The strength of the electric field 4.0 cm from a small glass bead that has been charged to 5.0 nc will be 7.912 x 106 N/C.
The strength of an electric field 4.0 cm from a small glass bead that has been charged to 5.0 nC can be calculated using Coulomb's law.
According to this law, the electric field, E, is equal to the charge, Q, divided by the permittivity of free space, ε, multiplied by the distance between the charge and the point in space, r, squared.
Therefore, the electric field at a distance of 4.0 cm from the bead is equal to:
E = (5.0 nC) / (8.854 x 10-12 [tex]C^{2}/ nm^{2}[/tex]) x (0.04 m)
E = 7.912 x 106 N/C
This means that the electric field at a distance of 4.0 cm from the glass bead charged to 5.0 nC is 7.912 x 106 N/C.
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a photoelectric experiment is performed by separately shining a laser at 450 nm (blue light) and a laser at 560 nm (yellow light) on a clean metal surface. assume that each laser is above the threshold frequency and delivers the same number of photons per second. a. which laser will eject more electrons per second? b. which laser will eject electrons with greater kinetic energy? c. which laser will eject electrons with shorter de broglie wavelength?
The same amount of energy is delivered to the metal surface by each laser, then the yellow light must be of higher intensity than the blue light. The yellow light must generate more electrons. The blue light has a lower wavelength, then the ejected electrons must have a higher kinetic energy.
What is meant by electrons?
A negatively charged subatomic particle known as an electron can either be free or attached to an atom (not bound).One of the three main types of particles inside an atom, along with protons and neutrons, is an electron that is linked to the atom.The nucleus of an atom is made up of electrons, protons, and neutrons together.The negatively charged particles known as electrons revolve around the outside of the nucleus.For scientists, it can be challenging to monitor them because of how quickly they spin.The tiniest particles in an atom, you can put 2000 of them into a proton, they are drawn to the positive charge of the protons.To learn more about electron refer to
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Cart 1 is 6 kg and traveling at 3 m/s to the right. It collides with cart 2, which is 4 kg and traveling 4 m/s to the left. After the collision, cart 1 is moving at 4 m/s to the left. What is the velocity of cart 2?
The velocity of cart 2 will be 2.5m/s
Explain collision
A collision is a brief interaction between two or more bodies that modifies their motion due to internal forces acting between them. the forces at work during collisions (there is a change in velocity).
Primary collision types include the following: Elastic collisions: Both momentum and kinetic energy remain constant. Only momentum is conserved during inelastic collisions. The kinetic energy is lost in collisions that are perfectly inelastic, causing the objects to stick together after the collision.
Before collision :
m1 = 6kg
v1 = 3m/s
p1 = m1v1 = 3*6 = 18kg*m/s
m2 = 4kg
v2 = 4m/s
p2 = m2v2 = 4*4 = 16kg*m/s
Δp1 = p1 + p2
After collision :
m1 = 6kg
v1 = 4m/s
p1 = m1v1 = 6*4 = 24kgm/s
m2 = 4kg
v2 =?
p2 = m2v2 = 4*v2 kgm/s
Δp2 = p1 + p2
We know Δp1 = Δp2
So, 18 + 16 = 24 + 4v2
4v2 = 34-24 = 10
v2 = 10/4 = 2.5m/s .
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The total rating of utilization equipment fastened in place, other than luminaires, is not permitted to exceed ____ of the branch-circuit rating if the branch circuit also supplies lighting, other cord-and-plug-connected equipment, or both types of loads
Where lighting units, cord- and plug-connected utilization equipment not fastened in place, or both, are also supplied, the overall rating of fastened-in utilization equipment, excluding luminaires, shall not be greater than 50% of the branch-circuit ampere rating.
What is the appliance's maximum permitted load when it is secured in place? Where lighting units, cord- and plug-connected utilization equipment not fastened in place, or both, are also supplied, the overall rating of fastened-in utilization equipment, excluding luminaires, shall not be greater than 50% of the branch-circuit ampere rating.Branch circuits must be rated in accordance with the overcurrent protection device's setting or the maximum permissible ampere rating.The rating for circuits other than individual branch circuits shall be 15, 20, 30, 40, and 50 amperes.A 15-amp circuit is often served by 14-gauge wire and is protected by a 15-amp circuit breaker or fuse.A 20-amp circuit must be serviced by 12-gauge or 10-gauge wire and protected by a 20-amp breaker or fuse.To learn more about branch-circuit refer
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what is the transition from ocean to cloud
Answer:
In Explanation
Explanation:
The transition from ocean to cloud refers to the process by which water vapour in the ocean rises and condenses into clouds. This process is known as evaporation and is a key component of the water cycle.
Evaporation occurs when the sun's energy heats the surface of the ocean, causing water molecules to gain enough energy to escape into the atmosphere as water vapour. As the water vapour rises, it cools and condenses into tiny droplets, which form clouds. The clouds can be made of water droplets or ice crystals, and they can be observed in the sky in different forms, such as stratus clouds, cumulus clouds, and cirrus clouds.
This process is important for the climate and weather, as clouds play a critical role in regulating the Earth's temperature by reflecting and absorbing solar radiation. Clouds also affect precipitation, as the droplets or crystals in the clouds grow and fall as rain or snow. The transition from ocean to the cloud is also important for the water cycle as precipitation, either in form of rain or snow, replenishes the water in the oceans and rivers.
In summary, the transition from ocean to the cloud is the process by which water vapour in the ocean rises and condenses into clouds, known as evaporation, and is a key component of the water cycle. This process is important for the climate and weather, as clouds play a critical role in regulating the Earth's temperature and affecting precipitation, and replenishing the water in the oceans and rivers.
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You are pushing a book across a desk with a constant velocity. What are the forces acting on the book and in what direction? Are the y-forces equal in magnitude, why or why not? Are the x-forces equal in magnitude, why or why not? Explain using Newton’s Second Law. If you push on the book, according to Newton’s Third Law of Motion, what is the equal and reactive force?
When you are pushing a book across a desk with a constant velocity, there are two forces acting on the book: friction and the force of your push.
The force of friction acts in the opposite direction to the motion of the book and opposes the motion of the book. The force of friction is caused by the interaction between the bottom surface of the book and the surface of the desk.
The force of your push acts in the same direction as the motion of the book and causes the book to move.
The y-forces on the book are not equal in magnitude, as there is only one force acting in the y-direction, which is the force of friction. The x-forces are also not equal in magnitude, as there is one force acting in the x-direction, which is the force of your push.
According to Newton's Second Law, the force acting on an object is equal to the mass of the object multiplied by its acceleration. In this case, since the book is moving with a constant velocity, the forces acting on the book are balanced, and the net force on the book is zero.
According to Newton's Third Law of Motion, for every action, there is an equal and opposite reaction. So, when you push on the book, the equal and opposite force is the force exerted by the book on your hand.
Answer:
The book is being pushed from the side meaning there are horizontal forces at work. The first is an applied force, the second is a force of friction against the motion. Since the book is moving at a constant velocity, the book is not accelerating. This means that the forces must be balanced.
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a puck slides with speed v on a frictionless sheet of ice at the north pole. in the non-inertial rotating frame of the earth the puck moves in a circle. a) what is the radius of the circle? b) what is the period of rotation? c) now let the puck slides with speed v toward the south on a frictionless sheet of ice at the equator. what is the radius of the circle? d) now let the puck slides with speed v toward the south on a
a) The North Pole is equal to the Earth's radius (6.371 x 10⁶ m).
b) The period of rotation is 24 hours.
c) The puck moves in a circle with a radius of zero.
d) The circle's radius would be R cos(45).
What is rotation, exactly?The process by which an object spins around its own axis is referred to as "rotation." The process by which an object moves around another object is referred to as a "revolution." The Earth's rotation on its own axis, for instance, is what creates the 24-hour day.
a) In the non-inertial rotating frame of the Earth, This is because objects at the poles move in circles with a radius that is equal to the Earth's. This is caused by the Earth's rotation.
b) The puck's period of rotation, or the time it takes for the puck to complete one full revolution, is approximately the length of a day. This is due to the fact that the puck moves as a result of the Earth's rotation, which takes one day to complete.
c) When moving at a speed of v toward the south on frictionless ice at the equator, the puck moves in a circle with a radius of zero. The puck would not travel in a circular path because the Earth's rotation does not cause objects to move in circles at the equator.
d) Because it is the projection of the earth's radius onto the plane perpendicular to the axis of rotation, the circle's radius would be R cos(45). The radius projected at 45 degrees latitude is shorter than the radius projected at the equator.
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The complete question is:
A puck slides with speed v on a frictionless sheet of ice at the North Pole. In the non-inertial rotating frame of the Earth the puck moves in a circle.
a) What is the radius of the circle?
b) What is the period of rotation?
c) Now let the puck slides with speed v toward the south on a frictionless sheet of ice at the equator. What is the radius of the circle?
d) Now let the puck slide with speed v toward the south on a frictionless sheet of ice a ta latitude of 45o. What is the radius of the circle?
Objects with masses of 232 kg and 538 kg are separated by 0.342 m. a 60.6 kg mass in placed midway between them. 538 kg 1232 kg 60.6 kg - 0.342 m. find the magnitude of the net gravitational force exerted by the two larger mnsses on the 60.6 kg mass. the value of the univorsal gravi tational constant is 6.672 × 10-in- m°/kg? answer in units of n 017.leaving che distance botron the 242 kg and che 538 koenasses fixed. at what distarco from the sas ke mass fother than tahinitely remote once) does the 60.6 ka mass experienco a net fored of pay?
No net force is experienced. To find the magnitude of the net gravitational force exerted by the two larger masses on the 60.6 kg mass, we can use the equation for gravitational force.
Gravitational force equation:
F = G * (m1 * m2) / r^2
Where F is the gravitational force, G is the universal gravitational constant, m1 and m2 are the masses of the two objects, and r is the distance between them.
In this case, m1 = 232 kg, m2 = 538 kg and r = 0.342 m.
So, F = G * (232 kg * 538 kg) / (0.342 m)^2
Plugging in the values, we get:
F = 6.672 x 10^-11 N*(m^2)/(kg^2) * (232 kg * 538 kg) / (0.342 m)^2
The magnitude of the net gravitational force exerted by the two larger masses on the 60.6 kg mass is 0.092 N.
To find the distance at which the 60.6 kg mass experiences a net force of zero, we can use the equation for the gravitational force between two masses. Since the force is inversely proportional to the square of the distance between the masses, we can set the force to zero and solve for the distance.
F = G * (232 kg * 60.6 kg) / (r)^2 = 0
r = √((232 kg * 60.6 kg) / (G))
r = √((232 * 60.6) / (6.672 * 10^-11))
r = 2.36*10^-5 m
At this distance, the 60.6 kg mass experiences no net force from the two larger masses, as the gravitational force exerted by the 232 kg mass balances out the gravitational force exerted by the 538 kg mass.
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Rock B ha a ma of 100 kg and i travelling at 7 m/ in the ame direction a rock A. Rock B ha a momentum of 700 kg m/. Rock A and rock B collide and join together. Calculate the velocity of the two rock after the colliion. Show your working.
Velocity is 700kg.If you know the other values of an object's properties, you may determine its momentum or velocity using the momentum equation p is m•v.
After two objects collide, how can you determine their respective velocities?Equation v′=m1v1+m2v2m1+m2 m1 is the mass of object 1, v1 is the initial velocity of item 1, m2 is the mass of object 2, and v2 is the starting velocity of object 2, with v′ = m 1 v 1 + m 2 v 2 m 1 + m 2. v' is the final velocity of the two objects once they move as one unit following the collision.If you know the other values of an object's properties, you may determine its momentum or velocity using the momentum equation p = m•v.If a particle A with mass m is travelling toward a particle B that is stationary with velocities u from infinity, collides with B with final velocities v, and then deflects away with final velocities v, then VR=v- u is the particle's relative velocity.
Explanation:
m*v =100 * 7 = 700 kg.
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what is the repulsivee electrical force between two protons 5.0*10^-15m apart from each other in an atomic nucleus?
The repulsive electrical force between two protons is 3.6 × 10³⁹ N. The result is obtained by using the formula for electrostatic.
What is the formula for electrostatic force?The formula for electrostatic force is
F = kq₁q₂/r²
Where
F = electrostatic force (N)k = Coulomb's constant (9 × 10⁹ Nm²/C²)q₁ and q₂ = charges (C)r = distance between the charges (m)Two protons are apart from each other in an atomic nucleus. The distance between them is 5.0 × 10⁻¹⁵ m.
Find the repulsive electrical force!
Proton has a charge of +1. So, the electrostatic force would be
F = kq₁q₂/r²
F = 9 × 10⁹(1)(1)/(5.0 × 10⁻¹⁵)²
F = (9 × 10⁹)/(2.5 × 10⁻³⁰)
F = 3.6 × 10³⁹ N
Hence, the two protos has repulsive electrical force of 3.6 × 10³⁹ N.
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an atomic nucleus has a net charge of 52e. what is the magnitude of the electric field (in nn/c) at a distance of 3.87 m from the center of the nucleus?
The electric field due to the net charge of the atomic nucleus is found to be 5 x 10⁻¹⁸ C.
The formula for the electric field is,
E = Kq/r²
K is the constant,
q is the charge of the source,
r is the distance from the center of the nucleus.
The charge on the atomic nucleus is given to be 52e and the distance is given to be 3.87 m.
Now, putting values,
E = 9 x 10⁹ x 52 x 1.67 x 10⁻¹⁹/(3.87)²
E = 5 x 10⁻¹⁸ C.
So, the electric field is found to be 5 x 10⁻¹⁸ C.
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a car, on a straight road, is stopped at a traffic light. when the light turns to green the car accelerates with a constant acceleration. it reaches a speed of 23.7 m/s (85.3 km/h) in a distance of 146 m. calculate the acceleration of the car.
The acceleration of the car is 146.3 m/s². The result is obtained by using the formula for acceleration.
What is acceleration?Acceleration is the rate of change in velocity of an object with respect to time. It can be expressed as
[tex]\bar{a} = \frac{\Delta v}{\Delta t}[/tex]
Where
a = accelerationΔv = change in velocityΔt = change in timeA car stopped and moves with a constant acceleration. It means that the car moves from rest. We have
Initial speed, v₁ = 0Final speed, v₂ = 23.7 m/sDistance, Δx = 146 mThe change in time is
Δt = Δv/x
Δt = (v₂ - v₁)/Δx
Δt = (23.7 - 0)/146
Δt = 0,162 s
The acceleration of the car would be
[tex]\bar{a} = \frac{\Delta v}{\Delta t}[/tex]
[tex]\bar{a} = \frac{23.7 - 0}{0.162}[/tex]
[tex]\bar{a} = 146.3 m/s^{2}[/tex]
Hence, the car has an acceleration of 146.3 m/s².
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if you have two resistors, r1 and r2, connected in parallel. what is the maximum equivalent resistance possible?
If you have two resistors r1 and r2, connected in parallel, then the maximum equivalent resistance is approximately equal to the smallest value of r1 and r2.
Suppose we have two resistors r1 and r2, connected in parallel, then its equivalent resistance is:
1/r = 1/r1 + 1/r2
Notice that since it is a reciprocal equality, the maximum possible r will occur when one of 1/r1 or 1/r2 is equal to zero.
Let's assume 1/r2 = 0, then r = r1.
1/r2 = 0 will never be achieved, but for very large r2, we can expect:
1/r2 ≈ 0
It means, the possible maximum equivalent resistance is approximately equal to the smallest value of r1 and r2.
Example:
r1 = 2 Ohm, r2 = 10000 Ohm
1/r = 1/2 + 1/10000
1/r = 5001/10000
r = 10000/5001 = 1.999 ≈ 2 Ohm ( which is approximately equivalent to r1)
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50% part (a) how much time, in seconds, will it take for the police officer to catch up to the speeding car, assuming that the car maintains a constant speed?
The police officer will take 38.9 seconds to catch up to the speeding car, as assuming that the car maintains a constant speed.
The pace at which an object's velocity with regard to time changes is referred to as acceleration in mechanics. They are endogenous variables, accelerations. The direction of the total force exerted on an object determines the direction of its acceleration.
An object is considered to be moving at a constant speed whenever it covers relatively similar distance in the identical amount of time. When moving at a constant pace, an object covers a certain distance in a fixed amount of time. S = d t is a formula that can be used to express the speed.
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A car speeds past a stationary police officer while traveling 140 km/h. The officer immediately begins pursuit at a constant acceleration of 10.9 km/h/s, just as the driver passes her. A. How much time, in seconds, will it take for the police officer to catch up to the speeding car, assuming that the car maintains a constant speed?
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A block is on a surface with
is = 0. 325. It takes 4. 11 N to
break it free from static friction.
How much normal force acts
on the block?
(Unit = N)
The normal force acting on the block is 4.11N/0.325 = 12.68N.
Can you explain the difference between static friction and kinetic friction?
Static friction is the force that opposes to the motion of an object when it is at rest. It acts between two surfaces that are in contact and are not moving relative to each other. The force of static friction is always less than or equal to the limiting friction, and it is needed to move an object to overcome the static friction and start moving.
On the other hand, kinetic friction is the force that opposes to the motion of an object when it is in motion. It acts between two surfaces that are in contact and are moving relative to each other. The force of kinetic friction is always less than the static friction and it is needed to maintain the motion of an object. In general, the coefficient of kinetic friction is lower than the coefficient of static friction.
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The normal force acting on the block is 12.68N when block is on a surface with is = 0. 325. It takes 4. 11 N to break it free from static friction.
Evaluating :Surface = 0.325
force = 4.11 N
Static friction = 4.11N/0.325
= 12.68N.
Static friction :Static friction is the force that opposes to the motion of an object when it is at rest. It acts between two surfaces that are in contact and are not moving relative to each other. The force of static friction is always less than or equal to the limiting friction, and it is needed to move an object to overcome the static friction and start moving.
Kinetic friction :On the other hand, kinetic friction is the force that opposes to the motion of an object when it is in motion. It acts between two surfaces that are in contact and are moving relative to each other. The force of kinetic friction is always less than the static friction and it is needed to maintain the motion of an object. In general, the coefficient of kinetic friction is lower than the coefficient of static friction.
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a large boulder has a volume of 1000 cubic meters and a mass of 3,200,000 kilograms. what is the density of the boulder, in grams per cubic centimeter?
The density of the boulder in gram per centimeter cube is found to be 3.2g/cm³.
The density of the object us calculated as the mass of the body divided by the volume of the body.
So, we can write,
Density = mass/volume
Here, it is given that the mass of the body is 3200000 kg and the volume of that large boulder is 1000 cubic meter.
Now, in order to find the density is grams per cubic centimeter, we use the relation,
1 kg/m³ = 0.001 g/cm³
Now, density of the boulder is,
= 3200000/1000
= 3200
The density in g/cm³.
3200kg/m³ = 3200 x 0.001 g/cm³
Density = 3.2 g/cm³
So, the density of the boulder is 3.2g/cm³.
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Find the magnitude of the velocity of the of the chain when 5. 58 m of the chain is hanging vertically. Answer in units of m/s
The magnitude of the velocity of the of the chain when 5.58m of the chain is hanging vertically is 10.46m/s.
Given the length of chain (s) = 5.58m
We know that from Newtons second law of motion :
v^2 = u^2 + 2gs where v is the final velocity, u is the initial velocity and g is the acceleration due to gravity.
Here u = 0m/s as the chain is at rest initially.
So, v^2 = 0 + 2 x 9.8 x 5.58
v^2 = 109.368
v = √109.368 = 10.46m/s
Hence the magnitude of the velocity of the of the chain = 10.46m/s.
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what is the magnitude, in meters per squared second, of the acceleration of the jet as it accelerates along the deck?
With a=11.43 m/s2, option 4 is the proper response. The airplane accelerates to 160+ mph in less than two seconds during a catapult launch.
What is the most straightforward explanation of acceleration?The speed about which velocity decreases is known termed accelerating. Acceleration typically indicates that the speed is changing, but not necessarily. An item that is moving in a circle while maintaining a constant speed is still accelerating because the direction of its motion is shifting.
What are two instances of acceleration?An object's velocity may alter depending on whether it is moving faster, slower, or in a different direction. The moon orbiting the earth and an apple falling to the ground are two instances of acceleration.
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an electrostatic paint sprayer has a 0.400 m diameter metal sphere at a potential of 23.0 kv. (a) what charge is on the sphere?
To calculate the charge on the metal sphere, we can use the formula:
Q = V × C
where Q is the charge, V is the potential difference, and C is the capacitance.
The capacitance of a sphere is given by:
C = 4 × [tex]\pi[/tex] × ∈ × R
where R is the radius of the sphere, epsilon (∈) is the electric constant and pi is the mathematical constant.
Substituting the given values, we have:
Q = 23000 V × (4 × [tex]\pi[/tex] × 8.854 x 10⁻¹² F/m × (0.4 m / 2))
Solving for Q, we get:
Q = 2.5 x 10⁻⁸ Coulomb
So, the charge on the metal sphere is 2.5 x 10⁻⁸ Coulomb.
What is Coulomb?A coulomb (C) is the unit of electric charge in the International System of Units (SI). It is defined as the amount of electric charge transferred by a constant current of one ampere in one second. Electric charge is a fundamental property of matter, and it is the charge that causes the attraction and repulsion of electric charges. The charge of an electron is -1.60 x 10⁻¹⁹ Coulombs, and the charge of a proton is +1.60 x 10⁻¹⁹Coulombs. Coulombs are used to measure the amount of charge on an object, the amount of charge flowing through a circuit, and the amount of charge stored in a capacitor.
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a ball is thrown from 1.0 m above the ground. the initial velocity is 20 m/s at an angle of 40 degrees above the horizontal. what is the maximum height of the ball above the ground?
1.0 m above the earth, a ball is hurled. 20 m/s at an angle of 40 degrees above the horizontal is the beginning velocity. The ball may rise 9.4 metres above the earth.
The vertical velocity component of the ball's starting velocity can be used to determine the maximum height of a ball thrown at an angle.
v iy = v 0 * sin(),
here v = 0 , initial velocity
it may be used to get the vertical component of the initial velocity.
maximum height , H = v iy2 / (2 * g),
where g = 9.8m/s2
H = (20 sin 40°)²/ 2 X 9.8
H = 165.27/ 19.6
H = 8.4 m
therefore, the maximum height is = 1+ 8.4m = 9.4
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The metal wing of an airplane acts like a ""wire"" flying through Earth’s magnetic field. A voltage is induced between the wing tips, and a current flows along the wing, but only for a short time. Why does the current stop even though the airplane continues flying through Earth’s magnetic field?
The current stop even though the airplane continues flying through Earth’s magnetic field because of Lenz's Law and the function of diode.
The current stops flowing even though the airplane continues flying through Earth's magnetic field because the current generates its own magnetic field that opposes the external magnetic field that induced it. This opposing magnetic field is known as Lenz's Law, which states that the direction of induced current is always such as to oppose the change in magnetic flux that causes it. As the current flows along the wing, it creates a magnetic field that opposes the external magnetic field. This opposing magnetic field reduces the external magnetic field, which then reduces the induced voltage, and thus reduces the induced current. Eventually, the induced current reaches a point where it is no longer able to maintain a sufficient opposing magnetic field, and it stops flowing. Additionally, in airplane, there is also a device called diode which is used to rectify the induced alternating current(AC) to direct current(DC) and it only allows current to flow in one direction and stops the current flowing in the opposite direction, which also causes the current to stop flowing. In summary, the current stops flowing in the airplane's wing because of Lenz's Law and the function of diode.
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if the solar system was the size of a basketball how far away would the closet star be the closest sun be
The closest star to the Sun is Proxima Centauri, which is about 4.24 light-years away from the Sun. If the Solar System was the size of a basketball, Proxima Centauri would be about 7,967,077,874,073.7 miles away.
That means that Proxima Centauri would be about 5,305,000 times farther away from the Solar System than it is in reality. To put this in perspective, light travels at 186,000 miles per second. It would take Proxima Centauri's light over 8 years to reach the Solar System if it was the size of a basketball. That's over 3 thousand times longer than it would take in reality!
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A child with kwashiorkor has a swollen belly appearance due to:
a. Not eating enough protein to synthesize proteins needed to maintain fluid balance or transport fat from the liver.
b. Not eating enough protein to maintain lean body mass.
c. Eating too much starchy gruel.
d. Eating too many fatty foods
The correct option: a. Not eating enough protein to synthesize proteins needed to maintain fluid balance or transport fat from the liver.
Explain the causes for the kwashiorkor?Kwashiorkor is a nutritional condition most frequently observed in areas undergoing famine. It is also known as "edematous malnutrition" due to its relationship with edoema (fluid retention).
It is a type of malnutrition brought on by a diet low in protein. All body parts of those with kwashiorkor are often exceedingly emaciated, with the exception of their ankles, toes, and bellies, which expand with fluid.Kwashiorkor is brought on by a diet that is deficient in protein.This continuous cell regeneration occurs in a healthy human organism. Additionally, protein is crucial for growth during pregnancy and youth. Lack of protein will cause the body to start shutting down its regular processes, including growth, and kwashiorkor may appear.Thus, a child with kwashiorkor will appear to have a bloated stomach as a result of: Not consuming enough protein to create the proteins required to keep the body's fluid balance or move fat from the liver.
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1/15 - 1/10 = 1/di
focal length is 15 and distance of object is 10. what is the distance of the image?
The distance of the image, given that the focal length is 15 cm and the object has a distance of 10 cm is -30 cm
How do I determine the distance of the image?The relationship between focal length, object and image distance is given by the following mirror formula:
1/f = 1/v + 1/u
Where
f is the focal length v is the image distanceu is the object distanceUsing the above formula, we can obtain the distance of the image as illustrated below:
Focal length (f) = 15 cmDistance of object (u) = 10 cmDistance of image (v) =?1/f = 1/v + 1/u
Rearrange
1/v = 1/f - 1/u
v = (f × u) / (u - f)
v = (15 × 10) / (10 - 15)
v = 150 / -5
v = -30 cm
Thus, we can conclude that the distance of the image is -30 cm
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How much power is used if a truck does 50 joules of work in 10 seconds to tow a car?
The truck does 50 joules of work in 10 seconds, so the power used is 5 Watts (W) i.e, 5J/s (Joules per second) .
Evaluating power :The truck does 50 joules of work in 10 seconds, so the power used is:
Power = 50J/10s = 5J/s (Joules per second)
= 5 Watts (W)
It is important to note that the power is a scalar quantity and its unit is Joules per second (J/s) or watts (W).
Alternatively, you can derive power in terms of force and velocity as well as P=F × v.
What is Power?Power is a measure of the rate at which work is done. It is the amount of energy that is used over time. It is a scalar quantity and it has units of Joules per second (J/s) or Watts (W). Work is defined as the transfer of energy from one place to another or the transfer of energy from one system to another. Power is a measure of how fast that work is being done. For example, if a machine does a lot of work in a short amount of time, it has a high power rating.
Power can be calculated by using the formula:
Power = Work / Time
Where Work is the amount of energy that is transferred and Time is the amount of time over which the work is done.
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a tennis ball is struck horizontally from a height of 1 m. with this information alone, can we find how long the ball stayed airborne?
We cannot find how long the tennis ball that is struck horizontally from a height of 1 meter will stay airborne with the information given.
To determine the time of flight, we would need additional information such as the initial velocity of the ball, the angle at which it was struck, and the drag coefficient of the ball.
The horizontal component of velocity does not change under the influence of gravity alone, so we can't use it to determine how long the ball stays in the air. Also, we need to know the angle of launch and the drag coefficient of the ball to calculate the time of flight.
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a load of laundry consisting of cotton socks is placed in the dryer. an acrylic sock was accidently left in the dryer from the previous load. after the socks are dried, the socks are all charged with static electricity. what method of charging happened in the dryer.
The cotton socks are made of a natural material and the acrylic sock is made of synthetic material. When the socks are tumbled around in the dryer, the friction between the different materials causes electrons to transfer from the acrylic sock to the cotton socks. As a result, the cotton socks become negatively charged and the acrylic sock becomes positively charged. The static electricity observed is the result of the buildup of these opposite charges on the different materials.
What are Electrons?Electrons are subatomic particles that carry a negative electric charge. They are found outside the nucleus of an atom, in the electron cloud or electron shell. Electrons are much lighter than the protons and neutrons that make up the nucleus of an atom, and they are negatively charged, while protons carry a positive charge.
The behavior of electrons is described by quantum mechanics. They occupy specific energy levels or orbitals around the nucleus of the atom, and their movement and behavior are governed by the laws of quantum mechanics.
Electrons are the fundamental building blocks of the atomic and subatomic world, which play a crucial role in the behavior and properties of matter.
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How many joules of solar energy fall on your back as you work on your tan for 1. 5 h ? express?
It is not possible to determine the exact amount of solar energy in joules that falls on an individual's back while they are sunbathing without additional information such as the individual's location, the time of day, and weather conditions.
How does the duration of time spent tanning affect the amount of solar energy absorbed by a person's skin?The duration of time spent tanning directly affects the amount of solar energy absorbed by a person's skin. The longer a person is exposed to the sun, the more solar energy their skin absorbs. This is because the skin's melanin production increases as it is exposed to the sun's UV rays for longer periods of time. Additionally, the amount of solar energy that reaches the skin's surface increases with longer exposure as the sun's position in the sky changes. It is important to note that prolonged sun exposure can also increase the risk of skin damage and skin cancer. Therefore, it is recommended to limit sun exposure and use sunscreen to protect the skin.
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Two balls of unequal mass traveling at different speeds collide head-on and rebound in opposite
directions.
1) How does the force that ball A exerts on ball B compare to the force that ball B exerts on ball A?
2) How do the impulses received by both balls compare?
3) How do the sums of the momenta of the balls before and after the collision compare?
Can someone please answers these for me i need help.
Any incident where two or more bodies exert forces on each other quickly is referred to be a collision in physics.
When two objects collide Which of these is are true?TRUE - Any time two things collide, they apply an equal and opposing amount of force to one another. Simple Newton's law of action-reaction, this.Concussion, impact, and shock are a few typical synonyms for collision. Despite the fact that all of these phrases refer to "a forceful, even violent contact between two or more things," collision means the coming together of two or more things with such force that both or all of them are harmed or their progress is significantly hampered.According to Newton's third law, the force exerted by one marble on the other during a collision is equal in magnitude and directed in the opposite direction. The acceleration of the balls during the impact is determined by Newton's second law since the masses of the balls are equal.To learn more about collision refer to:
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10. Two students push a 100kg cart from rest up a gentle hill at a constant rate
of 2 m/s how much work was done by the students at the time they reached a
point on the hill 3m above where they began.
After 10 seconds, the final speed is 32 m/s.After 10 seconds, the displacement is 170 m.
How to determine the final velocity ?After 10 seconds, the object's final velocity can be calculated as follows:
Initially traveling at 2 m/s
a = 3 m/s for acceleration
Time (t) equals ten seconds.
Final velocity (v) =
v = u + at
v = 2 + (3 × 10)
v = 2 + 30
v = 32 m/s
Consequently, the object's terminal velocity is 32 m/s.
2. Methods for calculating displacement
After 10 seconds, the object's displacement can be calculated as follows:
Initial speed (u) equals 2 m/s
Final speed (v) is 32 m/s.
The speed of sound is 3 m/s2.
Relocation (s) =
v² = u² + 2as
32² = 2² + (2 × 3 × s)
1024 = 4 + 6s
assemble similar terms
1024 - 4 = 6s
1020 = 6s
6 divided by both sides
s = 1020 / 6
s = 170 m
The displacement is 170 m as a result.
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a group of students are analyzing their results for this activity. they come up with the following explanation: the reason the velocity we measured was lower than the velocity we predicted is that some of the kinetic energy of the marble was converted to thermal energy during the collision. also, after the collision, air friction and bending in the pendulum rod converted more kinetic energy into thermal energy. does this explanation match with the your results? explain your reasoning.
Yes, this explanation matches with the results. The lower velocity that was measured is likely due to some of the kinetic energy of the marble being converted to thermal energy during the collision.
What is kinetic energy?Kinetic energy is the energy of motion. It is the energy associated with an object's movement, or the energy of a system due to the motion of its parts. Kinetic energy is defined as the work needed to accelerate an object of a given mass from rest to its stated velocity.
This is because when two objects collide, some of the kinetic energy is converted to thermal energy. Additionally, air friction and bending in the pendulum rod can also reduce the velocity of the marble by converting more of its kinetic energy into thermal energy. Thus, both of these factors could explain the discrepancy between the measured and predicted velocities.
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