What is the value of (-2.8)+0+(-2.6)+6.4

Answer:

AAS

Step-by-step explanation:

Answer:

443,226

Step-by-step explanation:

Answer:1.2389 million US$

Step-by-step explanation:

Answer: C

Step-by-step explanation: x represents the number of classes, not the cost of classes.

Answer:

213 crates

Step-by-step explanation:

There is enough space for 26000 kg - 13200 kg = 12800 kg. Divide this by 60 and you get 213 and 1/3. You cannot put 1/3 of a crate, so it is 213 crates.

Answer:

Yep linear functions look like diagonal lines. Vertical lines have a slope of 0 whilst horizontal lines aren’t even defined. Diagonal and horizontal don’t work since horizontal aren’t defined so if one doesn’t work then it won’t work.

So (a) is the answer

Diagonal lines are linear functions

Answer:

Diagonal lines........

Answer:

[tex]32\sqrt3[/tex]

Step-by-step explanation:

We need first to find the measure of the red horizontal line, call it x. The triangle i filled is a right triangle, so we can apply pythagoras theorem,

[tex]8^2 = x^2+(4\sqrt3)^2 \rightarrow 64=x^2+(16\times3) \\x^2=64-48 \rightarrow x^2=16 \rightarrow x=4[/tex]

(we are talking lengths of segment so we take only the positive root!)

At this point we can find the length of the smaller base of the trapezoid (which is [tex]10-4=6[/tex]) and apply the formula, or split the figure in a rectangle of sides 6 and [tex]4\sqrt3[/tex] and a triangle of sides [tex]4\sqrt3[/tex] and 4.

With the trapezoid formula

[tex]A=\frac12(B+b)h = \frac12(10+6)4\sqrt3 = 32\sqrt3[/tex]

With the sum of figures:

[tex]A= bh+\frac12 xh=6\times4\sqrt3 +\frac12\times4\times4\sqrt3=24\sqrt3+8\sqrt3=32\sqrt3[/tex]

Answer:

[tex]I(-2,0) \to\\ I \ ' \ (-0.5,0)\\\\J(3,2) \to\\ J \ ' \ (0.75,0.5)\\\\K(1,-1) \to\\ K \ ' \ (0.25,-0.25)\\\\[/tex]

==================================================

Explanation:

For each point, multiply each x,y coordinate by 0.25 (the scale factor) to dilate the preimage to the image. This will shrink the image because the positive scale factor is less than 1.

So for instance, point J(3,2) will have this scratch work

meaning J(3,2) moves to J ' (0.75, 0.5)

----------

Side notes:

Answer:

5/1

Step-by-step explanation:

the y is 5units and the x is 1unit

Answer:

7/4

Step-by-step explanation:

Use rise over run to solve

4-(-3)         7

-------- =      -

6-2            4

Therefore, we found that x = -5/2.

Hoped this helped.

[tex]BrainiacUser1357[/tex]

I do not know English :33333

Answer:

Question!! What is the relationship between A and B?

Step-by-step explanation:

b r = 178 + h;

b r + h = 676;

then, 178 + 2h = 676 => h = 498/2 = 249 => b r = 178 + 249 = 427

Answer:

676

Step-by-step explanation:

h=b+178=427

b=b=249

-------------

(b+178)+b=676

2b+178=676

2b=498

b=249

-------------

249+427=676

Kaneppeleqw and 2 more u

Answer:

first let's solve for x

x + (x + 30) + 2x = 180

4x + 30 = 180

-30          -30

4x = 150

/4      /4

x = 37.5

Now solve for the angle measures:

(x + 30)    =    (37.5 + 30) = 67.5

2x       =        2(37.5) = 75

x = 37.5

Answer:

X= 37.5

Step-by-step explanation:

Answer

hi

Step-by-step explanation:

ok

Using the Poisson distribution, it is found that:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by:

[tex]P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}[/tex]

The parameters are:

Item a:

In this problem, we are given the mean during an interval, which is a common event(1.4 every 8 hours), and intervals can be assumed to be independent, hence, the correct option is:

Item b:

Mean of 1.4 every 8 hours, hence, every 11 hours, the mean is:

[tex]\mu = 11 \times \frac{1.4}{8} = 1.925[/tex]

The probability is:

[tex]P(X \geq 1) = 1 - P(X = 0)[/tex]

In which:

[tex]P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}[/tex]

[tex]P(X = 0) = \frac{e^{-1.925}(1.925)^{0}}{(0)!} = 0.1459[/tex]

Then

[tex]P(X \geq 1) = 1 - P(X = 0) = 1 - 0.1459 = 0.8541[/tex]

0.8541 = 85.41% probability that from 10 A.M. to 9 P.M. there will be at least one shoplifting incident caught by security.

Item c:

The probability is:

[tex]P(X \geq 3) = 1 - P(X < 3)[/tex]

In which:

[tex]P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)[/tex]

Then:

[tex]P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}[/tex]

[tex]P(X = 0) = \frac{e^{-1.925}(1.925)^{0}}{(0)!} = 0.1459[/tex]

[tex]P(X = 1) = \frac{e^{-1.925}(1.925)^{1}}{(1)!} = 0.2808[/tex]

[tex]P(X = 2) = \frac{e^{-1.925}(1.925)^{2}}{(2)!} = 0.2703[/tex]

[tex]P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.1459 + 0.2808 + 0.2703 = 0.697[/tex]

[tex]P(X \geq 3) = 1 - P(X < 3) = 1 - 0.697 = 0.303[/tex]

0.303 = 30.3% probability that from 10 A.M. to 9 P.M. there will be at least three shoplifting incidents caught by security.

Item d:

[tex]P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}[/tex]

[tex]P(X = 0) = \frac{e^{-1.925}(1.925)^{0}}{(0)!} = 0.1459[/tex]

0.1459 = 14.59% probability that from 10 A.M. to 9 P.M. there will be no shoplifting incidents caught by security.

To learn more about the Poisson distribution, you can take a look at https://brainly.com/question/13971530

Answer:

10

Step-by-step explanation:

"Least" means smallest.

"Common" means same.

"Denominator " means the bottom number in a fraction.

Something/2 can be changed to something/10

AND something/5 can also be changed to

something/10

1/2 >>>> 5/10

3/5 >>>> 6/10

10 is the least common denominator.

Answer:

-21

Step-by-step explanation:

2-8 × 2-7 = 2-(8×2)-7

= 2-16-7

=-14-7

=-21

Answer:

A. Solution

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Algebra I

Coordinate Planes

Step-by-step explanation:

*Note:

A coordinate is a solution if both the left side and right side of the equation is equal.

Step 1: Define

Identify.

-6x + 6y = 9

(1/2, 2)

Step 2: Verify

Since 9 does indeed equal 9, the coordinate (1/2, 2) is a solution.

Answer:

  length: 13 cm

  width: 5 cm

Step-by-step explanation:

You may be aware that 65 = 5×13. We note that 13 is 3 more than twice 5, so these are the dimensions of the rectangle:

  5 cm wide; 13 cm long

__

If you want so solve this algebraically, you can let w represent the width. Then the length is 2w+3 and the area is ...

  A = LW

  65 = (2w+3)(w)

In standard form, this equation is ...

  2w^2 +3w -65 = 0

To factor this, you look for factors of 2×(-65) = -130 that have a sum of 3. Those would be ...

  -130 = (-10)(13)

Then the factored equation is ...

  2w^2 +13w -10w -65 = 0

  w(2w+13) -5(2w+13) = 0

  (w -5)(2w +13) = 0   ⇒   w = 5, -13/2

The positive solution makes sense in this problem, so ...

  width = 5 cm

  length = 2(5) +3 = 13 cm

Answer:ITS THE SECOND ONE

Step-by-step

Answer:

80

Step-by-step explanation:

Answer:

|-5| absolute be always + so 5

Answer:

[tex]5[/tex]

Step-by-step explanation:

Step 1:  Determine what absolute value does

Taking the absolute value of a number just returns how far a specific value is from 0.  So in this case we see a number -9 and although it's negative it's still 9 away from 0 therefore that would be the absolute value.

We are missing the absolute value of -5 or 5 so we know that taking the absolute value would just give us the distance from 0.  In this case that would just be 5.

Answer: [tex]5[/tex]

The decrease is  (95-68) = 27 .

As a fraction, the decrease is  27/95  of the original amount.

To change any fraction to a decimal, do the division:

                            (27)  divided by  (95) = 0.2842...

To change any decimal to a percentage, move the

decimal point two places that ==> way:

                            0.2842...  =  28.42... %Answer:

Step-by-step explanation:

[tex]\qquad[/tex]☀️ At first we need to find out the difference between 95 and 68.

[tex]\qquad[/tex][tex] \sf \longrightarrow 68 -95 \\[/tex]

[tex]\qquad[/tex][tex] \sf \longrightarrow -27[/tex]

[tex]\qquad[/tex]☀️ Now, divide the number by "the starting number.

[tex]\qquad[/tex][tex] \sf \longrightarrow \dfrac{-27 }{97}[/tex]

[tex]\qquad[/tex][tex] \sf \longrightarrow -0.2842[/tex]

[tex]\qquad[/tex]☀️ And finally, we have to multiply the result by 100 to get it in terms of percent.

[tex]\qquad[/tex][tex] \sf \longrightarrow -0.2842 \times 100[/tex]

[tex]\qquad[/tex][tex] \red{\bf \longrightarrow -28.42℅}[/tex]

[tex]\qquad[/tex]_________________________