What is the surface area of the square pyramid? ​

Answer:

C, D and F

Step-by-step explanation:

Procedure:

9x+5=5x+21

4x+5=21 (subtract 5x)

4x=16 (subtract 5)

x=4 (divided by 4)

Answer:

n

Step-by-step explanation:

s

Answer:

Surface Area

Step-by-step explanation:

You are calculating the measurements for the surface of the prism. The interior is volume.

Answer:

Surface Area

Step-by-step explanation:

Step-by-step explanation:

First u have to do the work of bracket and the solve

Answer:

K 1 k'1

J2 j'5

L,0 l'5

Step-by-step explanation:

1. Base presents the whole number

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Answer:

64

Step-by-step explanation:

A square has 4 equal sides so all you have to do is divide 4 by 256. 256/4 is equal to 64. Therefore, the answer is 64 paving stones.

If this has helped please mark as brainliest

Answer:

[tex]A(t) = 1400(1 - e^{\frac{-t}{50}})[/tex]

Step-by-step explanation:

The net mass flow rate dA/dt = mass flow rate in - mass flow rate out

mass flow rate in = concentration of brine in × brine flow rate in = 4 lb/gal × 7 gal/min = 28 lb/min

Let A(t) be the amount of salt at time t. The concentration of salt in the tank at time, thus C = amount of salt/volume of tank = A(t)/700 lb/gal.

Since the well mixed solution is pumped out at a rate of 14 gal/min, the mass flow rate out = concentration of salt in tank × volume flow rate out = A(t)/700 lb/gal × 14 gal/min = m(t)/50 lb/min

So, dA/dt = mass flow rate in - mass flow rate out

dA/dt = 28 lb/min - A(t)/50 lb/min

dA/dt = 28 - A(t)/50

dA/dt = [1400 - A(t)]/50

separating the variables, we have

dA/[1400 - A(t)] = dt/50

integrating both sides, we have

∫dA/[1400 - A(t)] = ∫dt/50

-1/-1 × ∫dA/[1400 - A(t)] = ∫dt/50

1/-1 × ∫-dA/[1400 - A(t)] = ∫dt/50

-1 × ㏑[1400 - A(t)] = t/50 + C

-㏑[1400 - A(t)] = t/50 + C

㏑[1400 - A(t)] = -t/50 - C

taking exponents of both sides, we have

[tex]1400 - A(t) = e^{\frac{-t}{50} - C} \\1400 - A(t) = e^{\frac{-t}{50}}e^{-C}\\1400 - A(t) = Be^{\frac{-t}{50}} ( B = e^{-C}) \\A(t) = 1400 - Be^{\frac{-t}{50}}[/tex]

when t = 0, A(0) = 0. So,

[tex]A(t) = 1400 - Be^{\frac{-t}{50}}\\A(0) = 1400 - Be^{\frac{-0}{50}}\\0 = 1400 - Be^{0}\\0 = 1400 - B\\B = 1400[/tex]

So,

[tex]A(t) = 1400 - 1400e^{\frac{-t}{50}}\\A(t) = 1400(1 - e^{\frac{-t}{50}})[/tex]

Answer:

x=[tex]\frac{4}{5}[/tex]

y=[tex]\frac{23}{5}[/tex]

Step-by-step explanation:

Look at the pictures!

Answer:

it is 32.

I know this because it was in my last year syllabus

Answer:

[tex]x=37.4[/tex]

Step-by-step explanation:

In an right triangle, the cosine of an angle is equal to its adjacent side divided by the hypotenuse (a/h).

Therefore, we have the following equation:

[tex]\cos 68^{\circ}=\frac{14}{x},\\x=\frac{14}{\cos 68^{\circ}}\approx\boxed{37.4}[/tex]

Answer: $44.96

Step-by-step explanation:

6 × 6.35 = 38.1

38.1 × .18 = 6.86

38.1 + 6.86 = 44.96

Answer:

[tex]\int _0^{\frac{3\pi }{2}}\left|\sin \left(x\right)\right|dx[/tex] = [tex]3[/tex]

Step-by-step explanation:

[tex]\int _0^{\frac{3\pi }{2}}\left|\sin \left(x\right)\right|dx[/tex] = [tex]\int _0^{\pi }\sin \left(x\right)dx+\int _{\pi }^{\frac{3\pi }{2}}-\sin \left(x\right)dx[/tex] = [tex]2+1[/tex] = [tex]3[/tex]

Answer:

u = 143º

Step-by-step explanation:

Sum of angles in a triangle is 180

The unknown angle IN the triangle

x + 90 + 53 = 180

x + 143 = 180

x = 37º

x and u are supplementary angle which total 180

u + 37 = 180

u = 143º

Answer:

517.2

Step-by-step explanation:

It has sides you're not seeing so don't forget those.

You need to find the area of the front, back, two sides, and bottom

Front & back:

6*5.2* 1/2

31.2/2 = 15.6 for each

Sides:

27*6 = 162 each

Bottom:

6*27 = 162

162+162+162+15.6+15.6= final answer

Answer: B

Step-by-step explanation:

First, you do 5.2 times 6 divided by two which is 15.6. Now you do 15.6 times two since there are two triangles and get 31.2. Now you do 27 times 6 times two and get 324 + 31.2 = 355.2. Lastly, you do 27 times 6 to get 162. 162+355.2 = 517.2

Answer:

B. In Section P, the function is linear and increasing.

Step-by-step explanation:

Answer:

B. In Section P, the function is linear and increasing.

Answer:

A≈1385.44in²

Step-by-step explanation:

A=πr2=π·212≈1385.44236in²

Answer:

1384.74 inches.

Step-by-step explanation:

The formula for area of a circle is:

[tex]a=\pi *r^2(3.14*radius*radius)[/tex]

[tex]\pi =3.14, r=radius.[/tex]

According to the word problem, the radius of the circle is 21 inches.

Now, we can just plug the numbers into the formula.

[tex]\pi *21^2(3.14*21*21)=1384.74[/tex]

Therefore, the area of the circle is 1384.74 inches.

Answer:

-30

Step-by-step explanation:

0.6x+7=0.1x-8

0.6x-0.1x=-8-7

0.5x=-15

x=-15/0.5

x=-30

Answer:

Step-by-step explanation:

Angle A and 50 will combined have an angle of 180

Angle A = 180-50

Angle C is opposite of angle A and both will be equal. Same with Angle B and it's opposing Angle.

You got this!

Answer:

8

Step-by-step explanation:

[tex]\angle RPS = 3x + 12,\ \angle QPR = 7x + 88\ =>\ \angle QPS = 3x + 12 + 7x + 88 = 180[/tex]

[tex]3x + 12 + 7x + 88 = 180[/tex]

[tex]10x + 100 = 180[/tex]

[tex]10x = 80[/tex]

[tex]x = 8[/tex]

Answer:

1568cm²

Step-by-step explanation:

28cm + 28cm = 56cm

35cm + 21cm = 56cm

56 × 56 = 3136cm²

3136cm² ÷ 2 = 1568cm²

Answer:

For a data set of N elements:

{x₁, x₂, ..., xₙ}

The median is the middle value (or the average of the two middle values)

The average or mean is:

[tex]m = \frac{x_1 + ... + x_n}{N}[/tex]

The mode is the value that is more repeated.

The range is the difference between the largest value and the smallest value.

Now, let's try to construct two sets A and B that meet the required conditions:

Let's suppose two sets of 5 values each:

A = {2, 2, 3, 4, 5}

The median of A is 3.

The range of A is = 5 - 2 = 3

The average of A is: (2 + 2 +3 +4 +5)/5 = 16/5

And the value "2" appears two times, so the mode is 2.

Now, let's try to find a data set B such that:

The mode is smaller than 2  (so for example, we can have a "1" that repeats two times)

The median is smaller than 3 (let's have a median equal to 2)

The average is larger than 16/5

The range is larger than 3

This is ratter simple:

B = {1, 1, 2, 6, 9}

The median of B is 2.

The mode of B is 1

The range of B is: 9 - 1 = 8

The average of B is: (1 + 1 + 2 + 6 + 9)/5 = 19/5

So, we just found an example for two data sets A and B such that A has a greater median and mode, while B has a greater average and range.

So the answer is yes, it is possible.

Answer:

0.1764

Step-by-step explanation:

This problem meets requirement that enables us to use the binomial probability relation :

Probability of success, p = 17% = 0.17

number of trials = 9

(1 - p) = 1 - 0.17 = 0.83

The binomial probability relation :

P(x = x) = nCx * p^x * (1 - p)^(n-x)

P(x = 3) = 9C3 * 0.17^3 * 0.83^6

P(x = 3) = 84 * 0.001606258054361897

P(x = 3) = 0.134925676566399348

P(x = 3) = 0.13492

P(x = 4) = 9C4 * 0.17^4 * 0.83^5

P(x = 4) = 126 * 0.000328992613544003

P(x = 4) = 0.041453069306544378

P(x = 4) = 0.04145

P(x = 3 or x = 4) = P(x = 3) + p(x = 4)

= 0.13492 + 0.04145

= 0.17637

= 0.1764

Answer:

100

Step-by-step explanation:

When h has the value 25, the expression 4h has the value 4(25), or 100.

Answer:

100

Step-by-step explanation:

4(25)=100

Answer:

Step-by-step explanation: