What is the upper quartile of this data set?
82, 97, 98, 100, 102, 102, 106, 112

Answer:

mark my answer as the brainliest

Step-by-step explanation:

x = 53/4

Answer:

4×+1-9 (2^)+2)=0

4×+1-9 (4+2)=0

4×+1(-36-18)=0

4×+1 (-54)=0

4×-54=0

4×=54

×=54÷4

×=13.5

Answer:

80

Step-by-step explanation:

The median is the middle line of the box plot

Answer:

def 80

Step-by-step explanation:

Answer:

I not understand

Step-by-step explanation:

what it this

Step-by-step explanation:

the inverse of the inverse of a function is the function itself

It's like going and coming back

Answer:

9

Step-by-step explanation:

The inverse of the inverse is the input

f^-1 (f^-1(9))  = 9

As a proof

f(x) = 4x+5

y = 4x+5

Exchange x and y

x = 4y+5

Solve for y

(x+5) = 4y

(x+5)/4 = y

f^-1 (x) =  ( x-5)/4

Then find the inverse of this function

y = ( x-5) /4

Exchange x and y

x = (y-5)/4

4x = y-5

4x+5 = y

Which gives us the original function back

f^-1( input) = 4x+5

Using the value given

f^-1 (9) =  ( 9-5)/4=4/4 =1

Using the 1 from the previous part as the input

f^-1( 1) = 4*1+5  = 4+5 = 9

Answer: [tex]\dfrac{x^2}{81}+\dfrac{y^2}{56}=1[/tex]

Step-by-step explanation:

General equation of ellipse : [tex]\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}[/tex]

Given: Vertices of ellipse : (± 9,0)

Since the vertices are of the form (± a, 0).

i.e. a=9

Thus, the major axis is along x-axis.

Also, foci of the ellipse = (±5,0)

Since, foci is of the form (± c,0), i.e. c=5

Since

[tex]c^2=a^2-b^2\\\\\Rightarrow\ 5^2= 9^2-b^2\\\\\Rightarrow\ b^2=81-25\\\\\Rightarrow\ b^2=56[/tex]

Equation of ellipse :

[tex]\dfrac{x^2}{9^2}+\dfrac{y^2}{56}=1\\\\\Rightarrow\ \dfrac{x^2}{81}+\dfrac{y^2}{56}=1[/tex]

Hence, the required equation : [tex]\dfrac{x^2}{81}+\dfrac{y^2}{56}=1[/tex]

Answer:

The answer is 5,  TRUST ME

Step-by-step explanation:

I tried the other answer but i got it WRONG.

The interquartile range (IQR) of the data represents the number of points scored by each player is 7.

The interquartile range is a measure of variability which can be calculated by dividing data into quartiles.

The formula of IQR = [tex]\rm Q_{3} -Q_{1}[/tex]

The given data is as follows

4, 5, 6, 8, 9, 10, 11, 13

To find the first quartile

[tex]\rm Q_{1}[/tex] = (n + 1)/4 term

   = (8+1)/4

    = 9/4

To find the Third quartile

[tex]\rm Q_{3}[/tex] = 3(n + 1)/4 term

    = 3 (9)/4

    = 27/4

The formula of IQR = [tex]\rm Q_{3} -Q_{1}[/tex]

                                = 27/4 - 9/4

                                = 28/4

                                = 7

The interquartile range (IQR) of the data represents the number of points scored by each player on the Wildcats basketball team last game is 7.

Learn more about the interquartile range:

https://brainly.com/question/4135956

Answer:

Tina

Step-by-step explanation:

Since Amy owns the dog, she doesn't have the ferret and we know that Jewel doesn't have the ferret so the answer is Tina.

Answer:

hope it helps

this is my best

please tell me if I'm wrong

Answer:

The correct answer is D: LL ( Leg-Leg Congruence)

Step-by-step explanation:

Theorem 4.6 Leg -Leg Congruence said that if the legs of one right triangles are congruent to the corresponding legs of another right right, then the triangles are congruent.

So in this case we can tell that both triangle are congruent by Leg-Leg Congruence due to the tick marks we have on both of the legs on the two triangles.

Answer:

The answer is LL

Step-by-step explanation:

thats what i got

Answer:

b = (8)tan(30)

Step-by-step explanation:

Use mnuemonic device SOHCAHTOA

Answer:

Total mass of materials = 4.8kg

For gravel

55% of the materials are gravel

So we have

55/100 × 4.8 kg

= 2.64kg

For sand

30% of the materials are sand

We have

30/100 × 4.8

= 1.44kg

For cement

The remaining materials were cement so we add the masses of both the sand and gravel and subtract it from the total mass

That's

4.8 - (2.64 + 1.44)

4.8 - 4.08

= 0.72 kg

She earns £ 800 per week

She receives a raise of 7.5% which is

100 + 7.5 = 107.5%

So we have

107.5 / 100 × £ 800

= £ 860

She now earns £ 860 per week

Hope this helps you

Step-by-step explanation:

1)of 4.8kg concrete 55% is gravel,30% is sand and 15% is cement.

percent=Rate*Base

Pgravel=55%*4.8kg

Pgravel=2.64kg

Psand=30%*4.8kg

Psand=1.44kg

Pcement=15%*4.8kg

Pcement=0.72kg

2)percent=Rate*Base

percent=7.5%*£800

percent=60£

total earn=60£ + £800

total earn=£860

Answer:

Range of Function :  { - 9, - 5, - 1,  4 }

Step-by-step explanation:

We know that y = 2x - 5 provided the domain ( x - values ) { - 2, 0, 2, 4 }. Let us substitute each element in this set of domain as x in the equation "y = 2x - 5" as to solve for the y - values, otherwise known as the range of the function.

{ - 2, 0, 2, 4 }

y = 2( - 2 ) - 5 = - 9,

y = 2( 0 ) - 5 = - 5,

y = 2( 2 ) - 5 = - 1,

y = 2( 4 ) - 5 = 4

We have the set of y - values as { - 9, - 5, - 1, 4 }. This is the range of our function.

Answer:

HIG=28°

Step-by-step explanation:

HI is a diameter therefore it's measure is 180°

HI-IG=HG

180-128=HG

52°=HG

HIG=1/2HG

HIG=1/2(56°)

HIG=28°

Answer:

3/10

Step-by-step explanation:

1/5 of total income - spent on car

remainder income = 4/5

3/8 of remainder = 3/8 ×4/5 = 3/10(of total income spent on rent)

the word "of" means you can find it by multiplication

e.g. 2 of 1/2 means 2 × 1/2 which is 1

Answer:

The arc measure, x, that the satellite can see is 160°

Step-by-step explanation:

Given that the two tangents intersect at a point outside the with circle center O

The angle formed between between the two tangent = 20°

The first arc formed is measured as x°, which is the arc opposite the point where the two tangents meet = The arc the satellite can see

The angle x is given by the relationship;

x = 2 × (90 - v/2)

Where;

v = The angle formed at the point where the two tangent meet = 20°

Therefore;

x = 2 × (90 - 20/2) =  2 × (90 - 10) =  2 × 80  = 160°

The arc measure, x, that the satellite can see = 160°.

Answer:

160

Step-by-step explanation:

edge

===========================================

Work Shown:

40 coins total

16 are dimes

40-16 = 24 coins are not dimes

Half of this is 24*(1/2) = 12 which are quarters. The other half (12) are pennies and nickels

n = number of nickels

p = number of pennies

This means n+p = 12 so that we have 12 pennies and nickels combined.

"There are 2 nickels for every penny", so we can write n = 2p. If p = 1, then n = 2. If p = 2, then n = 4, etc. Whatever p is, we double it to get n.

So,

n+p = 12

2p+p = 12

3p = 12

p = 12/3

p = 4, we have 4 pennies

n = 2p

n = 2*4

n = 8 and 8 nickels

-----------------------------------------

Here are all the coin counts

16+12+8+4 = 40 coins total

Answer:

Option (B) is correct, 4 pennies.

Answer:

[tex]$\frac{3\pi }{2}$[/tex]

Step-by-step explanation:

Solve for the interval: [tex][0, 2\pi)[/tex]

[tex]4 \csc(\theta)+1=-3[/tex]

[tex]4 \csc(\theta)=-4[/tex]

[tex]\csc(\theta)=-1[/tex]

[tex]$\frac{1}{\sin(\theta)} =-1 \Rightarrow \sin(\theta)=-1$[/tex]

We have [tex]\sin(\theta)=-1[/tex] for coterminal angles [tex]$\frac{3\pi }{2}+2\pi n$[/tex]

Once we just want the interval [tex][0, 2\pi)[/tex]

The solution is [tex]$\frac{3\pi }{2}$[/tex]

Answer:

Step-by-step explanation:

Let the missing percent be 'x'

[tex] x \: \times \: \frac{1}{6} = \frac{2}{3} [/tex]

Use the commutative property to reorder the terms

[tex] \frac{1}{6} x = \frac{2}{3} [/tex]

Multiply both sides of the equation by 6

[tex] \frac{1}{6} x \times 6 = \frac{2}{3} \times 6[/tex]

Calculate

[tex]x = 4 \:[/tex] %

b. [tex]x \: \times 1 \frac{3}{5} = 0.2[/tex]

Convert the mixed number into improper fraction

[tex]x \times \frac{8}{5} = 0.2[/tex]

Use the commutative property to reorder the terms

[tex] \frac{8}{5} x = 0.2[/tex]

Multiply both sides of the equation by [tex] \frac{5}{8} [/tex]

[tex] \frac{8}{5} x \times \frac{5}{8} = 0.2 \times \frac{5}{8} [/tex]

Calculate

[tex]x = 0.125 \: [/tex] %

Hope this helps..

Best regards!!

Answer:

1)  2/3 is 400% of 1/6

2) 0.2 is 12.5% of 1 3/5

Step-by-step explanation:

1) First, let's switch these two fractions to a low common denominator. I used sixths, and got 4/6 and 1/6. then, noticing that 4/6 is 4x bigger than 1/6, and 100% means all of the 1/6, and 4/6 is 4x that, 4x 100% is 400%, that's the answer ;-)

2) First, let's convert these both to fractions, 1/5 and 1 3/5, which converts to 8/5. 8/5 is 8x as much as 1/5, which means that it is 12.5%

hope this helps and gives a clear answer!

Answer:

The value of a is e³ and b is e.

The steps are :

First, you have to integrate the expression shown in the first picture.

Next, you have to solve it as simultaneous equation shown in the second picture.

You have to apply :

[tex] ln(b) - ln(a) = ln( \frac{b}{a} ) [/tex]

[tex] ln(y) = x \: ⇒ \: {e}^{x} = y[/tex]

Answer:

3,5,7

Step-by-step explanation:

Answer:

7,8.15

Step-by-step explanation:

a) The theoretical probability of landing on A or E is 2/5. This is because there are two sections we want to land on (either A or E) out of 5 sections total.

--------------------------

b) The empirical probability of landing on A or E is 3/10, which was reduced from 6/20. This is because there are 4+2 = 6 times we landed on either A or E out of 20 spins total.

--------------------------

c) Due to the nature of random events, the theoretical and empirical probabilities will not match up perfectly (basically every random experience will be different for each person). This is especially true for small sample sizes. However, as you do more spins, you should find that the empirical probabilities will slowly approach the theoretical probability. The theoretical probability is always going to be 2/5 for this problem; while the empirical probabilities will bounce around because of the nature of random chance.

Answer:

a = 9

Step-by-step explanation:

In the product (y−3)(y2+3y+9), we can get the first degree term of y in two ways,

y*(9),  or -3*(3y)...............value in parentheses are from the second factor

therefore a = 9

Answer:

a = 9

Step-by-step explanation:

Let's work on the product to answer the question:

[tex](y-3)\,(y^2+3y+9)= y^3+3y^2+9y-3y^2-9y-27[/tex]

therefore the value of the requested "a" is 9

3x+4y=12 is Linear.

y-1/2x+6 is Linear.

y=4x^2 is nonlinear.

y+2=|4| is linear.

y+6=4x is linear.

In order to tell whether an equation is linear or not, you have to first see if there is any variable^2 or more than ^1. If that is the case, it isn't linear. For example the equation x^2=4 or y^5=100 isn't linear. It also isn't linear if the equation is divided by X or Y.For example the equation 1/x=1 isn't linear or 1/y^2=5 isn't linear.

A question is also linear if you can write it in the form y=mx+b , 'm' meaning the slope of the equation and 'b' meaning the y-intercept of the equation.

Answer:

C. [tex](5-\frac{1}{2})^6[/tex]

Step-by-step explanation:

Given

[tex]15(5)^2(-\frac{1}{2})^4[/tex]

Required

Determine which binomial expansion it came from

The first step is to add the powers of he expression in brackets;

[tex]Sum = 2 + 4[/tex]

[tex]Sum = 6[/tex]

Each term of a binomial expansion are always of the form:

[tex](a+b)^n = ......+ ^nC_ra^{n-r}b^r+.......[/tex]

Where n = the sum above

[tex]n = 6[/tex]

Compare [tex]15(5)^2(-\frac{1}{2})^4[/tex] to the above general form of binomial expansion

[tex](a+b)^n = ......+15(5)^2(-\frac{1}{2})^4+.......[/tex]

Substitute 6 for n

[tex](a+b)^6 = ......+15(5)^2(-\frac{1}{2})^4+.......[/tex]

[Next is to solve for a and b]

From the above expression, the power of (5) is 2

Express 2 as 6 - 4

[tex](a+b)^6 = ......+15(5)^{6-4}(-\frac{1}{2})^4+.......[/tex]

By direct comparison of

[tex](a+b)^n = ......+ ^nC_ra^{n-r}b^r+.......[/tex]

and

[tex](a+b)^6 = ......+15(5)^{6-4}(-\frac{1}{2})^4+.......[/tex]

We have;

[tex]^nC_ra^{n-r}b^r= 15(5)^{6-4}(-\frac{1}{2})^4[/tex]

Further comparison gives

[tex]^nC_r = 15[/tex]

[tex]a^{n-r} =(5)^{6-4}[/tex]

[tex]b^r= (-\frac{1}{2})^4[/tex]

[Solving for a]

By direct comparison of [tex]a^{n-r} =(5)^{6-4}[/tex]

[tex]a = 5[/tex]

[tex]n = 6[/tex]

[tex]r = 4[/tex]

[Solving for b]

By direct comparison of [tex]b^r= (-\frac{1}{2})^4[/tex]

[tex]r = 4[/tex]

[tex]b = \frac{-1}{2}[/tex]

Substitute values for a, b, n and r in

[tex](a+b)^n = ......+ ^nC_ra^{n-r}b^r+.......[/tex]

[tex](5+\frac{-1}{2})^6 = ......+ ^6C_4(5)^{6-4}(\frac{-1}{2})^4+.......[/tex]

[tex](5-\frac{1}{2})^6 = ......+ ^6C_4(5)^{6-4}(\frac{-1}{2})^4+.......[/tex]

Solve for [tex]^6C_4[/tex]

[tex](5-\frac{1}{2})^6 = ......+ \frac{6!}{(6-4)!4!)}*(5)^{6-4}(\frac{-1}{2})^4+.......[/tex]

[tex](5-\frac{1}{2})^6 = ......+ \frac{6!}{2!!4!}*(5)^{6-4}(\frac{-1}{2})^4+.......[/tex]

[tex](5-\frac{1}{2})^6 = ......+ \frac{6*5*4!}{2*1*!4!}*(5)^{6-4}(\frac{-1}{2})^4+.......[/tex]

[tex](5-\frac{1}{2})^6 = ......+ \frac{6*5}{2*1}*(5)^{6-4}(\frac{-1}{2})^4+.......[/tex]

[tex](5-\frac{1}{2})^6 = ......+ \frac{30}{2}*(5)^{6-4}(\frac{-1}{2})^4+.......[/tex]

[tex](5-\frac{1}{2})^6 = ......+15*(5)^{6-4}(\frac{-1}{2})^4+.......[/tex]

[tex](5-\frac{1}{2})^6 = ......+15(5)^{6-4}(\frac{-1}{2})^4+.......[/tex]

[tex](5-\frac{1}{2})^6 = ......+15(5)^2(\frac{-1}{2})^4+.......[/tex]

Check the list of options for the expression on the left hand side

The correct answer is [tex](5-\frac{1}{2})^6[/tex]

Answer:

7 < (third side length) < 37

Step-by-step explanation:

Add these two side lengths together.  We get 37.  Unless the 3rd side is LESS than 37, we cannot form a triangle.  

Next, subtract 15 from 22, obtaining 7.  The 3rd side has to be GREATER than 7 in order for the sides 7+, 15 and 22 to form a triangle.

7 < (third side length) < 37

Answer:

26.63 ??

Step-by-step explanation:

I think you use pythagorean theorum to solve.

do 22^2 and 15^2 and get 709.1569

sqrt of that is 26.63

Answer:

The awnser is 64

Step-by-step explanation:

It is 64 because you devide the perimiter (32) by 4, to get all sides, and then multiply 1 side by the other to get 64

THIS METHOD ONLY WORKS FOR A SQUARE

Answer:

6 seconds

Step-by-step explanation:

Total distance between the 2 rear cars = [tex]\\\frac{1}{12} + \frac{1}{12} = \frac{1}{6}\\\\\\\\\\Relative speed of the trains = 50 + 50 = 100 mphT = \frac{Distance}{Speed} = \frac{1}{6} * \frac{1}{100} = \frac{1}{600} hours\\T = \frac{1}{600} hours or \frac{3600}{600} = 6 seconds[/tex]

Answer: B.

k=3

Step-by-step explanation:

g(x) is 3 units higher than f(x)

so k must be equal to 3

Answer:

it is b i think

k=3

Step-by-step explanation:

Part A

House 1: we make exponential can be used to describe the

value of house 1. After 1 year, 253480 = 249000 x 1.02

After 2 years, 259059.6 = 25398×1.02. After 3 years 264240.79 =259059.60x1.02.

House 1: we make linear. 256000=249000 + 1000.263000 = 256000 +7000.270000=263000 + 1000.

Part B.

House 1: f(x)=249000 1.02x [genometic sequence]

House 2: f(X) = 24900 + 1000x [arithmetic progression]

Part C

House 1: f(45)=249000×1.02 45 = 607025.697

House 2: f(45) = 249000 +7000x45 = 564000

"House 1 is an arithmetic sequence that increases in price each year while House 2 is an arithmetic sequence that only increases by 1000 per year.

In computational mathematics, a word problem is a problem of deciding whether two given expressions are equivalent with respect to a set of rewriting identities. A prototypical example is the word problem for groups, but there are many other instances as well.

Learn more about word problems at https://brainly.com/question/13818690

#SPJ2

Answer:

62.5°

Hope this helps :)