**Answer:**

**Power = 124.50 W**

**Explanation:**

Given that:

The Sound intensity of a speaker output is 102 dB

and the distance r = 25 m

For the intensity of sound,

[tex]\beta (dB)= 10 \ log_{10 } (\dfrac{I}{I_o})[/tex]

where;

the threshold of hearing [tex]I_o = 10^{-12} (W/m^2)[/tex]

[tex]\dfrac{102 }{10}= log_{10}( \dfrac{I}{10^{-12}})[/tex]

[tex]10^{10.2} = \dfrac{I}{10^{-12}}[/tex]

[tex]I = 10^{10.2} \times 10^{-12}[/tex]

I = 0.01585 W/m²

If we recall, we know remember that ;

Power = Intensity × A rea

Power = 0.01585 W/m² × 4 × 3.142 × (25 m)²

**Power = 124.50 W**

when hydrogen shares electrons with oxygen the outermost shell of the hydrogen atoms are full with how many electrons? and oxygens valence shell is full with how many electrons? because the valence shells of these atoms are full,the atoms are stable.

**Answer:**

2 and 8

**Explanation:**

please mark me brainiest I would really appreciate it.

You have made a simple circuit with one bulb. If you wanted to add an

extra bulb without the first bulb dimming. What would you need to

design?

A. A series circuit

B. A complex circuit

C. A parallel circuit

D. An incomplete circuit

**Answer:**

[tex]A. \: A \: series \: circuit[/tex]

**Explanation:**

♨Rage♨

**Answer:**

C. A parallel circuit

**Explanation:**

Adding a bulb in parallel with the existing bulb will apply the same voltage to both bulbs. They will light equally bright.

You would design** a parallel circuit**.

_____

In a series circuit the same current would flow in both bulbs, but that current would be at half the original current level. Both bulbs would be dimmer than the first bulb was.

It is difficult to create a "complex" circuit with only two components. An "incomplete" circuit would result in no light at all.

Find the linear velocity of a point moving with uniform circular motion, if the point covers a distance s in the given amount of time t. s

**Answer:**

The linear velocity is represented by the following expression: [tex]v = \frac{s}{t}[/tex]

**Explanation:**

From Rotation Physics we know that linear velocity of a point moving with uniform circular motion is:

[tex]v = r\cdot \omega[/tex] **(Eq. 1)**

Where:

[tex]r[/tex] - Radius of rotation of the particle, measured in meters.

[tex]\omega[/tex] - Angular velocity, measured in radians per second.

[tex]v[/tex] - Linear velocity of the point, measured in meters per second.

But we know that angular velocity is also equal to:

[tex]\omega = \frac{\theta}{t}[/tex] **(Eq. 2)**

Where:

[tex]\theta[/tex] - Angular displacement, measured in radians.

[tex]t[/tex] - Time, measured in seconds.

By applying **(Eq. 2)** in **(Eq. 1)** we get that:

[tex]v = \frac{r\cdot \theta}{t}[/tex] **(Eq. 3)**

From Geometry we must remember that circular arc ([tex]s[/tex]), measured in meters, is represented by:

[tex]s = r\cdot \theta[/tex]

[tex]v = \frac{s}{t}[/tex]

The linear velocity is represented by the following expression: [tex]v = \frac{s}{t}[/tex]

am I right? be honest

**Answer:**

I chose c because it is the greater slope at point c

When you place leftover food in the refrigerator, what kind of energy do you

decrease in the food?

A. Nuclear energy

B. Electromagnetic energy

C. Thermal energy

D. Chemical energy

By** cooling down** the food, the** thermal energy** in the **food molecules** is reduced.

A **refrigerator **is an appliance that is commonly used in the home for the purpose of **cooling down** a substnace especially water and drinks.

Due to the fact that the **molecules **that compose matter are is in a state of **constant random motion**, the food molecules contain **thermal energy. **Hence, by cooling down the food, the** thermal energy** in the food molecules is reduced.

Learn more about** thermal energy**: https://brainly.com/question/11278589

A car travels at a velocity of 80 m/s, accelerates than stops in 250 second. What is the acceleration of the truck?

(I’ll give brainliest please someone help me on this and explain it with work I don’t get it)

The acceleration is negative in other words it’s a deceleration.

using v^2 = u^2 + 2as

0 = (80^2)+ 2 a 250

0 = 6400 + 500 a

a = -6400/500 = - 12.8 m/s^2

using v^2 = u^2 + 2as

0 = (80^2)+ 2 a 250

0 = 6400 + 500 a

a = -6400/500 = - 12.8 m/s^2

An empty cup weighs 14 g. The same cup filled with ice cream weighs 120 g. All of the ice cream melts before anyone eats it.

What is the weight of the melted ice cream?

A.0 g

B. 14 g

C. 106 g

D. 134 g

**Answer:**

D

**Explanation:**

the weight of the melted ice cream is 134 g, D

A designer is creating an obstacle for an obstacle course where a person starts on a moveable platform of height H from the ground. The person grabs a rope of length L and swings downward. At the instant the rope is vertical, the person lets go of the rope and attempts to reach the far side of a water-filled moat. The left side of the moat is directly below the position where the person will let go of the rope. The designer runs several tests in which the rope has different lengths and moves the platform such that the rope is always initially horizontal. The designer notices that the person cannot land on the other side if the length L is very short. The designer also notices that the person also cannot land on the other side if the length L is very close to the height H.

Assume the size of the person is much smaller than the lengths L and H. Let D represent the horizontal distance from below the release point to where the person lands.

Required:

a. Why does the person land in the moat if the rope's length is very short?

b. Why does the person land in the moat if the length is nearly the same as the height of the platform?

**Answer:**

* when L → H chord too long

in this case we see that the speed to cross the well grows a lot (it goes towards infinity) therefore we do not have enough speed in the movement to cross

* when L → 0 very short string

the speed of the platform is very small, so we do not have the minimum required value

vox = √ (g / (2 (H)) D

**Explanation:**

For this exercise we are going to solve it using conservation of energy to find the velocity of the body and the launch of projectiles to find the velocity to cross the well.

Let's start with the projectile launch

as the body leaves the vertical its velocity must be horizontal

x = v₀ₓ t

y = y₀ + [tex]v_{oy}[/tex] t - ½ g t²

when reaching the ground its height of zero (y = 0) and the initial vertical velocity is zero

t = √ 2 y₀ / g

we substitute

x = vox √2y₀ / g

v₀ₓ = √(g / 2y₀) x

In the exercise, it tells us that the width of the well is D (x = D) and the initial height is the height of the platform minus the length of the rope (I = H - L)

v₀ₓ = √(g /(2 (H -L)) D

this is the minimum speed to cross the well.

Now let's use conservation of energy

starting point. On the platform

[tex]Em_{o}[/tex] = U = m g H

final point. At the bottom of the swing

Em_{f} = K + U = 1 / 2m v² + m g (H -L)

as there is no friction the mechanical energy is conserved

Em_{o} = Em_{f}

m g H = 1 / 2m v² + m g (H -L)

v = √ (2gL)

let's write our two equations

the minimum speed to cross the well

v₀ₓ = √ (g /(2 (H -L)) D

the speed at the bottom of the oscillatory motion

v = √ (2g L)

we analyze the extreme cases

* when L → H chord too long

in this case we see that the speed to cross the well grows a lot (it goes towards infinity) therefore we do not have enough speed in the movement to cross

* when L → 0 very short string

the speed of the platform is very small, so we do not have the minimum required value

vox = √ (g / (2 (H)) D

From this analysis we see that there is a range of lengths that allows us to have the necessary speeds to cross the well

V₀ₓ = v

g / (2 (H -L) D² = 2g L

4 L (H- L) = D²

4 H L - 4 L2 - D² = 0

L² - H L - D² / 4 = 0

let's solve the quadratic equation

L = [H ± √ (H2-D2)] / 2

we assume that H> D

L = ½ H [1 + - RA (1 - (D / H) 2)]

The two values of La give the range of values for which the two speeds are equal

A) The **person lands** in the moat if the **rope's length** is very short because :

B) The **person lands** in the moat if the rope length is similar to the **height** of the platform because :

Following the assumptions;

size of the person is much smaller than L and H

D = horizontal distance

The conditions that will cause the person to land on the moatTheHence we can conclude that The **person lands** in the moat if the **rope's length** is very short because The **speed** of the platform is less than the required **minimum speed** and The **person lands** in the moat if the rope length is similar to the **height** of the platform because,the** speed** required to cross the moat approaches **infinity.**

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The horizontal surface on which the block slides is frictionless. The speed of the block before it touches the spring is 6.0 m/s. How fast is the block moving at the instant the spring has been compressed 15 cm

**Answer:**

The final speed of the block moving at the instant the spring has been compressed is approximately 3.674 meters per second.

**Explanation:**

The spring constant is 2000 newtons per meter. Let consider the spring-block system, from Principle of Energy Conservation we can represent it by the following model:

[tex]U_{k,1}+K_{1} = U_{k,2}+K_{2}[/tex]

[tex]K_{2} = K_{1}+(U_{k,1}-U_{k,2})[/tex] **(Eq. 1)**

Where:

[tex]K_{1}[/tex], [tex]K_{2}[/tex] - Initial and final kinetic energies of the block, measured in joules.

[tex]U_{k,1}[/tex], [tex]U_{k,2}[/tex] - Initial and final elastic potential energy, measured in joules.

And we expand the equation above by definitions of elastic potential energy and kinetic energy:

[tex]\frac{1}{2}\cdot m \cdot v_{2}^{2} = \frac{1}{2}\cdot m\cdot v_{1}^{2} + \frac{1}{2}\cdot k\cdot (x_{1}^{2}-x_{2}^{2})[/tex]

[tex]v_{2} = \sqrt{v_{1}^{2}+\frac{k}{m}\cdot (x_{1}^{2}-x_{2}^{2}) }[/tex] **(Eq. 1b)**

Where:

[tex]m[/tex] - Mass of the block, measured in kilograms.

[tex]k[/tex] - Spring constant, measured in newtons per meter.

[tex]v_{1}[/tex], [tex]v_{2}[/tex] - Initial and final velocities of the block, measured in meters per second.

[tex]x_{1}[/tex], [tex]x_{2}[/tex] - Initial and final positions of spring, measured in meters.

If we know that [tex]v_{1} = 6\,\frac{m}{s}[/tex], [tex]k = 2000\,\frac{N}{m}[/tex], [tex]m = 2\,kg[/tex], [tex]x_{1} = 0\,m[/tex] and [tex]x_{2} = 0.15\,m[/tex], the final speed of the block moving at the instant the spring has been compressed is:

[tex]v_{2} = \sqrt{\left(6\,\frac{m}{s} \right)^{2}+\left(\frac{2000\,\frac{N}{m} }{2\,kg} \right)\cdot [(0\,m)^{2}-(0.15\,m)^{2}]}[/tex]

[tex]v_{2}\approx 3.674\,\frac{m}{s}[/tex]

The final speed of the block moving at the instant the spring has been compressed is approximately 3.674 meters per second.

Derivation 1.2 showed how to calculate the work of reversible, isothermal expansion of a perfect gas. Suppose that the expansion is reversible but not isothermal and that the temperature decreases as the expansion proceeds. (a) Find an expression

**Answer:**

(a) The work done by the gas on the surroundings is, 17537.016 J

(b) The entropy change of the gas is, 73.0709 J/K

(c) The entropy change of the gas is equal to zero.

Explanation:

(a) The expression used for work done in reversible isothermal expansion will be,

where,

w = work done = ?

n = number of moles of gas = 4 mole

R = gas constant = 8.314 J/mole K

T = temperature of gas = 240 K

= initial volume of gas =

= final volume of gas =

Now put all the given values in the above formula, we get:

The work done by the gas on the surroundings is, 17537.016 J

(b) Now we have to calculate the entropy change of the gas.

As per first law of thermodynamic,

where,

= internal energy

q = heat

w = work done

As we know that, the term internal energy is the depend on the temperature and the process is isothermal that means at constant temperature.

So, at constant temperature the internal energy is equal to zero.

Thus, w = q = 17537.016 J

Formula used for entropy change:

The entropy change of the gas is, 73.0709 J/K

(c) Now we have to calculate the entropy change of the gas when the expansion is reversible and adiabatic instead of isothermal.

As we know that, in adiabatic process there is no heat exchange between the system and surroundings. That means, q = constant = 0

So, from this we conclude that the entropy change of the gas must also be equal to zero.

**Explanation:**

What energy transformation takes place when you stretch a bungee cord?

**Answer:**

potential energy

**Explanation:**

A disc at rest without slipping, rolls down a hill of height (3×9.8)m.What is its speed when it reaches at the bottom?

**Answer:**

**The speed as it reaches the bottom is 24m/s**

**Explanation:**

Given parameters:

Height of hill = (3 x 9.8)m = 29.4m

Unknown:

Final speed as it reaches the bottom = ?

Solution:

To solve this problem, we apply;

v² = u² + 2gh

v is the final velocity

u is the initial velocity

g is the acceleration due to gravity = 9.8m/s²

h is the height

note, the initial speed of the body is 0;

Input the parameters and solve;

v² = 0² + 2 x 9.8 x 29.4

v² = 576.24

v = √576.24 = 24m/s

**The speed as it reaches the bottom is 24m/s**

A soccer ball accelerates from rest and rolls 6.5m down a hill in 3.1 s. It then bumps into a tree. What is the speed of the ball just before it hits the tree.

Answer:

2.096m/s

Explanation:

The speed of this soccer ball can be calculated using the formula;

Speed = distance/time

According to this question, the distance of the ball before it hits the tree is 6.5m, the time it takes is 3.1s, hence;

Speed = 6.5/3.1

Speed of the ball = 2.096m/s

Therefore, the speed of the ball before hitting the tree is 2.096m/s

The volume of water in a water bottle, is about 398

g

cm

km/hr

Kg

g/mL

ml

km

m/s

**Answer:**

milliliters (ml)

**Explanation:**

millileters is the correct measurement for liquids

A studious physics student is interrupted by a swarm of bees and chased off a cliff. Since she has her calculator in hand she quickly punches in numbers to figure out the initial velocity she needs to make it into the lake below. The cliff is 10 m high and the lake is 15 m away from the edge of the cliff. Find the time it takes her to drop. Find her initial velocity,

**Answer:**

The time is 1.4 sec

The initial velocity is 10.7 m/s.

**Explanation:**

**Given that,**

Height = 10 m

Distance = 15 m

**We need to calculate the time**

**Using equation of motion**

[tex]s=ut-\dfrac{1}{2}gt^2[/tex]

Put the value into the formula

[tex]10=0+\dfrac{1}{2}\times9.8\times t^2[/tex]

[tex]t^2=\dfrac{2\times10}{9.8}[/tex]

[tex]t=\sqrt{\dfrac{2\times10}{9.8}}[/tex]

[tex]t=1.4\ sec[/tex]

**We need to calculate the initial velocity**

**Using formula of velocity**

[tex]v=\dfrac{d}{t}[/tex]

Put the value into the formula

[tex]v=\dfrac{15}{1.4}[/tex]

[tex]v=10.7\ m/s[/tex]

**Hence, The time is 1.4 sec**

**The initial velocity is 10.7 m/s.**

Magnets are usually made up of which material

A. plastic

B. iron ore

C. copper

D. gold

**Answer:**

B. iron ore

**Explanation:**

Hope this helps

plz mark as brainliest!!!!!!

1. What is Ohm"s law?

2. If you placed a negatively charged hairbrush near your hair, what charge would your hair be?

3. You must change a lightbulb and the new lightbulb has a larger resistance. If the voltage of the battery does not change, what happens to the current going through the flashlight?

HELLPPPP

1. Ohm's law shows the relationship between:

voltagecurrentresistanceFormula: voltage = current x resistance

2. The negative charge on the hairbrush will induce a positive charge on your hair. As a result, your hair is going to be attracted to the hairbrush (and repelled by other strands of hair.)

3. V = IR, so if the resistance of the current increases, and the voltage of the current stays the same, there is as a result, going to be less current.

Best of Regards!

Two particles are separated by 0.38 m and have charges of -6.25x 10 C and 2.91 x 10 C. Use Coulomb's law to predict the force between the particles if the distance is doubled. The equation for Coulomb's law is Fe = g, and the constant, k, equals 9.00 x 10° Nm/C A. -1.13 x 10-6 N OB. 1.13x 106N O C. 2.83 x 10-7 N OD.-2.83x 10N sUBMIT

**Answer:**

I do not understand what you are asking

Which two types of energy does a book have as it falls to the floor

**Answer:**

kinetic and potential energy

**Explanation:**

A person walks 2.00 m east, then turns and goes 4.00 m west, then turns and goes back 1.00 m east. what is the distance and displacement

**Explanation:**

Let east = E, and, west = opposite to east = - E.

Here, displacement:

=> 2m east + 4m west + 1m east

=> 2E + 4(-E) + 1E

=> 2E - 4E + 1E

=> - 1E

=> 1(-E)

=> 1m west

And, distance,

=> 2m + 4m + 1m = 7m

The **distance **of a person is **7 m** and the **displacement **of the person is **1m west.**

To **find **the distance and displacement, the given values are,

A person **walks **2.00 m east, then turns and goes 4.00 m west, then turns and **goes **back 1.00 m east.

**Displacement**:

**Distance**:

Let us **consider **East = E and west = **opposite **to east = - E.

**Calculating **the **displacement**:

= 2m east + 4m west + 1m east

= 2E + 4(-E) + 1E

= 2E - 4E + 1E

= - 1E

= 1(-E)

= 1m west.

The **displacement **is **1m west**.

Now **calculating **the distance,

= 2m + 4m + 1m

= 7m

The **distance **is **7m.**

Thus, the displacement and the distance is found as **1 m west and 7m.**

Learn more about **distance **and **displacement**,

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Research has shown that this type of interview is the most effective in predicting later job

performance.

**Answer:**

Situational Interview

**Explanation:**

A situational interview is about as close to the real job as it gets. During this type of interview, candidates may be presented with a visual or audio simulation of a scenario and asked to respond to it. They are asked to analyze a problem and profer suggestions on how they would handle it.

If the candidate has solved similar problems in the past, it will come to the fore.

If they haven't then the best outcome is that it will tell the interviewers how well the candidate is able to solve similar problems.

An example of a Situational Interview question is this:

**How would you handle an angry customer who for no justifiable reason has decided to create a problematic scene to disrupt the business?**

Because Situational Interviews are about behavioral responses (present, past, and future), they are powerful tools in determining or predicting future job performance. An interviewing technique that is developed using this methodology is called the S.T.A.R.

This is an acronym for **Situation, Task, Action, Result.**

Situation: the candidate is asked to present a challenging situation that occurred recently. *This tests what the candidate sees as a challenging situation.*

Task: The candidate based on the situation is asked to identify what they need to do to remedy the problem. *This tells the interviewer(s) whether or not the candidate can think up a solution for the problem.*

Action: Here they define the actual steps taken to resolve the problem

Result: The candidate against the above is required to give the result gotten

**Action** and **Result **tell the interviewer the quality of the candidate's ability to follow through and achieve the intended results. This also judges the quality of execution in terms of cost and time. The candidate with the lowest cost and time and the highest quality of outcome is considered the best.

Cheers

Logan is a runner he in 60 seconds he can run 360 m what speed did he travel at

**Answer:**

hhhhhhhh

**Explanation:**

A dog has a mass of 60kg and an acceleration of 2m/s/s. What is the force of the dog?

The force 120 Newton’s

The coefficient of static friction between m1 and the horizontal surface is 0.50, and the coefficient of kinetic friction is 0.30. (a) If the system is released from rest, what will its acceleration be

This question is incomplete

Complete Question

m1 is 10kg, m2 is 4.0kg. The coefficient of static friction between m1 and the horizontal surface is 0.50. and the Coefficient of kinetic friction is 0.30.

a) if the system is released from rest what will be its acceleration

Answer:

0.7 m/s²

Explanation:

The coefficient of static friction between m1 and the horizontal surface is 0.50. and the coefficient of kinetic friction is 0.30.

(a) if the system is released from rest what will be its acceleration

g = acceleration due to gravity = 9.81 m/s²

Coefficient of Kinetic Friction = μk = 0.30

m1 = 10kg

m2 = 4.0kg

The formula to solve question a is given as:

a = acceleration at rest

m2g- μk m1g = (m1+ m2) a

Making a the subject of the formula:

a = (m2g- μk×m1g )/(m1+ m2)

a = [(4.0 kg × 9.81m/s²) – (0.30 ×9.81 × 10) ]/(10+4)

a = 0.7 m/s²

which two types of information are found in an elements box in the periodic table

**Answer:**

Each box represents an element and contains its atomic number, symbol, average atomic mass, and (sometimes) name.

**Explanation:**

**Answer:**

An element's period and group

At an amusement park, a swimmer uses a water slide to enter the main pool. You may want to review (Pages 234 - 241) . Part A If the swimmer starts at rest, slides without friction, and descends through a vertical height of 2.81 m , what is her speed at the bottom of the slide

**Answer:**

Her speed at the bottom of the slide is **7.42 m/s**

**Explanation:**

From the question,

The swimmer starts at rest, that is, her initial speed, u is 0 m/s.

Since she slides without friction and descends through a vertical height, then it is a free fall motion (due to gravity).

Also, from the question,

She descends through a vertical height of 2.81 m.

To determine her speed at the bottom of the slide, that is her final speed,

From one of the equations of motion for freely falling bodies

v² = u² + 2gh

Where v is the final speed

u is the initial speed

g is acceleration due to gravity (g = 9.8 m/s²)

and h is height

From the question,

u = 0 m/s

h = 2.81 m

Putting the values into the equation

v² = u² + 2gh

v² = 0² + 2×9.8×2.81

v² = 55.076

v =√55.076

v = 7.42 m/s

Hence, her speed at the bottom of the slide is **7.42 m/s.**

D

5. Mariam driving at a speed of 20.0 m/s applies

brakes close to a signal and travels a distance of

200 m before coming to rest. What was her

acceleration?

A. -0.50 m/s2

B. -0.70 m/s2

C. -1.00 m/s2

D. -2.00 m/s2

6. A trollen at rest is nushed to accelerate at a

**Answer:**

maibi.... D

**Explanation:**

I think is D

What is the net force acting on the piano?

0 11,500 N

0 -11,500 N

0 500 N

0 -500 N

**Answer:**

500

**Explanation:**

The net forces should be subtracted, so the number would be 500 N.

**Answer:**

the net force acting on the piano is -500N.

**Explanation:**

[tex]F=F_{g} -F_{t} \\F=5,500-6,000\\F=-500N[/tex]

negative sign shows that the force is acting in the upwards direction.What is force?An external agent that can change, shape, size, position, and direction is called force.

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According to Newton's first law, which characteristic of a moving object would remain constant if there were no other

forces acting on it?

O size

c

mass

O shape

O speed

Mark this and return

Save and Exit

NIKKI

Submit

in object in motion stays in motion; speed

Silly Goose falls 1.0 m to the floor. How long does the fall take

**Answer:**You need to give more explanation sorry

**Explanation:**

**Answer:**

4.20 seconds

**Explanation:**

Supposing that silly goose weighs 69 pounds, we need to start on the math.

Simple maths, truly and really. 69/1=69, of course.

Therefore it will take 4.20 seconds for silly goose to hit the ground. if he is going to be a silly goose though, he can just go in the pond, instead of wasting his time.

Researchers investigated whether the proportion of American teenagers with some level of hearing loss was diff erent in 20052006 than in 19881994. They collected data on random samples of American teenagers in those two time periods. Let the symbol 05-06 denote the population proportion of American teenagers with some level of hearing loss in 20052006 and similarly for 88-94. A 95% confidence interval for the parameter 05-06 88-94 turns out to be (0.0015, 0.0467). Required:What is an appropriate conclusion to draw?
State Hess' law of constant heat summation.(b) Calculate the enthalpy of formation of CH4 from the following data:i) C(s) + O2(g) CO2(g); H = -393.7 kJ/molii) H2(g) + 12 O2(g) H2O(l); H = -285.8 kJ/moliii) CH4(g) + 2 O2(g) CO2(g) + 2H2O(l); H = -890.4 kJ/mol
12. The table shows the height in feet of a stack of medium sized moving boxes. What is the height of a stack of 14 boxes
Which matches the cellular structure with its function in the human body?
Cualquiera de las dos rectas puede ser la de pendiente 1 o pendiente 2, slo hay queconservarla hasta el final de la operacin.BLOFrmula que vamos a aplicar:m-m1+m-mtan 0=Pendiente de la recta 3x - 4y + 8 = 0Pendiente de la recta 2x + 3y - 23 = 0Sustitucin de datostan 0 =Al realizar la operacin de la frmula se obtiene la tangente del ngulo, por lo que hayque buscar el inverso de la tangente, que es el valor del ngulo de interseccin entrelas rectas dadas.tan 8 =El valor del ngulo e es
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True or False: Squires were servants to medieval peasants.
A mi madre ___gusta bailar en el club.
What factors are included on a phase diagram?O A. Temperature and pressureO B. Pressure and volumeO C. Mass and volumeO D. Heat and kinetic energy
Choose the correct verb:The feeder (use, used) to be under a big tree in our backyard. o use o used
a.What is the length of AA?b.What is the length of BBBoth in units
Guys pls answer this for me in a minute it is really hard
WILL GIVE BRAINLST FOR WHOEVER ANSWERS FIRST Which of the following equations is equivalent to 6(3p 2) = 20?Group of answer choices9p 4 = 209p 8 = 2018p 12 = 2018p 2 = 20
im failing pls help !!!!!
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what are the main pros of cloning
what type of research is a demographer most likely to do
In a factor market, firms deliver payments in all of the following forms EXCEPT:A.rentB.profitC.loansD.wages
How do you think chemical change is defined?