What is the speed of a
rocket that travels
8,000m in 13 seconds?

mass = 30kg

frictional force = coefficient of friction * (mass * g)

g = 9.8 m/s^2

So:

60N = x * 294 N

x = 60 N / 294 N = 0,2

Answer:

All i got to say is that he is dead dead

Explanation:

Answer:

Heat was trapped within the marshmallow.

Explanation:

Increasing temperatures make air contained within the marshmallow extend to fill up more room, causing the versatile sugar combination to spread. Eventually, if there is so much tension? It's small explosion. But take the marshmallow out from the heat, and it's going to deflate even if the extended gelatin does not really recover quickly.

Answer:

Heat gets trapped within the marshmallow.

Explanation:

Explanation:

distance

speed =_________

time

distance = speed × time

= 2.5 × 5.0

distance = 12.5 m

Answer:

She is likely to crash because her flight gradient is lesser than the flight gradient required gradient to avoid crashing

Explanation:

The given parameters are;

The required gradient of the plane Ashley is flying needs to reach in order to take off and not crash = 360 m/km

The initial elevation of the plane Ashley is flying = Sea level = 0 m

The goal Ashley intends to make = Elevation of 1000 m at 2.8 km. distance

∴ Ashley's goal = Traveling from sea level to 1000 m at 2.8 km horizontal distance

We have;

The gradient  = Rate of change of elevation/(Horizontal distance)

Therefore;

The gradient of Ashley's flight = (1000 - 0)/(2.8 - 0) = 357.143 m/km

The gradient of Ashley's flight ≈ 357.143 m/km which is lesser than the required 360 m/km in order to take off and not crash, therefore, she will crash.

Answer:

maximum height reach by rockect =970.2metre

Explanation:

Answer:

A.) a bicycle moving at a constant speed on a straight, level road.

Explanation:

Force is given by the multiplication of mass and acceleration.

Mathematically, Force is;

[tex] F = ma[/tex]

Where;

F represents force measured in Newton.

m represents the mass of an object measured in kilograms.

a represents acceleration measured in meter per seconds square.

In Physics, when the net force acting on a body or an object is equal to zero (0); the body or object is said to be in a state of equilibrium because it is not accelerating. This ultimately implies that, an object whose net force is equal to zero is either moving with a constant speed or the object is static i.e not moving at all.

In this scenario, the situation in which the net force on the object is equal to zero would be a bicycle moving at a constant speed on a straight, level road because it is at equilibrium and as such its resultant force is equal to zero.

The net force on the object (bicycle) is zero due to its constant speed on a straight levelled road. Hence, option (A) is correct.

The given problem is based on the Newton's second law to define net force. The net force on any object is an external effort by which the object change its speed with respect to time or tends to change the state of its motion. The mathematical expression for the net force is,

F = ma

Here, F is the net force, m is the mass of object and a is the acceleration of object.

Thus, we conclude that the net force on the object (bicycle) is zero due to its constant speed on a straight levelled road. Hence, option (A) is correct.

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We have that for the Question "Light travels in a transparent material at 2.5 x 10 m/s. Find the index of refraction of the material." it can be said that

From the question we are told

Light travels in a transparent material at 2.5 x 10 m/s. Find the index of refraction of the  material.

Generally the equation for the  index of refraction  is mathematically given as

[tex]n=\frac{C}{v}\\\\Therefore\\\\n=\frac{3*10^8}{2.5 * 10 }\\\\n=12000000\\\\[/tex]

Therefore

The  index of refraction  of the material is

n=12000000

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Answer:

The distance is 1.04 m and time is 0.16 seconds.

Explanation:

Initial speed, u = 6.75 m/s

Final speed, v = 5.91 m/s

Acceleration, a = -5.11 m/s²

We need to find the distance Rickey slides across the ground before touching the base and the time he sliding for before touching the base.

Let d is the distance. It can be calculated using third equation of motion as follows :

[tex]v^2-u^2=2ad\\\\d=\dfrac{v^2-u^2}{2a}\\\\d=\dfrac{(5.91)^2-(6.75)^2}{2\times (-5.11)}\\\\d=1.04\ m[/tex]

Let t is the time he slides for before touching the base. Using first equation of motion as follows :

[tex]t=\dfrac{v-u}{a}\\\\t=\dfrac{5.91-6.75}{-5.11}\\\\t=0.16\ s[/tex]

So, the distance is 1.04 m and time is 0.16 seconds.

Answer:

B. New cells are created from pre-existing cells in the human body.

Explanation:

According to the cell theory, the correct assumption from the student's investigation is that "new cells are created from pre-existing cells in the human body".

So, the student is correct to say that new cells are created from pre-existing cells in the human body.

-- The distance the force moved through

-- How long the force lasted

The other thing we need to calculate the power is the "Velocity".

The relation can be shown as:

→ [tex]P= Fv[/tex]

where,

Thus the above is the right response.

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Answer:

it wont be because the hand brake would be on

Answer:

1. The subduction zone serves as the meeting point for two tectonic plates.

2. At the Mid- Ocean ridge, decompression melting occurs.

3 What causes the magma to rise is the increase in pressure caused by collection of gases by the magma.

Explanation:

Subduction zone is define as a zone where tectonic plates ( an oceanic plate slides beneath a continental plate) meets and contributes to the rise of magma to the surface in geological sciences.

At the Mid - Oceanic ridge, decompression melting occurs. As mantle ascends beneath the mid-ocean ridge, less and less rock lies above it, so large pressure changes occur, which leads to melting. The melt is less dense than the solid, and rises to the surface to form the oceanic crust.

At the subduction zone the magma that is formed is usually made up of silica rich lava. Thick silica rich magma does not release the gasses very easily so they build up inside the magma chamber. As the gasses collect in the chamber, the pressure rises. It is possible for the pressure to rise so much that the chamber cannot contain the magma and it erupts explosively.

Answer:

hey want you to separate the energy’s and put them in the categories they go in like why are They different what is chemically different about them? Etc.why do they act differently.. do they act the same in some ways? Think about that

Explanation:

[tex]\sf{m_1}[/tex] = 8kg

[tex]\sf{m_2}[/tex] = 4kg

g = 10m/s²

→Acceleration of block

→Tension in strings

Let, the two equation will be ,

[tex]\leadsto[/tex] 8g - T = 8a ..... Equation no (1)

[tex]\leadsto[/tex] T - 4g = 4a ..... Equation no (2)

Putting the value of equation no (1) and (2) we get,

[tex]\implies[/tex] 4g = 12a

[tex]\implies[/tex] 4 × 10 = 12a

[tex]\implies[/tex] 40 = 12a

[tex]\implies[/tex] a = [tex]\sf\dfrac{\cancel{40}}{\cancel{12}}[/tex]

[tex]\dashrightarrow[/tex] a = [tex]\dfrac{10}{3}[/tex]

Again, we have to putting the value of a in the equation no (2) we get,

[tex]\implies[/tex] T - 4g = 4 × [tex]\dfrac{10}{3}[/tex]

[tex]\implies[/tex] T - 4 × 10 = 4 × [tex]\dfrac{10}{3}[/tex]

[tex]\implies[/tex] T - 40 = [tex]\dfrac{40}{3}[/tex]

[tex]\implies[/tex] T = [tex]\dfrac{40}{3}[/tex] + 40

[tex]\implies[/tex] T = [tex]\dfrac{40 + 120}{3}[/tex]

[tex]\dashrightarrow[/tex] T = [tex]\dfrac{160}{3}[/tex] N

[tex]\therefore[/tex] Acceleration of block = [tex]\dfrac{10}{3}[/tex] m/s².

And, Tension in strings = [tex]\dfrac{160}{3}[/tex] N

Answer:

correction of farsightedness uses a converging lenses that compensates for the under convergence by the eye. the converging lens produces an image farther from the eye than the object so that farsighted can see it clearly.

Answer:

load (l)=400N

Effort(E)=50N

mechanical advantage (MA)= load ÷Effort

(ma)=400÷50

(ma)=8

Explanation:

I copy pasted from the answer from the same question. Remember to first check if ur question is there

Answer:

57,6N

Explanation:

To find the component  of a force on the x-axis we can simply do:

F * cos(36) = 72N * 0.8 = 57,6N

Answer & Explanation:

Crashing into the asteroid would cause the satellite to slow down, stop, or reverse direction, because it is a force in the opposite direction to the satellite's motion. Whichever crash was a stronger force would cause it to change motion more. It takes a stronger force to change the velocity of a more massive object.

Answer:

1. The stone will strike the ground 49.46 m from the base of the cliff

2. A) Approximately 0.542 seconds

B)  Approximately 3.69 m/s

3. A) The time the ball spends in the air is approximately 4.0775 s

B) The horizontal range is approximately  141.25 m.

Explanation:

1. The time it takes the stone to land is given by the equation, t = √(h/(1/2 × g)

∴ t = √(30/(1/2 × 9.81)) ≈ 2.473 seconds

The horizontal distance covered by the stone in that time = 20 × 2.473 ≈ 49.46 m

The stone will strike the ground 49.46 m from the base of the cliff

2. A) The time the ball spends in the air = t = √(h/(1/2 × g)

∴ t = √(1.44/(1/2 × 9.81)) ≈ 0.542 seconds

B) The initial horizontal velocity, u = Horizontal distance/(Time) = 2/0.542 ≈ 3.69 m/s

The initial horizontal velocity ≈ 3.69 m/s

3. A) The time the ball spends in the air is given by the following equation;

t = 2 × u × sin(θ)/g = 2 × 40 × sin(30)/9.81 ≈ 4.0775 s

t ≈ 4.0775 s

B) The horizontal range, R, of the  ball is given by the equation for the range of a projectile as follows;

[tex]Range, R = \dfrac{u^2 \times sin (2 \cdot \theta) }{g}[/tex]

Substituting the known values, gives;

[tex]Range, R = \dfrac{40^2 \times sin (2 \times 30^{\circ}) }{9.81} \approx 141.25 \ m[/tex]

The horizontal range ≈ 141.25 m.

Answer:

80 km is distance and 30km north is displacement

Explanation:

distance= 50+30=80km

displacement= 50-20=30

his displacement is 30km north

When Tyler drives 50 km north and then drives back 30 km south, we have:

1. The distance that he covers is 80 km.

2. Tylor's displacement is 20 km.  

1. The distance is a scalar that is given by the sum of the kilometers traveled by Tyler as follows:

[tex] d = d_{1} + d_{2} = 50 km + 30 km = 80 km [/tex]

Hence, the distance traveled by Tyler was 80 km.

2. The displacement is a vector that depends on the direction of travel. Takin the north direction as positive we have:

[tex] x = x_{1} + x_{2} = 50 km + (-30 km) = 20 km [/tex]

Therefore, Tyler's displacement is 20 km.

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Answer:

The energy transported by a wave is directly proportional to the square of the amplitude. So whatever change occurs in the amplitude, the square of that effect impacts the energy. This means that a doubling of the amplitude results in a quadrupling of the energy.

Explanation:

When the energy of a wave increases, the amplitude also increases. This is because the amplitude of the wave is directly proportional to the energy of a wave.

The amplitude of a wave may be defined as the maximum displacement or distance moved by a point on a vibrating body or wave measured from its equilibrium position. It is equal to one-half the length of the vibration path.

It is the principle of physics that when the amplitude of the wave is higher, the energy also gets higher. To summarise, waves carry energy. The amount of energy they carry is related to their frequency and their amplitude. The higher the frequency, the more energy, and the higher the amplitude, the more energy.

Therefore, when the energy of a wave increases, the amplitude also increases. This is because the amplitude of the wave is directly proportional to the energy of a wave.

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Answer:

Its the third law of motion.

Explanation:

Newton's third law of motion states that every action has equal and opposite reaction.

Answer:

10 m

Explanation:

PE = mgh

m = 50kg

g= 9.8 m/s^2

h=?

so,

4900= 50×9.8× h

50h = 4900/9.8

50h = 500

h = 10 m

The acceleration of the truck is obtained from the calculation done as  0.055 m/s^2.

We know that the acceleration is defined as the rate of the change of the velocity of the object with time and we can be able to obtain the acceleration by the use of the equations of kinematics as usual.

Initial velocity =  1.8 km/h  or 0.5 m/s

Final velocity = 24.0 km/h or 6.67 m/s

Distance covered = 4.0 * 10^2 m

Then;

v^2 = u^2 + 2as

v = final velocity

u = initial velocity

a = acceleration

s = distance covered

a = v^2 - u^2/2s

a = (6.67)^2 - (0.5)^2/2 *  4.0 * 10^2

a = 44.4 - 0.25/800

a = 0.055 m/s^2

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