What is the reciprocal of 3/9

Answer:

-3-7e/3e

Step-by-step explanation:

d - 4d=3/e +7

-3d= 3/e +7

-3d=(3+7e)/e

d=(-3-7e)/3e

The data cited is in the attachment.

Answer: 308.2±106.4

Step-by-step explanation: To construct a confidence interval, first calculate mean (μ) and standard deviation (s) for the sample:

μ = Σvalue/n

μ = 308.2

s = √∑(x - μ)²/n-1

s = 147.9

Calculate standard error of the mean:

[tex]s_{x} = \frac{s}{\sqrt{n} }[/tex]

[tex]s_{x}[/tex] = [tex]\frac{147.9}{\sqrt{12} }[/tex]

[tex]s_{x}[/tex] = 42.72

Find the degrees of freedom:

d.f. = n - 1

d.f. = 12 - 1

d.f. = 11

Find the significance level:

[tex]\frac{1-0.97}{2}[/tex] = 0.015

Since sample is smaller than 30, use t-test table and find t-score:

[tex]t_{11,0.015}[/tex] = 2.4907

E = t-score.[tex]s_{x}[/tex]

E = 2.4907.42.72

E = 106.4

The interval of confidence is: 308.2±106.4, which means that dental insurance plan varies from $201.8 to $414.6.

Answer: 8.85km

Step-by-step explanation:

8,850m = 8,850 m⋅1 km / 1,000 m

Answer: it’s undefined or 0

Step-by-step explanation:

Answer:

Undefined

Step-by-step explanation:

Slope= (y^2-y^1)/(x^2-x^1)

(x^1,y^1) and (x^2,y^2)

(9,4) and (9,-5)

SLOPE:

(-5-4)/(9-9)

-9/0

Undefined

kinda hard to show on brainy but there you go hope this helps

Answer:

m = 3

Step-by-step explanation:

It is given that there are two triangles [tex]\triangle[/tex]ABC and

[tex]\triangle[/tex]ABC ~

Also, the sides are:

AB= 3

BC= 4

DE= 2m

EF= m+5 and

∠B≅∠E

Please have a look at the attached figure for [tex]\triangle[/tex]ABC and

The triangles are similar so as per the property of similar triangles, the ratio of corresponding sides will be same.

i.e.

[tex]\dfrac{AB}{DE} = \dfrac{BC}{EF}\\\Rightarrow \dfrac{3}{2m} = \dfrac{4}{m+5}\\\Rightarrow 3 \times (m+5) = 4 \times 2m\\\Rightarrow 3m +15= 8m \\\Rightarrow 5m=15\\\Rightarrow m = 3[/tex]

So, value of m = 3.

Answer:

4/3 hours

Step-by-step explanation:

[tex]\frac{4*2}{6}\\=\frac{8}{6} \\= 4/3 hours[/tex]

Answer:

Step-by-step explanation:

1/2x^2

thats becuase that is the red parabola's equation. I don't know how to explain but I know the answer.

Answer:

Step-by-step explanation:

[tex](x + y)0 \\ x = -3 \\y = 5\\(-3+5)0\\(2)0\\= 0[/tex]

Answer:

dependent and 1.26

Step-by-step explanation:

These two individual events are dependent on each other as first they draw it and then instant they eat two red candy pieces

Now the probability of the combined event is as follows

P(Probability of combined event)  is

[tex]= P(Event 1) \times P \frac{Event 2}{Event 1}[/tex]

[tex]= \frac{55}{49} \times \frac{54}{48}[/tex]

[tex]= 1.122 \times 1.125[/tex]

= 1.26

We simply applied the above formula so that we can get the dependency or independency plus the probability of the combined event

Answer: independent & .057

Step-by-step explanation:

Answer:

The proportion of new car buyers who prefer foreign cars is 425/1519 = 0.280.

Step-by-step explanation:

The proportion of new car buyers who prefer foreign cars can be estimated from the sample proportion.

The sample results tells us that 425 out of 1519 preferred foreign cars over domestic cars.

Then, we can calculate the sample proportion as:

[tex]p=\dfrac{425}{1519}=0.280[/tex]

The proportion of new car buyers who prefer foreign cars is 425/1519 = 0.280.

Answer:

Integer

Step-by-step explanation:

Integer :a number which is not a fraction; a whole number that can be Positive or negative

Hope this helps.. Good Luck

Answer:

therefore the left work of worker will be 6/7 part of work

Answer:

The smallest sample size to satisfy the conditions is n=500.

Step-by-step explanation:

The condition for performing the inference related to the sample size is that, for all the categories, the expected success and failures in the sample are at least 10:

[tex]np\geq10\\\\n(1-p)\geq10[/tex]

The largest sample size required will be for the minimum p or (1-p).

This happens to be the proportion that can play other instruments: 2%.

Then, we can calculate the minimum sample size as:

[tex]np\geq10\\\\n(0.02)\geq10\\\\n\geq(10/0.02)\\\\n\geq500[/tex]

250

Remember there are 2 conditions to perform a goodness of fit chi-test:

Simple random sample: The data must come from a random sample or a randomized experiment.

Expected counts: All expected counts are at least five. You must state the expected counts.

To explain expected counts a bit better, imagine I surveyed 100 people about their ice cream preferences. Before beginning it is believed that 50% like chocolate, 47% like vanilla, and 3% like strawberry.

That means our expected counts are:

100(.50) = 50

100(.47) = 47

100(.03) = 3

This is a problem, because 3 < 5 and so we can not perform a goodness of fit chi-test.

So how do you find the minimum sample size? Use this formula:

sample size (n) * smallest proportion (p) = 5

In the context of ice cream:

n*.03 = 5

n = 5 / .03

n = 167 (because you can't interview 2/3s of a person)

In the context of the problem:

n* .02 = 5

n = 5 / 0.02

n = 250

This means we need to sample at least 250 people to meet our expected count condition.

Answer:The answer is B

Step-by-step explanation:

Answer:

Option B

Step-by-step explanation:

Cos A = [tex]\frac{Adjacent}{Hypotenuse}[/tex]

Where Adjacent = 28, Hypotenuse = 197

Cos A = [tex]\frac{28}{197}[/tex]

Answer:

a) 8.3 units of length

b) 31.6 units of length

Step-by-step explanation:

a) The distances traveled by each ball are given by:

[tex]d_1^2=100^2+10^2=10,100\\d_1=100.5\\\\d_2^2=90^2+(-20^2)=8,500\\d_2=92.2[/tex]

The diference between the distance traveled by both balls is:

[tex]d_1-d-2=100.5-92.2\\d_1-d_2=8.3[/tex]

The first ball traveled 8.3 units of length farther than the second ball.

b) The distance between both balls is:

[tex]d^2=(i_1-i_2)^2+(j_1-j_2)^2\\d^2=(100-90)^2+(10-(-20))^2\\d^2=1,000\\d=31.6[/tex]

The balls are 31.6 units of length apart.

Answer:

9+1224+12=1245

Hope this helps

Answer:

Mathematically,

9+1224+12 = 1245

But, Logically, here:

9+1224+12 = 21

Answer:

C.(3|-4)

Step-by-step explanation:

Given the vector:

[tex]\left[\begin{array}{ccc}4\\3\end{array}\right][/tex]

The transformation Matrix is:

[tex]\left[\begin{array}{ccc}0&1\\-1&0\end{array}\right][/tex]

The image of the vector after applying the transformation will be:

[tex]\left[\begin{array}{ccc}0&1\\-1&0\end{array}\right]\left[\begin{array}{ccc}4\\3\end{array}\right]\\\\=\left[\begin{array}{ccc}0*4+1*3\\-1*4+0*3\end{array}\right]\\\\=\left[\begin{array}{ccc}3\\-4\end{array}\right][/tex]

The correct option is C

The image after applying the transformation to the matrix is [tex]\begin{bmatrix}3\\ -4\end{bmatrix}[/tex].

Matrix, a set of numbers arranged in rows and columns so as to form a rectangular array. The numbers are called the elements, or entries, of the matrix.

It is given that the vector is

[tex]\begin{bmatrix}4\\ 3\end{bmatrix}[/tex]

and the transformation matrix is

[tex]\begin{bmatrix}0 &1 \\ -1 &0 \end{bmatrix}[/tex]

The image after applying the transformation

[tex]\begin{bmatrix}4\\ 3\end{bmatrix}\begin{bmatrix}0 &1 \\ -1 &0 \end{bmatrix}[/tex]

[tex]\begin{bmatrix}0*4+0*3 \\-1*4+0*3 \end{bmatrix}[/tex]

[tex]\begin{bmatrix}3\\ -4\end{bmatrix}[/tex]

Therefore the image after applying the transformation to the matrix is [tex]\begin{bmatrix}3\\ -4\end{bmatrix}[/tex].

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Answer:

sorry about that that was my sister . the correct answer is yes

Step-by-step explanation:

please mark as brainliest

Answer: There are systems with no solutions, and the graphs may show two regions with no intersections (as you know, the solution set is in the intersection of the sets of solutions for each inequality)

Step-by-step explanation:

Ok, suppose that our system is:

y > x

and

y < x.

This system obviously does not have any solution, because y can not be larger and smaller than x at the same time.

The graph of y > x is where we shade all the region above the line y = x (the line is not included)

and the graph of y < x is where we sade all the region under the line y = x (the line is not included)

So we will look at a graph where we never have a region with the two shades overlapping (so we do not have a intersection in the sets of solutions), meaning that we have no solutions.

Answer:

No.

Step-by-step explanation:

A quadrilateral with 3 obtuse angles is possible. You could have 100°+100°+100°+60° quadrilateral or whatever. As long as it's inner angles add up to 360°, it is possible.

Answer:

[tex]\boxed{\mathrm{It \: is \: not \: an \: empty \: set}}[/tex]

Step-by-step explanation:

A quadrilateral with 3 obtuse angles is possible.

A obtuse angle has a measure of more than 90 degrees and less than 180 degrees.

Let’s say three angles are measuring 91 degrees in a quadrilateral.

91 + 91 + 91 + x = 360

x = 87

The measure of the fourth angle is 87 degrees which is less than 360 degrees and is a positive integer, so it is possible.

Answer:  window = 0.50 m

Step-by-step explanation:

First, draw a picture (see image below).

Then set up two equations that eventually you can set equal to each other.

Given: Ladder (hypotenuse) = 2.5

           Angle to Top edge of window = 55°

          Angle to Lower edge of window = 38°

[tex]\sin \text{Top}=\dfrac{opposite}{hypotenuse}\qquad \qquad \sin \text{Lower}=\dfrac{opposite}{hypotenuse}\\\\\\\sin 55^o=\dfrac{h+y}{2.5}\qquad \qquad \qquad \sin 38^o=\dfrac{y}{2.5}\\\\\\\underline{\text{Solve both equations for y:}}\\2.5\sin 55^o-h=y\qquad \qquad 2.5\sin 38^o=y\\\\\\\underline{\text{Set the equations equal to each other and solve for h:}}\\\\2.5\sin 55^o-h=2.5\sin 38^o\\2.5\sin 55^0-2.5\sin 38^o=h\\\large\boxed{0.50=h}[/tex]

Answer:

B:<

Step-by-step explanation:

You can solve this question with fractions. The way I did it was by changing both equations into fractions like this: 6÷7=6/1x1/7=6/7 and     7÷8=7/1x1/8=7/8. Since they don't have a common denomintor and you still dont know which fraction is bigger/smaller, we are going to find a common denominator which is 56. After converting both fractions, (6/7=48/56 and 7/8=49/56)  Now you can see that 7/8 is bigger than 6/7, which shows that 6÷7<7÷8.

Answer:

1/4

Step-by-step explanation:

The classical probability assessment works based on the principle that the probability of an event occurring is equal to the number of times the event occurs divided by total number of outcomes.

That is:

P(A) = n(A) / N

Therefore, the probability that the next customer will buy a computer will be:

P(c) = 25 / 100 = 1/4

Answer:

The probability that it will take fewer than six customer contacts to clear the inventory is 0.8%.

Step-by-step explanation:

We have a probability of making an individual sale of p=0.15.

We have 4 units, so the probability of clearing the inventory with n clients can be calculated as:

[tex]P=\dbinom{n}{4}p^4q^{n-4}=\dbinom{n}{4}0.15^4\cdot 0.85^{n-4}[/tex]

As we see in the equation, n has to be equal or big than 4.

In this problem we have to calculate the probability that less than 6 clients are needed to sell the 4 units.

This probability can be calculated adding the probability from n=4 to n=6:

[tex]P=\sum_{n=4}^6P(n)=\sum_{n=4}^6 \dbinom{n}{4}0.15^4^\cdot 0.85^{n-4}\\\\\\P=0.15^4(\dfrac{4!}{4!0!}\cdot 0.85^{4-4}+\dfrac{5!}{4!1!}\cdot0.85^{5-4}+\dfrac{6!}{4!2!}0.85^{6-4})\\\\\\P=0.15^4(1\cdot0.85^0+5\cdot0.85^1+15\cdot0.85^2)\\\\\\P=0.00051(1+4.25+10.84)\\\\\\P=0.00051\cdot16.09\\\\\\P=0.008[/tex]

Answer:

Step-by-step explanation:

Given that: 3(m∠1+m∠3) = m∠2+m∠4.

From the diagram:

Therefore:

3(m∠1+m∠1) = m∠2+m∠2

3(2m∠1)=2m∠2

Divide both sides by 2

3m∠1=m∠2

m∠1+m∠2=180 (Linear Postulate)

Therefore:

m∠1+3m∠1=180

4m∠1=180

Divide both sides by 4

m∠1=45 degrees

Since m∠1=m∠3

m∠3=45 degrees

Recall: m∠1+m∠2=180 (Linear Postulate)

45+m∠2=180

m∠2=180-45

m∠2=135 degrees

Since m∠2=m∠4

m∠4=135 degrees

Answer:

[tex]t=\frac{r \sqrt{n-2}}{\sqrt{1-r^2}}[/tex]

And is distributed with n-2 degreed of freedom. df=n-2=12-2=10

The significance level is [tex]\alpha=0.01[/tex] and [tex]\alpha/2 = 0.005[/tex] and for this case we can find the critical values and we got:

[tex] t_{\alpha/2}= \pm  3.169[/tex]

Step-by-step explanation:

In order to test the hypothesis if the correlation coefficient it's significant we have the following hypothesis:

Null hypothesis: [tex]\rho =0[/tex]

Alternative hypothesis: [tex]\rho \neq 0[/tex]

The statistic to check the hypothesis is given by:

[tex]t=\frac{r \sqrt{n-2}}{\sqrt{1-r^2}}[/tex]

And is distributed with n-2 degreed of freedom. df=n-2=12-2=10

The significance level is [tex]\alpha=0.01[/tex] and [tex]\alpha/2 = 0.005[/tex] and for this case we can find the critical values and we got:

[tex] t_{\alpha/2}= \pm  3.169[/tex]

Answer:

Total revenue = 13.5 + 9 = $22.5

Step-by-step explanation:

The toll charges $1.00 for passenger cars and $2.25 for other vehicles. During daytime hours  60% of all the vehicles are passenger vehicles.

A particular daytime period 15 vehicle crossed the bridge. Recall that during daytime period, 60% of all the vehicles are passenger vehicles . Therefore,

Passenger vehicles = 60% of 15

Passenger vehicles = 60/100 × 15

Passenger vehicles = 900/100

Passenger vehicles = 9

9 of the vehicles are passenger vehicle and the charges for passenger cars is $1.00. other vehicle is $2.25.

revenue for passenger cars = 1 × 9 = $9

revenue for other vehicles = 2.25 × 6 = $13.5

Total revenue = 13.5 + 9 = $22.5

Answer:

15

Step-by-step explanation:

[tex]21-2a \\a =3\\21 -2(3)\\21-6\\15[/tex]

Answer:

Step-by-step explanation:

15 im sure

Answer:

Knowing that those vectors start at the point (0,0) we can "think" them as lines.

As you may know, two lines are parallel if the slope is the same, then we can find the "slope" of the vectors and see if it is the same.

A) the vectors are: (√3, 1) and (-√3, -1)

You may remember that the way to find the slope of a line that passes through the points (x1, y1) and (x2, y2) is s = (y2 - y1)/(x2 - x1)

Because we know that our vectors also pass through the point (0,0)

then the slopes are:

 (√3, 1) -----> s = (1/√3)

 (-√3, -1)----> s = (-1/-√3) =  (1/√3)

The slope is the same, so the vectors are parallel.

Part B:

The vectors are: (2, 3) and (-3, -2)

the slopes are:

(2, 3) -----> s = 3/2

(-3, -2)----> s = -2/-3 = 2/3

the slopes are different, so the vectors are not parallel.

∥v∥=√((6)^2+(-8)^2)=√(36+64)=√100=10. Dividing v by its magnitude, we get the unit vector u=(v/∥v∥)=(6i−8j)/10=(3/5)i−(4/5)j. Therefore, two unit vectors parallel to v are (3/5)i−(4/5)j and −(3/5)i+(4/5)j.

a. Two unit vectors parallel to v=6i−8j can be found by dividing the vector v by its magnitude. The magnitude of v can be calculated using the formula ∥v∥=√(v1^2+v2^2), where v1 and v2 are the components of v in the x and y directions, respectively. In this case, v1=6 and v2=−8. Thus,

b. To find the value of b when v=⟨1/3,b⟩ is a unit vector, we need to calculate the magnitude of v and set it equal to 1. The magnitude of v is given by ∥v∥=√((1/3)^2+b^2). Setting this equal to 1, we have √((1/3)^2+b^2)=1. Squaring both sides of the equation, we get (1/3)^2+b^2=1. Simplifying, we have 1/9+b^2=1. Rearranging the equation, we find b^2=8/9. Taking the square root of both sides, we get b=±(2√2)/3. Therefore, the value of b when v is a unit vector is b=(2√2)/3 or b=−(2√2)/3.

c. To find all values of a such that w=ai−a/3j is a unit vector, we need to calculate the magnitude of w and set it equal to 1. The magnitude of w is given by ∥w∥=√(a^2+(-a/3)^2). Setting this equal to 1, we have √(a^2+(-a/3)^2)=1. Simplifying, we get a^2+(a^2/9)=1. Combining like terms, we have (10/9)a^2=1. Dividing both sides by 10/9, we get a^2=(9/10). Taking the square root of both sides, we have a=±√(9/10). Therefore, the values of a such that w is a unit vector are a=√(9/10) or a=−√(9/10).

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