[/tex] = 92 kj/mol and [tex]\Delta S[/tex] = 2.38 kj/mol K.
True or False
Low temperatures lead to faster dissolution rates compared to high temperatures
Answer:
false
Explanation:
this is because , high temperature speeds up the the random motion of particles which leads to high dissolution
Question 2
3 pts
Which of the following names is correctly matched with the corresponding chemical formula (as
outlined in class)?
*Note: All numbers should be considered as subscripts!
O HCN - formonitrile
NH3 - nitrogen trihydride
HBr = monohydrogen monobromide
SiF4 = silicon tetrafluorine
Answer:
NH3 - nitrogen trihydride
Explanation:
In attempting to answer this question we should keep certain things in mind. We should remember that the subscripts show the number of atoms of each element present in the compound and we do not use the prefix "mono" twice in naming a binary compound.
The prefixes "mono", "di" etc are used when the central atom in the compound can form more than one compound with the same atom; E.g carbon monoxide and carbon dioxide. Hence the description, monohydrogen monobromide is incorrect.
Also, SiF4 is silicon tetrafluoride and not silicon tetrafluorine.
Hence, only NH3 was correctly described as nitrogen trihydride.
What human development period 2 years and 12 years called
Answer:
In these lessons, students become familiar with the four key periods of growth and human development: infancy (birth to 2 years old), early childhood (3 to 8 years old), middle childhood (9 to 11 years old), and adolescence (12 to 18 years old).
Calculate the total energy (in kJ) absorbed when 50.5 g of ice at -15.0°C is converted into liquid water at 65.0 °C.
Answer:
The total energy absorbed is 32.171 kilojoules.
Explanation:
The total energy absorbed by the ice is the sum of the sensible heat of ice and water and the latent heat of fusion of the water, that is:
[tex]Q = m\cdot [c_{i}\cdot (T_{2}-T_{1})+L_{f} + c_{w}\cdot (T_{3}-T_{2})][/tex] (1)
Where:
[tex]m[/tex] - Mass of the ice, in kilograms.
[tex]c_{i}[/tex] - Specific heat of ice, in kilojoules per kilogram-degree Celsius.
[tex]c_{w}[/tex] - Specific heat of water, in kilojoules per kilogram-degree Celsius.
[tex]L_{f}[/tex] - Latent heat of fusion, in kilojoules per degree Celsius.
[tex]T_{1}[/tex] - Initial temperature of water, in degrees Celsius.
[tex]T_{2}[/tex] - Fusion point of water, in degrees Celsius.
[tex]T_{3}[/tex] - Final temperature of water, in degree Celsius.
[tex]Q[/tex] - Total energy absorbed, in kilojoules.
If we know that [tex]m = 50.5\times 10^{-3}\,kg[/tex], [tex]c_{i} = 2.090 \,\frac{kJ}{kg\cdot^{\circ}C}[/tex], [tex]c_{w} = 4.180\,\frac{J}{kg\cdot ^{\circ}C}[/tex], [tex]L_{f} = 334\,\frac{kJ}{kg}[/tex], [tex]T_{1} = -15\,^{\circ}C[/tex], [tex]T_{2} = 0\,^{\circ}C[/tex] and [tex]T_{3} = 65\,^{\circ}C[/tex], then the total energy absorbed is:
[tex]Q= (50.5\times 10^{-3}\,kg)\cdot \left[\left(2.090\,\frac{kJ}{kg\cdot ^{\circ}C} \right)\cdot (15\,^{\circ}C) + 334\,\frac{kJ}{kg}+ \left(4.180\,\frac{kJ}{kg\cdot ^{\circ}C} \right)\cdot (65\,^{\circ}C)\right][/tex][tex]Q = 32.171\,kJ[/tex]
The total energy absorbed is 32.171 kilojoules.
In the lab, a 156 g sample of unknown compound KClOx was completely decomposed to produce 50.4 L of O2 (g) at STP and an unknown amount of KCl. What is the value of X
Answer:
2
Explanation:
Step 1: Write the generic decomposition reaction
KClOₓ ⇒ KCl + O₂
Step 2: Calculate the moles of O₂
At STP, 1 mole of an ideal gas occupies 22.4 L.
50.4 L × 1 mol/22.4 L = 2.25 mol
Step 3: Calculate the mass corresponding to 2.25 moles of O₂
The molar mass of O₂ is 32.00 g/mol.
2.25 mol × 32.00 g/mol = 72 g
Step 4: Determine the value of x
Every 156 g of KClOₓ there are 72 g of oxygen. The mass percent of O is:
%O: 72 g/156 g × 100% = 46.2%
In KClO, the mass percent of O is: 32.00 g/90.5 g × 100% = 35.4%
In KClO₂, the mass percent of O is: 64.00 g/138.5 g × 100% = 46.2%
Then, x = 2
Which of these is a major drawback of using fuel cells in a car?
a lack of hydrogen filling stations
a drop in reliance on petroleum products
an increase in water vapor into the atmosphere
an increase in the use of rechargeable batteries
A major drawback of using fuel cells in a car is a lack of hydrogen filling stations.
What is fuel cell?A fuel cell is an electrochemical device that converts the energy stored in a fuel, typically hydrogen, directly into electrical energy.
One significant disadvantage of using fuel cells in a car is the scarcity of hydrogen filling stations.
While fuel cell technology has several advantages, including increased efficiency and lower emissions, the infrastructure for producing, transporting, and storing hydrogen is currently limited, making it difficult to refuel fuel cell vehicles on the road.
Because of this limitation, fuel cell vehicles are less suitable for long-distance travel and have a limited market penetration.
Thus, the answer is "a lack of hydrogen filling stations".
For more details regarding fuel cell, visit:
https://brainly.com/question/4607420
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Answer:
its A trust!!!!!
Explanation:
1. How many moles of hydrogen are needed to completely react with two moles of nitrogen?
_N2 + _H2 -->_NH3
Please hurry it is for a big assignment
N2 + 3H2 --> 2NH3
Answer: 6 moles of hydrogen are needed to react with two moles of nitrogen.
Explanation:
1. What do you understand about equivalent weight for lime requirement?
2. What is the relationship between normality and equivalence?
Answer:
Explanation:
What do you understand about equivalent weight for lime requirement?
If field data are not available, lime requirements can be determined with the solution is added to a given weight or volume of soil and the pH is measured. Each milligram per liter of sodium bicarbonate is equal to 0.56 mg/L of alkalinity. A winter wheat crop grown on a light sand soil in a low rainfall area will mean an
To prepare 250mL of calcium chloride solution with a molar concentration of 1.20mol/L, what mass of calcium chloride would be required?
Answer:
33.30 grams of CaCl2 will be required
Explanation:
Given,
Volume of solution, V= 250 ml
Molarity of solution, M= 1.20 mol/L
Molecular mass of CaCL2, S= 40+(35.5 X 2)= 111
We know,
Required mass, W= SVM/1000
Now,
W = (111 X 250 X 1.20)/1000
= 33300/1000
= 33.30
Therefore, 33.30 grams of Calcium Chloride will be required.
The change in entropy of 20.0 moles of ideal monatomic constant volume gas as it changes from an initial temperature 300 K to its final temperature is 200 J/K. What is the final temperature of the gas
Answer:
668.9K is the final temperature
Explanation:
The change in entropy, ΔS, of an ideal monoatomic gas is obtained using the equation:
ΔS = n*Cv*ln (T2/T1)
Where ΔS is change in entropy = 200J/K
n are moles = 20.0mol
Cv is 3/2R for an ideal monoatomic gas (3/2*8.314J/molK)
T2 is final Temperature and T1 initial temperature = 300K
Replacing:
ΔS = n*Cv*ln (T2/T1)
200J/K = 20.0mol*3/2 *8.314J/molK*ln (T2/300K)
0.80186 = ln (T2/300K)
2.23 = T2 / 300K
668.9K is the final temperaturePLZ Help me I am confused
Answer:
i can not see photo very well
Explanation:
Which statements correctly describe metallic bonds
Answer:
E. They form because electrons can move freely between atoms.
Explanation:
Metallic bonding is a type of chemical bonding that arises from the electrostatic attractive force between conduction electrons and positively charged metal ions.
In the reaction Pb + 2Ag+ – Pb2+ + 2Ag, the Ag+ is.
a) reduced, and the oxidation number changes from +1 to 0.
b)reduces and the oxidation number changes from +2 to 0.
c)oxidized and the oxidation number changes from 0 to +1.
d) oxidized, and the oxidation number changes from +1 to 0.
In the reaction Pb + 2Ag+ – Pb2+ + 2Ag, the Ag+ is.
a) Reduced, and the oxidation number changes from +1 to 0.
b) Reduces and the oxidation number changes from +2 to 0.
c) Oxidized and the oxidation number changes from 0 to +1.
d) Oxidized, and the oxidation number changes from +1 to 0.
____________________Solution :-Given Information :-Reaction ➢ Pb + 2Ag⁺ ⟶ Pb²⁺ + 2Ag To Find :-Whether Ag⁺ is:-a) Reduced, and the oxidation number changes from +1 to 0.b) Reduces and the oxidation number changes from +2 to 0.c) Oxidized and the oxidation number changes from 0 to +1.d) Oxidized, and the oxidation number changes from +1 to 0.Answer :-Firstly let us know the meaning of Oxidation & Reduction and Oxidizing & Reducing Agent :-
Oxidation is process of loss of electron(s). Either atom or ion undergoing oxidation, is known as reducing agent.Reduction is process of gain of electron(s). Either atom or ion undergoing reduction, is known as oxidizing agent.In this reaction, Ag⁺ gains an electron to get reduced to Ag. The oxidation number changes from +1 to 0. Therefore, Ag+ is an oxidizing agent.
Since, this possibility is given in option a). Reduced, and the oxidation number changes from +1 to 0. Hence, option a is the correct answer.
____________________Final Answer :-Option a. Reduced, and the oxidation number changes from +1 to 0 is correct answer.____________________Evaluate each of the statements below. Select those that accurately describe the role of genes and chromosomes in
the process of inheriting a specific trait. Choose ALL that apply.
-0)
A)
Chromosomes are made of DNA.
B)
There are 26 pairs of chromosomes in humans.
C)
Alleles are the different forms of a gene that can exist.
D)
Chromosomes contain genes that control the inheritance of traits.
E)
Genes are made of chromosomes and contain all of the genetic information
for an organism.
Answer:
HEY CAN YOU POST YOUR LAST QUESTION AGAIN? CAUSE I HAVE THE ANSWER
what's the most lightest element known?
Answer:
Hydrogen
Explanation:
Hydrogen, most abundant in the universe, is the chemical element with atomic number 1, and an atomic mass of 1.00794 amu, the lightest of all known elements. It exists as a diatomic gas (H2).
Answer:
Hydrogen
Explanation:
Hydrogen, most abundant in the universe, is the chemical element with atomic number 1, and an atomic mass of 1.00794 amu, the lightest of all known elements. It exists as a diatomic gas (H2).
What are anti-oxidants? Why are they added to fat and oil containing food?
Answer:
A substance that protects cells from the damage caused by free radicals (unstable molecules made by the process of oxidation during normal metabolism). Free radicals may play a part in cancer, heart disease, stroke, and other diseases of aging.
What kind of reaction is this ? P+02-P4010
A.Synthesis
B. Decomposition
C.Single Replacement
D. Double Replacement
Answer:
A.Synthesis
Explanation:
Let's consider the following unbalanced reaction.
P + O₂ ⇒ P₄O₁₀
To get the balanced equation, so that the equation follows the law of conservation of matter, we will need to multiply P by 4 and O₂ by 5.
4 P + 5 O₂ ⇒ P₄O₁₀
This kind of reaction is known as a synthesis reaction, in which 2 simple substances combine to form a compound (P₄O₁₀).
How many L of 3.0 M H2SO4 solution can be prepared by using 100.0 mL OF 18 M H2SO4?
Answer:
[tex]V_2=600mL[/tex]
Explanation:
Hello there!
In this case, according to this dilution process, it is possible for us to solve this problem via the following equation:
[tex]V_2M_2=V_1M_1[/tex]
Thus, since we were given the initial and final concentrations but just the initial volume, we calculate the final one as shown below:
[tex]V_2=\frac{V_1M_1}{M_2}\\\\ V_2=\frac{100.0mL*18M}{3.0M}\\\\V_2=600mL[/tex]
Regards!
help please
A gas in a sealed container has a pressure of 125 kPa at a temperature of 303K. If the temperature in the container is increased to 487K, what is the new pressure?
A 201kpa
B 200kpa
C 400kpa
D 78kpa
Answer:
A. 201 kPa
Explanation:
We can solve this problem by using Boyle's law, which states:
P₁T₂ = P₂T₁Where subscript 1 stands for the initial Pressure and Temperature, while 2 stands for the final conditions. That means that in this case:
P₁ = 125 kPaT₂ = 487 KP₂ = ?T₁ = 303 KWe input the data:
125 kPa * 487 K = P₂ * 303 KAnd solve for P₂:
P₂ = 201 kPaWrite the Ksp expression for the sparingly soluble compound cobalt(II) sulfide, CoS. If either the numerator or denominator is 1, please enter 1.
Answer:
[tex]Ksp=\frac{[Co^{2+}][S^{2-}]}{1}[/tex]
Explanation:
Hello there!
In this case, according to the given information, it turns out firstly necessary to write the chemical equation for this reaction as shown below:
[tex]CoS(s)\rightleftharpoons Co^{2+}(aq)+S^{2-}(aq)[/tex]
Thus, since solids are not included in equilibrium expressions, we can set this one up as follows:
[tex]Ksp=\frac{[Co^{2+}][S^{2-}]}{1}[/tex]
Regards!
Name and describe the type of bond found in a water molecule.
Answer:
covalent bonds
Explanation:
covalent bonds hold together the hydrogen and oxygen atoms of individual H2O molecules. Covalent bonds occur when two atoms share electrons with each other.
If 22.5 mol of an ideal gas occupies 30.5 L at 447 K, what is the pressure of the gas?
pressure:
_______________________ atm
Answer:
P = 27.07 atm
Explanation:
Given that,
The number of moles, n = 22.5 mol
Volume, V = 30.5 L
Temperature, T = 447 K
We need to find the pressure of the gas. The ideal gas law is as follows :
[tex]PV=nRT\\\\P=\dfrac{nRT}{V}[/tex]
R = 0.0821 L-atm/mol-K
Put all the values,
[tex]P=\dfrac{22.5\times 0.0821\times 447}{30.5}\\\\P=27.07\ L[/tex]
So, the pressure of the gas is 27.07 atm.
Equal molar quantities of Ca2 and EDTA (H4Y) are added to make a 0.010 M solution of CaY2- at pH 10. The formation constant for CaY2- is 5.0 x 1010 and the fraction of unprotonated EDTA (Y4-) is 0.35 at pH10. Calculate the concentration of free Ca2 in this solution.
Answer:
the concentration of free Ca2⁺ in this solution is 7.559 × 10⁻⁷
Explanation:
Given the data in the question;
[tex]Ca^{2+[/tex] + [tex]y^{4-[/tex] ⇄ [tex]CaY^{2-[/tex]
Formation constant Kf
Kf = [tex]CaY^{2-[/tex] / ( [[tex]Ca^{2+[/tex]][[tex]y^{4-[/tex]] ) = 5.0 × 10¹⁰
Now,
[[tex]y^{4-[/tex]] = [tex]\alpha _4CH_4Y[/tex]; ∝₄ = 0.35
so the equilibrium is;
[tex]Ca^{2+[/tex] + [tex]H_4Y[/tex] ⇄ [tex]CaY^{2-[/tex] + 4H⁺
Given that; [tex]CH_4Y[/tex] = [tex]Ca^{2+[/tex] { 1 mol [tex]Ca^{2+[/tex] reacts with 1 mol [tex]H_4Y[/tex] }
so at equilibrium, [tex]CH_4Y[/tex] = [tex]Ca^{2+[/tex] = x
∴
[tex]Ca^{2+[/tex] + [tex]y^{4-[/tex] ⇄ [tex]CaY^{2-[/tex]
x + x 0.010-x
since Kf is high, them x will be small so, 0.010-x is approximately 0.010
so;
Kf = [tex]CaY^{2-[/tex] / ( [[tex]Ca^{2+[/tex]][[tex]y^{4-[/tex]] ) = [tex]CaY^{2-[/tex] / ( [[tex]Ca^{2+[/tex]][[tex]\alpha _4CH_4Y[/tex]] ) = 5.0 × 10¹⁰
⇒ [tex]CaY^{2-[/tex] / ( [[tex]Ca^{2+[/tex]][[tex]\alpha _4CH_4Y[/tex]] ) = 5.0 × 10¹⁰
⇒ 0.010 / ( [x][ 0.35 × x] ) = 5.0 × 10¹⁰
⇒ 0.010 / 0.35x² = 5.0 × 10¹⁰
⇒ x² = 0.010 / ( 0.35 × 5.0 × 10¹⁰ )
⇒ x² = 0.010 / 1.75 × 10¹⁰
⇒ x² = 0.010 / 1.75 × 10¹⁰
⇒ x² = 5.7142857 × 10⁻¹³
⇒ x = √(5.7142857 × 10⁻¹³)
⇒ x = 7.559 × 10⁻⁷
Therefore, the concentration of free Ca2⁺ in this solution is 7.559 × 10⁻⁷
b. Calculate the empirical formula of a formula unit with the following percent compositions: 59.7%
lithium (Li) and 40.3% nitrogen (N). Complete the table to help with the calculations. (5 points)
Given
Li - 59.7 %
N - 40.3 %
Solution,
First get the molar mass of each Atom,
Li- 6.941
N- 14.00
Second find the moles of both atom,
moles of Li = 59.7/6.941 = 8.60
Moles of N = 40.3/14 = 2.87
Third devide both the moles with smaller mole,
first- 8.6÷2.87 = 2.99 ~ 3
second 2.87÷2.87 = 1
Ratio of Li to N is 3:1
The compound is Li3N.
As the temperature increases from 0°C to 25°C the amount of NH3 that can be dissolved in 100 grams of water.
A) decreases by 10 grams
B) decreases by 40 grams
C) increases by 10 grams
D) increases by 40 grams
Answer:
decreases by 10 gram
Explanation:
is there a gravitation attraction between you and your computer
Using what you know about the structures of the amino acid side chains and the mechanisms presented in this chapter, which of the following amino acid side chain may play the following roles in an enzymatic mechanism: a. participate in proton transfer, b. act as a nucleophile
Answer:
a. participate in proton transfer - His
b. acts as a nucleophile - Ser
Explanation:
Enzymes are regulated because they are proteins. They are categorize based on how they catalyze. Heat weakens and inactivates the enzymes because of non covalent interaction. His amino acid participate in proton transfer because it is able to act as an acid as well as a base while Ser amino acid can act as nucleophile.
Question 1
3 pts
TI
Which part(s) of the following ground state electron configuration holds the valence
electrons?
At
o
1s22s22p63523p4
ОЗр
03s
O2s
O 35 and 3p
Answer:
3s and 3p
Explanation:
From the question given above, the following data were obtained:
Electronic configuration =>
1s² 2s²2p⁶ 3s²3p⁴
Location of valence electron =?
From the electronic configuration given above, we can see clearly that the atom has three (3) shells.
Valence electron(s) are located at the outer most shell of an atom.
The outer most shell of the atom above is 3s and 3p.
Therefore, 3s and 3p will contain the valence electron(s)
Write an equation for sodium chloride and sodium oxide
Answer:
Explanation:
The Chemical Equation for each one of these compounds would be the following
Sodium Chloride: NaCl
This compound contains 1 Sodium atom and 1 Chlorine atom
Sodium Oxide: Na₂O
This compound contains 2 Sodium atoms and 1 Oxygen atom.
A balance was tested against a standard calibration mass with a certified value of 200.002 g and produced the following readings in grams: 195.587, 195.586, 195.588, 195.587, 195.589. The performance of this balance is best described as:
Answer:
Precise but not accurate.
Explanation:
We can tell the performance of the balance is precise, because the repeated measurements give values close to one another.
However, the performance of the balance is not accurate, as the mean value of the repeated measurements (195.587) is not close to the value considered as true (in this case the standard calibration mass with a certified value of 200.002 g).